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Author Topic: ENERGY AMPLIFICATION  (Read 3510212 times)

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8565 on: June 10, 2020, 11:12:30 PM »
  No...  No free lunch in the real world. As free energy is killed by each and every component used. The more of them the less for us. Right?  So how do we get to OU. Remember OU...   As an old timer here, you should know how, by now. But, no...

In the strange case of cap to cap, of which you will not see in any circuits ever, Im just saying that whether we use that transfer to do something, or whether it were an ideal world where the energy IS just lost no matter what, then anything we do with that transfer is free in a sense. The idea of my findings is that here we do have a case where energy was not converted to another form when it came to the ideal format. I find it to be a very interesting example and want people to realize what is actually going on when ever they run across this problem in the future.

Mags

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8566 on: June 10, 2020, 11:16:21 PM »
In the strange case of cap to cap, of which you will not see in any circuits ever, Im just saying that whether we use that transfer to do something, or whether it were an ideal world where the energy IS just lost no matter what, then anything we do with that transfer is free in a sense. The idea of my findings is that here we do have a case where energy was not converted to another form when it came to the ideal format. I find it to be a very interesting example and want people to realize what is actually going on when ever they run across this problem in the future.

Mags

Like this.  If we have a real superconducting setup of the cap to cap, and we still lose 50% in the action and the energy did not convert to another form, then we should be able to say that we can create energy from nothing in a way. May be a better way of saying it, but you get my drift.  Just promoting a bit of hope. ;)

Mags

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8567 on: June 10, 2020, 11:32:26 PM »
That is 50% losses for 2 caps.

If we have 1x100uF, 20V and 10x100uF empty caps,
in each empty cap will be loss of 50%??? , 10x50% loss, if we try to equalize them parallel.
At the end empty parallel caps will eat all the energy from first one in the way you describe.
Is that so?
How much energy will remain in that case?

If I start with 100uF, 20V and I end up with 100uF, 20V, I will lost 50% of energy no matter that
values on the start and end are same?

So start 100uF, 20V and end 100uf, 20V does not contain same energy?

You are dividing 20 / 4 = 5
but then you adding 5 + 5 = 10 to get on the same point you started (20)
Can you mix operators ( * and / ) with ( + and - ) , because they are not the same order.

OF course, answer is, I don't know basic math.
For you 100uF, 20V and second caps serial 2x100uF, 10V (100uF, 20V in series) does not contain same energy?

But if you use step down transformer from 1A, 100V to 2A, 50V the energy is same (power)?
So in transformers it is the same, just in caps are not?

If you say so, then it must be true.

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8568 on: June 10, 2020, 11:52:22 PM »
If that what you say is true then if we double voltage on cap,
we should expect 4 times the energy?

Stick has two ends, so it can work in other way too...

Example:
We have 100uF, 20V and we raise voltage to 40V, then we have
100uF, 40V and 4 times larger energy?

Then it is not needed to search for free energy, this is solution,
just raise voltage in cap and energy is limitless.

Good luck with that.

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8569 on: June 11, 2020, 01:35:36 AM »
Your great knowledge comes from Wikipedia which says Q/2 and V/2,
and you accepted that without thinking.

In our case there is NO Q/2,
there is just V/2.
Our capacitors did not change capacity, they remained 100uF at the start,
just as they were 100uF at the end.

No capacity change, so Q/2 can not be applied.
There is only voltage change.
Capacity of 2 capacitors remains constant, 100uF.

Nobody ever said nothing about capacity change, none.

Can you understand there is no change in capacity in our capacitors?

There is no conundrum.
For this case there is only law of parallel and serial capacitors connection with constant capacitance of 100uF.

Electricity is not water, but caps are containers.
From 1 liter of gas at 10 psi, you can get 2 liter at 5 psi of gas if the volume of containers are equal,
but you can not do it with water. Water can not be pressed.
Analogy of gas pressure and volumes is more closely to our capacitors and voltage analogy then water analogy.
Voltage is pressure which can press charges close to each other with increase of voltage.

Otherwise, parallel and serial connection law would not work,
and we will have major violation of that laws,
laws which happened to be true for a long time,
and not from yesterday.

