Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Over Unity Lightbulb  (Read 46144 times)

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #30 on: November 09, 2010, 11:54:43 PM »
With that kind of impedance match, if your transistors are directly coupled to the transformer, it will be over unity, if you use a bridge H MOSFET to driver the first stage it will be over unity, if you use a push pull configuration that directly drives the first stage, it will be over unity.

If you capacitor couple that circuit, you'll always be burning up that 200 amperes you saw the circuit use when you started it, and it will never be over unity.  You'll have proven that there are better ways to get an output.  When I look, if I don't see the transistor's output, either collector or base, source or drain connected directly to that first primary winding, I'll know you're just screwing with me and everyone else in the room.

spinn_MP

  • Full Member
  • ***
  • Posts: 224
Re: Over Unity Lightbulb
« Reply #31 on: November 10, 2010, 12:01:56 AM »
With that kind of impedance match, if your transistors are directly coupled to the transformer, it will be over unity, if you use a bridge H MOSFET to driver the first stage it will be over unity, if you use a push pull configuration that directly drives the first stage, it will be over unity.
...

AMEN!

Ooops, sorry, what exactly is "overunity"?

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #32 on: November 10, 2010, 12:19:11 AM »
AMEN!

Ooops, sorry, what exactly is "overunity"?

You are so cynical, that I'm skeptical of your personal life.  Unless, you send me a picture of your wife naked, I won't even stop to think that you even have a relationship with her.  If she does have any kid, I can't believe that they're yours, I don't believe you even know what to do with that.  Okay, now, you prove something.

spinn_MP

  • Full Member
  • ***
  • Posts: 224
Re: Over Unity Lightbulb
« Reply #33 on: November 10, 2010, 12:40:33 AM »
You are so cynical, that I'm skeptical of your  life.  Unless, you send me a picture of your wife naked, I won't even stop to think that you even have  with her.  Okay, now, you prove something.
Sicko. I may be cynical, but it's you who definitely needs help.

YOU came here with all that fantastic claims.
It's YOU who need to prove something, remember?

Surely, a few skeptics won't stop you?





elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #34 on: November 10, 2010, 02:52:58 AM »
Sicko. I may be cynical, but it's you who definitely needs help.

YOU came here with all that fantastic claims.
It's YOU who need to prove something, remember?

Surely, a few skeptics won't stop you?

If you had first year College Level Electronics, you would have already had all of that proof in class.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #35 on: November 10, 2010, 03:33:07 AM »
What you are trying to say, is that the 67 Amperes of current doesn't exist between the capacitor and coil.  The operating Voltage is not at 100 volts RMS, and that if that were the primary winding of a transformer, it wouldn't work or be there.

Well, there is the simulation for you, and if you build the circuit, the AC power source, is only using 31.6 mA to keep all of that power there in the tank circuit.

Since, the bulb is only an open secondary by design, it will light up very brightly, with all of that energy.  Why?  Because, the secondary looks like there is no load on it.  The primary only looks like an inductor, and is stuck that way.  Any time another parallel tank circuit reaches it's peak output voltage and current, the next is fired up into resonance, and as a result Q of the next circuit is working together with the Q of the previous.  When it's fired up, the impedance of the parallel tank circuit goes high, and that makes the secondary of the first stage look or seem open due to the second tank circuit reaching resonance peak output values.  There's nothing more untested than your imagination.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #36 on: November 10, 2010, 03:35:51 AM »
In addition to that, I have maintained, that you cannot extract the energy if you short the secondary, or load the secondary of any of the stages, especially the last stage.  I have maintained, that you can extract heat from the transformer cores, or use it to produce light with a bulb designed to operate as an open secondary winding.

At the point that it is over unity, you are extracting all of the energy in a manner that doesn't effect the operation or the condition of this circuit in operation.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #37 on: November 10, 2010, 08:44:30 AM »
My spice simulator isn't showing me true AC readings correctly.  So, the Current Meters and the Voltage Meters are constantly changing values.  At the moment of the snapshot of circuit operation, there is 3,361.8 watts of power between the capacitor and coil, and only 1.68 watts being drawn from the power supply powering it.  That is without any extra stages adding to that effect.

