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Author Topic: MH's ideal coil and voltage question  (Read 487944 times)

tinman

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Re: MH's ideal coil and voltage question
« Reply #1230 on: June 23, 2016, 04:59:05 PM »
Good question - I don't know. The scenario you paint seems a bit like those dastardly 'which came first, the chicken or the egg' situations
Will have to sleep on that.
Cheers

Indeed ;)
Perhaps Poynt,PW,verpies,and the likes,will give it some more thought as well,instead of falling into the world of MHs endless garden paths.

I really do love that saying of verpies-->just because everyone else makes mistakes,it dose not mean we have to.


Brad

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1231 on: June 23, 2016, 05:46:31 PM »
Oh i see lol.

I say the very same thing as Poynt did,but i get a totally different reply.

To gutless to treat Poynt like you treat me?
Oh,and here is the kicker--the guy(me) that you think is such an amateur,and knows so little,gave the very same answer as Poynt,who is very well versed in EE--only i gave it first.

This speaks volumes about your true nature MH--your pathetic.

Brad

First of all, I don't know which posting you are referring to.  Secondly, kiss my ass.

Kiss my ass because Poynt made a long posting where he started to move significantly in my direction and your response was quite polite.  If I had said the same thing you would have said I lost my marbles and used a lot of other colourful expressions.  You were too gutless to treat Poynt like you have treated me?

In other words, your behaviour would be exactly the same as what you are accusing me of.  Here is where you can actually apply the term "hypocrite" to your own behaviour.

You are a hypocrite Brad.

i.e.;

And to think,you thought you had the smarts to give EMJ a hard time on his understandings about inductors and coils--and me for that matter.   <-- This one sounds like a rude insult.
You have yourself a great time MH,but i am done with your repeated stupidity,and re-writing of physics.  <-- this one sounds like a rude insult
I think you are a little lost when it comes to understanding what CEMF is in an inductor-or anything for that matter.   <-- This one sounds like a rude insult
Yep-you have finally lost your marbles.  <-- This one sounds like a rude insult
MH is just lost again.  <-- This one sounds like a rude insult

However, Brad, you might or might not know how after the fall of the Soviet Union in America they talked about the "peace dividend."

Well, let's say you got the "war dividend."  You can be so unbelievably obstinate and your knowledge was so screwed up and so skewed that you were hopelessly trapped in a backwards electronics pre-kindergarten.  You had to be battled with over and over and over to force some sense into you.  You still have a long long way to go.

You had to get your ass kicked over and over.  You were kicking and screaming all the way.  You still have a serious mental block about admitting that you are wrong.

Nonetheless, you have progressed more in the past three months than you progressed in the past six years watching pulse motors turn.

Don't believe me?  Just go read this thread from the very beginning and read yourself and what you have to say.  So for you, being told straight to your face by me that what you just posted was idiotic and completely and totally wrong who knows how many times was ultimately for your benefit.

Just go read the this thread from the very beginning and see how completely idiotic most of what you say is from your current perspective.

It's like very Old School schooling where knowledge had to practically be beaten into your behind.  And there is no way in hell I would keep this up.

Like it or not, you are 10 times smarter when it comes to electronics than you were three months ago.  And you still need to lock yourself in a room for a month and read and understand some books on basic electronics so you will stop dropping outrageously ignorant and stupid comments that make it look like you were born just yesterday.

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1232 on: June 23, 2016, 06:01:20 PM »
I think what this is saying is that the Vsource is NOT the same V that the inductor sees,, the inductor is going to see Vsource-VdropR and so VdropR becomes the EMF that the inductor matches with CEMF,, and since Vsource is larger than VdropR+(CEMF=VdropR EMF) current will still flow.

So the CEMF from the inductor is less than EMF from the SOURCE because the inductor sees the EMF from the RESISTOR and NOT the source.

That's right.  And if I was going to split hairs I would say, "the EMF from after the RESISTOR."

