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Author Topic: "g" paradox...  (Read 20349 times)

exnihiloest

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Re: "g" paradox...
« Reply #30 on: May 24, 2010, 04:39:13 PM »
...

    That is,if you allow a board to rotate under the influence of gravity,the free end will accelerate at a rate greater than "g".
...

Where is the "paradox" ?!
It is not "free fall" (one of the end of the bar is prevented from falling).


iacob alex

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Re: "g" paradox...
« Reply #31 on: May 24, 2010, 05:03:34 PM »

    Hi !

 If you type on Google :  "freefall paradox"  ...you can find plenty of information ,regarding this subject.

 It's a simple fact of reality...

 Maybe,this fact in itself is nothing...but it is valuable only for the idea of this forum, attached to it (the search of PM) ...

   All the best! / Alex

mr_bojangles

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Re: "g" paradox...
« Reply #32 on: May 28, 2010, 08:53:39 AM »
wouldnt it be that upon release, the rate at which the yard stick falls beyond the event horizon would be exponentially greater, accounting for the staggered fall? as in, the further away from the pivot point, the yard stick would travel faster, "releasing" the coins with a delayed effect.


it cant be the angle of the yard stick, it has to be the speed at which its dropped

the angle is attributed to friction, which is what would keep it in place on an inclined yard stick, and would only fall off if dropped fast enough

thats just how i see it

iacob alex

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Re: "g" paradox...
« Reply #33 on: May 30, 2010, 08:22:15 PM »

  ...is simply ,a "provocative topic" about the free fall in gravity:so many shapes,so many kind of mass distribution,different states of matter .

     As Prof. Milkovic said (you know his "Two Stages Oscillator"...),we must study and undestand firstly,no more than a simply "large" pendular fall...and you can make easy tests,in the manner of Mikhail Dmitriyev...

         All the best! / Alex

Dr

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Re: "g" paradox...
« Reply #34 on: May 30, 2010, 09:12:59 PM »
Hi Alex: It would be interesting to see the same experiment, but instead of coins, use a 1 lb. weight at 6" from the pivot point fixed to the yardstick and another 1lb. weight at 6" from the free end. when the pin was pulled to let the stick fall, in superslow motion it would look like the free weight was standing still, while the yardstick was accellerating away!!

iacob alex

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Re: "g" paradox...
« Reply #35 on: June 01, 2010, 08:33:47 PM »
 
         Hi Dr !

  Really,the first step is to study,the free gravity fall of a single mass,then of a pair of masses.

  If you take a look at   www.youtube.com/watch?v=FQ02MjqBk7s  and there at the sequences (23-30sec),(66-100sec),you can understand me better.

  With an increasing radius (diameter),we can get (and store...!) more and more energy,so to imagine a self process:the same input (unbalance),in the top position,can  develop a greater and greater output  ,in the bottom position...

       All the best! / Alex

Dr

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Re: "g" paradox...
« Reply #36 on: June 02, 2010, 01:46:04 AM »
HI Alex: I studied free falling weights for almost a full year,  My favorite setup was a 4 lb.hammer pivoting on a 30" handle free falling 90 degrees and smashing a .49 dia. lead ball. I wanted to see how much static weight it would take to get the same result. I was pretty surprised at the results.

iacob alex

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Re: "g" paradox...
« Reply #37 on: June 02, 2010, 08:24:02 PM »

       Hi Dr !
The free fall must be correlated with the storage (rotational inertia) of gravity power,so to "pay" the friction,the "remake" of the starting unbalance and...the utilizable ("free") output supply.

      All the best ! / Alex