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Author Topic: Partnered Output Coils - Free Energy  (Read 3530573 times)

Farmhand

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Re: Partnered Output Coils - Free Energy
« Reply #690 on: February 01, 2015, 06:58:50 AM »
Regardless of the result, it is still a result, good work Conrad for testing this stuff and providing an open source example of the measurements the pitfalls and so forth.

.....

To whoever wants to answer with a solid yes or no and why.

I have a question in the diagram below would it not be acceptable to ground the top of the secondary H2 to the function generator ground and make that end of H2 the neutral of the output then measure the secondary output that way ?
Basically flip his scope connections on the output . But use a thick short wire to make the connection. No good.

..


TinselKoala

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Re: Partnered Output Coils - Free Energy
« Reply #691 on: February 01, 2015, 07:53:13 AM »
TK,

Here are Conrad's Pin calculations:

Vt is the FG output.
Vh is the voltage at the top of the primary.
Vr is the voltage across the resistor (which is equal to Vt-Vh).

I (input current) is Vt divided by the 100R of the series CSR.

Phase angle not withstanding, Pin to the primary is simply Pin=(Vh*I).

Conrad used Vr instead of Vh.

However, that is (Vr*I), which is the power dissipated in the series resistor, not the primary.

So, if Pin=Vh*I*cos() =3.04*0.0024*cos(17) =6.98mw

PW

What I would like you to clarify is why the differential voltage across the 100R -- the voltage drop Vr --  does not give the current in the entire primary circuit.

John.K1

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Re: Partnered Output Coils - Free Energy
« Reply #692 on: February 01, 2015, 07:53:51 AM »
Tinsel- regarding to your scematic, I would recomend to use seriall capacitor to make it resonance motor,which suppose to be much efficient (some say even OU) and to use the feedback to comparator and increase signal by opamp to maintain the resonance?

Conrad: have you tried to run your scope from battery via inverter- proper isolation from main?

picowatt

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Re: Partnered Output Coils - Free Energy
« Reply #693 on: February 01, 2015, 08:01:13 AM »
What I would like you to clarify is why the differential voltage across the 100R -- the voltage drop Vr --  does not give the current in the entire primary circuit.

TK,

I don't understand this post.

The (differential voltage/100) does indeed give the current in the entire primary circuit.

The error was in also using that same differential voltage, Vr, as the voltage across the primary, which it is not.  The voltage across the primary is Vh.

PW

John.K1

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Re: Partnered Output Coils - Free Energy
« Reply #694 on: February 01, 2015, 08:01:51 AM »
Guys,am still playing with the kunel patent. How is it with the patenting process. Do they have to present functional model to get patent?
Any how, I made the shielding coil from Tesla's bifilar and it seems to be stronger electromagnet.  Now- just wondering how it would looks like to have bucket teslas bifillar coils ;)

conradelektro

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Re: Partnered Output Coils - Free Energy
« Reply #695 on: February 01, 2015, 08:48:26 AM »
TK,

Here are Conrad's Pin calculations:

Vt is the FG output.
Vh is the voltage at the top of the primary.
Vr is the voltage across the resistor (which is equal to Vt-Vh).

I (input current) is Vt divided by the 100R of the series CSR.

Phase angle not withstanding, Pin to the primary is simply Pin=(Vh*I).

Conrad used Vr instead of Vh.

However, that is (Vr*I), which is the power dissipated in the series resistor, not the primary.

So, if Pin=Vh*I*cos() =3.04*0.0024*cos(17) =6.98mw

PW

Picowatt is right, I made a stupid error and used the wrong Voltage for calculating power dissipation in the primary coil H1.

