Thanks Vidar,
I would start by manually switching and measuring the forces to see that there is
OU potential and then go on to making the valves work automatically and then
with the power available I'd kick the block over the edge and use that power to
switch the valves and hopefully have extra left over to use elsewhere.

In some other work I have done that has OU there has to be about 250-300% to
do the switching so that it will self run. So If I used 1 foot lb to push the block
in place then it would have to have lets say 100% more to do the switching and
100% more to kick the block out and 100% more to kick the next block in place
roughly.

Norman

Looks nice!
Now you need automatic valves that is activated by the buoyant material. Only one problem; How do the buoyant material jump out of the upper reservoir and down in the lower reservoir so it can repeat the cycle?


Vidar

its at the top of the water, because its floating.
so you only have to move it a small amount, then you have available all of the energy of the mass as it falls back to the bottom.
some kind of pulley system could be generating energy with the mass of several floats, and some of that can be used to pick up the floats out of the water.

that can be automated easily.
have a wheel with hooks on it, that picks them up and transfers them to the pulley belt. then at the bottom, you have some sort of mechanism to reload them into the tube.

switches inside the tube can be activated by the floats to open and close the locks.

Energy input takes place 4 times::

1)  E = mgh1
2) E = mgh2
3) E = dgh3 (d is the displacement)
4) E = energy to control valves in the tube (unknown?)
    note that this valve energy will be a constant value based on water pressure and volume of the water system.
    This is completely separated from the energy value of the mass cycle. we change the mass and buoyancy, the valve control energy does not change.

Energy out:   E = mgh`

    Hello everyone, I am from France, I offer my concepte, if you are interested in her by her and chat with me, thank you for the questions                                     http://overunity.com/15847/total-mouvement-autonome-france/msg454472/#new                     

sorry no abituer the forum, how I can remove about thank you

Just an idea:
Let there be plenty of buoyant objects in that tube. They cannot be so buoyant that they cannot submerge after a free fall from the top of the tube or reservoir. Imagine ice cubes.
A guide will guide them back into the tube in the moment they are submerged and still in motion. A torpedo shaped object will be good for reducing water resistance.
Now, let all the buoyant objects in the tube use their combined buoyancy to push one object at the time out of the tube. While that pushed object leaves the tube, it must fall down, submerge, be guided back into the tube. Now there is enough buoyant objects in the tube to push next one out of the tube.
The valves are in theory an effortless operation. At least one cannot take the energy they require to open and close into consideration. This energy requirement has nothing to do with the buoyant system.
We need only two valves because the tube must maintain the water column all the time.


I have not made my calculus on this one, but nature usually don't give a shit about what we believe or conclude. So what's left is to do the practical experiment.


This far, I am just confused.

EDIT: I did't notice the video link above when I posted this. It appears to be the same idea... 

Vidar

I have had a hard working week, very tired, but I got it now; When the sphere enter the water at the bottom, water level rise at the bottom.
When the sphere exit the water on top, water level descent at the top.
As the cycle continue, the water level will finally equalize...


So, no, it will not be OU.

ask help to the admin of this forum

  ok thank you Tagor