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1233 on: June 23, 2016, 06:08:23 PM »
I really do love that saying of verpies-->just because everyone else makes mistakes,it dose not mean we have to.

Brad

Exactly, so when is this mass hysteria about Kirchhoff's voltage law going to come to an end?

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1234 on: June 23, 2016, 06:24:26 PM »
This one is for the KVL hysterics.

Let's switch over to the physical world and discuss the bloody frictionless fully-loaded shopping cart.

Look at the attached graphic.  This time we are going to use the Force-Voltage analogy.  Pay attention to the variables.

You are pushing the shopping cart.  The force you push on the cart with your hands is the voltage.  The velocity of the cart is the current.  The heavy shopping cart is the inductance.

If you push on the cart with a constant force then you know that you have to start running faster and faster down the aisle because the shopping cart is speeding up - it's accelerating.

You push on the cart - that's the EMF.

The cart pushes back on you with the SAME FORCE, that's the CEMF.

"For every action there is an EQUAL AND OPPOSITE reaction."

COMMON SENSE PEOPLE, take an example from REAL LIFE and THINK.

minnie

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Re: MH's ideal coil and voltage question
« Reply #1235 on: June 23, 2016, 06:59:36 PM »



   Old Webby's gettin' a bit of steam up!!!
          J.

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1236 on: June 23, 2016, 07:27:59 PM »

   Old Webby's gettin' a bit of steam up!!!
          J.

Speaking of which, let's take a break and give the boys, girls, and zombies a little dose of culture.  And when I say "dose" I really mean "dose."

Sun Valley Serenade - Chattanooga Choo Choo

https://www.youtube.com/watch?v=V2aj0zhXlLA

poynt99

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Re: MH's ideal coil and voltage question
« Reply #1237 on: June 23, 2016, 07:58:23 PM »
The EMF and the CEMF are the same damn thing!  The battery says, "I am imposing 12 volts across you."  The coil says, "Oh shit, then I have to let changing current flow through me at a rate where I muster up the same 12 volts."   They are the SAME THING.  They both measure 12 volts with a volt meter and have the same polarity if you use the same ground reference.  They HAVE to be the same potential because they are CONNECTED to each other.
They measure the same, but not because the cemf is equaling the emf. It is because the emf source is holding the voltage constant. again, I think it is a very bad idea to equate a voltage drop with a cemf. They just simply are not the same, and historically have never been used interchangeably.

Quote
If they are the same damn thing then why is one called CEMF?  It's because you "travel though the loop" in ONE DIRECTION only.  So if you go clockwise and you go UP in potential because of the EMF, then as you continue on your journey through the coil you go DOWN in potential.  Hence the "counter."  You go up in potential and then you counter that by going down in potential.  But when you are not "in the loop" the EMF and the CEMF are EXACTLY THE SAME with the SAME polarity.
I disagree. One is called cemf because that is precisely what it is; i.e. it is a generated voltage in this case. Going around the loop is simply confirming KVL, and it always holds.

poynt99

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Re: MH's ideal coil and voltage question
« Reply #1238 on: June 23, 2016, 08:13:37 PM »
OK-good.
Now i want you to think about this very carefully Hoptoad-very carefully.

We have an ideal coil,and that is one free from any winding resistance. It is also void of a time constant--has none.
So from T=0,a voltage is applied across this ideal coil from an ideal voltage source-remember,no time constant,due to no winding resistance resistance.
At T=0,the current will continue to rise at a steady rate,and never reach a peak--the current rises to an infinite amount over an infinite amount of time. The CEMF as you said,is governed by the change in current flow induced by the applied voltage over time. But with our ideal coil,there is no change in current,as the current rises at a steady state for an infinite amount of time. So the current flow is the same as it was at T=0(-the moment a voltage was placed across the coil)for an infinite time.

Will the CEMF change from it's starting value(T=0),if the induced current from the applied voltage always rises at the same rate for an infinite amount of time?

