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Author Topic: Possiblility to increase the "percieved" efficientcy of a cell.  (Read 5670 times)

CrazyEwok

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Possiblility to increase the "percieved" efficientcy of a cell.
« on: April 24, 2009, 04:24:51 AM »
There is one thing that has been bothering me lately and that is the massive amount of wasted power in these cells... These cells being all the cells i have seen. Electrical current is only slowed/diminished by resistance until it hits its sink... now everyone is using seperate lines of power in order to get their cells to work, but what about efficientcy? why cant we use the "tail end" or insert something in front of the power chain for the cell. There is already a lot of amps cycling around the engine bay as it is. can we not "Tap" into one of these lines and have the power for the cell run further down stream... then the only power consumed by the cell will be the resistance of it...
example (please note that this is only an example and not to be taken as the placement as it won't work)
Battery----Cell----fuel pump (i know the fuel pump isn't always running and it doesn't have a high amp line) but you see my point... there maybe some nasty electronics needed but the efficientcy of your cell has now increased by a lot. As some of the unused current from the cell is now being used by the fuel pump. But in order for this to happen the Fuel pump needs to be on constantly...
This idea of "chaining" electrical items is not uncommon and can decrease the amount of drain on the system...
Looking at maybe placing smaller less draining cells on seperate electrical lines.
Just something i have been mulling over
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TheNOP

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #1 on: April 24, 2009, 07:23:45 AM »
resistances in series are voltage dividers.
and with resistances in series, total currents is determine by the resistance sum, each resistance having the same currents passing trough it.

if your cell has a really low resistance, you coulds try hooking it between the alternator and the battery.
but this will cause you a drop in the voltage reaching the battery.
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CrazyEwok

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #2 on: April 24, 2009, 08:14:24 AM »
This is a good spot except for one small problem... if you want the use of amps while your battery is fully charged then the alternator won't produce it... but the idea is there... i don't know of many cars that have a constant drain in the 10-20 amp range for any part of their car (drain on all the time)... But the idea first would need someone to test their cell to see the voltage and amp losses from each side of their cell...
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TheNOP

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #3 on: April 24, 2009, 06:20:36 PM »
Quote from: CrazyEwok on April 24, 2009, 08:14:24 AM
i don't know of many cars that have a constant drain in the 10-20 amp range for any part of their car (drain on all the time)...
think about it again.

to where are all the electric things of a car connected too ?
are your car's head light always on when the car is running ?

but the problem still remain, no matter where you place the cell, resistances in series are voltage dividers.
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CrazyEwok

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #4 on: April 28, 2009, 06:20:01 AM »
ok wel obviously i am not describing my intentions well enough... i will attempt it and display results...
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TheNOP

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #5 on: April 28, 2009, 07:41:06 AM »
Quote from: CrazyEwok on April 28, 2009, 06:20:01 AM
ok wel obviously i am not describing my intentions well enough... i will attempt it and display results...
maybe it is me that is not explaining myself clearly.

take 2 heating elements of 1000 watts each at 240 volts operating voltage

R = Vsquared / W    resistance = voltage * voltage / watts
one element resistance = 240 X 240 / 1000 = 57.6 ohm

2 elements in serie, resistance is 2 times bigger R = 115.2 ohm

I = V / R     current = voltage divide by the resistance
since resistance is 2 times bigger, currents will be 2 times smaller

so, what about the watts ?
W = Vsquered / R
240 * 240 / 115.2 = 500 watts for in series connection
250 watts for each element see above formula :  I = V / R


voltage accross the 2 elements is 240 volts.
so each element only have half the voltage, 120 volts.
if you want to calculate the voltages by yourself to see if i am right :

V = squarerootof(watt * ohm)
or
V = W / I
or
V = I * R

that mean, assuming the lowest resistance in your car(fan, pump,etc...) is the same as your cell,
you will need 2 times the voltage to make them(fan, pump,etc...) work correctly.
if the cell's resistance is higher, you will need an higher voltage then just 2 times.

note that a cell's resistance is not a fixe one.
just like a light bulb, the resistance change when currents is applyed to it.
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CrazyEwok

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #6 on: May 01, 2009, 06:25:09 PM »
i was going to let sleeping dogs lie but i think by leaving it people may think your misunderstandings are correct.... resistance in PARALLEL are voltage dividers and resistance in SERIES are current couplers. In other words the item which allows the least amount of current through will determine the current of the circuit... so in order for my idea to work you simply need to find a circuit on your car that uses the same amount of amps as your cell... might be kind of hard since your using a variable amount of current...
http://en.wikipedia.org/wiki/Series_and_parallel_circuits
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TheNOP

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Re: Possiblility to increase the "percieved" efficientcy of a cell.
« Reply #7 on: May 02, 2009, 03:48:26 AM »
Quote from: CrazyEwok on May 01, 2009, 06:25:09 PM
resistance in PARALLEL are voltage dividers and resistance in SERIES are current couplers. http://en.wikipedia.org/wiki/Series_and_parallel_circuits

 ::)
from the link you posted.
Quote

In a series circuit , the current through each of the components is the same, and the voltage across the components is the sum of the voltages across all the components.
series circuit = voltage divider
the voltage drop at each resistance base on its value.
current is the same for all resistances in the circuit.
 
 
Quote
In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents through all the components.
parallel circuit = current divider.
the current sum is divided through each resistance base on its resistance value.
 
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