http://www.sccoia.org/articles/top-fuel-dragster-fast-facts/

"One Top Fuel dragster 500 cubic-inch Hemi engine makes more horsepower than the first 4 rows at the Daytona 500."


Bill

Yes, I meant 10,000.  Just about all of the top fuel dragster run engines based on the Chrysler 426 hemi engine design.  Some make a lot more HP than this.

"The calculated Power output of these engines is most likely somewhere between 8500 and 10,000 horsepower (approximately 6000-7500 kilowatts), which is about twice as powerful as the engines installed on modern Diesel locomotives, and approaches the power output of the largest aviation turboprop engines, with a torque output of approximately 6000 lbf·ft (8135 N·m) and a brake mean effective pressure of 80–100 bar (8.0-10 MPa"



Bill

Its odd to think about it, that say 5 or 6 electric space heaters could equal that sort of power.


"On the P85D, Tesla pretty much maintained the existing high-performance rear motor--at 350 kilowatts (470 horsepower)--and added an additional 165-kW (221-hp) motor up front."

http://www.greencarreports.com/news/1094911_tesla-model-s-dual-motor-is-quicker-has-higher-range-too-how-do-they-do-that


Hmm. I wonder how they come up with those numbers?

Mags

Its odd to think about it, that say 5 or 6 electric space heaters could equal that sort of power.

Perhaps you meant to say 5 or 6 thousand electric space heaters...

PW

1.21 gigawatts!

Just looking it over again, if we say 6 to 7.5MW, it sounds  pretty monstrous.

7500 heaters. For 3 seconds.

375 heaters for 60 seconds.

6.25 heaters for an hour

So the total amount of power, 7.5MW for 3 seconds, is enough to run 1 space heater for about 6 hours.  Hmm, kinda makes me think about inductive field collapse spikes.

lol, is that correct?  Ive been known to be wrong, today.

Mags

10 Hp
gotta Luv that

it does sound like a Hollywood sound effects machine ,just needs a couple Horn squeaks mixed in .

I wonder how efficient it was to run?

Grum would probably have a good idea

Loner wrote.

"
As to all the posts between your question and this reply, I think think the thread has been fully hijacked.  Interesting stuff I suppose.  I don't visit the forum enough to keep up, these days.

How a discussion of ideal Inductor and voltage came to this...  "

Dear Loner.

My apologies for the hijack. If my posts seem irrelevant, please advise, I can remove them far quicker than it took to post them.

Resonance and tuning both play a great part to the efficient running of an ICE both internally and externally.

Cheers Grum.

In an attempt to enlighten the non-believers (those having difficulty understanding currents through voltage sources), let's alter/simplify MH's question to the following:

- same ideal voltage source and ideal 5H inductor connected across each other.
- between t=0 and t=3, V=+4V
- between t=3 and t=6, V=-4V
- from t=6 to infinity, V=0V
(see scope shot)

We know from previous discussions that between t=0 and t=3, the circuit current will ramp up linearly to 2.39A. I think everyone agrees with this, even the non-believers. We can also calculate the power and conclude that the power delivered by the voltage source ramps up from 0W to 9.56W during the same period of time. But since we know that the current and voltage in a voltage source are 180º out of phase, the power will actually ramp down to -9.56W.

What happens between t=3 and t=6 when the voltage inverts from +4V to -4V? Well, the non-believers have stated the following:

Loner
I would not bother with this question based around a voltage source that dose not exist.
MH is also not able to understand that an ideal voltage cannot be placed across a conductor that has 0 ohms of resistance,and current flowing against that that the ideal voltage wants to create.This is like placing an ideal voltage across an ideal capacitor.
At T=3 seconds--kaboom--bye bye equipment and components.

But how can that be? Real world experiments certainly don't result in the catastrophic end of the earth, and a simulation debunks this notion as well. Well, the non-believers argue that the L/R ratio of 5000:1 is not close enough to ideal (5H/1m), yet I have shown via sim that a ratio of even 100:1 is close enough for a 5% error. That converts to a total series resistance of 50m Ohms.

The fact is, most high quality high power audio amplifiers have an output damping factor of about 400:1, which means the output resistance is on the order of 20m Ohms (based on 8 Ohm load). So a big audio power amp is a good ideal voltage source.

The other fact is that we can indeed short out an ideal inductor that has current flowing through it, by ideal wire or ideal voltage source. If in our example the inductor is shorted by an ideal wire right at t=3, what happens? does the inductor and the world blow up? I think we all agree that the current would remain at 2.39A. If the voltage source went to 0V rather than -4V at t=3, we know that it would act the very same way as the previous case of the ideal wire, and the current would remain at 2.39A and there would be no explosions.

But my example switches the voltage from +4V to -4V, right at the instant 2.39A is flowing in the coil and voltage source. What happens next is the opposite from the period between t=0 and t=3; the current ramps down from 2.39A to 0A, and the power instantly changes from -9.56W to +9.56W, and ramps back down to 0W. The energy stored in the inductor is returned to the voltage source. No energy was dissipated when the inductor was energized, and none is dissipated when it de-energizes.

Green=voltage Source
Red= Circuit Current
Purple= Voltage Source Power