Author Topic: Kapanadze Cousin - DALLY FREE ENERGY (Read 11882302 times)

00 · « **Reply #2430 on:** September 20, 2013, 03:12:10 PM »

orthgonal winding variant two layered

00

Hoppy · « **Reply #2431 on:** September 20, 2013, 04:52:46 PM »

Corrected inverter vs overunity winding diagram.

guruji · « **Reply #2432 on:** September 20, 2013, 09:06:01 PM »

Hi 00

did you light a bulb with one layer on your setup?

Regarding 2 layered setup so 1st from centre then 2nd layer 1inch gap to 1st layer then 2nd layer to centre.

Did I understood the windings?

Thanks

ctbenergy · « **Reply #2433 on:** September 21, 2013, 10:57:43 AM »

Quote from: magpwr on September 20, 2013, 03:47:10 AM

hi everyone,

I have made an interesting discovery last night on my 3layers with 20 turns on each layer(CW) and 3layers with 20 turns on each layer(CCW)
2.5mm electrical wire was used for the windings.

After connecting both CW & CCW winding in the middle .Base on multimeter Ohm reading it's 0.9Ohm for each winding for both CW & CCW.

This is a interesting part.
Since we all know connecting 2 coils in "series" each with 0.9ohm should give us 0.9Ohm+0.9Ohm =1.8Ohm.

But for CW and CCW winding it's the reverse i'm getting 0.5Ohm since i know my multimeter can't give reading 0.45Ohm.It was simply rounded off to 0.5Ohm instead.

The resistance of the 2 windings in series consisting of CW & CCW became half instead of doubling.It's like cancelling each other out.I wonder if "negative resistance" could be applied here.
"The only way to prove me wrong is to experiment.I know there is no error on my part"

hi magpwr,

I know there is no error on your part.

measured with Agilent U1733C

1 layer bifilar coil with 10 turns, 1.5mm CW (.0338Ohm)
1 layer bifilar coil with 10 turns, 1.5mm CCW (.0338Ohm)

2 coils in "series" (.0180Ohm)

TheCell · « **Reply #2434 on:** September 21, 2013, 12:52:08 PM »

The 12V Lamp is not lit.
However there is a small resonance that has maximum
when the thick coil is moved to the right.
With the osci - probe on the cap there are 1V pp .
The gap btw the 2ferrite coils is 1 inch = 2,5cm.
I don't have a thicker copper tube for the primary
, if this crucial for further improvements.
Please 00 give some advice.

TheCell · « **Reply #2435 on:** September 21, 2013, 12:52:51 PM »

TheCell · « **Reply #2436 on:** September 21, 2013, 12:53:07 PM »

TheCell · « **Reply #2437 on:** September 21, 2013, 12:54:25 PM »

TheCell · « **Reply #2438 on:** September 21, 2013, 12:55:04 PM »

magpwr · « **Reply #2439 on:** September 21, 2013, 03:30:52 PM »

Quote from: ctbenergy on September 21, 2013, 10:57:43 AM

hi magpwr,

I know there is no error on your part.

measured with Agilent U1733C

1 layer bifilar coil with 10 turns, 1.5mm CW (.0338Ohm)
1 layer bifilar coil with 10 turns, 1.5mm CCW (.0338Ohm)

2 coils in "series" (.0180Ohm)

hi ctbenergy,

Thanks for helping in validating this interesting discovery.
Time to re-write those formula in the books.

---------------------------
If you are keen recently i have conducted this experiment to validate base on youtube link found below which show us all how to achieve "resonance amplification" the key to ou devices in the most simple to understand video.
http://www.youtube.com/watch?v=D7QiI8p1gi4

As per video for the CW and CCW winding i used say 6 turns but ensure both winding have similar inductance value (shown in LCR meter).Then i merely use similar high voltage capacitors 500pf (50Kvolts but 1KV..3KV would do) soldered to CCW and CW winding.For the center coil i used 2.2nf 50KV(At least 10KV or 20KV rated).The hot side of hv is going to spark gap.

I am able to achieve resonance amplification similar or better than the one shown in video.The trick is center coil got to be close to coil on the right as seen in video to get real nice resonance amplification.
The left coil is connected to Oscilloscope similar to video.
(Experiment on resonance amplification start to end less than 1 hour including winding and soldering caps after planning in head)
------------------------
Once my entire home renovation is completed 3rd week of Oct.I will resume with couple of experiment in one go.12volt 7.5KV 20mA (25...30KHZ)Neon sign transformer and capacitors is on the way at the moment for this experiment mentioned below.
I can't use modern HV transformer with "diode" for SR193 device.

Base on the link shown below.Please note circuit diagram isn't accurate i have already taken down the connection base on photo&video.

http://user.qzone.qq.com/278885050/blog/1378191565#!app=2&via=QZ.HashRefresh&pos=1378191565

00 · « **Reply #2440 on:** September 21, 2013, 06:14:17 PM »

NickZ · « **Reply #2441 on:** September 21, 2013, 06:29:57 PM »

Yet another guess at the Akula circuit??? As this is NOT what he is showing on his video.
Has there been anyone that actually built his circuit, as he has it? NO?

ctbenergy · « **Reply #2442 on:** September 21, 2013, 09:01:36 PM »

hi magpwr,

1 layer coil with 40 turns (20 turns each), 1.5mm CW/CCW (red coil)
1 layer bifilar coil with 20 turns (10 turns each), 1.5mm CW/CCW (green/yellow coil)

2 coils center connected, red coil output shorted and ferrite core inside the pvc tube

.0001Ohm

Grumage · « **Reply #2443 on:** September 21, 2013, 10:03:01 PM »

Quote from: ctbenergy on September 21, 2013, 09:01:36 PM

hi magpwr,

1 layer coil with 40 turns (20 turns each), 1.5mm CW/CCW (red coil)
1 layer bifilar coil with 20 turns (10 turns each), 1.5mm CW/CCW (green/yellow coil)

2 coils center connected, red coil output shorted and ferrite core inside the pvc tube

.0001Ohm

Dear ctbenergy and magpwr.

