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Author Topic: Some Questions  (Read 4373 times)

Alexioco

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Some Questions
« on: August 05, 2010, 02:48:22 AM »
Hey everyone, I have just a few questions I would like to ask you.

1. Can a 1 pound weight drop 4 times as low, lifting a 4 pound weight 1 times as high, or does it balance?

2. Can a 4 pound weight drop 1 times as low, lifting a 1 pound weight 3 times as high?

Thanks, Alex

AB Hammer

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Re: Some Questions
« Reply #1 on: August 05, 2010, 03:57:03 AM »
Hey everyone, I have just a few questions I would like to ask you.

1. Can a 1 pound weight drop 4 times as low, lifting a 4 pound weight 1 times as high, or does it balance?

2. Can a 4 pound weight drop 1 times as low, lifting a 1 pound weight 3 times as high?

Thanks, Alex

Greetings Alex

1. No, for if it balances it will try to level. If it is far enough out you will have to have stoppers to maintain the positions.

2. even with this one is dealing with a balance or unbalanced effect. An unbalanced effect has to have control stoppers. If it balances it is just that, balanced.

Over all you have to have the platform design to figure it out. For instance the 1lb far enough out for lifting the 4 lbs will keep going until stopped. and the 4lbs lifting the 1lb will keep going until stopped unless it is far enough out to balance. It is either balanced or it is not.

Alan

The Eskimo Quinn

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Re: Some Questions
« Reply #2 on: August 05, 2010, 05:41:26 AM »
1) no, a 1 pound weight can't lift a four pound weight at all much less drop lower (trick question)

2) a 4 pound weight will lift a 1 pound weight 4oo times as high on a pulley as the weight will keep falling, on a see saw until it hits the ground, distance is not related to weight lift unless a lever length is given, on a suspended lever the 4 pound weight will fall centre bottom and the one pound weight will be at the top, however the same thing will occur with a 2 pound weight. this question is missing the lever. if it is simply a power ratio question the answer is 4 to 1 not 3 to 1.

edit:

I think you are trying to find fall v lift equations without leverage

1 pound falling 4 metres will produce the same enegry as 4 pounds falling 1 metre, or the base math says this anyway and at that distance it would be close. however if one considers distance and velocity and terminal speed 400 pound falling 1 metre is less powerful than 10 pounds falling forty metres, speed and velocity increase over greater distance. what is the purpose of the math?

Alexioco

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Re: Some Questions
« Reply #3 on: August 05, 2010, 10:42:49 AM »
Thanks for the answers everyone and the reason i asked is i am about to build a little device which from according to those known principles, a 1 pound weight will drop 1 times down lifting a 4 pound weight 1 times up. In other words, at equal distances. It might sound impossible, and indeed it may be lol, however, I hope it does work, and ill post on here the updates after i have tested it. You can't beat building it and seeing the true results, Thanks again for the answers.

Alex

christo4_99

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Re: Some Questions
« Reply #4 on: September 10, 2010, 06:18:18 AM »
 :o here you are on the wrong track ::) .just because Bessler was stating the impossible...(16 ounces cannot lift 4 pounds in a rotating system,to the same height anyway...and the same height would have to be accomplished continually to achieve P.M.)doesn't mean that is what he was inferring.what he was inferring i.m.o. is the "sorting out" of the problem,the engineering and mechanics of controlling weights,should be your aim...not doing the impossible.assuming that his wheel was in fact a perpetual motion machine he evidently got far beyond the confines of logic into the freedom of function and knowing.getting hung up on concepts that are logically problematic are no way to solve problems.don't you know that if you could see the mechanism of the wheel that you would fully understand it?it is this that we seek...something that we see as impossible becoming a reality.kind like when you pay to see the secret of a magic trick...expect the extraordinary to become ordinary.