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Author Topic: Electromagnet Question  (Read 26357 times)

gyulasun

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Re: Electromagnet Question
« Reply #30 on: August 06, 2008, 10:22:04 PM »
...
 When I move the magnet in and out of the charged solenoid the voltage reading is steady at 9 volts.  If the battery is not connected I can induce voltage spikes of ~4 Volts. 

Hi Mondrasek,

The 9V battery also has a very low inner resistance like a good power supply so any voltage drop caused by changing a current in the circuit it feeds is also very low, hence you cannot see it with a 3 and a half (or even a 4 and a half) digit resolution your multimeter has.

Quote

...   I also see no change in current with any of the experiments, but here is the weakest part of my test set up.  I have no current probe to use with the o-scope.  So I have a Fluke multimeter reading current and that may miss any transients.  But I cannot get it to read anything but the expected 120 mAmps even while pushing the magnet through the solenoid field (which should be generating +- 4 volts).

Well if you have the true RMS type Fluke multimeter like Fluke 87, then you may try it reading AC current in its most sensitive (ACmA) range. In this AC current range the 120mA DC current will not show up of course but you may be able to cause some small mA change when moving quickly the magnet away or towards the solenoid.  You can test this without the battery first, (especially if you do not have the RMS measuring type Fluke) by setting the most sensitive  ACmA range and connecting parallel the tips with the solenoid, then quickly moving the magnet in and out. You will hopefully see some peak mA change...  EDIT: If you see about 4V induced peaks across the unloaded solenoid, then you close the solenoid with the ACmA meter, the AC peak current will approximately be 4Vp / 75 Ohm=53mAp in the solenoid.

Here is some hint on making an AC current probe if you happen to have a higher permeability toroidal ferrit core... :
http://cappels.org/dproj/aciprobe/ACCurrentProbe.html
No need for calibration and the low value resistor termination, only would be useful for indication with your scope...

rgds,  Gyula
« Last Edit: August 06, 2008, 10:46:20 PM by gyulasun »

mondrasek

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Re: Electromagnet Question
« Reply #31 on: August 07, 2008, 12:50:55 AM »
Gyula,

I had a bit more time to play before leaving work.  The Fluke MM I am using says it is an RMS type so I tried to set up for ACmA as you said in parallel with the solenoid. But it would not read anything when I introduced the permanet magnet to the solenoid.  It also would not energize the solenoid.  I placed it in series and I was able to see very large readings while moving the permanent magnet in and out of the solenoid, both with and without power to the solenoid applied.  I then switched back to DC and was able to witness small fluctuations to the current readings while moving the magnet in and out.  I realized that I had added some more magnets to my original permanent magnet in order to increase the mass and keep it from firing so high since I had lost it in my work area several times after failing to catch it.  So the increased length of the magnet, and possibly the strength (I added a much larger diameter magnet, one that could not enter the solenoid, to the top) are allowing me to finally get readings.

I will work on making a toroidal current probe.  I assume I can use a core from an old circuit board.  We have a junk bin of various boards in our repair department that might have one.

Any reason this type of probe will not work with DC current?

I am still thinking the sample rate on my available o-scope is not high enough to show the diference in the current traces when charging the solenoid with and without the permanent magnet present, but it is all I have now.  My father teaches at a local University and he agreed to check with their Engineering Department to see if I can use some better equipment if I need to go further.

M.

mscoffman

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Re: Electromagnet Question
« Reply #32 on: August 07, 2008, 01:50:09 AM »
That lead me to what I believe is the problem with my test set up and measurements.  I am using an industrial 24 V power supply.  This supply is likely adjusting current/voltage for the changing load and not allowing me to see the real differences between charging the solenoid with and without the permanent magnet in place.


Actually that is the job power supply to keep it's voltage as constant as possible even as it's input current changes.
And yes, current probes will help. Unless you have a "crappy" scope it should be fast enough for these inductor speeds.
Also if you has any choice it would be better to use FET field effect transistors like IRF511 as they have very high off
resistance and can have very low on resistance like .01 Ohms on for specials, much closer to relay contacts. FET are
voltage mode triggered and that makes them easier to understand bipolars. Bipolars (2nxxxx) are current mode controlled
and harder to design with and that control current has a cost - they are often used less efficiently.

