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Author Topic: how do i convert a motor (step one two three)  (Read 5547 times)

Charlieb000

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how do i convert a motor (step one two three)
« on: November 19, 2008, 08:33:21 AM »
hi,
i prefer to study up first before buying anything.
what do i expect to see when i open one up and what do i do?

if i get permission from my father, i could get a large motor (a pump) for adjustment. i think the monitoring devices needed are already there, (amp meter, pressure) so if this rotoverter is any good we will be able to tell you if it performs better or less better than the original.

there is going to be some difficulties:
it is 400/440 Volt (69-65 A)
50Hp, 37Kw
over 200KG, im2001 (if that helps)
oh yes can we keep it at 3Ph please or is two wire the only choice?

but first what will i see and what do i do, layman's please!
Charlie.

Charlieb000

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Re: how do i convert a motor (step one two three)
« Reply #1 on: November 19, 2008, 11:11:53 AM »
continuing on from the last,
i saw video:
http://www.youtube.com/watch?v=RzO_lzgfoKM
which did go through the step by step of this.

it does appear that it will have to be on the two wire setup.
the label only indicates the singular voltage (400's) - a series mod for the coils may not be possible (unless there are things that can be done in the case). i do prefer to connect to the 440v (not 240v) as the amp guage is on that (and all the safety over-pressure stuff too)

lol - i hope that the relubrication, fan removal and coil disconnection is not your only way to make it save power (as i cant do the coil-series thing).... but i guess i will have to see the output first before making any final judgements

cb.

Charlieb000

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Re: how do i convert a motor (step one two three)
« Reply #2 on: November 20, 2008, 08:57:54 PM »
i didnt get permission so i might find a 3PH air-con... when i find out how to delete this topic, i will

Charlieb000

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WASTE OF TIME >:(
« Reply #3 on: December 03, 2008, 12:00:21 PM »


i thought that the current induced into the rotor came out of the coil that was connected to the cap, the cap delayed it and the power would return into the mains at the right time.
however,
i am not so persuaded anymore, i think now that the cap'd coil is acting as a generator coil and consuming the power fed into the motor to make it turn, the cap delays it and it would make the motor consume less, ok for idling, not ok for OU.


Charlie.
a syncronous induction motor might be a bit more OU, as the rotor coil has to be shorted for it to turn, and it may act as a diff when it gets under load, and the power would be diverted through the rotor brushes.

Charlieb000

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konehead's quick explanation
« Reply #4 on: December 06, 2008, 01:28:41 AM »
This is important for you to know:
The AC  SINEWAVE FEEDING THE AC ROTOVERTOR'ED MOTOR  (regular sinewave) Has PEAKS- the is a neg peak and a pos peak if looking with scope (you know the shape of it I am sure)
And if you have a generator or alternator of some kind on the shaft of the motor, you want those sinewave peaks of the AC sinewave feeding the motor to be exaclty WHEN the caps the genrator or alternator fills to hit the LOAD (the resistance or batery or light or wahtever is the load to the geneartor)
Now your AC motor will NOT go up in draw under generator load (!!!!!!!!!!!)
DO NOT load that generator throughout the sinewave peaks! This WILL lug the motor up indraw horrible.
Think of that run cap phase in the rotovertor system also as an "inboard" generator/alternator!!!
Do same thing explaeind to generatoir/alternator on shaft to run cap phase (output only at sinewave peaks of the AC sinewve feeding AC motor)
 
Another thing to do. is simply turn off completely the motor whenever you output to load from generatoir but sinewave peaks is the way you want to do it.

Charlieb000

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Re: WASTE OF TIME >:(
« Reply #5 on: January 04, 2009, 12:13:54 AM »


a syncronous induction motor might be a bit more OU, as the rotor coil has to be shorted for it to turn, and it may act as a diff when it gets under load, and the power would be diverted through the rotor brushes.


no that wont work as the power going in creates the magnetic field for the stator to push on.