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Mechanical free energy devices => mechanic => Topic started by: Goat on June 30, 2009, 11:43:28 PM
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Hi All;
I came across this stupid simple One-wire bulb circuit by Brian Prater that was on page 59 of the RE-OU-v6_1.pdf document on RV setups and was wondering...
Has anyone ever tried this?
Can anyone try it if they have a 3 phase motor and a 60W bulb?
Here's the details :
3.6 One-wire bulb - Brian Prater (Cavetronics Labs R&D)
The one wire bulb works on the concept of magnetic reconnection.
Magnetic reconnection is the process whereby magnetic field lines from different magnetic domains are spliced
to one another, changing the overall topology of a magnetic field. It is a violation of an approximate
conservation law in plasma physics, and can concentrate mechanical or magnetic energy in both space and time.
Solar flares, the largest explosions in the solar system, are caused by reconnection of large systems of magnetic
flux on the Sun, releasing in minutes energy that is stored in the magnetic field over a period of weeks to years.
Magnetic reconnection in Earth's magnetosphere is responsible for the aurora, and it is important to the science
of controlled nuclear fusion because it is one mechanism preventing magnetic confinement of the fusion fuel.
In an electrically conductive fluid or plasma, magnetic field lines are grouped into 'domains' - bundles of field
lines that connect from a particular place to another particular place, and that are topologically distinct from
other field lines nearby. This topology is approximately preserved even when the magnetic field itself is strongly
distorted by the presence of variable currents or motion of magnetic sources, because effects that might
otherwise change the magnetic topology instead induce eddy currents in the plasma; the eddy currents have the
effect of canceling out the topological change.
See http://farside.ph.utexas.edu/teaching/em/lectures/node84.html for an explanation on magnetic energy.
The diagram to below gives an overview of concept and
wiring.
The system uses 64 W from the line input, running the motor
and light, the light being 58 W. The motor running at 1725
RPM without a light uses 58 W, where the light uses the 58 W
that the motor has past off to the light bulb, matching the
current. So we get 116W out version 64W in, as such there is
about 52 W free.
The input is about 118 VAC single phase. At that voltage the
light will use about 58 W (same as the motor). Now when
looking at the voltage coming off the motor without a light as a
load, it reads 92 V no load. Now when the motor output is
loaded, it rises to 109 V and the light is lit up. So a rise of
about 17 V.on the output of the motor.
Specific:
63.67 W-in - 42.45 W-out = 21.22 x 2 = 42.45
42.45 - 63.67 = -21.22 (+- 42.45 bandwidth)
106.12 W-out (63.67+42.45) - 42.45 = 63.67 W-used
= 106.12 total W-out / 63.675 total W-in = 1.667:1 gain
This motor is started with a smaller motor, as there are currently no run or start caps on the system.
The remarkable fact is that the light once lit, stays lit after you switch open one of its input lines, as to be lit by
"one wire", costing just 5.8W for the 58W of energy used (not to account the other 58W running the motor). So
the light burns on 58 watts one wire, and in fact uses the same amount of energy, switched on or off… "one wire
or both wires" cost the same energy. (the light resistance is around 174-280 Ohms while lit). Node-anti-node,
wherever you are at it you get it with one wire.
You can run some DC caps (e.g. 8900μF 250VDC) off where the light is hooked up, through a FWBR. You can
then get 89 V at 0.5 A for free while running the light and motor.
Total input = 64 W; total output = 158+ W; 158/64= 2.46875 gain
Looks pretty simple, wish I had a 3 phase motor to try it on.
Regards,
Paul
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@ All
The suspense is killing me, I see 30+ views on the diagram which is "stupid simple" but I just don't have a 3 phase motor.
Hello, anyone out there a 3 phase motor and a 60W bulb?
Regards,
Paul
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@ All
If we can get a 3ph motor to run and light a 60W bulb and get 2.46875 gain wouldn't that be a good thing?
Regards,
Paul
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@ All
Did anyone notice that the light bulb can be light (pronounced lit in english) with only 1 wire?
If breaking the circuit at the bottom end of the circuit (see above circuit) continues to light the bulb then it is truly a "One-wire bulb", how then is the light bulb being light (lit) if the circuit isn't complete?
Please replicate this if you have the means and let us know.
Regards,
Paul
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@ All
Well after 50+ views on the schematic either nobody has a spare 3 phase motor and a 60 Watt bulb to do the test or not enough people are interested enough to give us feedback.
