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Author Topic: DIODES! Newman does not use his "special commutator" anymore  (Read 14095 times)

Offline kmarinas86

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DIODES! Newman does not use his "special commutator" anymore
« on: November 09, 2009, 10:19:12 PM »
Diodes are used to separate the current surge of the back-spike away from the coil. This is essentially a current divider, and it is NOT a voltage divider. As a result, for a given current resulting from the back-spike, most of the power goes through the diodes, but the same voltage passes through both the diode pack and the circuit it connects across. The power of the back-spike comes from the energy of charges that got trapped at the end of a circuit whenever the gap was created. It is therefore depleted from that storage of energy. That is NOT overunity.

Since the energy of the back-spike is divided across the circuits, there is less of that spike's energy in the coil relative to the voltage it applies to it. Because voltage is electrical potential energy per charge, the amount of charge that corresponds to that applied voltage is reduced. This reduces the amount of energy dissipated by the collected charge which goes into the coil, allowing the atoms to align more effectively.

It is clear from the operation of capacitors that a displacement current creates a magnetic field with the same polarity as current going the same direction.

When displacement current forms, a curl of the B-field is generated to which the magnetic moments of copper (a diamagnetic material) attempts to cancels out. Because such a B-field can be made of such a magnitude to domineer over the magnetic dipole moments among neighboring copper atoms, the subatomic particles of those copper atoms will attempt to align their magnetic moment dipole axes in helical configurations in contrast to their typical random configurations. The change of configuration actually consumes potential energy by the formation of "paratoroidic (magnetic) moments" of copper (an as-yet-unconfirmed paramagnetic analogue of the experimentally validated "ferrotordic (magnetic) moment").

See timeline on verification of ferrotorodicity: http://www.google.com/search?hl=en&client=firefox-a&rls=org.mozilla%3Aen-US%3Aofficial&hs=Hek&tbo=1&tbs=tl%3A1&q=ferrotoroidicity&aq=f&oq=&aqi=

By keeping the impedance of the back-spike larger (i.e. voltage higher and its current lower) than in the initial pulse, copper's reaction to the voltage back-spike can provide the same polarity of magnetic field as current going forwards. The back-voltage does dissipate after a while, and you are right when you say that, "This oscillation seems related to the length of the conductor and maybe other factors like self-inductance, self capacitance, insulation, wire diameter, etc."

So where does the energy come from to restore the potential energy lost via alignment of the paratoroidic (magnetic) moments? Certain frequencies of electromagnetic radiation get absorbed by the (PARAtoroidic) arrangements of magnetic moments in the copper atoms, in effect, restoring their potential energy. When some of the moments fall out of alignment, others will follow suit.

I do not see this a violation of any laws of thermodynamics. The 2nd law in particular says nothing about any "impossibility" of zones of decreasing entropy, nor is it disproven by the existence of self-organizing structures. Don't get me started on the 1st law, that is simply fact because we can always define a potential energy in reference to new energies discovered. And the 3rd law is about absolute zero....

The generation of frost in some failed operations of the Steven Mark TPU device can be explained by generation of excess magnetic fields. If you remember the fact that temperature is dependent on motion, it is clear that atoms locked in position as a result of mutual magnetic inductance have a lower temperature; this is obviously not the same as keeping a macroscopic object still! At some point, this temperature change can spur surrounding photons to make up the difference, restoring the atoms into their natural, random configuration.

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Offline jadaro2600

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #1 on: November 09, 2009, 11:07:41 PM »
Very interesting, but what does this have to do with Newman?

Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #2 on: November 10, 2009, 01:20:15 AM »
Very interesting, but what does this have to do with Newman?

He uses diodes in his device. He uses that to capture the current of the back-emf. This is done to prevent the coils from burning at higher-voltage switching. The voltage of the back-spike is still applied to the coil. That voltage aligns the atoms. The second half of the first post in this thread shows how that voltage aligns the atoms of that coil.

In the video below, you can see a demonstration made by Joseph Newman. At some portions of the video, he claims that he captured the back-spike and that he had built his own diode pack to achieve it.

http://video.google.com/videoplay?docid=-6157958993884349118&ei=EbD4SuONOZ3KqQKSldGTCg&q=joseph+newman+site%3Avideo.google.com&view=2&dur=3#

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #2 on: November 10, 2009, 01:20:15 AM »
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Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #3 on: November 20, 2009, 01:34:37 AM »
When I connected the diodes in parallel, I was surprised by the fact that that their resistance did not reduce to the degree I had expected. There are two possibilities for this:

1) The tips of the diodes were not connected to allow for current movement.
2) Some other, yet unknown, reason.

