Author Topic: Partnered Output Coils - Free Energy (Read 3543788 times)

synchro1 · « **Reply #660 on:** January 31, 2015, 09:49:38 PM »

Quote from: conradelektro on January 31, 2015, 09:34:56 PM

I think the best is to just not answer the postings of Mr. synchro1. An attention seeker will be disappointed once he gets no reply. That works with children and should therefore be the right treatment of a never-grown-up.

Greetings, Conrad

@Conradelectro,

Bootlicker!

Here's the comment from Chris. Pay attention to what he's saying: This is the test Chris asked for, not MileHigh!

@ALL,

About Frequency's, a small experiment:

1: Fuse your input just to be safe first!
2: Slowly drop your running frequency down...
3: Hold in your hand, a small magnet, close to your device.
4: Keep dropping your Frequency until you can Feel the Magnet Jump around.
5: Check all around your device with the Magnet

I found this good to get a feel for what's going on. And, yes easy for the sceptics to go to town here, but it did help me.

Also, on a side Note: Start thinking about the potentials of the Partnered Output Coils! Think about each Coil being a Bucket, How much Water can it hold...

Kind Regards

Chris Sykes - hyiq.org
To Reach New Horizons!

P.S: You should hear a Chattering of your device. Aim for around 25 - 40 Hz to do this experiment.

P.P.S: This Experiment is fairly important, so please don't pass it by! Please Run the Experiment and report your Results!

Wobbulation=The magnet jumping around!

Why can't you run the test Chis asked you too? Clean the poop from your nose and get off your knees to that bigoted bully for a change Conrad!

synchro1 · « **Reply #661 on:** January 31, 2015, 10:29:35 PM »

Here's the formula for the resonant harmonics:

"The first zero beat occurred at a point where the magnet rotation frequency was equal to 60 Hz divided by the fourth root of the Golden ratio (= (4/π)2) The next zero beat was at 60 Hz which was no surprise and both amplitudes were about twice the noise level of the 60 Hz hum. The next zero beat was about four to five times the ambient 60 Hz hum level and occurred at the square root of the golden ratio times 60 Hz. This means that the rotation frequency (wobbulation rate) reduced its rate by the amount of being divided by the square root of the Golden Ratio".

The square root of the Golden Ratio!

conradelektro · « **Reply #662 on:** January 31, 2015, 10:41:32 PM »

I did again the test of the coil with both parts of the secondary (H2 + H3) connected in parallel with R2. The resistor R1 (input) should be in the right place this time:

10 Vpp sine wave from function generator, 2 khZ

Vh = 3.04 V
Vt = 3.28 V
Vr = 3.28 - 3.04 = 0.24 V
I = 0.24 / 100 = 0.0024
Ɵ = 17°
Watt through the primary H1 (input) = 0.0024 * 0.24 * cos(17°) = 0.55 mW
V0 = 0.38
Io = 0.38 / 100 = 0.0038
Watt through R2 (output) = 0.38 * 0.0038 = 1.4 mW

Result: input of 0.55 mW through primary H1 results in an output from the partnered secondary (H2 + H3) through R2 of 1.4 mW.

As you might have noticed, it seems to be an OU result. This stems from the rather high Voltage over the primary of 3.04 Volt. This means that the primary H1 has a much higher resistance (impedance) than the 100 Ohm shunt R1.

The Voltage (RMS) over (R1 + H1) is 3.28 Volt, which means that the Voltage drop over the shunt has become very small i.e. 0.24 Volt, indicating that very little current is running from the function generator into the primary circuit.

In the "normal transformer" situation, the current through the primary circuit is about 10 times higher, due to the very low resistance (impedance) of the primary. The resistance of the 100 Ohm shunt R1 is much higher than the resistance (impedance) of the coil H1 in the "normal transformer situation" (see here http://overunity.com/15395/partnered-output-coils-free-energy/msg436051/#msg436051 ).

I do not understand the measurement, there probably is a measuring error which I can not identify at the moment.

More tests are needed, please do not get excited. I am not an expert and the chance is very high that I made a stupid error.

Would be great if someone else (may be TinselKoala) could make a similar replication. I will switch to the audio amplifier to get a higher input, but it will take time, my free time is limited in the next week.

As I recall, EMJunkie was writing about very little current through the Primary if the secondary is in a bucking configuration. And my last measurements (checked and rechecked) show exactly that. The error is not in my numbers, it must be in the measurement set up.

