Easy to confuse with scope stuff. Most folks do confuse current flow as voltage. Unless you use a current probe, it is the conversion of current to voltage you see on the scope.

Part of the problem with this item.

 The scope shot in question is invalad any way.

 The question in this sytem is how he charges the cap so fast.

 The law does come into play during the gen cycle. No way around it even with centrifical force.

 The only place the cap can be charged that fast is on the flyback cycle. Even worse to do so it must go with the ringing that can be made to happen by the switching curcit going on more than the extra time.

 Problem is it can not be powered by the main capacitor, so how did Mike do such.

 Well after looking over diferent curcits for them solid state relays, there is anoughter capacitor that can be used.

 Sollid state relay was placed between positive and collecter of PNP. This is a normal closed switch, meaning it will open (turn off) with the hall IC. Has that other thing going for it there of reducing the loss over the PNP.

 The rectifyer was only conected to the third (generator) coil.

 The extra diode goes across the Main capacitor of corse so it will not short it. It also alowed the capacitor in the switch to feed current in the proper direction during the motor curcit turn on that will use that capacitor charge instead of the main one.
 It is still a ballance I am working on. But it does give the main an extra boost, instead of loss that will be used to drive the motor.


 The problem mike has is that when he got his new switch ;the curcitry was changed in them: It most likly will not do what Mikes original switch did. What was in the original is simply a capacitor and resistor posibly a diode ( some split the ac input) so that the switch in off position is an open.

 The new one uses two capacitors and a transient surge protecter. Whole diferent game.  With out putting a capacitor resistor in the curcit his motor never ran itself again.

 If it was not for these fact I would easly say it was faked. 

 The hall or switch will not even kick in untill about 4.5 volts. The switch would have to be in the open position until voltage is reached or the cap would never charge enough to run the thing.

 That this thing will run itself  is even still in question; if the ballance can be achived . From Mikes vidio it should.

 Folks have to remeber that those solid state relays are not a switch. in the normal terms. In this case it is an unknown box of electronic parts.

 


 

http://home.valornet.com/hotspringstradingie/cmkie.jpg

 if you folks are using the replacment ssr it will not work due to the snuber curcit has been changed. This can be replicated.  The diode is for feedback to cause the triger coil to turn on the curcit.

 Mike just left out the positive conecton to were the diode is.

Added "he did in fact get the motor working again with the new Crouzet relay!'

Nope: Mike never said self runing did he?

LOL
 Now we get to the strange stuff. Leave out the diode in the posting. Look at were I put the cap.

 Flyback current will drain both sides of it to a positive state.

 Not excactly what I excpected and will have to give an electron vacume some time to sink in to see if it could be causing something in this curcit to aid capacitor charge.

 To make sure folks understand the electrons are pulled out of both sides of a  capacitor. Both plate will attract free electrons creating curent twords both plates.

 Z_P_E are you replicating or experminting with the curcit?  Yea I might confuse some folks. Reality is that whole vidio, Mikes scematic etc is confusing.  Know of any one that has got it to work yet?   The junction stuff on the fly back easly will confuse most folks.  The energy has to come from some were, and the charge rate shown in the vidio with out a battery is almost unbelivable. Something has to cause that.

 

Hi Darren
thats interesting, thats 14ma to charge the cap,so with my motor drawing about 20ma + supplying 14ma to charge the cap, thats 70% more energy than is being used by the motor, so once this excess energy charges the cap to 7 volts where does the excess go after that?
Or does it mean that his machine is OU only below and upto 7volts where it then neutralizes any excess energy, also does this mean it is more OU at 6 volts than at 7 volts.
Your charge graph from the film, appears to show the lower the voltage is steeper , so therefore i may be correct that it appears more OU at 4 volts than at 7.

Food for thought.
Peter

Your charge graph from the film, appears to show the lower the voltage is steeper , so therefore i may be correct that it appears more OU at 4 volts than at 7.

A capacitor charging to a particular voltage always forms a curve that looks like that.

It appears that the time constant of Mike's curve is right at 5 seconds, compared to 23.5 seconds for the 500 ohms, 47000 uf.

This means his circuit charges as though a voltage is applied through a resistance of about 100 ohms, or about 60ma charging current at the start of the charging.

c'mon guys let this treat not die.
   I'm shure a lot of people still testing this motor trying to make work even if it seems it was a fake but who cares anyways? what's important it is the union of all brains as a whole so lets keeep trying we can do it.