Here is the correct calculation:

Vh = 3.04 V
Vt = 3.28 V
Vr = Vt - Vh = 3.28 - 3.04 = 0.24 V
I = Vr / R1 = 0.24 / 100 = 0.0024
Ɵ = 17°

Watt through the primary H1 (input) = I * Vh * cos(Ɵ) = 0.0024 * 3.04 * cos(17°) = 6.9 mW  (which of course shows that there is no OU, because the output is 1.4 mW)

An other clarification: the Voltages Vh, Vr and Vo are indeed true RMS as calculated by my scope. (I did not do the calculation Vpp * 0.7)

Why did I connect the probes and the resistors R1 and R2 as depicted in the diagram?

Because that resolves the "GND connection" issue between function generator and scope! Remember that my function generator and my scope have a ground connection via the "mains GND" (220 V wall socket). Both scope probes and the output of the function generator have the same GND as indicated by the blue line in the drawing,
as shown here:

http://overunity.com/15395/partnered-output-coils-free-energy/msg436056/#msg436056 (which does not show OU, because I confused Vh wit Vr in the "power in" calculation, Vh and Vr are shown correctly in the drawing).

Thank you all for thinking about my measurement and my calculations. Together we can find the truth. Unfortunately I do not have much spare tim in the coming days, but I intend to do more tests.

My error shows again how important it is to make all measurements and calculations openly available. Only in this way a review by others possible. An error is quickly made when tired and after many measurements numbers are easily confused. And measurements are often much more involved than anticipated (e.g. the ground connection problem). In general, one can easily use a scope in the wrong way. The GND of a scope probe can not be put everywhere in a circuit, its placement has to be carefully chosen, and especially if two scope probes are used (their GND is the same).

Greetings, Conrad

TinselKoala

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Re: Partnered Output Coils - Free Energy
« Reply #696 on: February 01, 2015, 09:03:09 AM »
TK,

I don't understand this post.

The (differential voltage/100) does indeed give the current in the entire primary circuit.

The error was in also using that same differential voltage, Vr, as the voltage across the primary, which it is not.  The voltage across the primary is Vh.

PW

Ah, ok, I just had my eyeballs crossed, sorry. Somehow I thought he had used Vr/100 x Vh correctly but now I see the error, he used Vr/100 x Vr.  Thanks for catching that one.

Quote
Watt through the primary H1 (input) = 0.0024 (Vr/100)  * 0.24 (Vr)  * cos(17°) = 0.55 mW
Error!
Ok, it's time for Synchro to change his mind again!

 ;)

@Conrad: I got confused because you have the equation algebra correct... but I missed the fact that you had plugged in the wrong actual value into the algebra.
Keep up the good work, I've never changed _my_ mind about you!
 

TinselKoala

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Re: Partnered Output Coils - Free Energy
« Reply #697 on: February 01, 2015, 09:30:03 AM »
Tinsel- regarding to your scematic, I would recomend to use seriall capacitor to make it resonance motor,which suppose to be much efficient (some say even OU) and to use the feedback to comparator and increase signal by opamp to maintain the resonance?
Well, you do understand that the "M" in the schematic is now replaced by the primary coil, right? Adding a capacitor to make a resonant tank circuit did occur to me but that is different from the situation we are exploring, I think. Using a self-resonant Royer type oscillator with a capacitor chosen to produce the correct "magic" frequency with the coil's inductance is a possibility... once we have some idea what the "magic" frequency actually is. 
That being said, under certain conditions my circuit does oscillate spontaneously (and lights the output LED loads brightly) when the thing is turned on without sufficient Signal  Input to the op-amp Pin3 non-inverting input from the FG. But this is a flaw, not a feature, I think, and could probably be stopped with some tiny bypass caps sprinkled around the 741 in the usual places. But I don't think I'll do that because the self-oscillation is kind of interesting and now I know how to control it.
Quote

Conrad: have you tried to run your scope from battery via inverter- proper isolation from main?

It would probably be better to isolate the Function Generator rather than the scope.

conradelektro

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Re: Partnered Output Coils - Free Energy
« Reply #698 on: February 01, 2015, 09:43:26 AM »

I have a question in the diagram below would it not be acceptable to ground the top of the secondary H2 to the function generator ground and make that end of H2 the neutral of the output then measure the secondary output that way ?
Basically flip his scope connections on the output . But use a thick short wire to make the connection. No good.