Although interesting, I wonder what the method of resistance measurement is employed by your Multimeters? I feel it would be quite different using the old fashioned Wheatstone bridge method!!

I have attached a formula for the calculation of resistance. The answer is based on a 1 Metre length of 2 mm Sq Copper wire.

If a frequency is involved with the measurement then all sorts of spurious values will be seen.

Dear magpwr. I have studied the link you posted earlier, (schematic attached). I don't understand why you have effectively shorted L2 & L3 together??

Cheers Grum.

magpwr · « **Reply #2444 on:** September 22, 2013, 02:15:53 AM »

Quote from: Grumage on September 21, 2013, 10:03:01 PM

Dear ctbenergy and magpwr.

Although interesting, I wonder what the method of resistance measurement is employed by your Multimeters? I feel it would be quite different using the old fashioned Wheatstone bridge method!!

I have attached a formula for the calculation of resistance. The answer is based on a 1 Metre length of 2 mm Sq Copper wire.

If a frequency is involved with the measurement then all sorts of spurious values will be seen.

Dear magpwr. I have studied the link you posted earlier, (schematic attached). I don't understand why you have effectively shorted L2 & L3 together??

Cheers Grum.

hi Grumage,

Glad you dropped by.
I have constructed the SR193 device consisting of CW and CCW for the outer winding as i also wanted to emulate the experiment which was conducted in China using neon sign transformer but i had no proper caps yet.
Stripped copper or aluminum tube not inserted yet for SR193.It's purely taking measurement like resistance and etc at this moment.

My discovery was based on measurement taken after CW and CCW was connected in series at the middle and my reading is taken from 2 points extreme left and right of the CW&CCW windings.
I just noticed the latest photo posted by ctbenergy which is similar to the winding in your schematic where 2 ends shorted together.This might have caused the confusion.I guess he was trying different variation consisting of CW & CCW.

CW & CCW winding in series on a pvc pipe does defy the laws of resistance if you connect multimeter probe either way.

----------------------------
By the way have you seen this interesting experiment in JLN Lab.
GEGENE v1.1-Close loop test on induction heater with pancake coil

http://jnaudin.free.fr/gegene/gegene13en.htm

That experiment was on the verge of success the shortfall was that he was using mere 500watt "grid tie inverter"(This is important) .Base on my calculation he would need inverter rating 750w+500w=1250watt just to break even.2000watt 220volts grid tie inverter is impossible to find in ebay.Unless i combine 2 x 1000w grid tie inverter which isn't great although it would work(space constraint).
I will be conducting this experiment as well since i love to plan many experiments in my head and execute accordingly.
I have just purchased a set of capacitors consisting of100,000uf x 3 40vdc for the above experiment from ebay.I was unable to spot any other 100,000UF caps 40VDC at least which is able to be shipped outside of USA in ebay.

It makes sense why the creator mentioned he is only getting 250watt to go into the inverter.
The fast diode "HFA25PB60" 25Amp used is underrated big time.

Say 15volts input base on example x 25Amp =375watt power would ever reach the inverter.Not forgetting the voltage drop and heat factor in the diode.
Solution-
If he were to use 100Amp for each diode or (25Amp x 4 for each existing diode) with same 15volts .The maximum power to the inverter would be 100Amp x 15volts=1500watt.
At this point it would be a close loop device for sure.

News:

User Menu

Author Topic: Kapanadze Cousin - DALLY FREE ENERGY (Read 11882302 times)

00

Re: Kapanadze Cousin - DALLY FREE ENERGY

Hoppy

Re: Kapanadze Cousin - DALLY FREE ENERGY

guruji

Re: Kapanadze Cousin - DALLY FREE ENERGY

ctbenergy

Re: Kapanadze Cousin - DALLY FREE ENERGY

TheCell

Re: Kapanadze Cousin - DALLY FREE ENERGY

TheCell

Re: Kapanadze Cousin - DALLY FREE ENERGY

TheCell

Re: Kapanadze Cousin - DALLY FREE ENERGY

TheCell

Re: Kapanadze Cousin - DALLY FREE ENERGY

TheCell

Re: Kapanadze Cousin - DALLY FREE ENERGY

magpwr

Re: Kapanadze Cousin - DALLY FREE ENERGY

00

Re: Kapanadze Cousin - DALLY FREE ENERGY

NickZ

Re: Kapanadze Cousin - DALLY FREE ENERGY

ctbenergy

Re: Kapanadze Cousin - DALLY FREE ENERGY

Grumage

Re: Kapanadze Cousin - DALLY FREE ENERGY

magpwr

Re: Kapanadze Cousin - DALLY FREE ENERGY