 If you want to do power measurements you need to put a resistor across the coil when you disconnect all else - make
 it identical to the DC resistance of inductor.  That way you transfer maximum power, when source and output resistance
(impedance) are equal. <= read this; it answers why you seem to see no effect when you have power connected vs nothing.
A battery's job is to have very low internal impedance.  As Guyla said. Good Luck!

:S:MarkCoffman

gyulasun

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Re: Electromagnet Question
« Reply #33 on: August 08, 2008, 12:33:59 AM »
Gyula,

I had a bit more time to play before leaving work.  The Fluke MM I am using says it is an RMS type so I tried to set up for ACmA as you said in parallel with the solenoid. But it would not read anything when I introduced the permanet magnet to the solenoid.  It also would not energize the solenoid.  I placed it in series and I was able to see very large readings while moving the permanent magnet in and out of the solenoid, both with and without power to the solenoid applied. 

@Mondrasek,

Sorry if I was not a 100% clear with my suggestion but I meant first do a induction test without any power supply or 9V battery  and then with the battery (or the power supply), ok?
And in the without battery test, I meant you connect the ACmA meter's tips directly to the coil's wire endings (to me this means a parallel connection, there is nothing in between the meter and the coil endings, ok?) and move the magnet. This way you test the induced current because the meter as a load simply places a short circuit onto the coil and the induced current is limited only by the coil own copper resistance + some inductive reactance.
You wrote you did not see anything in this parallel connection and placed the meter in series with the coil?  You lost me here, sorry.

If you happen to have access to better instrumentation by your farther's help,  it would save you a lot effort and time on not 'tinkering' with AC current probe building, I think.

Such type of current probes do not work on DC because their principle is based on normal transformer operation so a DC current can only bias them in one or other direction on their cores' B-H curve, that is all.  It takes a current change like an AC does to get transformation on the secondary coil.

rgds,  Gyula

mondrasek

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Re: Electromagnet Question
« Reply #34 on: August 08, 2008, 02:53:11 AM »
Gyula,

I see that I misunderstood your suggestion.  I look forward to trying it correctly.  Unfotunately I must visit a customer tomorrow and will not be able to play with my simple test set up.

When I modified your suggestion to "in series" it was only a guess that you had accidentaly said parallel and truely meant in series. 

I have access to quality ferrous toroids and built a simple AC current probe this morning but of course it did not work on this DC circuit.  I suspected as much.

At least with every failure I learn something new!  Maybe that is what I enjoy the most?

Thanks for all your support.

Any other way to see the current trace of a DC electromagnet when it is initially energized?

M.

gyulasun

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Re: Electromagnet Question
« Reply #35 on: August 08, 2008, 03:13:08 PM »
Hi Mondrasek,

Ok, no problem on misunderstanding.

In the meantime I learned about DC current probes as well but they use Hall effect device.  See this here:
http://www.testpath.com/Categories/Current-Probes-536114.htm   and their A622 would be good for you now  :) :
http://www.testpath.com/Items/ACDC-Clamp-on-Current-Probe-for-DMMs-and-Oscilloscopes-100kHz-100A-117-283.htm

It works from DC to 100kHz AC (has no toroidal core of course).  Other types with also both DC-AC ranges but with higher upper frequency coverage use both the Hall device and the toroidal core transformer.

I would suggest a very cheap but still correct solution both for DC and AC: use a 1 Ohm (or 5 or maybe 10 Ohm) value resistor and connect it in series with your electromagnet coil and measure the voltage drop across it by your oscilloscope.  Because your coil resistance is around 74 Ohm with this coil, the additional 1 Ohm (or say 5 or 10 Ohm if you wish to increase the current measurement sensitivity)  will not modify significantly the value of the original current (or if it does, you can correct it by some calculation).
And in the 50 or 100ms scope time range you surely will see the peak currents that are made by your moving the magnet in and out of the coil while your power supply or the 9V battery also feeds the coil . 
You can use several different value resistors to arrive at the final 1, 5 or 10 Ohm value, with the correct wattage, using the digital Ohm meter of the MM, no need for a high precision single resistor which tends to be expensive too.

rgds,  Gyula

capthook

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Re: Electromagnet Question
« Reply #36 on: August 09, 2008, 12:10:09 PM »
If one is to energize any electromagnet (you pick the specs) for 1 msec, what is the power consumed by the electromagnet?
vs.
If one is to energize the same electomagnet for 1 msec, but this time, with a permanent magnet (you pick the specs) in close proximity such that the permanent magnet N pole is facing the electromagnet N pole so as to repel the permanent magnet, what is the power consumed by the electromagnet?

