Hi Geotron,

That's a very ingenious triggered spark gap you show in your post #13.  With a non connected grid the voltage on the outer surface will increase when the charge on the rod is neutralized.  It still has the same amount of charge, with voltage related to both the charge and the capacitance.  After the center rod is neutralized the grid becomes a single terminal capacitor, with less capacitance than it had relative to the rod, so the voltage will be higher.

That reverse diode you show by the end of the converter tube is part of Gotoluc's Water SparkPlug circuit.  This is the key to making YOUR circuit work.  The WSP plasma burst occurs between the rods in the tube, and this plasma shorts out the inside of your non connected grid to the rod, leaving only the charge on the outside of the grid.  This provides the higher voltage pulse you need to trigger your spark gap.

Also read this message:

http://www.energeticforum.com/62165-post1674.html

Aaron says:  "the voltage from another source can even go backwards through a diode"

So you'll have to use a cap in the circuit which is charged from a different power supply. 

If the plasma burst between the rods doesn't short out the grid, use a smaller grid.  Or you can add a third electrode from the inside of the grid down towards the plasma spark, like the three point arc switch shown elsewhere as an "Ed Gray Test Circuit".  With the arc switch INSIDE the tube the conversion tube also becomes a "switching element".

If you try this approach I think your circuit will work.  Like I say, it's very ingenious.

Some builders like to use 2N3055 transistors.

Are you planning to put magnets on your armature?

A layout and connection detail for the pulse timer

It seems I'm going to have to perform some additional research
on positive VS negative voltage ... does it have to do with how the
waveform looks?

The reason I've shown the Zener diode appearing after the capacitor
is due to something brought up in a discussion elsewhere on Bedini's
N-Pole Motor design, and how it might be changed to allow collection
of b-EMF.

nievesoliveras first suggested it [link], using the Zener diode to
prevent the capacitor from discharging until it is filled up.

The output of an ignition coil also depends on the input voltage.  You can control this with a rheostat.  On a scope the positive voltage is above the base line, with the negative below it.

My experience with diodes is that when they blow they become conductive in both directions.  You can use two or more in series for a higher voltage.

You can read higher voltages with your meter if you have a few resisters in series and take the reading across only one of them

Only an little help...

@Zarko
your Reply19
With 1 pcs BFY51 you can never drive
1 (or more) 2N3055 in fully satuaration (in fully avaiable current)

--------
@ Geotron
Reply 18,20,23
An combination from (Zener-)Diode with an Condensor in Seies, will NOT WORK.
IF... The Condensor charged up after one cycle.

An find the end of work ....

Pese

Little help for all.

please give attention to the datasheets of semiconductors.

example 2n3055 have an gain af (i belive it) from 20 at 4 Amps.
but at 10 Amps only from 5 !!
So you must drive with 2 Amps in the base of ONE 2n3055 to have
clollector currents of 10 Amps. 

Next you will give attention to the Vce(sat)
Satuartion Voltage between C an E.
If this is 2volts  or 5 . then this Voltage ist lost to become the
fulle supply voltage to the load.


If you take 4 pcs 2N3055 in paralell, this is fine.

The load current will distributed to 4 transistors,
so the bedd collector current (each) is lower
als the gain is higher (because lower IC. and Vce(sat)
is also better. So the LOAD becomes mor power.
BUT you must drive this with 4 time base currents.
so you will see , if the =,8 or 1,0 Amp BFY51 is
strong enough to drive it,  because, the gain of
such transistors (if you work on the end of his
(limits)  is also only 10, with Vce(sat) from most 1,0Volts
---------

diode + condensor.

You will become in head , the circuit from an small
power supply.

Source (DC or AC . added an diode .
on the outut lead of diode. an condensor between out an ground.

So the current will flow an short time - TO CHARGE te Condensor.

Nothing wore will follow, if you not decharge the condensor wih
an short or with an LOAD on it.


I think ALL will understand this now, and find beter ways.

Gustav Pese

www.alt-nrg.de/pppp

englisch and german link collections
(collected myself sine 2002)

---------------

Added:

I know, the selled papers (instructions)to rebuild /reconstruct ED GRAYs device, 4 yers ago.
I understad, that the instruction have no value.

also the type of tube as shown in circuit, is not
avaiable. I dont belived this.

Now : I find in another forum following:

With Gray you have to be careful, because after his engineer Marvin Cole, the real inventor of Grays stuff, dissappeared, they never were able to replicate their earlier succes, because they didn't understand how the HF, HV spark gap oscillator worked. Basically that delivers you the same kind of spikes as Bedini shows, only very high voltage and very high frequency. So, the "LV" rod gives you the oscillating signal, the HV rod is at HV DC. The grid and the "LV" rod are basically a capacitor, which is one of the high pass filter caps. Component 38 is the other. And everything in between the "LV" rod, all the way trough the commutator and such should be considered a shortcut in your analysis. See here: Resonating TF using Bedini circuit


-----

If you "googl-ing" an part of this txt, you find the fully article (if necessary)

So you and other reader, will give a little attention.

GIVE not any money for instruction and plans !!

GP

Thank You Gustav!!

You have certainly explained how to use the transistors!

But I don't believe the article is correct that the LV rod is a capacitor with the grid.  The picture of the Tube in the patent shows the grid around the HV rod ONLY.  And Gray says the arc "electrostatically couples" with the grid.  He doesn't say anything about capacitive coupling.  And he ALWAYS uses the word "couple" to mean "connect".

The reason Hackenberger couldn't replicate the earlier success was because the first thing he did was rewind all the motor coils with bigger wire.  With positive potential only, little wires don't burn out, but give much more power because there's a lot more amp turns.

Fin, that is understand.
Jed the gray, device , the condensor is in other function.
Waht i will explain: Above shematics diodes zener caps in serie is another mind, that i tried to transferre in engisch words and sense.  ONLY AC will transferred (near) correctly over condensors.
(half waves , or unsemetrica half waves -over zeers- ,
will only charge up an cap with DC.

(an zener with (Example) 0,7volt (one side) 7 volt (other direction), will  transferre  about 2 volt ac to the cap,
IF the Input (AC) to this circuit was 10volts.

Possibly its now better to understend. otherwise i will
do small handwritten schematics for you

Gustav