This reduced the degree by which the current was able to diverge into the diode pack. I did not experience significant changes in rpm. I got my hopes up for a while though, then realized that this was simply due to me altering the commutator. There was no drop in back-spikes that couldn't be explained by the commutator.

In one part of Newman's video he talks a little about using diodes to capture the back emf:

http://video.google.com/videoplay?docid=-6157958993884349118

He does not make it clear as to whether it is connected with positive bias or negative bias. So it is possible that he inserts it using positive bias.

My plan now is to attach ONE diode forward-biased at the front the coil. The resistance of the diode will prevent forward current going to high. It will also block the flyback current from reaching the battery. However, it will cause charge to collect on the end-side of the diode, just like a capacitor. This will slow down charges going backward while not inhibiting charges going forward. This helps to maintain the forward current as well as the magnetic field. At the same time, any attempt to collapse the magnetic field would have to send the energy forward rather than backwards. However, to reach a magnetic field of zero, the charges would have to obtain zero velocity. This puts pressure on the electrons which increases their voltage. When the counter-emf no longer exists, the energy recovered by the electrons is dispensed at a smaller interval, and the process repeats itself.

The key is that with this process, electrons in the coil lose more energy in a given cycle then the would otherwise have been. This increases the potential difference between the electrons in the battery and those within coil, and this maintains the voltage of the battery better. This means more speed for the motor.
« Last Edit: November 20, 2009, 06:06:24 AM by kmarinas86 »

Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #4 on: November 21, 2009, 06:38:17 AM »
It seems I keep on changing my hypotheses!

 :P

Now I know that the diodes I am using do barely anything to change the operation of the system.

Also, know I am discovering that the commutator itself is of far greater importance. I am using smoother aluminum contacts this time.

When I have the motor operating at 120 rpm, I notice that the temperature of the wind tends to vary rapidly. Even when the thrust of the wind does not change, I can feel the temperature of the wind drop when meter shows negative spikes. Many of these negative spikes show up as negative 300 milliamps on the meter. Yet I am using 230 volts on 930 ohms. The downside is that the spikes can half as easily jump to postive 300 milliamps. The difference of temperature is unmistakable. I believe I am reaching the point where I am actually physically observing (feeling) a temperature drop below ambient.

Free Energy | searching for free energy and discussing free energy

Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #4 on: November 21, 2009, 06:38:17 AM »
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Offline jadaro2600

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #5 on: November 21, 2009, 09:32:01 PM »
You know what's strange about this video is that he claims that it would be nearly impossible to turn the rotor by hand but that the voltage turns it...  when he goes to start the machine, he turns the end rotor (commutator) with his hand.

Offline seekingknowledge

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #6 on: November 30, 2009, 10:18:03 AM »
You know what's strange about this video is that he claims that it would be nearly impossible to turn the rotor by hand but that the voltage turns it...  when he goes to start the machine, he turns the end rotor (commutator) with his hand.
yes i noticed that also but you mustconsider that it would be much easier to turn at the end of the commutator because obviously there is more leverage at that point.

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #6 on: November 30, 2009, 10:18:03 AM »
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Offline jadaro2600

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #7 on: December 01, 2009, 02:45:08 AM »
yes i noticed that also but you mustconsider that it would be much easier to turn at the end of the commutator because obviously there is more leverage at that point.

Not sure I follow you - He clearly states that it would be impossible to turn by had - that it weighed some 1600 pounds.

The only explanation is that he turned it on and then turned it by hand to get it started - which I still find dubious.  In this instance, it would be him acting like a capacitor to on an AC motor - you know, the kinds they use to keep the surge from frying the motor at outset.

Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #8 on: December 01, 2009, 03:01:38 PM »
Not sure I follow you - He clearly states that it would be impossible to turn by had - that it weighed some 1600 pounds.

The only explanation is that he turned it on and then turned it by hand to get it started - which I still find dubious.  In this instance, it would be him acting like a capacitor to on an AC motor - you know, the kinds they use to keep the surge from frying the motor at outset.

People.

It's just the way he talks.