I'm going to sleep on it overnight and buy a 3 phase motor and a 60 Watt bulb tomorrow if I don't hear from a brave soul willing to try it.
Bye for now.
Paul
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The remarkable fact is that the light once lit, stays lit after you switch open one of its input lines, as to be lit by
"one wire", costing just 5.8W for the 58W of energy used (not to account the other 58W running the motor). So
the light burns on 58 watts one wire, and in fact uses the same amount of energy, switched on or off… "one wire
or both wires" cost the same energy. (the light resistance is around 174-280 Ohms while lit). Node-anti-node,
wherever you are at it you get it with one wire.
Hi Paul,
please show another circuit diagram, how it is supposed to be running
on just 1 wire input ?
How should it draw then 5.8 Watts ?
Do you mean 1 wire input from the AC 118 Volts 60 Hz line
or do you mean something different ?
Normally 1 wire systems like Avramenko plugs etc, only work at
radio frequency ranges , where the capacitance coupling plays a huge role...
and not at 60 Hz.
Please explain.
Many thanks.
Regards, Stefan.
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Hi Stefan
From the description he gives there would be a switch in the circuit (see image below) to disconnect the input feed to the light bulb making it run on only one wire.
Regards,
Paul
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Hi Paul,
if he uses the switch as you have shown,
it would only be possible
to light up the lamp, if there was RF frequencies
on the line to the lamp.
Maybe some RF bursts from a sparking commutator ?
But as it is an AC 3 phase motor there are
probably no sparking commutators involved ??
Or are there any sparks somewhere ?
In a pure 60 Hz environment the bulb
can not light up with just 1 wire.
Regards, Stefan.
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Hi Stefan
I'm really not sure how it works! His explanation is that it is due to magnetic reconnection.
"The one wire bulb works on the concept of magnetic reconnection.
Magnetic reconnection is the process whereby magnetic field lines from different magnetic domains are spliced
to one another, changing the overall topology of a magnetic field. It is a violation of an approximate
conservation law in plasma physics, and can concentrate mechanical or magnetic energy in both space and time."
I read somewhere that RE (Radiant Energy) has an RF component to it so you may be right about the RF burst. Also as you mentioned it's a 3 phase motor so I also doubt that it's being done through sparking.
I was hoping that someone who has a 3 phase motor could try it out and look into it further as I don't have the equipment to test it right now. Today is Canada day here and most places are closed so I can't even call around to find a used surplus 3 phase motor to try it out on. Oh well, tomorrow is another day :)
Regards,
Paul
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Hmm,
maybe you are wrong with the way the bulb is wired into the circuit ?
Is there anywhere a video can be seen, that will show it ?
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No video just the document which can be seen here http://www.cavetronics.com/Archives/One_wire_bulb.doc
Brian Prater was a member here a few years ago as "cavetronics" but he didn't discuss this circuit from what I've seen when doing a search through the forum.
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No video just the document which can be seen here http://www.cavetronics.com/Archives/One_wire_bulb.doc
Brian Prater was a member here a few years ago as "cavetronics" but he didn't discuss this circuit from what I've seen when doing a search through the forum.
Weird. When I click that link above, I get a "404" error from the cavetronics server. But on this page below there's a link to the document, that looks exactly like the link above...only that link works for me. Hmm.
http://www.cavetronics.com/works.html
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Hee hee...I just browsed another of Brian's articles. Here's a quote:
(begin quote)
* 139 coils spaced at 2.58992805755395 degrees between coils
* 120 (5.8 watt) magnets spaced at 3 degrees between magnets
Ratio of degree spacing (per coils & magnets):
1.1583333333333363900462962963044
Total of the system overall (degree spacing):
150.00416666666706251099537037137
Total degrees configuration gained for 139 coils and 120 magnets verses standardized architect:
29.9958333333329374890046296287
(end quote)
So if you can't replicate his system and get free energy out, you can always blame your measuring tools...
(I wonder where he got those 5.8 watt magnets. Mine all seem to be 6 watts...What???)
(excuse me while I ROFLMAO)
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Weird. When I click that link above, I get a "404" error from the cavetronics server. But on this page below there's a link to the document, that looks exactly like the link above...only that link works for me. Hmm.
http://www.cavetronics.com/works.html
There was a dot too much at the end.
I corrected it.
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Hi All
Well I finally found a 3 phase motor dirt cheap...LOL...It's a 3 phase Hemco motor model RB0014FBA.
