OK, today I have best
50Hz resonance with
1.5µF (instead of
1.34µF) with the same
transformer. Maybe that is because today the moon is in a different conjunction with the sun (or maybe due to the temperature of the transformer, don't know). Thus my transformer's coil today has an induction value of
6.75 Henry.
Connected to grid voltage (
50Hz sine wave) the measurements are as follows: On the 230V coil the voltage is
344V and
0.356A (equals
122.46W of power) when in resonance (via
1.5µF), direct connected the voltage is
226V and
0.048A (equals
10.85W of power) without resonance. Hence the factors are
1.52 times higher voltage and
7.42 times higher current and
11.28 times higher power when in resonance. The secondary coils are not in use.
My connected
230V inverter draws
0.5A from a
13.5V DC power supply without resonance and
1.5A with resonance. Without any load the inverter draws
0.2A idle current. This calculates to
0.3A current =
4.05W drawn by the connected transformer without resonance and
1.3A current =
17.55W with resonance. That is a factor of
4.33 higher power consumption when in resonance.
So, what does this all mean? Do I get additional power from thin air due to the resonance? Or is the power consumption of the transformer just higher (due to the higher voltage) and therefore it heats up more quickly? When the power drawn from the DC supply is
6.76W (13.5V × 0.5A) how can it be that the power measured on the transformer is
10.85W without resonance? When the power drawn from the DC supply is
20.25W (13.5V × 1.5A) how can it be that the power measured on the transformer is
122.46W with resonance? Are there errors in my measurements and/or calculations? Or do I have OU even without resonance?
Never mind, now something rather easy: How to get high current? It is as simple as that: All what is needed is a low-ohmic voltage source! Great, isn't it?
As a matter of fact, the orange cable in the 2004 setup carries up to
25A at
220V (equals more than
5000W), and these amps are not created in the visible coil (that's impossible) neither they are created in the visible transformer inclusive diode bridge and capacitor, because there are no thick wires suitable for 25 amps of current leading to this parts.
Therefore the orange cable must be connected to something within the tin can that is low-ohmic in order to provide high current. What could that be? A
50Hz transformer that provides
5KW (5000VA) of power? Even when in resonance with something (so it collects the power from thin air), the wire of the secondary coil nevertheless has to forward this power to the heavy orange cable. Now that is how a
5000VA transformer looks like. Even if only the secondary coil is needed I don't think it will fit into TK's tin can. A
toroidal transformer rated at
5000VA would be slightly smaller in size but the diameter is still about
12inch (30cm).
Since it makes no sense at all to connect the heavy orange cable within the round box to something that has only a thin wire, there are (IMHO) only two options left, a) there is a high frequency transformer in the round box, thus it can be a lot smaller in size (but still has to have a thick wire, like a coil of an induction cooker), although I have no idea how the transformation from 50Hz input to high frequency back to 50Hz output could ever work in the TK 2004 device, b) the low-ohmic voltage source is some kind of a capacitor. But whatever it is, it has to be something low-tech, that was (and is) available to Kapanadze.
1V on 1Ω = 1A, 1V × 1A = 1W, 220V on 220Ω = 1A, 1A × 220V = 220W, 5000W ÷ 220W = 22.73, 220Ω ÷ 22.73 =
9.68ΩThus Kapanadze's
five 1KW lamps should have a combined parallel
resistance of
9.68Ω, that means the voltage source (in the tin can) should have no higher resistance than that. If the voltage source is a coil then this is not the DC resistance but the apparent resistance (impedance) at
50Hz.
So, what's next?