Hi folks

I am new at this forum. I have read all this thread and I am really curious if Ali's device is truly overunity or no. Sorry if my english is no perfect, I am from Slovakia.

I have some idea what this mysterious siphon effect could be. Imagine two capacitors with the same capacity C. Let both plates of both capacitors to be electrically neutral (i.e. number of positive and negative charges is the same). First capacitor is charged by moving some number of electrons from one plate to another. After that first plate has charge +Q and second plate has charge -Q. So the charge difference is 2Q. Voltage between plates then will be:
U1 = 2Q/C

Second capacitor will be initially charged by moving double amount of charges. So amount of charges at both plates will be -2Q and +2Q. Voltage between plates will be:
U2 = 4Q/C
Now comes important step. Imagine, that from some source we move charge -2Q to second plate. After this plate becomes electrically neutral. But first plate still contains charge -2Q, which creates potential difference:
U2' = 2Q/C (in absolute terms)

So if we use conventional voltmeter, these two capacitors will be indistinguishable. But if we connect positive pole of first capacitor with positive pole of second capacitor and negative pole of first capacitor with negative pole of second capacitor, there will be current flowing because of charge imbalances. So maybe not only voltage is important, but also potential! Remember, that Ali said, that his circuit must be powered with AC source with both polarities against neutral wire.

Here is a better resolution diagram from Dr. Jeong, that he emailed me.
Enjoy !
Regards, Stefan.

OK, a nice puzzle for you:

1) charge C1 to +12V, C2 to +24V with common ground. C1 has equal capacity as C2.
2) disconnect C1 and C2 from each other and from ground
3) connect C1+ with C2- , resulting in 36V overall voltage
4) disconnect C1 and C2, what is the voltage across each C?
5) connect C- of either C to ground, whats the new voltage over C?

LERN /Cold Fusion