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Author Topic: MH's ideal coil and voltage question  (Read 487977 times)

poynt99

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Re: MH's ideal coil and voltage question
« Reply #1395 on: June 29, 2016, 03:06:07 PM »
With a non ideal coil,i have no problem with the current rising,as the CEMF value cannot be, and is not the same as that of the applied EMF,as we have a current rise that has an exponential curve,and this curve starts at T=0. And this is why i said that the resistance of the coils windings are the reason that the CEMF is a slightly lower value than the applied EMF. Even that !minute !amount will start a chain reaction when winding resistance is involved,and so the current can flow,due to the coils ability to dissipate energy. But that just is not the case when talking ideals--that is why they are ideal.
I've already stated this and I know it did not register, so here it is again:

With a non-ideal inductor, the instant Vin is applied, all the voltage appears across the inductance, and nothing across the resistance (assuming a lumped inductance and resistance model), therefore Vin=cemf, and lo and behold, current still begins to flow. In fact this is the moment the A/s is the highest rate!

Now, what happens if we were able to make R smaller and smaller?

picowatt

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Re: MH's ideal coil and voltage question
« Reply #1396 on: June 29, 2016, 03:21:13 PM »
;) :)

Makes perfect sense.

I do not know if Tinman is actually unable to grasp the concept of a negative feedback mechanism or if he is just being contrary to adhere to his belief that an inductor with zero resistance cannot function as an inductor (in spite of the large number of zero resistance inductors in use daily throughout the world).

PW

minnie

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Re: MH's ideal coil and voltage question
« Reply #1397 on: June 29, 2016, 03:44:56 PM »



    Time to sharpen up your measurement skills tinman!
     If photons can go say 30,000,000,000. centimetres
     in a second it's going to take some doing.
              J.

tinman

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Re: MH's ideal coil and voltage question
« Reply #1398 on: June 29, 2016, 04:00:47 PM »
I do not know if Tinman is actually unable to grasp the concept of a negative feedback mechanism or if he is just being contrary to adhere to his belief that an inductor with zero resistance cannot function as an inductor (in spite of the large number of zero resistance inductors in use daily throughout the world).

PW

Why do you wish to single me out PW,when there are more that believe what i believe,than there is those who believe what you believe on this thread.

It would seem that yourself,Poynt,and MH are the three that stand alone on this belief that current can flow when the EMF and CEMF are of the same value--the rest of us seem to be of the opinion that when the EMF and CEMF are of the same value,that no current will flow.

You also forget the fact that these !0! resistance inductors have stored energy applied to them in order to make them super conductors.
So no-we do not have !room! temperature super conductors,or ideal coils/inductors that do not dissipate energy--this is a fact,and for you to bring this into the discussion,only diverts traffic in the wrong direction.

The answer is always avoided by way of introducing real world configurations that dissipate power/energy--such as your feed back system.

A quote from my dad's book

Quote
Because no one has been able to discover fundamental realistic answers to explain phenomenal events like these, scientists have resorted to using strange speculative theories and extremely complicated mathematics in an attempt to perfect their otherwise imperfect scientific theoretical models.

And to quote Poynt

Quote
Even the official definitions don't make sense; "Increasing current in a coil of wire will generate a counter emf which opposes the current." How does an emf oppose a current?


It really comes down to this,the EE guys are always right,and need no such test to prove they are,and the rest of us are wrong--it's that simple.

I thank you for your time PW--and all,but my journey to find those who can see past the known is complete.



Brad

picowatt

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Re: MH's ideal coil and voltage question
« Reply #1399 on: June 29, 2016, 04:38:02 PM »
Why do you wish to single me out PW,when there are more that believe what i believe,than there is those who believe what you believe on this thread.

It would seem that yourself,Poynt,and MH are the three that stand alone on this belief that current can flow when the EMF and CEMF are of the same value--the rest of us seem to be of the opinion that when the EMF and CEMF are of the same value,that no current will flow.

I have repeatedly stated that current will not flow if the EMF and CEMF are equal.  That is the basis for how an inductor limits the rate of change.  I truly wonder if I would have as much difficulty explaining any other negative feedback mechanism to you, or as I stated, if you are just being contrary for the sake of argument. 