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8570 on: June 11, 2020, 01:39:17 AM »
That is 50% losses for 2 caps.

If we have 1x100uF, 20V and 10x100uF empty caps,
in each empty cap will be loss of 50%??? , 10x50% loss, if we try to equalize them parallel.
At the end empty parallel caps will eat all the energy from first one in the way you describe.
Is that so?
How much energy will remain in that case?

If I start with 100uF, 20V and I end up with 100uF, 20V, I will lost 50% of energy no matter that
values on the start and end are same?

So start 100uF, 20V and end 100uf, 20V does not contain same energy?

You are dividing 20 / 4 = 5
but then you adding 5 + 5 = 10 to get on the same point you started (20)
Can you mix operators ( * and / ) with ( + and - ) , because they are not the same order.

OF course, answer is, I don't know basic math.
For you 100uF, 20V and second caps serial 2x100uF, 10V (100uF, 20V in series) does not contain same energy?

But if you use step down transformer from 1A, 100V to 2A, 50V the energy is same (power)?
So in transformers it is the same, just in caps are not?

If you say so, then it must be true.
You are not figuring in what it takes in energy to fill the cap to 40v vs 20v.  At 20v there is an amount of energy there which is 20mj for 100uf.  And 100uf at 40v is 80mj.  So are you saying it doesnt take more energy to charge the 20v cap up to 40v than it did to just charge the cap to 20v in the first place? ???
I understand what you are thinking, but it is wrong. Just like in a car audio amplifier, if the rails are +20v and -20v and the rms sine output before clipping is 14.14v, then that divided by 4ohms speaker is rms 3.535amps, then the power sent to the speaker is 49.9849w..  But if the rails are 40v + and - we calculate the same. 28.28v sine just below clipping gives us 7.07amps rms to the speaker which is 199.9396w.   

So you cant think of energy and voltage numbers as linear.  get it? ;)
Mags

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8571 on: June 11, 2020, 01:52:37 AM »
Your great knowledge comes from Wikipedia which says Q/2 and V/2,
and you accepted that without thinking.

In our case there is NO Q/2,
there is just V/2.
Our capacitors did not change capacity, they remained 100uF at the start,
just as they were 100uF at the end.

No capacity change, so Q/2 can not be applied.
There is only voltage change.
Capacity of 2 capacitors remains constant, 100uF.

Nobody ever said nothing about capacity change, none.

Can you understand there is no change in capacity in our capacitors?

There is no conundrum.
For this case there is only law of parallel and serial capacitors connection with constant capacitance of 100uF.

Otherwise, parallel and serial connection law would not work.
Again you are missing the point.
If we have 1 cap 100uf at 100v and we calculate the energy, and then do the cap to cap into another 100uf cap at 0v then end up with 2 100uf caps at 50v each, there is no coming back from that. 50% was lost. No matter how you reconfigure the caps, parallel, series, the total amount of energy left after the fact is only 50% of what you started with. Lets say we connected the 100v cap to the 0v cap and we leave them connected, we then have 2 100uf caps in parallel, which equals 200uf total and 50v total.  There was 100% more energy in the 100uf cap at 100v than there is in a 200uf cap at 50v.  50% of 100 is 50. 100% of 50 is 50.  So 100uf 100v has 100% more energy than the total of 2 100uf caps at 50v, or to say also 200uf(2 100uf caps in parallel) at 50v.
Trust me. I have this down and imprinted. Unless you do your own real calculations and overall research, you 'cannot' change my mind on this. Cannot.
You come in like an all knowing being when really you are totally in the dark. That is not my problem any further here.

Mags

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8572 on: June 11, 2020, 02:06:24 AM »
I am not here to make you think differently.

I am here for you to change my mind.

I start with 100uF, 20V.
I make parallel 2 caps 100uF, 10V.
Connect them in series, I end up with 2 caps which act as one 100uF, 20V,
according to law of serial connection.

Start = 100uF, 20V
End = 100uF, 20V

How the start and end have same values and different energy levels?

Something is wrong, isn't it.
I studied cap conundrum and it violates parallel, serial law of connection.

