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Author Topic: Chas Campbell free power motor  (Read 725920 times)

hansvonlieven

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Re: Chas Campbell free power motor
« Reply #435 on: September 08, 2007, 02:15:24 AM »
G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

zero

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Re: Chas Campbell free power motor
« Reply #436 on: September 08, 2007, 02:23:09 AM »
Hans, if you say that there is no more potential in such a manor, then
either you are a LIAR, or you have not looked at the device in motion and
do not understand what I am talking about.

 As I said before..

 If I put a basket on your back..  and gently set a 100lb ball into it...

 OR

 I roll a 100lb ball on a 3ft rail at a 30 degree slope downwards,
 which then slams into your basket at speed...


 Is there no energy difference?!   If you say there isnt,  then You are Not
a physicist.


hartiberlin

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Re: Chas Campbell free power motor
« Reply #437 on: September 08, 2007, 02:24:27 AM »
From the starting position cambell_harti5.gif ,
when the 2 red balls have gone down to the lower rolling track,
the wheel has  lifted the next yellow ball at 11 o?clock to the
12 o?clock top position, so this ball rolls out ,
so that it becomes the
cambell_harti4.gif  position, where only 1 red ball is at the
left about 4x distance of the axis, but this
still is enough to lift the next yellow ball from the 11 o?clock to the
12 o?clock top position, so this ball rolls out again to the right.

Humbugger

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Re: Chas Campbell free power motor
« Reply #438 on: September 08, 2007, 02:27:38 AM »
Hans, if you say that there is no more potential in such a manor, then
either you are a LIAR, or you have not looked at the device in motion and
do not understand what I am talking about.

 As I said before..

 If I put a basket on your back..  and gently set a 100lb ball into it...

 OR

 I roll a 100lb ball on a 3ft rail at a 30 degree slope downwards,
 which then slams into your basket at speed...


 Is there no energy difference?!   If you say there isnt,  then You are Not
a physicist.



This is deteriorating into silly name calling now.  Yes there is an energy difference.  It is identical to the extra energy it takes you to lift the ball that extra distance up to the top of your inclined ramp.  Not a drop more!

Humbugger
« Last Edit: September 08, 2007, 07:38:35 AM by Humbugger »

hartiberlin

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Re: Chas Campbell free power motor
« Reply #439 on: September 08, 2007, 02:28:05 AM »
G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

Then why don?t you calculate  the torque arms ?
Where is my error in my calculation ?

Here it is once again:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units

Divided by 2 cause only for 30 instead of 60 degres rotation
we still have a 3.9 versus 3.6 advantage.


rMuD

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Re: Chas Campbell free power motor
« Reply #440 on: September 08, 2007, 02:30:02 AM »
Okay,
here we go,
now with 8 balls.

Let us keep all calculating it with 8 balls,
cause this is the starting position,
where you have the 2.16 to 1 torque start configuration
as I calculated earlier.



ok 8 balls.. so were back to the 2x model? 

the 4x model has  6 balls 10% of the time and 7 balls 90% of the time,
the 3x model only has 8 balls 23% of the time and 7 the other 27%,
the 2x model has 8 balls 97% of the time  (with a 3 degree slope combined with the ramps)

how are you compensating for the -3.6 force on the right side for 10% of the time at 4x the distance?

zero

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Re: Chas Campbell free power motor
« Reply #441 on: September 08, 2007, 02:30:51 AM »
A) I said "Either"   and also, I didnt call him a name.  I simply stated he was lieing
if he was saying there was no additional energy.

 Dont twist my words.

 And

B)  You dont know what the additional forces would equal out to be,
so dont be so confident.

hartiberlin

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Re: Chas Campbell free power motor
« Reply #442 on: September 08, 2007, 02:31:22 AM »
Okay,
here we go,
now with 8 balls.

Let us keep all calculating it with 8 balls,
cause this is the starting position,
where you have the 2.16 to 1 torque start configuration
as I calculated earlier.



ok 8 balls.. so were back to the 2x model? 

the 4x model has  6 balls 10% of the time and 7 balls 90% of the time,
the 3x model only has 8 balls 23% of the time and 7 the other 27%,
the 2x model has 8 balls 97% of the time  (with a 3 degree slope combined with the ramps)

how are you compensating for the -3.6 force on the right side for 10% of the time at 4x the distance?

