Are you saying it's wrong MH--alone with all your insult.

Brad

Here you weasel.

If you cannot work out where the current flow continues from where the marked dot's are,then you clearly do not belong here.

Lol
MH

I bet you think im mad right now lol,but you couldnt be more wrong .
I just fried ya ass once again,and once again showed everyone here your true nature lol


!BIG! epic fail that time MH--BIG

Lol--this is a hoot

Brad

Brad:

When  you act like you are acting, I think it could be an indication that you have some serious psychological problems.

MileHigh

The way you act MH,is a clear sign of being both delusional and sarcastic.

The diagram you posted is from me-post 1219.
Here is the description of that diagram.
Quote: If we look at the schematic below,i have drawn in two options for L2s current path.
The red dots show the current flowing back into the battery.
The blue dot's show the current from L2 flowing into L1.
It is my belief that the later is correct,and that the current flowing through L2 flows into,and is additive to the current flowing through L1,and the LED.

Your post to Chet
Post 1275 Quote: Here, go ahead and please complete the current loop from Brad's diagram for the red dots for after the transistor has switched OFF.  The current starts in the right L1 coil moving from top to bottom.  Please mark up the diagram showing the full current loop and settle it once and for all.  Fulfill your destiny as a mother hen.

Here we can clearly see that you are trying to Catch Chet out,so as you can claim some sort distorted victory.
I clearly stated that the diagram shows two possible current paths for L2,and state clearly that i believe that the path marked with blue dot's is correct for L2's current flow path during the transistor off period.
You then ask Chet to complete the RED dot current path,and to further throw in some sort of delusional effort to catch Chet out,you state that the current flow path starts at the top of L1--yes L1,and then proceed to say-->The current starts in the right L1 coil moving from top to bottom.
A clear indication that you want Chet to mark out the current flowing through L1.

You are a sleazy delusional twat MH-->but we have all woken up to your antic's,and now know that you are nothing more than a man who's aim in life is to cause trouble,and misguide those here on this forum.

You never dare answer any of your own question's,as you have no answers--you do not know the answer's. But ,instead ,you spend your time trying to belittle others in an attempt to turn the spot light of incompetence away from your self.

I just caught you out red handed trying to trap Chet into answering another loaded question from you.

How about you complete the current path of the red dot's,that start at the top right of L1,and move from top to bottom.

Go ahead child--complete the path--answer your own question,and then once again,i will come back and correct yet another of your mistake's.

You need to go back to your doctor,and get a refill for your presciption drug's,as the delusions are increasing within you every day MH.

Brad.

P.S
Just so as you dont try and distort thing's again,i have added your original schematic--just incase you try and say--er i dont know which one is L1 and L2.
And do not try and distort the fact that this diagram and related current flow paths was in regards to MY JT that had your !!!death spike!!--no more distorting of facts MH to try and save your ass.

Brad:

If we look at the schematic below,i have drawn in two options for L2s current path.
The red dots show the current flowing back into the battery.
The blue dot's show the current from L2 flowing into L1.
It is my belief that the later is correct,and that the current flowing through L2 flows into,and is additive to the current flowing through L1,and the LED.

We are talking about the event of the transistor collector-base junction breaking down and current being observed flowing in the reverse direction through the base.  The source of the current flow causing the breakdown of the junction is L1.  So when you talk about the "two options for L2s current path" anybody that has a Brad Secret Decoder Ring knows that what you are really saying is the "two options for L2s current path after that current is supplied from the discharge from L1."   It's just the usual scrambled brains in action.

You have avoided responding to this issue because Dr. Brainfry is supposedly infallible.  Push has come to shove and instead of acknowledging that you failed to think through your statements before you posted them and admit that you were in fact wrong, now you are instead having a good freak out and going nuts in an attempt to still not admit that you are dead wrong.  Dr. Brainfry is having a brain seizure.

MileHigh

Brad:

We are talking about the event of the transistor collector-base junction breaking down and current being observed flowing in the reverse direction through the base.

  Dr. Brainfry is having a brain seizure.