But if you say that is the case, let it be.


WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8573 on: June 11, 2020, 02:15:32 AM »
When you got more on output, it violates law of conservation of energy.

Now you lose energy in thin air and always by 50%, strange, and it does not violate law of conservation?

Stick has 2 ends, but for you only one is right.
For you it does not apply for loss, but only for gain?

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8574 on: June 11, 2020, 02:19:49 AM »
I am not here to make you think differently.

I am here for you to change my mind.

I start with 100uF, 20V.
I make parallel 2 caps 100uF, 10V.
Connect them in series, I end up with 2 caps which act as one 100uF, 20V,
according to law of serial connection.

Start = 100uF, 20V
End = 100uF, 20V

How the start and end have same values and different energy levels?

Something is wrong, isn't it.
I studied cap conundrum and it violates parallel, serial law of connection.

But if you say that is the case, let it be.
No.
2 100uf caps in series becomes 50uf total.  If you cannot find that info anywhere, then you did not look. The only other thing with the series caps is that you have increased the voltage 'rating' to double.. 

2  100uf caps rated at 50v each. if put in parallel, then we have 200uf rated at 50v. In series we end up with 50uf that can 'handle' 100v, 50v each in series connection.Pretty simple. Those facts have not changed since I started in electronics at 10yrs old. Radioshack kits.


Mags

Magluvin

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Re: ENERGY AMPLIFICATION
« Reply #8575 on: June 11, 2020, 02:30:03 AM »


Electricity is not water, but caps are containers.
From 1 liter of gas at 10 psi, you can get 2 liter at 5 psi of gas if the volume of containers are equal,
but you can not do it with water. Water can not be pressed.
Analogy of gas pressure and volumes is more closely to our capacitors and voltage analogy then water analogy.
Voltage is pressure which can press charges close to each other with increase of voltage.


Voltage is pressure. It is the pressure that causes current to flow, just like pressurized air, and just like the pressure measured at the bottom of a water container, the more water, increased water height, more pressure. it is an excellent way to teach electrical things in a way many without electrical experience can understand.
20ft tall water tank 2ft dia.  Connect a hose to the bottom of the tank.  release the nozzle to water your garden.  Would you not have more water flow with 20ft of water than say 5ft of water in the tank?

Mags

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8576 on: June 11, 2020, 02:55:51 AM »
Yes, you are right.
I was wrong for the serial cap calculation.

You changed my mind.
Sorry for the trouble, you helped.

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8577 on: June 11, 2020, 03:00:38 AM »
Voltage is pressure. It is the pressure that causes current to flow, just like pressurized air, and just like the pressure measured at the bottom of a water container, the more water, increased water height, more pressure. it is an excellent way to teach electrical things in a way many without electrical experience can understand.
20ft tall water tank 2ft dia.  Connect a hose to the bottom of the tank.  release the nozzle to water your garden.  Would you not have more water flow with 20ft of water than say 5ft of water in the tank?

Mags

It will if you use gravity to assist.

Try that with water outside earth gravity field.
But you can compress gas in tanks even in space outside gravity influence.
You can not compress water without gas outside the gravity well of earth.

That is why I used gas analogy.

If the voltage is pressure and we use medium which can not be pressed then gas is more suitable,
because it can be pressed.

WhatIsIt

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Re: ENERGY AMPLIFICATION
« Reply #8578 on: June 11, 2020, 03:17:01 AM »
Thank you Mags for clearing the cap conundrum,
which is not conundrum at all,
It is just how parallel and serial connection behave.
There is nothing else to solve.
It is what it is.

Thanks.

P.S. Cap conundrum bothered me, and now it is easily explained.

lancaIV

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Re: ENERGY AMPLIFICATION
« Reply #8579 on: June 11, 2020, 12:11:00 PM »
#8574 :
But what if this " phantom pressure or phantom  force" can be recovered and used as capacitive coil circuit arrangement,displacement current : but "wattless power" !?


