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Author Topic: Mostly Permanent Magnet Motor with minimal Input Power  (Read 252395 times)

TinselKoala

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #150 on: August 12, 2014, 04:50:47 AM »
NO! You must not write
A/h
for Amp-hours!

The slash is used, in English, to indicate division. Like 1 Watt = 1 Joule/second. It can even be assigned a word: "per", as in km/hr, kilometers per hour.  It is the number of kilometers divided by the number of hours. The English (Latin) word "per" indicates a division operation.

One amp-hour is not one amp per hour! So you cannot write A/h for amp-hour.

The - sign is also ambiguous, usually indicating subtraction. But since the quantity "amps - hours" is nonphysical and nonsensical we know that the dash does not indicate subtraction in the "amp-hour" expression.

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #151 on: August 12, 2014, 05:28:39 AM »
Thanks TK for making it clear!... even though it took a year

Better late then never ;)

Luc

tinman

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #152 on: August 12, 2014, 12:42:53 PM »

One amp-hour is not one amp per hour! So you cannot write A/h for amp-hour.

???
One amp hour is  a steady current of one ampere flowing for one hour,-is it not?

TinselKoala

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #153 on: August 12, 2014, 01:48:35 PM »
???
One amp hour is  a steady current of one ampere flowing for one hour,-is it not?
Yes, but that is not a "rate". It is a quantity. The Ampere is a rate, so if you go at a rate for a time, you have what? A quantity. Go 1 km per hour for one hour. How far have you gone? One km. 1 km/hr x 1 hr = 1 km.
  Just as "per" denotes division, "for" denotes multiplication.

Consider what we mean by "three amps per hour".  This is written 3A/H. How I got that number is I started with zero amps and I turned my variac up slowly and at the end of an hour I was up to three amps, and at the end of two hours I was up to six amps, and at the end of three hours I was up to nine amps. I turned the current up at a RATE of 3 A/H, or three amps per hour.  If you want to know my current at, say, 90 minutes, you multiply the rate by the time: 3 a/h x 1.5 h = 4.5 A. This use is in effect the "rate of change of the rate" or the first derivative, the slope, of the graph of the current vs. time.

One Amp-Hour is a _quantity_.  To get there mathematically you _multiply_ the number of amps by the number of hours. So if I have a system that produces one amp-hour at 12 volts and I run it for one hour, I have sent (one amp-hour) x (12 volts) or 12 Watt-hours past my measuring point, for that hour. A quantity, distributed over the hour time. And for that one hour, then, I am dissipating the energy at a _rate_ of 12 Watt-hours per hour.  12 W-h / 1 h = 12 Watts... a _rate_, the power dissipation, the rate of energy dissipation. Power in Watts = Joules of energy per second -- a rate.

Now are we completely confused?

tinman

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #154 on: August 12, 2014, 02:35:30 PM »



Now are we completely confused?
No-all clear

1A/h=raising the current flow to 1 amp over 1 hour.
1Ah=is a stedy current flow of 1 amp for 1 hour.

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #155 on: August 12, 2014, 05:36:22 PM »
To everyone,

since this topic has been re-opened I may as well share a better performing version of my Mostly Magnet Motor which I compared its pulling force to an off the shelf speaker.

So here is the link to the unlisted video if anyone is interested to see it.

https://www.youtube.com/watch?v=qa1dO8qWPQU

Luc

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #156 on: August 12, 2014, 05:55:22 PM »
Here is the second part of the demo video with the Signal Generator attached to it.

https://www.youtube.com/watch?v=oDXq8wkhV2c

Luc

woopy

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #157 on: August 13, 2014, 12:04:47 AM »
Here is the second part of the demo video with the Signal Generator attached to it.

https://www.youtube.com/watch?v=oDXq8wkhV2c

Luc

Hi Luc

thank's for that

i made a replication and it works very well

it is amazing that as the magnetic fields are totally opposing, the coil should behave as per along a single steel non magnetic bar, i mean very weakly, but it seems not to be the case , the coil is very powerfull.
 
Youp i will follow your work as usual

thank's very much for sharing and bravo !!

Laurent

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #158 on: August 13, 2014, 01:09:12 AM »
Bonjour Laurent,

thank you for posting your replication and results.

What is happening in this design is once the coil is energized it produces a north and south in the core (steel laminations). Now if all 4 magnets are all facing north in the center core the energized coils south side will attract to the PM north and the north side of the coil will repel from the other PM north side. So here we have both poles of the coil performing work and zero cogging from the PM because they don't leave the cores.
However, it doesn't stop there. Some may not know this but half way through the thickness of a coils windings the polarities start to flip. Meaning, if you put core material on the outside of a coil windings and energize the coil the poles in the cores will be opposite from the coils center core. So here we are also taking advantage of the coils opposite outside magnetic field to do as much work as the coils inner magnetic field.
This basically doubles the work output.

