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Author Topic: cop > 1  (Read 33938 times)

Offline guruji

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Re: cop > 1
« Reply #30 on: May 12, 2010, 09:24:38 PM »
Hi Ground loop thanks for response. It's a normal bedini circuit but instead of the 1n4001 a 10k resistor and a 20k from base to collector.
This type is a solid state.
Thanks

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Re: cop > 1
« Reply #30 on: May 12, 2010, 09:24:38 PM »

Offline Groundloop

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Re: cop > 1
« Reply #31 on: May 12, 2010, 09:54:08 PM »
@guruji,

It is impossible for me to guess what your circuit looks like.
Can you make a simple drawing in Windows Paint and post it here?

Groundloop.

Offline guruji

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Re: cop > 1
« Reply #32 on: May 12, 2010, 10:31:47 PM »
Here it is

Free Energy | searching for free energy and discussing free energy

Re: cop > 1
« Reply #32 on: May 12, 2010, 10:31:47 PM »
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Offline Groundloop

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Re: cop > 1
« Reply #33 on: May 12, 2010, 10:52:40 PM »
@guruji,

Keep your transistor and output diode(s) and the Neon bulb,
but wire the input to the transistor as shown in the attached drawing.
If the oscillator does not start then reverse the trigger coil. (Coil going to the base.)

Groundloop.

Offline Groundloop

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Re: cop > 1
« Reply #34 on: May 12, 2010, 11:08:04 PM »
First test of my 555 controlled switch:

Input: 6,02 Volt at 0,1896 Amp = 1,141392 Joule
Input was from lab psu and was measured via a 0,25 Ohm 1% non-inductive resistor.
(The resistor is 1% so result may be +/- 1% off for the input.)

Out: 4,13 Volt at 0,187727 Amp = 0,775314 Joule
Output was tested by using a 22 Ohm resistor in parallel with a 10000uF cap.
(The resistor is 5% so result may be +/- 5% off for the output.)

COP = 0,55

At higher input voltage:

Input = 12,03 * 0,440 Amp = 5,293200 Joule
Out   = 9,55 * 0,434 Amp = 4,145568 Joule
COP = 0,78

So the cop is improving with higher input voltage.

Input = 15,03 Volt * 0,5568 Amp = 8,368704 Joule
Out =  12,26 Volt * 0,5572 Amp = 6,832163 Joule
COP = 0,81

Even better.

Input = 18,02 Volt * 0,6916 Amp = 12,462632 Joule
Out = 15,00 Volt * 0,6818 Amp = 10,227272 Joule
COP = 0,82

At 18 volt the transistor started to heat up a little so this is the limit for this
circuit version. The coil remained cold.

Groundloop.
« Last Edit: May 13, 2010, 12:22:08 AM by Groundloop »

Free Energy | searching for free energy and discussing free energy

Re: cop > 1
« Reply #34 on: May 12, 2010, 11:08:04 PM »
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Offline guruji

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Re: cop > 1
« Reply #35 on: May 12, 2010, 11:17:39 PM »
Thanks Groundloop I try this setup.
Thanks

Offline Inquorate

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Re: cop > 1
« Reply #36 on: May 13, 2010, 09:15:13 AM »
can you try it with an air core coil?

Free Energy | searching for free energy and discussing free energy

Re: cop > 1
« Reply #36 on: May 13, 2010, 09:15:13 AM »
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Offline Groundloop

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Re: cop > 1
« Reply #37 on: May 13, 2010, 09:21:51 AM »
@Inquorate,

Air Core Coil:
1000 Turn 0,5mm
Enameled Copper Wire
H=90mm D=55mm d=40mm
12,5 Ohm DC Resistance

Circuit adjusted for best performance at 15 Volt Input:
IN  5,6340 Joule
OUT 3,0192 Joule
COP= 0,53

Circuit adjusted for best performance at 19,97 Volt Input:
IN  10,248604 Joule
OUT 5,63 Joule
COP = 0,55

Groundloop.
« Last Edit: May 13, 2010, 10:55:04 AM by Groundloop »

Offline Inquorate

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Re: cop > 1
« Reply #38 on: May 13, 2010, 10:53:43 AM »
hmm, why did my batteries gain voltage then? They most certainly did not lose voltage, which they would have quickly done at a cop of 0.5

Free Energy | searching for free energy and discussing free energy

Re: cop > 1
« Reply #38 on: May 13, 2010, 10:53:43 AM »
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Offline Groundloop

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Re: cop > 1
« Reply #39 on: May 13, 2010, 10:57:40 AM »
@Inquorate,

The circuit (the ferrite core version) is a very good battery charger.
Maybe the ou you see is because of something happening inside the batteries?

Groundloop.

Offline guruji

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Re: cop > 1
« Reply #40 on: May 13, 2010, 12:54:20 PM »
Hi Groundloop about that circuit is it ok on the upper wire that one is positive and on the other end is negative?
Thanks

Free Energy | searching for free energy and discussing free energy

Re: cop > 1
« Reply #40 on: May 13, 2010, 12:54:20 PM »
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Offline Groundloop

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Re: cop > 1
« Reply #41 on: May 13, 2010, 01:45:39 PM »
@guruji,

The circuit output side is a direct copy of the circuit drawing you posted.

Groundloop.

Offline gyulasun

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Re: cop > 1
« Reply #42 on: May 13, 2010, 03:31:54 PM »
Hi Groundloop about that circuit is it ok on the upper wire that one is positive and on the other end is negative?
Thanks

Probably he means in Reply#33 in the schematics the upper right hand side connection symbol has a green color, just like the negative connection symbol on the lower left side.  And the same wire from the upper right hand connection point goes to the upper left connection point which is clored as red,  his problem is the same piece of wire has differing polarity symbols at its ends....

Guruji,  it is green because of the OUTPUT point of view that is all, ok?

With respect to the INPUT the upper wire from red to green is fully positive, ok?

Gyula

Offline Groundloop

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Re: cop > 1
« Reply #43 on: May 13, 2010, 03:54:47 PM »
@gyulasun,

Yes, you are correct.

Groundloop.

Offline guruji

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Re: cop > 1
« Reply #44 on: May 13, 2010, 05:06:37 PM »
Hi Groundloop and Gyulasun thanks for help. Groundloop that circuit worked fine thanks. How can I hook multicoil with it?;the same as bedini coils in his circuit?.
Thanks again.

 

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