..

Yes, one can do that and I flipped the scope connections on the secondary (when measuring the "normal transformer situation" with only H2 or H3 for out put and when measuring the "paired bucking situation" with H2 and H3 in series).

This flipping of the scope probe on the secondary showed me that I initially had the shunt R1 in the wrong place, see here
http://overunity.com/15395/partnered-output-coils-free-energy/msg436026/#msg436026

But still, there is an issue which I have not resolved:

The secondary in the "paired bucking situation" with H2 and H3 in series has a strange "potential". I have to do more tests and measurements to clarify that. At the moment I am just confused. One has to compare the "normal transformer situation" with the "paired bucking situation" in order to understand what is going on. And keep in mind, it was MileHigh who drew our attention to that approach.

Greetings, Conrad

conradelektro

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Re: Partnered Output Coils - Free Energy
« Reply #699 on: February 01, 2015, 09:50:48 AM »
Conrad: have you tried to run your scope from battery via inverter- proper isolation from main?

It would probably be better to isolate the Function Generator rather than the scope.

I am thinking about a cheap battery operated scope from China. They cost around 60.-- EUR. But they are very small and have tiny knobs and buttons. Good ones from Fluke cost a fortune (several thousand Euros).

I do not have an inverter. They have become quite reasonably priced lately.

Greetings, Conrad

TinselKoala

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Re: Partnered Output Coils - Free Energy
« Reply #700 on: February 01, 2015, 09:54:33 AM »
Don't I get any credit for the "Secret of DPDT" which allows changing from "bucking" to normal transformer "aiding" configuration with the flip of a switch?

Awww. I'm crushed.   :'(

And don't forget that reversing a probe connection will also flip the measured phase by 180 degrees...

TinselKoala

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Re: Partnered Output Coils - Free Energy
« Reply #701 on: February 01, 2015, 09:57:47 AM »
I am thinking about a cheap battery operated scope from China. They cost around 60.-- EUR. But they are very small and have tiny knobs and buttons. Good ones from Fluke cost a fortune (several thousand Euros).

I do not have an inverter. They have become quite reasonably priced lately.

Greetings, Conrad

Oh, please don't spend money on cheap tools! They are no bargain in the long run.

You could probably just "hack" your FG and bypass its AC supply and run it directly from some batteries. Do you have a schematic for the FG? What's its make and model number, let me see if I can find out any information.

Or simply use a "ground lift" adapter, which essentially just cuts off the Ground prong of the mains cord, eliminating the connection from chassis to the mains Ground, solving the groundloop issue. Don't use this all the time though, just for specific projects like this one.

conradelektro

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Re: Partnered Output Coils - Free Energy
« Reply #702 on: February 01, 2015, 10:14:19 AM »
Guys,am still playing with the kunel patent. How is it with the patenting process. Do they have to present functional model to get patent?

The patenting procedure (in all countries of the world) is a "written procedure", no physical models or parts can be submitted. And the patent offices (in all countries) never request any physical models or parts.

But the applicant can submit an expertise (from an accepted expert in the pertinent field of knowledge) to support his claims.

It will sound strange to most, but a patent does not prove that an "invention" really does what is claimed. The patent office does not test or examine the functionality of an invention per se.

What is examined?

- Whether the invention can be exploited commercially (is usually the case, unless it is prohibited by law)
- Whether the invention is new (nobody else has published a very similar thing)
- Whether the invention has a surprising technical effect (means, it is an invention and not something commonly known)
- Whether the invention contradicts commonly known laws of physics (perpetuum mobile is not accepted)

No proof of proper functioning is required.

If you file a "perpetuum mobile" and a patent is denied you could file an expertise about its functioning (e.g. from an accepted test laboratory), but you can not bring a model to the patent office. They do not want to do tests, the only want to push paper.