The power consumed is determined by Ohms Law.  See the attached pic I
find useful.
For this calculation:
P=U2/R
so if you apply 10 volts across a 5 ohm coil:
(10x10)/5 = 20 watts

Is this the thinking of your question? :
Will the electromagnet in proximity to a permanent magnet require additional energy because the field of the p.m. is 'sucking' up the field of the e.m. requiring additional input?

Has this been answered? What would be the answer?

At first blush I would have said no - but am now thinking - 'maybe'?
And why/why not?
And the variation due to induction of the moving p.m. near the e.m. windings would be negligable? (see following)

If the electromagnet is energized in proximity to a permanent magnet in repulsion the power consumption should be slightly more, maybe 21 of 22 watts.  When a magnetic force (the permanent magnet) is moved away from a coil of wire(in this case caused by repulsion) it generates electricity, so the power level rises, although only slightly.
So the power would rise because it's in repulsion resulting in an 'opposite flow' of charge due to induction of the p.m./windings to the e.m. requiring additional energy from the power supply?  And 1 or 2 watts?  Would that be a HUGE magnet?  Or would it be more like .1 or .2 watts (or less) for a small neo (.75x.5x.25)?  The p.m. is not moving ACROSS the windings but away, so even smaller?

Interesting thread - and I have alot of questions/thoughts to follow

tx


capthook

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Re: Electromagnet Question
« Reply #37 on: August 09, 2008, 12:47:21 PM »
Here's my take/thoughts.  Hoping for further clarifications/corrections/thoughts

So, say one is to take a cylindrical electromagnet with opposite pole configuration.  Set it with the North pole facing up and uncharged.  Place a perminant magnet on top so that it's North pole is down and it is in contact with and in attraction to the ferous core of the electromagnet.  When you apply an electric source to the electromagnet it should repel the perminant magnet.

How much power is required to break the attraction of the perminant magnet to the electromagnet core?

That would depend on:
Magnet size/strength
Core surface area/composition/dimensions
Air gap

Testing would probably be easier than trying to plug numbers into formulas.
You might hang/place the p.m. BELOW the e.m. and put a potentiometer between the e.m. and power supply and adjust it until the p.m. drops.

If two perminant magnets are forced together in a vertical arrangment so as to repel, and then the top magnet is released, it will accelerate upwards to a height much greater than where it will eventually settle and hover over the bottom magnet. 
Can the electromagnet/perminant magnet arrangement be made to act the same?
Given enough power quickly enough - it could.

What is the relationship of the power consumed by the electromagnet to the strength/size of the perminant magnet to create this equal opposing force?
You would need to make your e.m. the same strength as your p.m.  This requires the appropriate AT (amp-turns).  This is achieved by combining the variables of:
wire size/length
# of turns
core size/permeability
coil resistance
voltage applied

This link is a java coil simulator.  It's for an aircore but is helpful for determing # turns, resistance, wire length etc.

http://www.coilgun.info/mark2/inductorsim.htm

Does the fact that we must first break the attraction require more power to the electromagnet than if there was not the attraction?
Yes 

Does the acceleration of the perminant magnet away require more power to the electromagnet due to the fact that the perminant magnet is moving through the electromagnet field?  Or will the electromagnet field generate outwords from the center of it's core and drive the perminant magnet away so that the two fields never overlap?

This goes to the question in your first post.  Not sure - hoping for further answers....