With your help I would like to test this wiring cct for a 1 wire AC/DC output soon ;)
All I need to know which wires from the AC single phase goes to which terminal.
Right now the motor coil leads are wired for 208/230V marked T1 through to T9 and are grouped together by wire nuts in the following order:
L1 - T1 & T7
L2 - T2 & T8
L3 - T3 & T9
T4, T5 & T6 are all tied together.
This corresponds to a 3 phase motor cct diagram I found at http://homemetalshopclub.org/news/may05/may05.html in the Checking Out a Junk 3-Phase Motor by Dick Kostelnicek - HMSC Member section of the web page.
The questions I have are:
1. Which polarized wire coming from the AC source goes to which Terminal (Or does that matter)?
2. Which terminal connection does the second wire from the AC source connect to?
3. Which terminal connection is used for the third wire from the motor going to the 1 wire light cct?
4. Which terminal connection does the third wire that feeds the 1 wire light cct connect to initially to test the bulb, is it the polarized wire or the other (Or does that matter)?
Any help in the above would be greatly appreciated.
Regards,
Paul
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Hi All
Well I got the motor running on single phase with the AC input on L1 & L2 and the 60 Watt incandescent bulb from L3 to L2.
The bulb runs fine on L3 to L2 but the bulb shuts off when L2 is disconnected, so no 1 wire bulb or magnetic reconnection on this replication.
Oh well the motor was dirt cheap so no great loss.
Edit:
Brian Prater - One wire bulb - Test1 08/01/2009
Material:
3 phase 1 HP Hemco motor model RB0014FBA
1 - 60 Watt incandescent light bulb
12VDC to 120VAC 400 Watt inverter
12VDC Marine Deep Cycle/Starting Battery - 550 CCA, 140 Reserve Capacity (No Amp Hour rating).
Power Input:
12VDC to 120VAC from 400 Watt inverter.
House A/C socket.
Tests and observations:
Started motor using rope,Plugged to DC/AC inverter, meter showed 90 Watts draw and 120 W with the bulb not very bright but hot to touch after a short period of time. Battery ran for 5 minutes from 12.8 to 12.2 Volts while running the bulb and motor.
Started motor using rope, plugged to house A/C socket, ran only long enough to test the one wire light after motor was up to speed, no measurements taken. The bulb Was brighter than from the battery and also hot to touch after a short period of time.
The motor used more than the 60 Watts mentioned in the article so 3/4 HP or less 3 PH motors could bring different results, the original notes by Brian Prater doesn't mention how many HP the motor is but a smaller motor should use less than the 90 Watts that was used on this test using the 1 HP motor.
Regards,
Paul
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Cross current vector transformation as H and I have been stating all along
If i am correct the diode plug is here as a cross current vector
transformations same as how i got the one wire light bulb to work on the RV.
The cross product occurs in the formula for the vector operator curl. It is also
used to describe the Lorentz force experienced by a moving electrical charge in
a magnetic field. The definitions of torque and angular momentum also involve
the cross product.
http://en.wikipedia.org/wiki/Cross_product
where as Pseudovector becomes is a quantity that transforms like a vector under
a proper rotation, but gains an additional sign flip under an improper rotation
(a transformation that can be expressed as an inversion followed by a
proper rotation). The conceptual opposite of a pseudo vector is a (true)
vector or a polar vector.
This concept can be further generalized to pseudoscalars and pseudotensors, both
of which gain an extra sign flip under improper rotations compared to a true
scalar or tensor.
Physical examples of pseudovectors include the magnetic field, torque,
vorticity, and the angular momentum.
The transformations may be continuous (such as rotation of a circle) or discrete
(e.g., reflection
of a bilaterally symmetric figure, or rotation of a regular polygon).
Continuous and discrete transformations give rise to corresponding
types of symmetries. Continuous symmetries can be described by Lie groups while
discrete symmetries are described by finite groups (see Symmetry group).
Symmetries are frequently amenable to mathematical formulation and can be
exploited to simplify many problems
Distinction between vectors and pseudovectors is overlooked, but it becomes
important in understanding and exploiting the effect of symmetry on the solution
to physical systems. For example, consider the case of an electrical current
loop in the z=0 plane: this system is symmetric
(invariant) under mirror reflections through the plane (an improper
rotation), so the magnetic field should be unchanged by the reflection.