Greetings, Conrad

synchro1 · « **Reply #663 on:** February 01, 2015, 12:05:57 AM »

Quote from conradelectro,

"Result: input of 0.55 mW through primary H1 results in an output from the partnered secondary (H2 + H3) through R2 of 1.4 mW".

Definitive proof that all my allegations about MileHigh are entirely justifiable.

@Conradelectro,

Congratulations! You may be a candidate for the annals of "World Records". 2khz is probably right on a harmonic node. (4/π)2

MileHigh · « **Reply #664 on:** February 01, 2015, 12:24:26 AM »

Quote from: synchro1 on January 31, 2015, 08:09:04 PM

@MileHigh,

Conradelectro's just an ass kisser and you're still completely full of shit! Chris specifically asked the experimentors to examine for "Scaler Activity" in adjacency to the "Bloch Wall" of the "Bucking Coils" down in the Shumann resonant frequency range with magnet detectors. All you "Sting" racketers have done is find more ways to not get any authentic results as usual. Conrad and you both found ways to trivialize this kind magnet excitation demonstrated by Conrad last year in his "Took a Dive" Synchro coil tests.

You are shameless in how disgusting you can be. What a horrible spectacle you are for everyone to see. You are not even addressing your problem. You stop harassing me with your gutter trash mouth.

If you persist in harassing me I am asking people of good will to report Synchro1 to Stefan.

synchro1 · « **Reply #665 on:** February 01, 2015, 12:34:38 AM »

Quote from: MileHigh on February 01, 2015, 12:24:26 AM

You are shameless in how disgusting you can be. What a horrible spectacle you are for everyone to see. You are not even addressing your problem. You stop harassing me with your gutter trash mouth.

If you persist in harassing me I am asking people of good will to report Synchro1 to Stefan.

I'll report you back you two faced scum bag.

MileHigh · « **Reply #666 on:** February 01, 2015, 12:36:25 AM »

Quote from: synchro1 on February 01, 2015, 12:34:38 AM

I'll report you back you two faced scum bag.

The only reportable person will be you.

TinselKoala · « **Reply #667 on:** February 01, 2015, 12:41:47 AM »

Quote from: synchro1 on February 01, 2015, 12:05:57 AM

Quote from conradelectro,

"Result: input of 0.55 mW through primary H1 results in an output from the partnered secondary (H2 + H3) through R2 of 1.4 mW".

Definitive proof that all my allegations about MileHigh are entirely justifiable.

@Conradelectro,

Congratulations! You may be a candidate for the annals of "World Records". 2khz is probably right on a harmonic node. (4/π)2

You are indeed an astounding hypocrite. Conrad is a "bootlicker" when his results don't please your preconceptions, and when they do, he's a candidate for "world records."

Please show how (4/π)2 relates to 2kHz in some "harmonic node" fashion.

4/π = 1.273239545...
1.273239545... x 2 = 2.546479089...
Or is the "2" supposed to be an exponent?
(1.273239545...)² = 1.621138939...

None of which come anywhere near 2000 Hzor anywhere near an integer divisor or multiple of it. So explain your use of "harmonic node" and how (4/π)2 corresponds to 2kHz in such a manner.

Pirate88179 · « **Reply #668 on:** February 01, 2015, 12:55:06 AM »

If Chris is now over at OUR and makes a claim of overunity without backing it up...he won't last long over there either.

Bill

picowatt · « **Reply #669 on:** February 01, 2015, 12:55:24 AM »

Quote from: conradelektro on January 31, 2015, 10:41:32 PM

I did again the test of the coil with both parts of the secondary (H2 + H3) connected in parallel with R2. The resistor R1 (input) should be in the right place this time:

10 Vpp sine wave from function generator, 2 khZ

Vh = 3.04 V
Vt = 3.28 V
Vr = 3.28 - 3.04 = 0.24 V
I = 0.24 / 100 = 0.0024
Ɵ = 17°
Watt through the primary H1 (input) = 0.0024 * 0.24 * cos(17°) = 0.55 mW
V0 = 0.38
Io = 0.38 / 100 = 0.0038
Watt through R2 (output) = 0.38 * 0.0038 = 1.4 mW

Result: input of 0.55 mW through primary H1 results in an output from the partnered secondary (H2 + H3) through R2 of 1.4 mW.

As you might have noticed, it seems to be an OU result. This stems from the rather high Voltage over the primary of 3.04 Volt. This means that the primary H1 has a much higher resistance (impedance) than the 100 Ohm shunt R1.

