but vidar failed to connect the lead-out energy battery, so the result is invalid...

Is a lead-out battery a lead/acid battery you take the lead out of? If so, I have only lead-in batteries...

Is a lead-out battery a lead/acid battery you take the lead out of? If so, I have only lead-in batteries...

If you indeed have lead-in batteries, the solution is easy...simply reverse the polarity and you will have lead-out batteries...or a fire...I am not really sure.

Bill

One more video to prove Lawrence wrong  . Firm vs. loose pendulum base.
The loose base absorb reactive power from the oscillation, and force the pendulum to stop.

https://youtu.be/V_d7oIZ0-A0

Vidar

One more video to prove Lawrence wrong  . Firm vs. loose pendulum base.
The loose base absorb reactive power from the oscillation, and force the pendulum to stop.

https://youtu.be/V_d7oIZ0-A0

Vidar

It's the magic of damping!  The earlier video also demonstrated the magic of damping.

 @Lawrence,

My understanding of the lead-out theory comes from your ‘Divine Revelation 2’ spreadsheet.  From what I understand of the theory, gravitational energy can be ‘led out’ in the vertical direction when the horizontal balancing force is decreased, allowing the pendulum bob to drop.  The weight of the pendulum bob times the vertical drop distance represents the energy ‘led out’.  There is nothing new here unless my understanding of the theory is incorrect, so please correct me if I am in error.
 
Assuming my understanding of the theory is correct, I'm having a problem with a statement you made in another post.  In post "Reply #3159 on April 13, 2015, 10:27:17 AM" you provided a link to another post.  An excerpt from that linked post is below:
 
   Cheung:  … Can you explain the energy lead-out process more?"
   Tseung:  … The effective weight going down is higher because of the centrifugal force when the Unbalanced Weight is going down.  The
                     effective weight going up is less.  If there were no loss of energy, the height going up will be higher."
 
The explanation you gave to Cheung suggests centrifugal force is the principle energy creator and not the dropping pendulum bob as you described in the 'Devine Revelation 2' spreadsheet.  Perhaps I am not fully understanding what you are saying to Cheung, or are taking the comments out of context.  Can you please elaborate to help clear up my confusion.
 
 

@Lawrence,

My understanding of the lead-out theory comes from your ‘Divine Revelation 2’ spreadsheet.  From what I understand of the theory, gravitational energy can be ‘led out’ in the vertical direction when the horizontal balancing force is decreased, allowing the pendulum bob to drop.  The weight of the pendulum bob times the vertical drop distance represents the energy ‘led out’.  There is nothing new here unless my understanding of the theory is incorrect, so please correct me if I am in error.
 
Assuming my understanding of the theory is correct, I'm having a problem with a statement you made in another post.  In post "Reply #3159 on April 13, 2015, 10:27:17 AM" you provided a link to another post.  An excerpt from that linked post is below:
 
   Cheung:  … Can you explain the energy lead-out process more?"
   Tseung:  … The effective weight going down is higher because of the centrifugal force when the Unbalanced Weight is going down.  The
                     effective weight going up is less.  If there were no loss of energy, the height going up will be higher."
 
The explanation you gave to Cheung suggests centrifugal force is the principle energy creator and not the dropping pendulum bob as you described in the 'Devine Revelation 2' spreadsheet.  Perhaps I am not fully understanding what you are saying to Cheung, or are taking the comments out of context.  Can you please elaborate to help clear up my confusion.

The more complete explanation is in reply 3120.  The key point is listed here:
From the collection of QMOGENs, some did not use flywheels or unbalanced wheels at all.  They do not lead-out gravitational energy.  Can they lead-out magnetic or electromagnetic energy directly?


I believe the answer is YES.  Let me first list the possible situations that can lead-out gravitational energy.


1.  Horizontally push a pendulum.  The tension of the string will increase.  This increased tension will bring-in or lead-out gravitational energy.
2.  The Milkovic 2SO effect[/size].  The Centrifugal Force will be highest when the bob is at the lowest point.  This plus the weight on the RHS will produce a higher clockwise moment and raise the Weight W1 on the LHS.  Gravitational energy is brought-in.  The [/size]Chan Wheel[/size] is the improvement.
3.  The athlete on a trampoline[/size] will exert the jumping force at the right time.  The re-bouncing force plus the jumping force will send the athlete up higher with each successive jump.  Some gravitational energy is brought-in to provide the greater height.
4.  A rotating unbalanced wheel at the end of a spring.  There will be vertical oscillation of the spring.  If the period of rotation matches that of the spring, the successive pulls will reinforce and bring-in gravitational energy.
5.  An unbalanced cylinder is effectively a super set of unbalanced wheels.  It can lead-out more gravitational energy.[/size]If gravitational energy can be lead-out, magnetic or electromagnetic energy must be able to be lead-out in a similar fashion.  This can be proven with the horizontal magnetic pendulum.


Thus, it is likely magnetic or electromagnetic energy can be lead-out in an oscillation system or rotating system.  Almost all electric motors or generators have rotations.  Leading-out magnetic or electromagnetic energy is theoretically possible.


My recommendation is - do the simplified Tsinghua University QMOGEN first and confirm that the unbalanced cylinder can lead-out gravitational energy.  Add this unbalanced cylinder to almost all rotating systems and bring-in the gravitational energy


Divine Revelation 2 spreadsheet focused on point 1 - Horizontally push a pendulum. The tension of the string will increase.  This increased tension will bring-in or lead-out gravitational energy.  It does not matter whether the pendulum bob is swinging.

A few months ago, I re-examined the Milkovic 2SO.  I looked at it for over 10 years but did not see.  I finally saw that the Milkovic 2SO is overunity and was able to lead-out gravitational energy with a different mechanism.  The Centrifugal Force will be highest when the bob is at the lowest point.  This plus the weight on the RHS will produce a higher clockwise moment and raise the Weight W1 on the LHS.  Gravitational energy is brought-in.  The Chan Wheel is the improvement.

The reply to Cheung takes the theory one step further.  It extends the theory to vertical oscillation in gravitational field.  The athlete on a trampoline will exert the jumping force at the right time.  The re-bouncing force plus the jumping force will send the athlete up higher with each successive jump.  Some gravitational energy is brought-in to provide the greater height.


Another way of looking at the vertical oscillation scenario is the effective weight change.  The effective weight going down is higher because of the centrifugal force when the Unbalanced Weight is going down.  The effective weight going up is less.  If there were no loss of energy, the height going up will be higher."


Lawrence
reply 3156

Three teams in Hong Kong are doing the simplified Tsinghua University QMOGEN experiment.  At least one team is willing to share the results.


There are at least 60 QMOGEN claims now.  There is strong possibility that another one will come from Hong Kong with comments and videos from me.  Just wait...


Low-Q may be able to do the simplified Tsinghua University QMOGEN experiment also.  Another member - noonespecial - is in a good position to do it also.  His videos on youtube use the username purelyprimitives.  He has already done the Chalkalis experiments.

https://www.youtube.com/watch?v=IlUHCMtfvwg

It is simply amazing how you post links to videos that DISPROVE your unworkable ideas.  That video you linked indisputably shows the machine performing work on the stand, thereby losing, not gaining energy.  That video reinforces what we observe in Low-Q's video where the unbalanced wheel quickly slows down when the supporting structure: the pendulum is loaded.