But reflecting the actual magnetic field through that plane changes its
sign—this contradiction is resolved by realizing that the mirror
reflection of the field induces an extra sign flip because of its
pseudovector nature
http://en.wikipedia.org/wiki/Pseudovector becomes a real vector
That gets transformed to become non-reflective,
For example, an electrical wire is said to exhibit cylindrical symmetry, because
the electric field strength at a given distance r
from an electrically charged wire of infinite length will have the same
magnitude at each point on the surface of a cylinder (whose axis is the
wire) with radius r. Rotating the
wire about its own axis does not change its position, hence it will
preserve the field. The field strength at a rotated position is the
same, but its direction is rotated accordingly. These two properties
are interconnected through the more general property that rotating any system of
charges causes a corresponding rotation of the electric field.
The two examples of rotational symmetry - spherical and cylindrical - are each
instances of continuous symmetry.
These are characterised by invariance following a continuous change in
the geometry of the system. For example, the wire may be rotated
through any angle about its axis and the field strength will be the
same on a given cylinder. Mathematically, continuous symmetries are
described by continuous or smooth functions. An important subclass of continuous
symmetries in physics are spacetime symmetries.
Time reversal:
Many laws of physics describe real phenomena when the direction of time
is reversed. Mathematically, this is represented by the transformation.
This may be illustrated by describing the motion of a particle thrown
up vertically (neglecting air resistance). For such a particle,
position is symmetric with respect to the instant that the object is at
its maximum height. Velocity at reversed time is reversed.
maximum height is where the neon peak circuit works best
C, P, and T symmetries
The Standard model
of particle physics has three related natural near-symmetries. These
state that the universe is indistinguishable from one where:
C-symmetry (charge symmetry) - every particle is replaced with its
antiparticle.P-symmetry (parity symmetry) - the universe is reflected as in a
mirror.T-symmetry
(time symmetry) - the direction of time is reversed. (This is
counterintuitive - surely the future and the past are not symmetrical -
but explained by the fact that the Standard model describes local
properties, not global properties like entropy.
To properly time-reverse the universe, you would have to put the big
bang and the resulting low-entropy conditions in the "future". Since
our experience of time is related to entropy, the inhabitants of the resulting
universe would then see that as the past.)
Each of these symmetries is broken, but the Standard Model predicts
that the combination of the three (that is, the three transformations
at the same time) must be a symmetry, known as CPT symmetry. CP violation,
the violation of the combination of C and P symmetry, is a currently
fruitful area of particle physics research, as well as being necessary
for the presence of significant amounts of matter in the universe and
thus the existence of life. !!!!!
More advanced groups
http://en.wikipedia.org/wiki/Lie_group
Lie groups may be thought of as smoothly varying families of
symmetries. Examples of symmetries include rotation about an axis. What
must be understood is the nature of 'small' transformations, e.g.
rotations through tiny angles, that link nearby transformations. The
mathematical object capturing this structure is called a Lie algebra (Lie
himself called them "infinitesimal groups"). It can be defined because
Lie groups are manifolds, so have tangent spaces at each point
http://en.wikipedia.org/wiki/Bose-Einstein_statistics
Fermi-Dirac and Bose-Einstein statistics apply when quantum effects have to be
taken into account and the particles are considered "indistinguishable". The
quantum effects appear if the concentration of particles
How does it become a ampla-phi-R
scalar multiplication is commutative with cross multiplication
http://en.wikipedia.org/wiki/Cross_product
More generally, the result of a cross product may be either a vector
or a pseudovector, depending on the type of its operands (vectors or
pseudovectors). Namely, vectors and pseudovectors are interrelated in
the following ways under application of the cross product:
vector × vector = pseudovectorvector × pseudovector = vectorpseudovector ×
pseudovector = pseudovector
Because the cross product may also be a (true) vector, it may not
change direction with a mirror image transformation. This happens,
according to the above relationships, if one of the operands is a
(true) vector and the other one is a pseudovector (e.g., the cross product of
two vectors). For instance, a vector triple product involving three (true)
vectors is a (true) vector.
. Why is it a 3 phase RV ?
A vector triple product typically returns a (true) vector. More exactly,
according to the rules given in cross product and handedness, the triple product
a × (b × c) is a vector if either a or b × c (but not both) are pseudovectors.
Otherwise, it is a pseudovector. For instance, if a, b, and c are all vectors,
then b × c yields a pseudovector, and a × (b × c) returns a vector
So now we hold the vectors and we call them charge and now you see how it
becomes OU
Vectorizing
Thanks
Cavetronics Labs
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http://en.wikipedia.org/wiki/Autocovariance (http://en.wikipedia.org/wiki/Autocovariance)