In the video, when you connected the amp. meter.
When you set the scale on 0.5 A you were getting 150 mA not 15mA.
So your input power was 34 Watts not 3.4 Watts.
15ma stands for power consumption at listed below condition Sir.
The power supply is bipolar power supply that gives 5 v only out when is not under load .
At the output board ( printed board) you see very small green transformer on that printed board
This is output transformer.
When under load than this power supply= 16.8khz generator adjust voltage by itself.
Please note that two fan (ventilator) are rated 12V 1.1A = 13.2W and because we have 2 of them that is 26.4W.
Now how much difference do you have? based on your calculation
AbbaRue
?
34 Watts - 26.4W. = 7.6W
This is your mathematics Sir.
and in the effect we have 100W light bulb under load Take out from 7.6W rest of electronics usage inside power supply and you come to less than 3W
Or you do calculation my way:
(The problem with data is that was not displayed in the easy to understand format.)
We found that fan are not required at all.
I have device in my lab.
I need to find the time and deliver you video that will stay about power consumption under load.
In my video
you see spark shorting input with no load representing caduceus present.
So please try to short your power supply by sparking on it
HOW MUCH TIME IT WILL SURVIVE?but surprisingly our power supply with that small transformer did not get affected by that.Very important is to notice!!!!!!All of the comments of mine are related to my video.
videos of Arunas show more but you can
clearly see energy consumption under real load as well.compare power consumption with spark and with no spark.
I did my job now you do yours.
That what counts SIR AbbaRue
Another words it is not important how much money you have initially but how much money you have spend for operation.
We have showed you max the worse scenario of shorting power supply using HV flyback and how much the difference would be.
PLEASE do not confuse that we are dealing with two devices one is operated from two small generators ( deflection yoke) Please forget about it for the moment.
We are talking about the one that uses caduceus coil.
For these who still have problem with it I'm going to use example:
15 years old skinny girl wants to run 1 mile so she is using x amount of energy from initially available energy of the body. Her energy consumption is 3% of energy of her body.
or
You have 200 liters of water but you need to use only 3% of that water...
or another example..
You use X amount of energy to carry on 15 years old girl. Than in addition to that she decided to take with her 1 book of encyclopedia Britannica 7kg.
How much energy was used to carry on that book?
O boy... That book is consumption of our device.... that is all Forget how much energy is used by carrier( he could always be replaced by small boy 10 years old, who can carry on 7 kg book only using the same amount of Jules as the big one.)
We can always drop the girl she is not needed and not important at all.
So why you count initial energy consumption and you do not count:
energy difference between initial energy consumption and energy consumption under load of spark?
Do your math and tell me what is the difference.
THAT WOULD BE YOUR ENERGY CONSUMPTION understand?yes?no?maybe?
you do not know?When on my video we show current without the spark and current with the sparkTHE CURRENT INDICATOR ALMOST DID NOT MOVE I
ASSUME WE HAVE BEN DEALING WITHLESS THAN 3 W IN REAL MEASUREMENT WHERE IMPEDANCE OF CADUCEUS WAS PRESENT that would decrease current even more... SHORTING SPARK..was the most we could draw from power supply.SO PLEASE CHECK IT OUT. Wesleyand what will be damaging current?
