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Author Topic: Same input-greater output...  (Read 10008 times)

Alexioco

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Re: Same input-greater output...
« Reply #15 on: March 26, 2010, 12:37:58 AM »
Quote from: iacob alex on March 24, 2010, 05:01:48 PM
....it's a simple logic :

     -an off-balance lever (equal masses,unequal arms/"h" is their difference ).

      -starting unbalance: long arm on top position.

      -due to unbalance state and gravity "pressure",the mass on long arm plays positive work(torque),the mass on short arm plays negative work (torque).

      -the motion of the lever (fall) is determined by their torque difference.

       -if we are interested (really...!),to collect more power,we need more space (height "H")...or time (v=g*t).

       -if we have more stored power,we can easy to remake the starting unbalance ( mgh),to "pay" friction and to take out some power supply...

          All the best! / Alex

Yes the greater the fall, the greater the energy, but how do you get it make it back to its starting position in order to repeat?

Alex
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iacob alex

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Re: Same input-greater output...
« Reply #16 on: March 26, 2010, 05:49:25 AM »

 .... is the first sequence:gravity fall working as an unbalance amplifier.
 
      The second sequence is an UNBALANCE JUMP...

      The classical and old (15-th century...) simple hinged arm,as a natural suggestion (leg,arm) is the best expression,for the "self"- switch of unbalance from bottom to top position.

      To get a continuous process ,we need to use a part of the  stored power for a second unbalance jump(small input...)...in some manner.

      All together,we must play a mechanical unbalance amplifier(due to gravity),then a mechanical oscillator (due to rotational inertia)...

         All the best! / Alex
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