The Voltage (RMS) over (R1 + H1) is 3.28 Volt, which means that the Voltage drop over the shunt has become very small i.e. 0.24 Volt, indicating that very little current is running from the function generator into the primary circuit.

In the "normal transformer" situation, the current through the primary circuit is about 10 times higher, due to the very low resistance (impedance) of the primary. The resistance of the 100 Ohm shunt R1 is much higher than the resistance (impedance) of the coil H1 in the "normal transformer situation" (see here http://overunity.com/15395/partnered-output-coils-free-energy/msg436051/#msg436051 ).

I do not understand the measurement, there probably is a measuring error which I can not identify at the moment.

More tests are needed, please do not get excited. I am not an expert and the chance is very high that I made a stupid error.

Would be great if someone else (may be TinselKoala) could make a similar replication. I will switch to the audio amplifier to get a higher input, but it will take time, my free time is limited in the next week.

As I recall, EMJunkie was writing about very little current through the Primary if the secondary is in a bucking configuration. And my last measurements (checked and rechecked) show exactly that. The error is not in my numbers, it must be in the measurement set up.

Greetings, Conrad

Conrad,

For input power calculations, should not "Vr" actually be "Vh", and therefore closer to 7mw in?

PW

synchro1 · « **Reply #670 on:** February 01, 2015, 01:17:31 AM »

Quote from: MileHigh on February 01, 2015, 12:36:25 AM

The only reportable person will be you.

Go ahead and follow through with your threat and find out where you really stand in the pecking order.

TinselKoala · « **Reply #671 on:** February 01, 2015, 01:19:23 AM »

@Conrad: You don't specify that your output current and voltage numbers are RMS, but I hope that they are.

Are these RMS values taken from the scope's computation "numbers in boxes" or are you taking the peak voltage of the sine waveform as displayed on the trace and dividing it by square root of 2?

In any case could you please repeat the output measurement by reading current through a 1ohm or 0.1ohm Current Viewing Resistor in series with the load resistor, using two probes, one for voltage across the entire 101 (or 100.1) ohm load, and one just across the CVR itself for voltage drop=current.
I am always a bit suspicious of using a high-value CVR, and also of using the load itself as the "CVR" in power measurements.

There may be some information in this document that you would find helpful:
http://web.pdx.edu/~bseipel/Alternating%20Current.pdf

synchro1 · « **Reply #672 on:** February 01, 2015, 01:19:53 AM »

Quote from: TinselKoala on February 01, 2015, 12:41:47 AM

You are indeed an astounding hypocrite. Conrad is a "bootlicker" when his results don't please your preconceptions, and when they do, he's a candidate for "world records."

Please show how (4/π)2 relates to 2kHz in some "harmonic node" fashion.

4/π = 1.273239545...
1.273239545... x 2 = 2.546479089...
Or is the "2" supposed to be an exponent?
(1.273239545...)² = 1.621138939...

None of which come anywhere near 2000 Hzor anywhere near an integer divisor or multiple of it. So explain your use of "harmonic node" and how (4/π)2 corresponds to 2kHz in such a manner.

I changed my mind about Conrad! The harmonic has to start at the frequency of first wobbultion!

TinselKoala · « **Reply #673 on:** February 01, 2015, 01:43:10 AM »

Quote from: picowatt on February 01, 2015, 12:55:24 AM

Conrad,

For input power calculations, should not "Vr" actually be "Vh", and therefore closer to 7mw in?

PW

This is indeed confusing. The probes are connected so as to provide essentially a "differential" measurement of the voltage across R1. Why would this not be a valid current measurement?

Hmm.... at these frequencies with a nice sinusoidal waveform, an ordinary DMM connected inline will usually provide quite accurate measurements of average current, won't it?

TinselKoala · « **Reply #674 on:** February 01, 2015, 01:44:58 AM »

Quote from: synchro1 on February 01, 2015, 01:19:53 AM

I changed my mind about Conrad! The harmonic has to start at the frequency of first wobbultion!

And you'll change it back again before this is all over, I'll wager.

Now please address the actual challenge before you:

Quote from: TK

Please show how (4/π)2 relates to 2kHz in some "harmonic node" fashion.

4/π = 1.273239545...
1.273239545... x 2 = 2.546479089...
Or is the "2" supposed to be an exponent?
(1.273239545...)² = 1.621138939...

None of which come anywhere near 2000 Hz or anywhere near an integer divisor or multiple of it. So explain your use of "harmonic node" and how (4/π)2 corresponds to 2kHz in such a manner.

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Author Topic: Partnered Output Coils - Free Energy (Read 3543788 times)

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