Free Energy | searching for free energy and discussing free energy

Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #8 on: December 01, 2009, 03:01:38 PM »
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Offline jadaro2600

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #9 on: December 02, 2009, 06:47:49 AM »
He also claims that hundred of fortune 500 companies bought his book..etc.

Honestly find the guy interesting, I wish his books weren't selling for 1200usd on ebay, I might buy one.  Too bad all his master prints were destroyed in a fire.

Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #10 on: December 02, 2009, 09:00:46 AM »
He also claims that hundred of fortune 500 companies bought his book..etc.

Honestly find the guy interesting, I wish his books weren't selling for 1200usd on ebay, I might buy one.  Too bad all his master prints were destroyed in a fire.

Or don't buy it.

Adobe PDF file:

http://www.megaupload.com/?d=5MF8ZFAJ

Free Energy | searching for free energy and discussing free energy

Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #10 on: December 02, 2009, 09:00:46 AM »
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Offline jadaro2600

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #11 on: December 03, 2009, 02:37:32 AM »
Or don't buy it.

Adobe PDF file:

http://www.megaupload.com/?d=5MF8ZFAJ

Thank you for that, I think some of his other versions may have more diverse content.

Offline seekingknowledge

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #12 on: December 03, 2009, 10:09:36 AM »
People.

It's just the way he talks.

Its funny you should say that actually, since reading this thread the other day ive been thinking again about an idea ive had but havnt tried yet of how newman has "transformed lightening to torque" i think it is easier then one may think, i have considered every idea possible on how he may of achieved this and like you said it is "just the way he talks", im a 100% with you on that one, just like when he talks and says he can turn his 7500lb machine "with a 9 volt transistor battery" well we all know he doesn’t mean using just one 9 volt battery he in actual fact uses several in series but he says he can do it "with a 9volt transistor battery" cos that is just the way he talks.

So how has he "transformed lightening to torque"?  mmmmm well lets just talk for a moment about his motor with the correct switching time that recharges its battery at an efficient rate, now forgetting about the fact that the spikes can kill the battery lets say that the back spikes are recovering 95% of the input energy back into the battery then if we wanted the battery to stay fully charged none stop we would only need to put in (from an external source) the 5% that is lost out of the system.
   
So i believe he has just replaced the battery with a capacitor which he openly shows in his later videos and uses an external source to keep the capacitor fully charged, that external source could be the solar panels or the grid, now lets just talk about how he uses the grid in some videos, well he has the motor connected to the capacitor and the capacitor connected to the grid (well actually through a transformer before the grid but forget that for a second) and instead of measuring input power between the capacitor and the motor he measures input power between the grid and the capacitor and so there for the volt/amp meters only show what is comming out of the grid into the capacitor not what is going from the capacitor into the motor.

So you see if we regard the grid as “the source” and the capacitor as “apart of the motor” and measure power from the grid into the motor then yes we can see a mechanical over unity of more than 100% but if we measure power between the capacitor and  the motor we will see less than 100% efficiency , there is one video where Joe unplugs  the motor from the grid and says  “look at how much power this thing makes all the time while its running” and even unplugged from the grid it continues to pump water for some time that is because it has charge in the capacitor and is putting charge into the capacitor while it continues to run, which seems like magic but however you unplug the motor from the capacitor then bang that motor will stop dead just like any other.

Now im a believer in Joe and im not trying to scream fake at all im actually saying what he is saying, somewhere on his website it is stated while a conversion efficiency  can never be more then a 100% a production efficiently can exceed 100% and more, well I think if you measure power input between the capacitor and the motor then you will see the conversion efficiency but if you measure power between the grid and the capacitor then you will see the production efficiency , the production efficiency is the one that counts.

I would like to elaborate more Kmarinas86 (and everyone else) but im hungry and tied , ive pretty much covered my theory on how “lightening is converted to torque” ( just the way he talks remember) if you need me to explain myself further I can plus an idea I have to raise the amps in the spikes, using diodes, anyway another time.

Offline JustAnElectrician

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #13 on: December 28, 2009, 02:06:02 AM »
Very cool, I'm sure I can get some good info out of this, it is similar to my so-called
Solid State non-rotary Newman device  ;D


Offline kmarinas86

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Re: DIODES! Newman does not use his "special commutator" anymore
« Reply #14 on: December 31, 2009, 02:57:18 AM »
Right now, I feel fortunate of the fact that I bought a multimeter that comes with a temperature probe.

And to think I was going to buy a seperate temperature probe!