P.S
To add your statement
Quote:  If the cemf was a steady value, all other factors would also be steady.


Brad
Since the amps/sec is constant, the induced cemf should be steady.

picowatt

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Re: MH's ideal coil and voltage question
« Reply #1239 on: June 23, 2016, 08:29:26 PM »
The EMF and the CEMF are the same damn thing!


I am going to have to disagree with this.

I believe I understand what it is you are saying with regard to your definition of CEMF.  However, by your definition, even if your "black box" were empty (a perfect insulator), that perfect insulator would also be creating a CEMF equal to the "applied" EMF.  And, by your definition, I can even see the argument that can be made to make the case for that being true.
   
However, this thread is about inductors and the definition of CEMF, regarding inductors, is very well defined.  As defined, the CEMF related to inductors is generated by way of a very specific mechanism (induction).  With all the harping on about the use of proper terminology, and to avoid confusion, it is perhaps best to stay with the existing definition of CEMF as it relates to inductors.

In the above you state that EMF and CEMF are the same thing.  You make this case based solely on a voltage drop measured across the two terminals of the inductor.  When connected across an ideal voltage source, the voltage measured across the inductor has little to do with the defined mechanism and actions of an inductor's CEMF.  In fact, by using only a voltmeter to measure across the inductor, it is impossible to measure, or identify, any parameter related to the inductor's CEMF.  By definition, the CEMF will oppose _current_ and in order to see the effects of CEMF (as defined), one must measure current.

The voltage portion of the definition related to an inductor's CEMF is, rather clumsily, something along the lines of "a rate of change dependent voltage induced into a conductor that produces a _current_ in opposition to the current that induced it".  Whether or not the induced voltage related to an inductor's CEMF is realized externally across the inductor's two terminals will depend heavily on the impedances external to the inductor.  In the case of being connected across an ideal voltage source, the effects of an inductor's CEMF will not manifest externally as a voltage.  Only by measuring the rate of change dependent opposition to the flow of current can the effects of an inductor's CEMF be realized.

Tinman's question, "what if the EMF and CEMF were equal", with regard to an inductor connected to an ideal voltage source, had little to do with any _voltage_ measured at the two terminals of the inductor.  In this instance, CEMF will only manifest by measuring current.

As I responded to Tinman, if it were somehow possible to cause all the magnetic flux created by a current flowing thru an ideal conductor to be confined to, and cut thru, that conductor in such a way as to make the inductor's CEMF be equal to the EMF, I believe that inductor would have infinite inductance.  To avoid the "chicken or egg paradox" in answering whether current could flow thru such an inductor, I stated that I believed that an infinitely small current would flow over an infinitely long period of time.

At no time were we discussing CEMF in reference to any _voltage_ measured across the inductor.   

Just my .02...

PW       

minnie

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Re: MH's ideal coil and voltage question
« Reply #1240 on: June 23, 2016, 08:48:31 PM »
What have I learned today?
 EMF is not a force.
      J.

picowatt

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Re: MH's ideal coil and voltage question
« Reply #1241 on: June 23, 2016, 08:57:05 PM »
What have I learned today?
 EMF is not a force.
      J.

May the EMF be with you...


MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1242 on: June 23, 2016, 11:09:01 PM »
They measure the same, but not because the cemf is equaling the emf. It is because the emf source is holding the voltage constant. again, I think it is a very bad idea to equate a voltage drop with a cemf. They just simply are not the same, and historically have never been used interchangeably.

When I say, "The EMF and the CEMF are the same damn thing!" I am talking about the measurement of the voltage magnitude itself.  i.e.; Are the EMF and the CEMF the same value or is there a "requirement" for there to be a difference between the two values for current to flow?  The setup is an EMF source connected across a coil.  Not too many people have chimed in on that one recently.