If you want a patent, best go to a patent attorney and he will file one for you. And yes, it costs a lot of money. A patent in your home country will cost you at least 3000.-- Euros and you will probably never need it. Patents are for enterprises who manufacture something and have means to sell it. Every now and then a lone inventor can make money with a patent, but it is very rare and usually the lone inventor already has ties to a commercial enterprise.

A patent is totally useless for an OU invention, it will not even be accepted by the patent office because it obviously contradicts commonly known physics. The US patent office was liberal in the past with strange patent claims, but that has changed. Usually the OU inventors do not claim any unknown effect in their patents, they just claim ordinary constructional details which nobody questions. But this is useless, the patent is not worth its paper. It is mostly done to attract investors (better said, to fool investors).

Greetings, Conrad

conradelektro

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Re: Partnered Output Coils - Free Energy
« Reply #703 on: February 01, 2015, 10:29:04 AM »
Don't I get any credit for the "Secret of DPDT" which allows changing from "bucking" to normal transformer "aiding" configuration with the flip of a switch?

Awww. I'm crushed.   :'(

And don't forget that reversing a probe connection will also flip the measured phase by 180 degrees...

Sorry I forgot your contribution. All good ideas have many fathers and if there are problems, nobody has wanted it.

Yes, the phase was flipped when I reversed the scope probe at the output (over R2).

My function generator is a Peak Tech 4060
http://www.peaktech.de/productdetail/kategorie/dds-multifunktionsgeneratoren/produkt/peaktech-4060.871.html

(I did not quickly find a manual in English, but it must be out there on the wild net.)

Disconnecting the mains GND is simple, but I am worried about charges building up in the instrument. Battery plus inverter sounds good. But I think if one knows about the "GND connection problem" one can work around it by carefully choosing the measuring set up (and a little mathematics, but with the right numbers plugged into the formulas).

Greetings, Conrad

MileHigh

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Re: Partnered Output Coils - Free Energy
« Reply #704 on: February 01, 2015, 11:22:20 AM »
Gentlemen,

Some good progress is being made and thank you Picowatt for catching the wrong voltage being used in the input power calculation.  For Conrad, you deserve all the credit for doing your test and faithfully reporting your results.  You made a "typo" more than a big error because all of your data was made available.

I think a very important thing is that Conrad did two tests and reported power input and power output measurements for both tests.  That is a "huge hurdle" that many experimenters never manage to cross.  You can't always get bogged down in discussions all the time, you have to actually replicate the actual circuit (not a funky variation on the circuit) and make the measurements and share your data.

I know that Conrad is busy, and will move on to new tests.  But one thing that is interesting is that for the normal setup you have 6 milliwatts in and 1.4 milliwatts out.  Anybody that is a real keener that wants to understand the secondary-level details should be trying to understand where all the "missing" power went.  I am pretty sure that earlier on Conrad reported his coil resistances.  So a keener could crunch the power dissipated in the coils, add the power in the 100-ohm in-line signal generator resistor, etc.  If you could account for say 90% of the input power that would be "satisfying."

The lesson in making a "regular transformer" test and a "bucking coils tranformer" test is now at least you have some kind of baseline and frame of reference.  The regular transformer outperforms the bucking transformer, surprise surprise - on the same hardware platoform.  I am the type that can dream up an endless series of experiments if I want to.  In terms of where my curiosity would lead me is the following:  Put a very high value of load resistor on the regular transformer so that the output power is about the same as when the bucking power transformer is driving a 100-ohm load and then poke around and compare.  Just out of curiosity.

The elephant in the room that Chris is avoiding and everyone on OUR is avoiding is that a perfectly symmetrical bucking coils transformer has a zero output.  I think Chris even talks about making the transformer as perfectly matched on the bucking side as possible as if that is a good thing.  This is just a hard fact of life and when Chris reads here I wonder what he says to himself.

MileHigh