About linear and dynamic :

DE2733719 Chitta Mukherjee  "Electrical generator ..." https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=2&ND=3&adjacent=true&locale=en_EP&FT=D&date=19790215&CC=DE&NR=2733719A1&KC=A1#


Magnetic field strength H and magnetic flux density B related , force as BIL and the needed counterforce in VA !
When B=1  and Counter-B = 2     1/2V and 1/2A  = 1/4 VA or   25% VA counter-force

When B=1  and Counter-B = 3     1/3V and 1/3A  = 1/9 VA or   11,1%VA counter-force

When B=1  and Counter-B = 4     1/4V and 1/4A  =1/16VA or     6,25%VA counter-force

Push&pull lever effect



An other linear/dynamic example :

we see an one thousand watt and 1000 RPM nominal windgenerator his propeller rotating,

by low wind and 10 RPM generator shaft  :  10 RPM is the 1/100 part from 1000 RPM nominal
The electricity generation : 1000 W x (1/100)^3 =  0,001 W = 1/1000000 the nominal generator power output


little stronger wind : 100 RPM propeller generator shaft rotation ,
100 RPM the 1/10 part from 1000 RPM nominal
The electricity generation : 1000 W x (1/10)^3= 1 W = 1/1000 the nominal generator power output


Not only rotations,the internal torque gives (angular) moment=(angular)force !

Barometer,Hygrometer,Thermometer,Anemometer,Seismometer,DMM
The scale and the metric

https://translate.google.com/translate?hl=de&sl=auto&tl=en&u=https%3A%2F%2Fwww.meteorologyshop.eu%2Fmeteo-blog%2Fgrundlagen-der-windmesstechnik

from www.arestov.de ( old page)
Example: A wind turbine with a nominal 400 W (manufacturer's specification) generated at a wind force of approx. 20 m / sec. an output of 70 watts. After converting the generator to combined windings, the system delivered with a wind force of 5-6 m / sec. 140 watts. At 10-12 m / sec. were generated over 320 watts !

FIRST IMPROVEMENT
From 20 m/sec. = 70 W  Beaufort scale 9 to 10-12 m/sec. = 320 W Beaufort scale 6

The point to think and for experiments :
we have not only the diminuation from wind velocity spead

from 20 m/sec and 70 W output
to 12-10 m/ per sec and 70 W but to 320 W

First advantage : instead 20 m only 12 m/sec improvement wind factor 4,65
Second advantage: after first improvement not only 70 W output but 70 W x improvement factor = 320 W

20 m-sec /12 m-sec = 1,666 (1,666)^3 = 4,65 speed to force ratio-squared = 21,38 times improvement  = 1,66^6


David Yurth :
Induction Coil Coating Increases Generator Output by One-Third – Coating the induction coils of generators with a proprieta[/font]ry material increases their output by one-third using the same amount of fuel.

SECOND IMPROVEMENT
 By steady Beaufort 6 condition steady nominal 400 W generation from " modified" 400 W nominal wind turbine

free energy to enforced and concentrated energy only one side/two axis/3 axis compressed chamber

Turbine concentrator
https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=3&ND=3&adjacent=true&locale=en_EP&FT=D&date=19860911&CC=DE&NR=3607644A1&KC=A1#

THIRD IMPROVEMENT
By steady Beaufort 4 steady nominal 400 W generation

Possible improvement : less material or higher generator output
https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=5&ND=3&adjacent=true&locale=en_EP&FT=D&date=20130314&CC=US&NR=2013062983A1&KC=A1#

with Linevich-Arestov,Kango Iida or Andreas Sumera rotative torque converter(speed amplifyier) down to Beaufort 2


this improvements are natural part from this "compressed (dry/humid)air wind turbines" :

https://worldwide.espacenet.com/publicationDetails/biblio?DB=EPODOC&II=1&ND=3&adjacent=true&locale=en_EP&FT=D&date=20140917&CC=CN&NR=104047814A&KC=A#


and the "Fanerator" : https://patentauction.com/patent.php?nb=9318

2.  The High Velocity Electric Fan (Blowing directly on the PMA
          Blades from a distance of only 8 inches)   

     transforming this in Beaufort scale  ?! Distance to propeller/rotor  ! Force in velocity/speed !
« Last Edit: June 11, 2020, 07:50:39 PM by lancaIV »