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### Author Topic: AETHER VORTEX TPU  (Read 62624 times)

#### dezeinstein

• Newbie
• Posts: 12
##### Re: AETHER VORTEX TPU
« Reply #60 on: April 19, 2016, 10:57:24 AM »

This is the part of Overunity forums that leads me to believe that nobody playing with this stuff has exhibited any knowledge with cold electrical output. The reason I say this is because cold electricity does quite the opposite as conventional power does with an impedance. If we take the hairpin circuit and we throw in a 200w bulb on it's output, it will not light no matter what we do. If we feed that bulb with a 40 awg wire, it will illuminate some. If we take the same setup and add a 100w bulb, the bulb will light so bright you will face temporary blindness. Take the 40 awg wires away (by the way are unburnt because there is NO amperage running within them) and add 12 awg wires to the 100w bulb. The bulb will NOT illuminate. Add a 20 watt bulb and there will be so much energy running through the filament that it will light, arc and blow the filament. Install a 40w bulb and it lights again to cause blindness.

The moral of the story is the resistor you speak of with cold electricity running through it will produce more of an output if the resistance is higher than it were lower, but, it won't matter what the wattage rating is because this power is not accumulated from the circuit's input, it is an energization through it's impedance and it only illuminates by the vibration of the electrons in it's filament caused by it's input frequency and higher resistances of either the bulb or it's feed wire size. There will  be no current at all in the circuit, however, the bulb will light at higher levels than that of high current or forced current conventional electricity which is wasteful energy. We can illuminate 50 bulbs with the hairpin circuit at the correct impedance, and, the higher the impedance, the more energy drawn into it's output with no effect on it's source. The source remains the same, we just need the same amount of energy for initiation of every process with no differences. The only differences I have witnessed were the input's amperage levels of maybe 16ma would be reduced to 12 ma at hv's of 5kV to 15kV depending on the transformers used.

This means that those conventional equations may be useless with any type of cold radiation that is drawn in from the environment, even if the output may seem to be conventional, the effect needs to be duplicated first to see what really happens. Determination can not be made by a simple equation unless we compare apples with apples. Your circuit formulas are like comparing an apple to a maple branch.. Not even being a fruit... You may as well try the circuit first before shouting out formulas that may not even apply here.

#### pomodoro

• Hero Member
• Posts: 720
##### Re: AETHER VORTEX TPU
« Reply #61 on: April 19, 2016, 02:09:36 PM »
I can only recommend that you build it then, and tell us how well it went. If it works, make a few units and sell them at cost price to a few of us on here so we can confirm this.

I'm not trying to be rude, but I have made countless crap that was supposed to work but never did. It turn out that 99% of this sort of garbage is someone great  idea that in their minds should work, and they pretend it worked, with the hope that others will replicate and hopefully get it to actually work.

Eat, Sleep, Build

#### FatBird

• Hero Member
• Posts: 1178
##### Re: AETHER VORTEX TPU
« Reply #62 on: April 20, 2016, 04:00:18 PM »
@ dezeinstein

Can you do a YouTube video to show us an example?
Thank you.
.

#### NickZ

• Hero Member
• Posts: 5225
##### Re: AETHER VORTEX TPU
« Reply #63 on: April 20, 2016, 06:13:46 PM »
As a newbie, it's easy to assume that you know what you're talking about. How about some proof to back it all up.
We've heard theories till the cows come home.  But, no self runners, as yet. Nor a replication of a TPU, that works.

#### Hoppy

• Hero Member
• Posts: 4135
##### Re: AETHER VORTEX TPU
« Reply #64 on: April 21, 2016, 02:19:24 PM »
This is the part of Overunity forums that leads me to believe that nobody playing with this stuff has exhibited any knowledge with cold electrical output. The reason I say this is because cold electricity does quite the opposite as conventional power does with an impedance. If we take the hairpin circuit and we throw in a 200w bulb on it's output, it will not light no matter what we do. If we feed that bulb with a 40 awg wire, it will illuminate some. If we take the same setup and add a 100w bulb, the bulb will light so bright you will face temporary blindness. Take the 40 awg wires away (by the way are unburnt because there is NO amperage running within them) and add 12 awg wires to the 100w bulb. The bulb will NOT illuminate. Add a 20 watt bulb and there will be so much energy running through the filament that it will light, arc and blow the filament. Install a 40w bulb and it lights again to cause blindness.

The moral of the story is the resistor you speak of with cold electricity running through it will produce more of an output if the resistance is higher than it were lower, but, it won't matter what the wattage rating is because this power is not accumulated from the circuit's input, it is an energization through it's impedance and it only illuminates by the vibration of the electrons in it's filament caused by it's input frequency and higher resistances of either the bulb or it's feed wire size. There will  be no current at all in the circuit, however, the bulb will light at higher levels than that of high current or forced current conventional electricity which is wasteful energy. We can illuminate 50 bulbs with the hairpin circuit at the correct impedance, and, the higher the impedance, the more energy drawn into it's output with no effect on it's source. The source remains the same, we just need the same amount of energy for initiation of every process with no differences. The only differences I have witnessed were the input's amperage levels of maybe 16ma would be reduced to 12 ma at hv's of 5kV to 15kV depending on the transformers used.

This means that those conventional equations may be useless with any type of cold radiation that is drawn in from the environment, even if the output may seem to be conventional, the effect needs to be duplicated first to see what really happens. Determination can not be made by a simple equation unless we compare apples with apples. Your circuit formulas are like comparing an apple to a maple branch.. Not even being a fruit... You may as well try the circuit first before shouting out formulas that may not even apply here.

That's: 60W @ 12mA / 5KV: 180W @ 12mA / 15KV: 80W @ 16mA / 5KV: 240W  @ 16mA / 15KV.
Therefore assuming good impedance matching, that equals some bright lamps even without the cold electricity!

#### FatBird

• Hero Member
• Posts: 1178
##### Re: AETHER VORTEX TPU
« Reply #65 on: April 22, 2016, 04:11:29 PM »
@ dezeinstein

Can you do a YouTube video to show us an example?
Thank you.
.

#### catalin23

• Newbie
• Posts: 1
##### Re: AETHER VORTEX TPU
« Reply #66 on: June 08, 2016, 10:41:26 PM »
Just stumbled upon this topic... If these claims hold true, did anyone tried to actually "close the loop" and use a fraction of the output power to feed the HV source input, thus self-maintaining the device in operation (while extracting some energy for external use...)?
If start-up is an issue, one could use a buffer battery which starts up the HV source and gets charged while the device generates power. It could be easily proven if the flow of energy is in the desired direction (or the battery could be subsequently disconnected to keep the setup "clean" of any "externally measurable" power sources).
BTW, does anyone really knows where does this energy come from? Is it similar to a ZPE extraction tentative?

It looks extremely easy to build - and if it works, I would be baffled that no one could do this (much!!!) earlier... or did they?? I would be tempted to build one myself.

All the best,
Catalin