- - - -

Something similar I've been wondering:

The Adams motor design applies the principal that it uses less power to:
Have a p.m. attracted to the iron core of an e.m. and then pulsing the e.m. with just enough power to negate that attraction to the core allowing the p.m. to continue onwards. (kind of like turning the iron core into an air core).  Rather than using the pulsed e.m. as attraction or repulsion to the p.m.
Is this a valid principal?  Why/why not?  What might be a better principal?

tx

mondrasek

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Re: Electromagnet Question
« Reply #38 on: August 09, 2008, 09:07:00 PM »
@capthook, thanks for all the thought and input.  I'm glad you are interested by these questions.  When I first asked them I thought I would receive a simple textbook answer or reference to experimental data that would make everything clear.  I didn't imagine this was going to be a testing/theory brain teaser.

@all

So after looking further into Bedini for a BEMF capture circuit I went ahead and made Imhotec's Bedini fan this morning.  Destroyed quite a few good fans trying to find one that had the correct coil wrap configuration as well as trying to understand the various instructions.  But it works and I'm trying it out now to recharge and old NiMH 9V that has been in a box for 6 or so years since I was last into micro electric RC planes.  That circuit is what I wanted to understand so I could apply my ideas *if* the permanent magnet does not consume an equal amount of power from the electromagnet when it is fired vertically.  I still look forward to trying everyone's ideas back at my deck at work with the test setup on Monday.

I've coorresponded with mscoffman a bit in the background as well.  He said he has some more info to forward once he has the time to collect it and pass it along.  I'm interested in his response to my questions about the Bedini SSG circuit as well.  I'm trying to understand it from a clasical EE point of view (ie without the "radiant energy" theories) for now.  I'd like to hear your opinions on that as well if you have any.

Thanks,

M.

Honk

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Re: Electromagnet Question
« Reply #39 on: August 10, 2008, 06:21:11 PM »
A little tip on the way to perfection.

When you design the best electromagnet possible, used in pulsed mode you must avoid to deep winding layers.
In pulsed mode you have higher core loss than you have copper loss, due to the hysteresis of iron.
I calculated the surrounding flux of a current-carrying wire to how much it decreases by distance.
This affects the level flux that actually penetrates the core and gives you the magnetism you desire.
As you can see in the picture, you should aim for a maximum of 5mm deep winding and also try to keep it as
tight as possible to fit the most amount of copperwire. Using thicker wire gives you lesser turns at lesser
inductance and vice versa. It all depends on the speed you intend to pulse it. More turns = slower response.
The number of turn doensn't affect the flux output, lesser turn require more current and vice versa.
Most important for high flux efficiency is the winding depth. To deep winding gives a lot of copper loss at
small gain in flux output.

http://www.imstrading.com/cgi-bin/flux-graphs?page=fluxgraphs

mondrasek

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Re: Electromagnet Question
« Reply #40 on: August 11, 2008, 08:07:27 PM »
I put a 1.6 Ohm resistor in series with the solenoid per Gyula to read the votage drop across it as an indirect way of measuring current in the solenoid circuit.  I'm not really interested in the absolute values, just the difference in the current over time as the permanent magnet is accelerated away from it's starting position inside the solenoid.  Again, I did not see the results I expected.

Without the permanent magnet inside the solenoid the voltage measured across the solenoid and the in-line resistor both rise to their steady state values and hold when I press the switch connecting them to the 9V battery.  The o-scope traces look exactly like a square wave.

With the permanent magnet inside the solenoid the voltage measured across the solenoid and the in-line resistor both rise to the same values initially.  But the voltage across the in-line resistor then drops slightly before returning back to the expected steady state value.  The shape of the curve of this voltage drop and it's return to normal appears to be a nice parabola.  I assume the drop in the voltage curve represents is the permanent magnet accelerating and the return icurve representss the two magnetic cores increasing in distance.

So does this mean the current to the solenoid actually decreased as the permanent magnet was accelerated away?  Did the power consumed by the solenoid actually decrease as it did work upon the permanent magnet?  Or where (oh where) is the measurment error now?

Thanks,

M.

triffid

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Re: Electromagnet Question
« Reply #41 on: August 12, 2008, 12:04:04 AM »
test

mscoffman

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Re: Electromagnet Question
« Reply #42 on: August 12, 2008, 07:15:39 PM »
@modrasek;

If that is what you measure then that is probably it. One thing to think about is the
fact that the magnet has two poles and what does the solenoid see as it accelerates
the magnet through itself. It could be that the solenoid's stronger field actually forms
lenz current in the magnet. That bounce could also be from the power supply recovering.
See a better method below.