I will take temperature measurements inside of the coil itself. Doing this will help me determine whether or not I am getting energy out of heat.

Quote from: kmarinas86
http://www.youtube.com/user/kmarinas86 December 30, 2009

THE ENERGY MACHINE OF JOSEPH NEWMAN

Various names for the device, in order of decreasing use:
1) Newman Motor
2) Newman Machine
3) Newman Generator
4) Newman Engine

Various parts necessary in a Newman motor:
1) Electrical energy source
2) Inductor
3) Rotor magnet

Various characteristics required in each part to obtain the type of operation specific to Newman motors:
1) Storage of electrical energy
2) High inductance coil
3) Magnetic

Various names for the energy source used, in order of decreasing credibility, importance, relevance, etc.
1) Heat (real)
2) Cold Current (estoeric)
3) Cold Electricity (poorly-defined umbrella term)
4) Vacuum Energy (misuse of mainstream terminology)
5) Zero-Point Energy (ditto)

Various forms of magnetism used:
1) Electromagnetism
2) Diamagnetism
3) Ferromagnetism

Role of the forms of magnetism:
1) Pass current through the coil
2) Extract heat at ambient
3) Convert potential to kinetic energy

Endothermic operation is the goal.

The Newman...

...shares the same source of energy as a Sterling engine

...can run off ambient heat provided the temperature of atoms drops below ambient temperature as a result of alignment

...has three stages of operation (excitation, alignment of magnetic moments at the scale of infrared wavelength - i.e. groups of atoms, mechanical output)

STAGE 1:

Excitation of the coils is achieved simply by turning on an electromagnet.

STAGE 2:

FACT: The energy of photons is acquired by the machine as potential energy.

QUESTION: Does the energy of the absorbed photons play a role?

YES: To restore a diamagnetic potential that is hardly ever used in the first place.

QUESTION: Is the diamagnetic potential rare? I've never heard of it.

NO: It is ubiquitous, but this magnetic potential field is almost never observed outside a diamagnetic material. The reason is that consumption of this potential energy is necessary to observe its effects macroscopically. Noticeable consumption is prevented by the presence of heat, the general exception being cases where there exists a very strong magnetic field. For example:

1) A giant external magnetic field to straighten the otherwise wandering magnetic potential of diamagnetic materials into straight lines. (A great example is the levitating frog experiment.)

2) A superconducting magnet.

The former case does not rely on removing heat. Rather it relies on strength of a magnetic field. A superconducting magnet does rely on removing heat to the extent necessary for superconductivity.

A THIRD WAY

Diamagnetism is most easily observed in the presence of very strong magnetic fields. However, it is hard to achieve the effect when there is visible distance from the material.

To achieve this within a material, all we need is a spark gap. This makes it more feasible to generate a strong magnetic response through the diamagnetic properties of the conductor.

In the Newman, a BEMF spike is used to produce a curl of the magnetic field around the wire. The atoms in the conductor's respond by aligning in opposite polarity to the back-EMF (Lenz's law). All atoms have a residual magnetic polarity. Theoretically, atoms lacking a crystalline structure (e.g. copper) are generally more responsive to back-EMF.

QUESTION: Can the net magnetic field curling around the wire be opposite the polarity of the magnetic field produced by the BEMF?

YES: When potential energy extracted from "atom alignment" exceeds the potential energy of the magnetic field of the backspike.

STAGE 3:

To allow utilization of the diamagnetic component of the magnetic potential energy, circular alignment of the magnetic moments of the diamagnetic material must be maintained throughout the time of extraction. This can be done through a combination of high magnetic circuit inductance and low electron flow density.

The extraction itself can be done using a permanent magnet as the rotor in the proximity of the electromagnet.

The output is eventually remitted as heat through inevitable friction.

JWN's machine:

http://video.google.com/vid...

http://video.google.com/vid...

IF the anomalous power (7.5HP minus 17 watts) comes from copper (200 lbs), this is equivalent to (7.5 horsepower - 17 watts) / (200 pounds) = 0.0374HP/lb!!! 27.88 watts per pound.

One pound of recycled copper sells for $1.2819, but copper in large motors can be cheap as "20 - 40 cents per lb". Each lb of Cu would collect 10 KwH of light, in 15 DAYS.

The type of electronic commutation seen in the Steven Mark TPU could easily bring this factor up several fold. However, less power density is necessary for preventing unstable temperature rise. There must be concessions....

 

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