I don't think you should take issue with the term "voltage drop" when you put your KVL hat on.  As you go around the loop there _is_ a tangible, measurable voltage drop as you spiral your way through the coil.  Granted, it is not a voltage drop like a voltage drop in a resistor, but it is still a voltage drop.  It's all a question of your perspective and your semantic approach to the issue.  The CEMF due to the changing current flow through the coil and the measurable voltage drop as you go through the loop are one in the same.  At least from my perspective there is no big issue using either term with the proviso that you establish the frame of reference for using the term.  Or arguably, both contexts are mutually understood by the parties concerned and you can use either/or without ruffling too many feathers.

Take the example of a capacitor.  If you are doing a KVL analysis of a loop in some circuit, the capacitor could represent a voltage drop or a voltage increase.  Saying, "there is a voltage drop across that capacitor" sounds pretty ordinary and mundane to my ears.

Quote
I disagree. One is called cemf because that is precisely what it is; i.e. it is a generated voltage in this case. Going around the loop is simply confirming KVL, and it always holds.

I am not really going to disagree with you here but I will just restate what I have stated before.  It is possible to put aside how closely CEMF is tied to changing current through an inductor, and simply work with the literal meaning of the term.  A voltage that is counter to my reference voltage is a voltage that is opposite in polarity to my reference voltage.  For example, say my reference voltage or reference EMF was -25 volts.  If there is a two-terminal device in the loop that is +5 volts, then that device is a counter-EMF device when I am going about my business of summing voltages in the loop.  I suppose this is an exercise in the technical use of the English language, and not really mainstream electronics.  The point being that I have license to choose to use those words if I want to and if the people you are discussing something with are all on the same page, then it works.

MileHigh

MileHigh

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Re: MH's ideal coil and voltage question
« Reply #1243 on: June 23, 2016, 11:46:50 PM »
PW:

Your posting is a doozie and I am always amazed how sometimes it feels like you a permanently prepped to write a final exam because you have all of the hard-core theoretical and technical information at your fingertips, which is something that I don't have.

You responded to my statement, "The EMF and the CEMF are the same damn thing!"  Just a quick recap from what I just posted:  I am talking about the measurement of the voltage magnitude itself.  i.e.; Are the EMF and the CEMF the same value or is there a "requirement" for there to be a difference between the two values for current to flow?

You bring the focus of the CEMF discussion back to inductors which is fine.  I have conceded that point and said for resistors "potential difference" is more appropriate and less confusing.

Quote
When connected across an ideal voltage source, the voltage measured across the inductor has little to do with the defined mechanism and actions of an inductor's CEMF.  In fact, by using only a voltmeter to measure across the inductor, it is impossible to measure, or identify, any parameter related to the inductor's CEMF.  By definition, the CEMF will oppose _current_ and in order to see the effects of CEMF (as defined), one must measure current.

I agree and I cited Wikipedia and that is mentioned in the first sentence of the article, "The counter-electromotive force (abbreviated counter EMF, or CEMF), also known as the back electromotive force, is the voltage, or electromotive force, that pushes against the current which induces it."

What I am not saying and what is implicit is that if you measure CEMF on an inductor with your voltmeter, you are aware that increasing current is flowing through the inductor and that is the real mechanism at play.  You don't even know the magnitude of the increasing current, you are only aware that the process is taking place.

I don't know if you _must_ measure the current.  If you know the inductance, and you measure the voltage you at least know the rate of change of the current, but you don't necessarily know the magnitude of the current, unless you know the initial conditions, etc.

Quote
Whether or not the induced voltage related to an inductor's CEMF is realized externally across the inductor's two terminals will depend heavily on the impedances external to the inductor.  In the case of being connected across an ideal voltage source, the effects of an inductor's CEMF will not manifest externally as a voltage.  Only by measuring the rate of change dependent opposition to the flow of current can the effects of an inductor's CEMF be realized.