So if you see a decrease in current it maybe true. Don't forget that energy is measured
in "milliwatt seconds" and time plays a factor, if you have to keep the solenoid energised
longer to fire the magnet and increase the field then it has potentially used more total
energy.
 
IMHO you will not see overunity when an electromagnet accelerates a magnet. You will
see overunity if one PM lifts another. (but then lose momentum of the wheel trying to
pull them away from one another). There is also Smot runner gain, but one hasn't (yet)
extricated the runner to get it to the beginning of the track array.


@ALL

If you want to see overunity energy production from the Bedini
Fan I recommend use of acid/lead storage batteries or Gel Cells
for both the source and the charging battery as the overunity
part occurs due to battery chemistry. Don't use strange battery
chemistry ..and then say that the overunity part doesn't work,
please.

Small Acid/Lead Batteries are available in those automotive jump-start
units and small grey or orange Gel Cells are available in building
emergency lights that come on when the utility power fails. I like
the small batteries used in ICE motorcycles. They also make 9Volt
size acid/lead's I believe. 9volt batteries are probably too
small to support the fan well but it's worth a try.   

imhotep's Bedini Fan is an excellent experimental device as it doesn't
have an electrical interference footprint much larger then a normal
DC fan. imhotep's Morray's Vibrator Overunity Light unit also is
an excellently simple device, some experimentation will be required
to modify the base unit for other applications however. See
imhotep's youtube.com videos for more details on building these devices.
A Bedini Fan might be a valid manufactured product...overunity included!
Rather then build a Bedini SGS motor which I don't consider a good
experiment why not include *your own* electrically run wheel motor as
an actuator in a custom version of a Morray's Vibrator circuit?

imhotep's videos:

http://www.youtube.com/user/kojsza


The principal being demonstrated;

http://uk.youtube.com/watch?v=qaCk0jK--8s


----

Magnetic Pulse Experiment

The following experiment should let one see then pulse from a magnet
in a straw accelerating away from being fired by a solenoid coil when
you apply power through a switch. This isn't easy to do experiment but
here goes;

Remember that a capacitors store power proportional to it's voltage
while inductors store power proportional it's current. So it is
easier to think about inductor equations in terms of current.

What we are going to do is look at the current flowing through
two coils simultaneously and use one coil as reference and
subtract that from the coil that accelerates the magnet using
functions available on most oscilloscopes. The "invert" and "add"
channels functions.

a) you need;
   two identical solenoid coils and if you don't have scope current
   probes we can use two "current transformers" instead. (see Wikipedia)

http://en.wikipedia.org/wiki/Current_transformer

   A valid current transformer is a 20KHz bandwidth audio transformer
   line-to-load transformer with a 600 ohm impedance primary
   (audio line = 600ohms) and a 1.6 ohm secondary or the lower
   the better. I would say 100Watt audio transformer
   (audio bandwidth = 0->20KH) you then must solder a 600 ohm 5watt
   resistor across the 600 ohm primary or match the primary resistance
   in a way that is won't accidentally disconnect else a current
   transformer can become a shock hazard and damage equipment. Now
   connect the low resistance secondary(s) in series with coil(s)+power
   supply and attach one each primary+resistor to each of two scope voltage
   channels.

b) now flip the "invert" switch on the reference scope channel

c) find the "add" channels button on the scope

d) the "invert"+"add" now equals "subtract" one channel signal from
   the other

e) now one has to adjust the gain of the channels so that the pulse
   visible then the power supply is "fired" into the two solenoids
   then adjust the channels so that the difference is as small as
   possible when there is nothing fired from both solenoids.

f) You can validate that swapping the straw and magnet between
   solenoids should create a plus going pulse when the magnet
   is in one and a minus going pulse when it is the other.
   The magnet uses most energy at the beginning to accelerate
   therefore the pulse.
 
g) you can also watch as a magnet flies-by with an some other inductive
   coil attached to the scope. There will be a bidirectional pulse
   at the moment the magnet flies past, with the zero transition
   at the point of closest approach. The Bedini Motor 2n3055 transistor
   circuit uses a sense coil that works this way.