Here is an older video that demonstrates the benefits

Link to video: https://www.youtube.com/watch?v=-eTQ49RcFKM


Your test setup would be much more powerful if your coil winding would fill the bobbin so that the windings would be as close to the outside cores as possible. Also, if you add 4 more magnets and 2 more core laminations to cover most of the outside area like in the video I posted in this reply it will do even more work.

The more the permanent magnet force the more the pulling or pushing force is without any increase in power to the coil.
Surface area is important, so again the more surface area the more the force it has.

Glad you enjoyed this old idea

Luc

Khwartz

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #159 on: August 13, 2014, 06:19:48 AM »
Yes, but that is not a "rate". It is a quantity. The Ampere is a rate, so if you go at a rate for a time, you have what? A quantity. Go 1 km per hour for one hour. How far have you gone? One km. 1 km/hr x 1 hr = 1 km.
  Just as "per" denotes division, "for" denotes multiplication.

Consider what we mean by "three amps per hour".  This is written 3A/H. How I got that number is I started with zero amps and I turned my variac up slowly and at the end of an hour I was up to three amps, and at the end of two hours I was up to six amps, and at the end of three hours I was up to nine amps. I turned the current up at a RATE of 3 A/H, or three amps per hour.  If you want to know my current at, say, 90 minutes, you multiply the rate by the time: 3 a/h x 1.5 h = 4.5 A. This use is in effect the "rate of change of the rate" or the first derivative, the slope, of the graph of the current vs. time.

One Amp-Hour is a _quantity_.  To get there mathematically you _multiply_ the number of amps by the number of hours. So if I have a system that produces one amp-hour at 12 volts and I run it for one hour, I have sent (one amp-hour) x (12 volts) or 12 Watt-hours past my measuring point, for that hour. A quantity, distributed over the hour time. And for that one hour, then, I am dissipating the energy at a _rate_ of 12 Watt-hours per hour.  12 W-h / 1 h = 12 Watts... a _rate_, the power dissipation, the rate of energy dissipation. Power in Watts = Joules of energy per second -- a rate.

Now are we completely confused?
So we agree :) just Luc was speaking of the quantity of electrical charges provided by the battery then I only correct him on this point; great you went further :)

Q : quantity of electrical charges in Coulombs (C)

T: duration in second or hour

I: flow of current in Amps (A)

E: voltage in Volts (V)

W: energy in Joules (J)

P: power in Watts (W)

Amps × duration = Q (not//// energy) (Coulombs or Ah, depending of the time unit).

But as the voltage is near steady 12 V, it makes an equivalence for energy consumption as per:

E × Q = W

while A/h makes an indirect equivalence with power by:

E × (I/T) = P

BUT! "A/h" would mean an acceleration of flow of charges, as mathematical dimensions:

I / T = (Q / T) / T = Q / T^2,

which has usually no use for a battery.

Cheers!  ;)

Khwartz

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #160 on: August 13, 2014, 06:21:27 AM »
Hi Luc! :) How is going your reactive genertor ? :)

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #161 on: August 13, 2014, 07:14:03 AM »
Hi Luc! :) How is going your reactive genertor ? :)

It ended when TinMan replicated it to see if the power was coming from the exciter field of the alternator. Looks like I was tapping into it without affecting the prime mover. So it was not really a free gain, more like a transfer of energy.

Luc

Khwartz

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #162 on: August 13, 2014, 08:08:54 AM »
Understand!  VAR are all about pure movement of energy stored ;) But could be it is not "all the scene" as the present academic models of electricity look not enbounding all the stuff. Didi you read Eric P. Dollards writing?

Anyway, regarding your mostly permanent magnets motor, did you make progress compaire to you nice vid where you started from 0.3 N to 25 N? (If my calculations are correct).

BTW, please remember Luc that  P = W T^-1 = (M L^2 T^-2)T^-1 = (M L T^-2)  (L T^-1) = F V, "F" for "force" and "V" for "velocity"? Then measurements of the pulling force is very good to see your progress but not to get the efficiency (would be overunity or not). In your vid you did not compare power against power, right? Only force against power, as we discussed already last year of I remember well ;)

gotoluc

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #163 on: August 13, 2014, 05:01:58 PM »
Hi Khwartz,

I have next to no schooling. The things I can do are mostly self taught. The experiments I do are my way of trying to learn more in hopes that one day I'll know enough to build a device to be energy independent.

I don't know why but learning all those math equations does not interest me.

I've always been hands on and not into reading patents and theorizing about this or that.

If I find something interesting from the stuff I build that's not commonly done, I share it and hopefully the more knowledgeable ones will find a use for it, suggest different tests or explain in a laymen way why it's not useful.
Anything thrown at me from an academic level is like water on a ducks back.

Luc

woopy

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Re: Mostly Permanent Magnet Motor with minimal Input Power
« Reply #164 on: August 13, 2014, 05:05:01 PM »
Hi Luc

thank's for your very clear explanation.

I tried to use the setup as an alternator, and connected 2 opposite LED, so they light alternatively, and it works very well. I am amazed how bright the LED are shining with very slow movement of the coil.

And yes , i think it can be very much improved by adding magnets and cores all arround the coil.

Thank's for sharing

Laurent