Quote
You also forget the fact that these !0! resistance inductors have stored energy applied to them in order to make them super conductors.
So no-we do not have !room! temperature super conductors,or ideal coils/inductors that do not dissipate energy--this is a fact,and for you to bring this into the discussion,only diverts traffic in the wrong direction.

Zero resistance inductors are in use daily all over the world.  The fact that they must be cooled is not relevant to the discussion.  As energy is stored or retrieved using those zero resistance inductors, none of that energy is dissipated as heat.  It is the flow of heat towards the superconductor from the outside environment that must be dealt with.

Quote
       
The answer is always avoided by way of introducing real world configurations that dissipate power/energy--such as your feed back system.

A quote from my dad's book

And to quote Poynt
 

It really comes down to this,the EE guys are always right,and need no such test to prove they are,and the rest of us are wrong--it's that simple.

I thank you for your time PW--and all,but my journey to find those who can see past the known is complete.

Brad

So are you saying that you believe the "EE guys", as you put it, have not heavily investigated zero resistance inductors, that is, tested and proved, that as the resistance is removed from an inductor it behaves more and more like an ideal inductor?  The study of the properties of devices made from superconductors is a very large field of research.         

PW

minnie

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Re: MH's ideal coil and voltage question
« Reply #1400 on: June 29, 2016, 05:00:39 PM »



 The tinman doesn't seem to believe in theoretical guys.
  I watched this thing on YouTube.
  "Harold Black and the invention of the negative feedback amplifier"
  He had the idea,got it down on paper and his colleague built it.
  It's men like those who have given us all these marvellous
  communication devices.
        J.

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1401 on: June 29, 2016, 05:08:59 PM »
It really comes down to this,the EE guys are always right,and need no such test to prove they are,and the rest of us are wrong--it's that simple.

Brad

I asked you a couple of times to give a concrete example of where the CEMF must be less than the EMF for current to flow using a simple example with a coil and voltage source with actual numbers and you refused.  You can't actually put substance to your beliefs.

So, we often hear, "This is what I believe but I can't really explain it and I cannot give you a concrete example illustrating my theory with numbers."  And that is just plain bogus.  Here is a classic example, "Repeatedly shorting a coil gives extra energy."  The thread name is , "Shorting coil gives back more power."

With respect to the discussion, there is more than one way to skin a cat and so different ways of explaining the whole EMF/CEMF business have been explored.  Then there is the pure reality of doing tests on your bench.  And within that reality you must have the full conscious realization that within the real coil on your bench, there is actually an ideal coil, and that ideal coil is functioning exactly like the EE equations state it should function like.  Saying, "I only deal with real stuff on my bench" is almost a strange thing to say because the exponential response of the real coil comes directly from the ideal coil that is the basis for the real coil.

I suppose what I am really saying is that if you take the top five old wives' tales that you see on the forums and actually demand that people put substance to those tales and show that they are REAL, you end up coming up goose eggs.

And it's bizarre when you look at somebody on YouTube like TheOldScientist.  He uses all the cliches and the old wives' tales all the time in his presentations, but when it comes to the nitty-gritty, and you really look for substance in what he is saying and demonstrating, he comes up short.  And he has fantastic test equipment!  The other guy that comes to mind is that Quanta Magnetics guy, talk about empty calories.

And you fell into the trap (or the trance) yourself when it came to graphene supercapacitors.  In one of your clips you make this claim, something like your home-brew capacitor is 10,000 Farads - but you make no attempt to measure it.  Just like my "buddy" RMS.  All that you have to do is do a few test runs with a few different resistors to discharge your graphene capacitor and measure the time constant and then crunch the numbers to give you a capacitance value - and you don't.  I could smell that your claimed capacitance was grossly exaggerated.

MileHigh

partzman

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Re: MH's ideal coil and voltage question
« Reply #1402 on: June 29, 2016, 05:35:58 PM »

I asked you a couple of times to give a concrete example of where the CEMF must be less than the EMF for current to flow using a simple example with a coil and voltage source with actual numbers and you refused.  You can't actually put substance to your beliefs.

[snip]

MileHigh

Actually MH doesn't every scope shot of an inductor with a voltage applied across it's terminals generating a linear current rise give proof that Emf = L*dI/dt or rearranging di = Emf*dt/L? Where is the evidence of Cemf? So, anyone adhering to the notion that Emf = Cemf in a single inductor has the burden of proof IMO to show by experiment or math derivation that it exists.