:S:MarkSCoffman



gyulasun

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Re: Electromagnet Question
« Reply #43 on: August 12, 2008, 08:58:23 PM »
.... The o-scope traces look exactly like a square wave.   

Hi Mondrasek,

It seems like a square wave first but if you change a little on the timebase of the scope then you can see a typical exponential voltage (i.e. current) curve every inductance produces.  See this link where you can find a series LR circuit with typical current-voltage curves in the function of time. Notice that the value of R in Figure 2-10A  includes the DC copper resistance (if I recall it 75 Ohm in your case) plus your 1.6 Ohm series inserted resistance too. Here is the link:
http://www.tpub.com/neets/book2/2c.htm

Try to reach similar scope pictures on your scope like in Fig. 2-10B  and then you may proceed to the tests with the inserted magnet, ok? 

Edit: I just noticed that on the next page of the link there is the typical exponential curnet curve shown in Fig.2-11 here: http://www.tpub.com/neets/book2/2d.htm   

Quote
With the permanent magnet inside the solenoid the voltage measured across the solenoid and the in-line resistor both rise to the same values initially.  But the voltage across the in-line resistor then drops slightly before returning back to the expected steady state value.  The shape of the curve of this voltage drop and it's return to normal appears to be a nice parabola.  I assume the drop in the voltage curve represents is the permanent magnet accelerating and the return curve represents the two magnetic cores increasing in distance.
So does this mean the current to the solenoid actually decreased as the permanent magnet was accelerated away?  Did the power consumed by the solenoid actually decrease as it did work upon the permanent magnet?  Or where (oh where) is the measurment error now?

When the magnets starts moving up, it obviously starts inducing current in the coil and if you see the current reducing parabolically during this time it should mean the current consumption for these moments also reduces. Interesting. Maybe the position of the magnet where it starts kicking out from the coil influences the current reducement? would stand to reason.  It would be interesting to see the shape of the curve in the same time base scope set where you already can nicely see the coil exponential current curve without the magnet.

rgds,  Gyula

mondrasek

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Re: Electromagnet Question
« Reply #44 on: August 12, 2008, 10:10:12 PM »
@mscoffman.  Great information as always.

@Gyula.  I was able to see the correct exponential curve when adjusting the timebase as you suggested.  Unfortuantely I was working with another unfamiliar o-scope since the one I had played with earlier was out in the field with a technician doing actual work (not my desk experiments).  This new scope was taking too much time to learn and the only way to see the current drop due to the magnet on screen was to change the timescale so that the exponential curve was compressed to look like the square wave.

I was very interested by the current drop, but as mscoffman says, this drop is over a much longer time period than I would have expected compared to the saturation rate of the circuit.  Interesting effect, but what could it be good for?

I was curious if I could keep the circuit/solenoid charged only as long as the current drop was occuring.  In a failed attempt I replaced my mechanical switch with a custom design, utilizing the perminant magnet as a switch contact.  I placed the two wires oringally connected to the switch into the bottom of the tube supported by other elements so that they were contacts that would be bridged by the permanent magnet.  With this in place I then was able to move the solenoid up and down the straw to different locations with respect to the permanent magnet, into repelling and attracting, up and down configuarations.  When the solenoid pushed or pulled the magnet upwards it would break the circuit and allow the magnet to fall again, re-connecting the current.  The result was interesting at best.  The resultant pulses of current applied to the solenoid would only raise the magnet a less than noticable amount, though you could hear and see the vibration and arcing.  So the switching frequency was fairly high.  Putting the multimeter across the solenoid in AC mode caused readings from several hundred milliVolts to several Volts above the DC supply Voltage.  I'm not sure if that was due to the moving permanent magnet, the BEMF, or both.  But it was interesting all the same.  I'd like to see a similar setup that allowed the solenoid to to be energized for longer.  I don't see this as being easily possible with a mechanical set up and instead would require a variable rate switching circuit.  Again, I'm not sure what this would accomplish, but now I'm just playing while trying to think where the current drop effect could possibly be useful.

Thanks again to everyone for all the info and ideas.

M.