I am puzzled by that statement with respect to an ideal voltage source.  Are you making reference to a real-world inductor with resistance?  I didn't state it explicitly before but I am assuming an ideal inductor unless stated otherwise.  If you do mean a real-word inductor then I agree, the CEMF could be mixed in with an IR voltage drop.

Quote
Tinman's question, "what if the EMF and CEMF were equal", with regard to an inductor connected to an ideal voltage source, had little to do with any _voltage_ measured at the two terminals of the inductor.  In this instance, CEMF will only manifest by measuring current.

Are we back to a real-word inductor as I referenced above?

Quote
As I responded to Tinman, if it were somehow possible to cause all the magnetic flux created by a current flowing thru an ideal conductor to be confined to, and cut thru, that conductor in such a way as to make the inductor's CEMF be equal to the EMF, I believe that inductor would have infinite inductance.  To avoid the "chicken or egg paradox" in answering whether current could flow thru such an inductor, I stated that I believed that an infinitely small current would flow over an infinitely long period of time.

I can't see where you are coming from for this one.  In my mind the inductance value from a coil of an ideal conductor is still a function of geometry as per the derivation.  So you can go to the Hyperphysics web site and punch in the coil parameters and then get your inductance value and take it from there.  I can't envision an infinite inductance here.

When you say, "all the magnetic flux created by a current flowing thru an ideal conductor to be confined to, and cut thru, that conductor" to me that means a "perfect coil" where the magnetic flux still flows through the center of a coil, and then wraps back around the outside of the coil through all 3D space.  I just don't see an infinite inductance with that model.  I suppose if you had an infinite number of turns in the coil form that would be a different story.

MileHigh

Magluvin

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Re: MH's ideal coil and voltage question
« Reply #1244 on: June 24, 2016, 12:00:57 AM »
Good question - I don't know. The scenario you paint seems a bit like those dastardly 'which came first, the chicken or the egg' situations
Will have to sleep on that.
Cheers

Back some many pages ago I posted a possible scenario for this. 

There must be something that happens first, as in applying input and that input must create some mag field before cemf is created. So we have to figure if just the tiniest amount of current from the input begins, the field should induce cemf instantaneously.

If at T0 there is no current, then nothing has happened yet. Why is that? Is there cemf at t0? It is an ideal conductor which should have immediately taken on current.
But the T0 point in time is supposedly a point that when the input is connected to the ideal inductor, but if we stop time at the point of connection, then current should not have happened yet, which is sort of hard to conceive considering ideal conductors.  But I would have to say that at T0, the ends of the coil leads have charge potential from the input equaling the input.  This is where it gets tough for me I admit.  I may go as far to say that the inductor leads get some sort of say static charge even just before the contact is made, no matter how small the input voltage is. If so, could that static charge be enough to get anything moving in the inductor before the full connection is complete? Moving as in some electron flow that may set up a bit of cemf just before the connection is completed? ???

If so, then when the connection is finally made, could the cemf possibly be already in opposition to the input? Egg before chicken? ;)

Again, we will most likely never know for sure.  When we see these demos of super conductors, they are most likely still far from ideal yet, as they need to be super cooled. Why? Because they still dissipate heat, thus the cooling, of which takes the heat away that IS being produced. I had seen a demo of a copper coil inductor with enough resistance that in series with a small light bulb and a source, the bulb was dim as compared to the bulb direct to the source. But then they dipped the coil in liquid nitro and the bulb seemed to come to full brightness.  As I see it, the cooling helps to keep the heat generated by the coils resistance was just continuously taken away instead of being allowed to heat up more as current is flowing causing the resistance to become higher with the build up of heat. 

A real world inductor has also capacitance. Even if it is super tiny amount of capacitance, that capacitance takes on a charge in the coil nearly immediately. I will be doing a test of that with the scope here when I get time.  A bifi coil should have a larger spike of input when the source is applied as the capacitance is greater than a single winding coil, like Tesla said, the bifi windings take on input current as if the inductance was not there at all. I want to see if it is true.


Mags