MileHigh

Wrong

Try again.
Lets see who has the brain seizure.
The first scope shot is of your death spike.
The second scope shot is showing the trace over a 1 ohm CVR at the collector.
I have placed the ch2 probe at the base,so as you can see where the timing of the !!death spike!! is
Where is this current flowing through the collector,that flows into the base via this junction breakdown of your's?.

Brad

 author=MileHigh link=topic=8341.msg478758#msg478758 date=1459169878]
         

 

The cycle time is 75 microseconds for one trace (spike) and 60 microseconds for the second trace (collector).

What planet are you on MH?.
The first scope shot was across the 1k ohm resistor--to show you that the death spike is still there--read bloody post.
The spike trace--blue base trace is shorter than than the collector current trace-the yellow trace.
Can you not follow a very simple schematic and scope placements?--do you not know that voltage leads current in an inductor,and thus the reason for the blue trace(base trace) being slightly shorter than the yellow trace-collector current trace in time period-->voltage leads current MH-you doofus.



 

Was the CVR for the collector trace in the same place when you captured the spike trace?

All was taken on the same circuit--nothing changed.

Or did you have two different circuits for each test and that's why the cycle time is different between the two?Oops you don't say anything about that and even the best Brad secret decoder ring can't help in this situation.

No-as stated above-->same circuit.
It is not my fault you do not understand the fact that voltage lead's current with inductors,and not my fault you cant work out the time difference between voltage and current rise.
The transistor switches off(blue trace) at the very same time the CVR on the colletor shows 0 volts across it. Then the voltage from the battery show across L1 and L2 before(BEFORE MH) current starts to flow,and you get a voltage drop across the collector CVR.

Why didn't you put the CVR for the collector trace on top of L1

For the very simple reason that we are looking for your current flow through the collector junction,into the base junction,due to junction breakdown.
You ask the dumbest of questions some time's.

You are second-guessing our mutual original conclusion (yourself, myself, Picowatt) about the death spike and now you are questioning me about your own second guessing?

No-i said the current flow through the base in the opposite direction,was due to junction capacitance-->and PW said that is quit possible. So dont go bullshitting again,as your about to learn something--guru.

Remember in your ever present quest to insist that you are never wrong that you were insisting that the reverse current spike was normal?

It is normal when you wind a JT toroid so as it will operate at a lower voltage--there is no set MH winding parameters for the JT.

Did you even try to reduce the number of turns in L2 to see if the reverse current spike would go away in the original setup?  Brain fry indeed.

Many time's. But why would i wind a JT to stop functioning at 320mV,when i can wind one that keeps running right down to 180mV?

Not surprisingly and as expected Brad, what you have shown is incomplete and it is a complete shambles.

Whats not suprising, is that you dont know that voltage appears across an inductor,before current flows through it. If you did,you wouldnt be asking as to why the two time basses are different.
Biiiggg blunder there MH--again.

The battery was run down to 500 odd mV in the last scope shot's,so here are the new ones with a fresh battery--1.6 volts.
The first scope shot is with the probe ground on one side of the 1k base resistor,and the probe tip on the other side of the 1k base resistor--is that clear enough MH?
The second scope shot is as the circuit depic's-->the circuit is not changed at all during the tests--is that clear MH?

Minimum voltage across 1 ohm CVR at the collector is 0mV-->no reverse current is flowing from the collector ,through the collector/base junction,and out through the base-->none.

Wrong my ass.

Yes-wrong your ass
Please try again MH.

Brad

MH

I have decreased the VPD on CH1,and inverted it.
I have also moved it across,so as it lines up with the current triggered death spike shot.

Dose this make it any clearer as to what is happening ?

Brad

Exceeding the base-emitter reverse breakdown voltage of Q1 does not turn on the collector-emitter junction. 

The spike seen in the recent "death spike" capture looks more like a Miller current spike than as being due to Vbe breakdown current.

In these recent captures, there is no evidence that the base voltage is exceeding the Vbe breakdown voltage (I believe Tinman measured his 2N3055's as breaking down around 20 volts)

PW