I don?t understand your calculation, please show me the error in my
calculation above.
Thanks.

rMuD

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Re: Chas Campbell free power motor
« Reply #443 on: September 08, 2007, 02:32:43 AM »
G'day Stefan,

You are still stuck with the basic problem and that is how to rotate the entire assembly 30 degrees to bring the next ball into play when you only have 27 degrees or less to play with and only one ball to do it with. The potential energy in the system does not change with a 3 dimensional arrangement or any other arrangement.

Incidentally zero, I am a qualified engineer, physics major at that :-)

Hans von Lieven

Then why don?t you calculate  the torque arms ?
Where is my error in my calculation ?

Here it is once again:

2 balls 0.5 distance from axis x 1 Kg = 1.0 units
2 balls 0.8 distance from axis x 1 Kg = 1.6 units
1 ball   1.0 distance from axis x 1 Kg = 1.0 units
====================================
sum= 3.6 units

On the right side we have then only for 2 x 15 degrees:

1 ball 3.8 distance from axis x 1 Kg = 3.8 units
1 ball 4.0 distance from axis x 1 Kg = 4.0 units
===================================
sum= 7.8 units
Devided by 2 cause only for 30 instead of 60 degres
we still have 3.9 versus 3.6.



you error in the calculation is that at 15 degrees on the right side, and 30 degress on the left side

you need 10 balls on the left to have 2 balls on the right to make a closed system

hartiberlin

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Re: Chas Campbell free power motor
« Reply #444 on: September 08, 2007, 02:37:46 AM »


you error in the calculation is that at 15 degrees on the right side, and 30 degress on the left side

you need 10 balls on the left to have 2 balls on the right to make a closed system


????

I just stated, I want to run the system with just 8 balls,
which is clearly enough.
Just calculate it all please based on just 8 balls
inside the whole system inclusive on the ramps,
no more balls in the whole system.

Humbugger

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Re: Chas Campbell free power motor
« Reply #445 on: September 08, 2007, 02:38:05 AM »
I am realizing how poor a web forum like this really is for discussing these kinds of things when the pace gets rolling like this.  Every verbal description that refers to a picture needs to have the picture right there with it or the scrolling gets totally out of hand.  Then people start jumping in and calling names and demanding that their view be agreed upon before anything proceeds.  Posts are entirely missed and left pages behind without ever being understood.  The discussion opens to half a dozen distracting competing tangential viewpoints.  Nine different guys decide their particular aspect is the only thing that totally explains everything.

I can see how the "fuck it, just buid it and see" attitude would develop rapidly!   ;D

Humbugger

Suggesdtion...if we really want to nail anything down, let's let Stephan moderate.  Stephan, please have your diagram of reference in each post so we can stay on one page.  Pose4 a qestion...ask for various answers.  Then move on.

Probably much easier said than done...

hansvonlieven

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Re: Chas Campbell free power motor
« Reply #446 on: September 08, 2007, 02:42:16 AM »
G'day Stefan,

The error in your calculation is that you are only looking at one moment in time. This is a kinetic system, not a static one and the ratios shift as the wheel turns. sometimes they are in your favour but more often they are to your detriment.

Incidentally hum and zero, don't take it too seriously, after all we are supposed to have a bit of fun while we air our particular views.

Hans von Lieven

hartiberlin

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Re: Chas Campbell free power motor
« Reply #447 on: September 08, 2007, 02:43:18 AM »
Edit now it shows right...

Okay, Hum,
here again with the 2 pics over each other:

Starting point:

(http://www.overunity.com/index.php?action=dlattach;topic=2487.0;attach=12541)
From the starting position
when the 2 red balls have gone down to the lower rolling track,
the wheel has  lifted the next yellow ball at 11 o?clock to the
12 o?clock top position, so this ball rolls out ,
so that it becomes the
cambell_harti4.gif  position, where only 1 red ball is at the
left about 4x distance of the axis, but this
still is enough to lift the next yellow ball from the 11 o?clock to the
12 o?clock top position, so this ball rolls out again to the right.

(http://www.overunity.com/index.php?action=dlattach;topic=2487.0;attach=12539)

zero

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Re: Chas Campbell free power motor
« Reply #448 on: September 08, 2007, 02:44:13 AM »
Humbugger, I never swore at anyone.  But to deny a fact is just that.  A denial
of the true potential.
---

 Also, curious if we remove some ball load chambers what will happen:




rMuD

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Re: Chas Campbell free power motor
« Reply #449 on: September 08, 2007, 02:47:01 AM »
pass me the specs.. I'll draw it.. well I will if you want me too.. 

assumption is now 4x sized wheel with 15 degrees between ball holders?

if that's the case, I'll draw it..

stephan you can msn me, or icq, or aim, or skype.. just pm me