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Author Topic: Electrostatic mill  (Read 4414 times)

_GonZo_

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Electrostatic mill
« on: March 26, 2006, 11:12:47 PM »
Just yesterday an idea that I found in internet time ago (It was a phisics problem to be solved in a university web page...) went back to my head.

It was a wheel of 5 charges (q) suspenden in a wheel and another charge (Q) fixed out of the wheel
In the problem there was only 5 charges in the wheel (odd number)
Then I thought why not a even number of charges like 6 for example?
The bottom of the wheel is sumerged in a dielectric fluid so there is a diference in the dielectric constans (K and k) of the to areas that wheel travels.

Find attached picture of it to see what I mean.

I am very tired tonigh to make the calculations so if someone can take over...
The equation that gives you the force of atraction or repulsion between 2 charges is:

F = Q x q / K x r2

Being:
F = Force
Q and q = Charges
K = Dielecric constant
r = Distance

If both charges are equal then the wheel is suposse to turn clockwise and if they are oposite then the wheel will turn anti-clockwise.

_GonZo_

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  • Posts: 68
Re: Electrostatic mill
« Reply #1 on: March 26, 2006, 11:54:23 PM »


If both charges are equal then the wheel is suposse to turn clockwise and if they are oposite then the wheel will turn anti-clockwise.


Sorry I forgot to add here that K>k

_GonZo_

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  • Posts: 68
Re: Electrostatic mill
« Reply #2 on: March 29, 2006, 03:17:32 AM »
No Reply to this one?

Advanctech

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  • Posts: 4
Re: Electrostatic mill
« Reply #3 on: March 31, 2006, 11:11:15 PM »
Nice going GonZo! I guess I owed you one so here it is, get your mumy to proof read for you as you said you needed. Question? what does this wheel have to do with OU?

_GonZo_

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  • Posts: 68
Re: Electrostatic mill
« Reply #4 on: April 01, 2006, 12:06:52 AM »
Well if K is diferent than k then the resultan forces of the up side of the wheel are diferent from the down side of the wheel so it may turn? ???

It is still puzeling me out...

I still not done the maths sorry.