By definition, Cemf is opposite to Emf.  The current increase in the above example is in phase with the applied Emf and follows Faraday's law without Lenz. How do we justify any amount of negative Cemf to be added to the Emf and still adhere to Faraday's law? I am willing to change my view if and when I see something convincing.

pm

Edit


Magluvin

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Re: MH's ideal coil and voltage question
« Reply #1403 on: June 29, 2016, 06:20:42 PM »
Been thinking a bit on the emf=cemf as in if there would be current flow of an ideal inductor when input is supplied.

One conclusion as to how cemf could be always less than emf is probably distance. Distance from one winding to all others. Some are adjacent and some a couple or several or more wire thicknesses away from each other. Emf through the inductors windings, as in each winding will create its own field, and those fields are weaker the further they are from their origin. Like if we apply current to a length of wire, the field around that wire is stronger close to the wire and weaker the further out from the wire we go. So if we placed another length of wire next to the wire to be powered up, the further that second wire is from the powered wire, the less effect the field will have on the second wire.  I can see that as an issue in thinking that current would not flow in ideal wires and inductors.

And even in a single wire, the fields of the moving electrons have distance from other moving electrons, and the field from one to another is weaker than closer to the point of origin.

Dont know if that sounds right for sure. Just came up with it this morning at work.

So with that, I can say that ideal wires and inductors can flow current most likely and I can agree that cemf is most likely always in some way less than the emf. 

Mags

tinman

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Re: MH's ideal coil and voltage question
« Reply #1404 on: June 29, 2016, 06:38:09 PM »

         

PW

Quote
I have repeatedly stated that current will not flow if the EMF and CEMF are equal.

And you have repeatedly stated that the EMF and CEMF are equal,but current will still flow.

Quote
or as I stated, if you are just being contrary for the sake of argument.

This is always how it is always seen--an EE says this is how it is,and anyone that disagrees with them,is the one who is doing the arguing. It could just as easy be seen to be the other way around.

 
Quote
That is the basis for how an inductor limits the rate of change.  I truly wonder if I would have as much difficulty explaining any other negative feedback mechanism to you,


If the negative feedback is slightly lower,then yes,i can see how that would work. But as we are dealing with an ideal coil,and none of that negative feedback energy is dissipated,then i see a balance--such as i have tried many times now to explain. The mere fact that current would continue to flow through this coil,if the coil was bridged,and became an ideal loop,shows that there is no losses in any way shape or form--not even to the magnetic field.
It also tells us that we would get back every bit of energy that went into that coil,when we open that loop,and collect the stored energy.

Quote
So are you saying that you believe the "EE guys", as you put it, have not heavily investigated zero resistance inductors, that is, tested and proved, that as the resistance is removed from an inductor it behaves more and more like an ideal inductor?  The study of the properties of devices made from superconductors is a very large field of research.


If you can point me in the direction of such tests,then i would be happy to read the results.

Below is a couple of diagrams.
Do we have diagram A showing the correct relationship of the CEMF to that of the EMF polarity,or diagram B showing the correct relationship between the CEMF and EMF polarities ?.


Brad

poynt99

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Re: MH's ideal coil and voltage question
« Reply #1405 on: June 29, 2016, 06:52:22 PM »
I've already stated this and I know it did not register, so here it is again:

With a non-ideal inductor, the instant Vin is applied, all the voltage appears across the inductance, and nothing across the resistance (assuming a lumped inductance and resistance model), therefore Vin=cemf, and lo and behold, current still begins to flow. In fact this is the moment the A/s is the highest rate!

Now, what happens if we were able to make R smaller and smaller?

The above is germane to the argument, yet no comments.

tinman

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Re: MH's ideal coil and voltage question
« Reply #1406 on: June 29, 2016, 07:00:12 PM »
 author=MileHigh link=topic=16589.msg487413#msg487413 date=1467212939]









Quote
I asked you a couple of times to give a concrete example of where the CEMF must be less than the EMF for current to flow using a simple example with a coil and voltage source with actual numbers and you refused.  You can't actually put substance to your beliefs.