In reality, I applied 100 Peak, which 200 volts peak to peak, or 70.7 volts RMS.  The readout on the Oscilloscope is in RMS.  Which is really 141.4 volts peak, 282.8 peak to peak or 100 volts RMS.

When you do the math and have meters that work properly, there's 100 volts at 100 amperes RMS present between the capacitor and coil, which totals out to 10KW.  There's approximately 740 watts for every horsepower.  Eventually, the core can heat up fast enough to keep a coolant running at a high enough number gallons per minute to keep the core within it's curie temperature range.  At the same time, you'll be able to use the transformer's core like a nuclear reactor's fuel rod, just by keeping it from overheating.  The heat extracted would then travel to a heat exchange unit that utilized the thermoelectric generator cells.  It would look allot like a radiator where one both sides of a flat rectangular pipe lined with thermoelectric cells.  If it were not for the thermoelectric cells it would look just like a car's radiator after that including the fan blowing the heat off of the thermoelectric cells.  Oddly enough, heavy water that's been loaded with minerals has a much higher boiling temperature, and you could use it to move the heat via a fluid out of the ferrite core.  As long as the coolant is non-magnetic, and non-conductive, it will pass with very little resistance to flow and fluid friction shouldn't change during operation.   If the coolant were conductive or ferromagnetic, it would get trapped in the core, and the pump would see the on state of the circuit as a kind of fluid brake. There are so many different configurations of heat exchanges, I would suggest an all ceramic heat exchange unit, and loading every other tube with ferrite slugs, and only passing fluid through every other tube.  A toroid core wouldn't be so easy to work with, but a U core or an E core could be.  The method would have to account for empty space that reduce the permeability of the form due to the volume left to coolant.  Ferrite does tend to get hot.  But, the quantity of ferrite would be much smaller than you'd normally see for that much power due to the use of a coolant other than air and the effecincy of the heat exchange.  That adds up to allot more math than I'm doing for a light bulb.
« Last Edit: November 10, 2010, 09:06:34 AM by elgersmad »

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #38 on: November 10, 2010, 09:12:10 AM »
I highly suggest that if you design the circuit that you use cores in sort of fashion.

1st stage Permeability of 2
2nd stage Permeability of 200
3rd stage Permeability of 20000

Or a similar set of ratios.  Any permeability greater than one will cause the magnetic lines to follow the core and magnetic circuit, so all you are really looking is something greater than one.  If 1.1 were used, then 110, and 11000 would be used.  When you have a series of step up transformers, you need more resistance in the winding of the previous stage's secondary, than there is in the next stage's primary and for the most part, nearly equal inductances.  Making the Q value of every secondary much lower than the Q of primary windings of each stage.  When you build the real circuits, you'll see that helps.  Those core values are ideal for 1:10 step up transformer turn ratios.  If your step up turn ratio is lower, then the difference between cores will be lower.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #39 on: November 11, 2010, 12:17:05 AM »
Anyone know what propaganda is?

Propaganda is this circuit, when you don't need Uranium to do that.  When you tune it, you simply tune it up to the resistance of the filament of the bulb at it's resistance during operation.  When you first turn on a lightbulb, it's a short circuit, and the filiment's resistance is near zero, then as temperature rises, so does the resistance of the filiment.  So, here's a propadanda link:
Written to keep you in the dark, when ferrite would work better.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #40 on: November 11, 2010, 12:30:32 AM »
This is changing the subject, but when I was member of Tesla Pupman, I wrote about this same circuit.  A Ph. D Student then went on to write paper on the subject of multiple resonant circuits.  At that time I was working on circuit harmonics, where the fundimental frequency was on the output, and each an octave up to the input.  So, the input was resonant at 1MHz, the next stage 500KHz, and the last 250KHz in order to utilize larger and larger cores effectively.  It works, and quite well.  Sometimes, it will do some strange things but, the average power doesn't really change at all.  It just allows you to better utilize larger powdered iron cores or ferrite cores.