Well Mr resonance,i have done this by way of showing that when the BackEMF in a DC PM motor equals the applied EMF,then no current flows,and no BackEMF voltage can be measured--the same applies for every other electronic component. Show me just one other component that will allow for current flow,when there is no potential difference across it's terminals.

Quote
So, we often hear, "This is what I believe but I can't really explain it and I cannot give you a concrete example illustrating my theory with numbers."  And that is just plain bogus.  Here is a classic example, "Repeatedly shorting a coil gives extra energy."  The thread name is , "Shorting coil gives back more power."

And you know this is bogus by experimentation MH?

Quote:Additional phenomenon has also been discovered in atomic physics and has created a lot of confusion and speculation about how the atom fundamentally works. An example of this atomic phenomenon is based on the fact that all atoms are considered to have orbiting electrons, which in theory should radiate electromagnetic energy as they orbit the positive nucleus. This theoretical loss of un-replenished radiated electromagnetic energy should result in the negative electron eventually spiralling inwards and collapsing into the positive nucleus. But in reality this loss of radiated energy is not observed as happening. Scientists are still unclear as to why this is so.

Quote
With respect to the discussion, there is more than one way to skin a cat and so different ways of explaining the whole EMF/CEMF business have been explored.  Then there is the pure reality of doing tests on your bench.  And within that reality you must have the full conscious realization that within the real coil on your bench, there is actually an ideal coil, and that ideal coil is functioning exactly like the EE equations state it should function like.  Saying, "I only deal with real stuff on my bench" is almost a strange thing to say because the exponential response of the real coil comes directly from the ideal coil that is the basis for the real coil.

It is funny to watch you tried to compare real and ideal as one in the same,where one will dissipate energy,and the other will not. All your electrical models which include inductors,have a series resistor,and that is to show that there is a resistance associated with real world inductors. It also clearly shows there will be losses associated with that inductor.

Perhaps you would like to have a go at the diagrams below--which is correct?



Brad

tinman

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Re: MH's ideal coil and voltage question
« Reply #1407 on: June 29, 2016, 07:08:48 PM »
Actually MH doesn't every scope shot of an inductor with a voltage applied across it's terminals generating a linear current rise give proof that Emf = L*dI/dt or rearranging di = Emf*dt/L? Where is the evidence of Cemf? So, anyone adhering to the notion that Emf = Cemf in a single inductor has the burden of proof IMO to show by experiment or math derivation that it exists.

By definition, Cemf is opposite to Emf.  The current increase in the above example is in phase with the applied Emf and follows Faraday's law without Lenz. How do we justify any amount of negative Cemf to be added to the Emf and still adhere to Faraday's law? I am willing to change my view if and when I see something convincing.

pm

Edit

Faradays own Faraday disk generator dosnt even follow his own law.
Here we have no rate of change in time between the magnetic field and conductor,but current still flows. We can have the magnets stationary to the rotating conductor,or we can have them spining with the conductor--it makes no difference.
But im sure there has been some tweaking to the laws to account for this--as they often do.


Brad

picowatt

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Re: MH's ideal coil and voltage question
« Reply #1408 on: June 29, 2016, 07:18:41 PM »
But as we are dealing with an ideal coil,and none of that negative feedback energy is dissipated

You are correct, it is not dissipated.  That which cannot be dissipated is either stored in, or retrieved from, the magnetic field.  It is what inductors do using and obeying the laws of inductance...

We are going on what, 130 years or so of modern man investigating, defining, and verifying the operation of inductors?  All manner of wire types, geometries, resistance and capacitance, use at frequencies into the THz region, study of inductance in the realm of nano-length conductors, inductors using zero resistance conductors, and all manner of core types have been investigated over those years.

PW

tinman

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Re: MH's ideal coil and voltage question
« Reply #1409 on: June 29, 2016, 07:20:18 PM »
The above is germane to the argument, yet no comments.

This seems to go against what we discussed before Poynt.
We agreed that the CEMF is what limits the current,and stops it from going straight to its steady state value. A voltage appears across a resistor as soon as it is placed across that resistor. The only reason the current value is far less than that steady state value at T=0,is because we have the added series resistance generated by the CEMF ,that is added to the coils winding resistance. We know this to be true,because if there was no CEMF(as we discussed),then the current would go straight up to the steady state value.


Brad