The real difference is that you'll need to run your simulations for a much longer time frame, and it would require a computer or allot time to calculate average power with some of the circuits.  It tends to maintain a chaotic output.  With real components, you do want to have every other ground 180 degrees out of phase to achieve maximum power.  Ground, shouldn't be starved of free electrons, and hot electrons work better.  The only way to manage that is alternate ground stage per stage and the computer may or may not model that correctly.  An electron can heat up to 10s of thousands of degrees, and never really change the temperature of the material, and if anything recognized as a static potential lost in the conductor.  If you just alternate grounds stage per stage, and keep them 180 degrees out of phase, you'll have hot electrons.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #41 on: November 11, 2010, 09:30:01 AM »
Metglas VS Powdered Iron

If you want a resonant reactor, that will produce more energy than it uses, and last a decade in operation, use metglas.  The thermal properties of metglas allow it to operate at 150C, where most ferrites and iron powders can't even come close.  Powdered Iron, or Ferrite will most likely not last a whole year, whereas metglas will operate at 150C, where powdered iron and ferrite deteroirate rapidly at must 200C.  Ferrite is cheap, and good enough to prove that it will work but, it is far from ideal.  Amorphous metglas is in there for the job and lasting at least a decade in operation if you are extracting heat from the core.  If you're working with lighting, then there is no need to see the cores overheat or change in temperature more than 10 degrees C in operation.  If it does heat up beyond that, then use a larger core.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #42 on: November 11, 2010, 10:17:39 PM »
In this set of equations, do no square Pz2 in the formula.  When I wrote it, it's just a reference to a power equation, and I was remembering that I had to reverse the square by finding the square root.  So, when you work the equation, Pz and Pz2 should be the same and equal.  Do not actually square it.  Rw, does need to be squared before being subtracted.

I appologize for my unwritten mental note being stuck there.  It should look like the second set of equations.

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #43 on: November 11, 2010, 10:52:40 PM »
Now, this equation should work better with the simulator, where T, is actually the time step.  It uses that to calculate angular frequency at the moment and convert it into the equivalent of 2*pi*f.  Which then takes frequency away from the AC source, and calculate it as rapidly as the load might change, expanding the merit of the model.

Stick with the 2*pi*f equation for now.  I keep trying to figure out how to convert di/dt to XL, or frequency.  di/dt, for any given moment is really the quarter frequency of a triangle wave.  Sine, is a different function.  But, the way the simulator steps, the adjustment would or could make it more accurate to a smaller time step.  I don't see this one working because, the time step doesn't directly translate to a frequency.
« Last Edit: November 12, 2010, 03:18:37 AM by elgersmad »

elgersmad

  • Jr. Member
  • **
  • Posts: 72
Re: Over Unity Lightbulb
« Reply #44 on: November 14, 2010, 12:03:15 AM »
I sat down today to plot a graph of the Primary's Inductance in relation to the load on the secondary.  I did find that as I moved the potentiometer from 1 Meg to 0 Ohms, the inductance of the primary windings do change without question.  I also found that at about 70K Ohms, it has maxed out as if the secondary were open, and it didn't matter from there up.  At that point, I realized that LMax for LP_Variable is really required to keep the model accurate.  Where, LMin, is really the Leakage inductance, and LP_Variable, is usually defined as the Mutual Inductance.  So, the whole truth is that in using circuit simulations, the models that are typically used will not produce actual results due to the simple fact that the Primary's inductance will not change.  Most models do not support that event, which is typical and normal for the operaton of any transformer having either a step up or step down turn ratio.  In the circuit simulators, it has become obviouse too me that you cannot just flip the schematic model, but would require two for the same transformer.  One model used when the transformer is used as a step up, and another to be used when the same part is being used as a step down transformer.  LMax, is the stopping point in the inductance calculation based upon the formula/equation I provided.  Until I get a decade box, I won't be able to plot a primary inductance to load resistance plot to tell me if it's linear, which I believe is true, or a curved change.  I must check that.  When you design your spice model equaton, you have to remember to write the equation to stop at LMax, which is or should be a measured value of inductance.  The models should always be based upon measurements.  Then I'll link it to my computer, and preform a frequency sweep, and I wish I had a programmable Resistive Decade Box.