Author Topic: ENERGY AMPLIFICATION (Read 3546604 times)

Magluvin · « **Reply #4275 on:** February 02, 2014, 11:16:30 PM »

Well as we have gone over earlier in the thread, discharging a cap directly into another cap, we lose 50% of our initial energy. That loss is avoided by using inductors in the path from cap to cap. In the sim of the circuit above, I even used very low ohm switching and no resistance added to the circuit. Still lossy. Cap to cap is like a full air tank into an empty. Once they equal out, 50-50 in each tank, the total amount of energy left in both tanks total is 50% of what was in the first full tank.

Now, if we insert a turbine in the path of air pressure pipe that was connected to a fly wheel, then as we release the pressure from the full tank, it begins to fill the empty tank, but, as the pressure flows, the turbine spins up the flywheel(inductor) and once the empty tanks pressure reaches the same pressure as the first tank, the fly wheel is near max rpm, and continues to feed the previously empty tank from the tank that was full, and in the end, using check valves(diode), the empty tank could be the full tank and the first empty, if it were not for inefficiencies of the total system.

So I have a valid argument with the circuit presented, as there are losses in dumping caps into caps.

Mags

totoalas · « **Reply #4276 on:** February 02, 2014, 11:37:09 PM »

Eric dollards way

stupify12 · « **Reply #4277 on:** February 03, 2014, 03:13:10 AM »

Hello everyone.

what you have is the proof of the what actually the true nature of capacitor and a cap discharge. Okay i give you this hint. All the necessary parts and set up to have free energy has already been posted here and well understood by our friend a.king21.

I will explain it in words. We need a pre charge capacitor lets say 1.5v in a 1uf to 10uf 250v to 400v cap ( the purpose of smaller capacity is to fill it with charge faster) , then we discharge this cap to a coil which has very low resistance-we also have a many turns of secondary coil which is induced by the capacitor 400v discharge which make will result into multiplication of electrostatic energy. The output of the secondary is to charge a HV cap lets say .50uf 2000v to 4000v, this 4000v energy is to create a HF transformer( this is the part which create the extra energy=frequency)- the primary is also a very low resistance which also has a Secondary- capture only the charge which is more POSITIVE=Spike/Surge of CEMF/BEMF to charge another BANK of capacitor it depends how many capacity you need- it is still be charged faster because you have here a HF charger.Again capture only the POSITIVE and connect it on the POsitive of the BANK, and for the negative- I already give you all the hint of it to where you will get it. We call it charge funnel of energy from the environment.

The capacitor Bank should be timely discharge back to the first capacitor when your switch of the cap 400v is OPEN Circuit. So you can charge it fully. At the same time the path of your discharge is true a transformer, so clock your discharge with 50/60hz.

P.S. with capacitor discharge you can also fast charge a battery it depends upon your frequency of choice. The pre charge could be from 9volt battery, electrostatic machine, Aerial capacity.

Quote from: DilJalaay on February 02, 2014, 07:34:45 PM

Cadman · « **Reply #4278 on:** February 03, 2014, 04:18:48 AM »

From Tito's posts

Quote

Suppose two capacitors of C value initially charged at Q charges each one,(that is at V potential).

When capacitors are in parallel, the battery of 2*V waste Q charges to fill one capacitor, and other Q charges to fill the other at the same time. The capacitors rise to the same voltage as the battery (2*V).

Then you've got the capacitors charged at 2*V volts.

Now you disconnect the parallel.

Now you've got two C capacitors, each one charged at 2*Q. This means that each one of the disconnected capacitors have the same 2*V volts as the battery.

Now connect them in series. Now you've got 2*V volts of one 2*Q/C capacitor plus 2*V volts of the other 2*Q/C capacitor (series connection). That is 4*V.

They say that two series C capacitor are equal to C/2 because (in terms of voltage):

4*V = 2*Q/C + 2*Q/C = 4*Q/C = 2*Q/(C/2)

Now, it's clear that two C series capacitors at 4*V are the same as a unique C/2 capacitor at 4*V (but charged at half the charge!).

Why free energy?

Now, connect the series capacitors to the battery. The 4*V volts will be "dumped" into the battery. Then, the charges stored in the C capacitors will go to the battery, until the potential level of the series capacitors rise 2*V volts of the battery again.

Now, if you've got 2*V in the series connection, you must have V on each capacitor when you disconnect them. That means that each one of the capacitors is charged at V so the relation of charges is Q/C that is initial conditions.

SO YOU HAVE THE SAME CHARGES ON CAPACITORS THAN WHEN YOU STARTED THE CYCLE, SO THE CHARGES THE BATTERY GAVE ON PARALLEL CHARGING PROCCESS RETURN TO THE BATTERY ON SERIES DISCHARGING PROCCESS, so THE BATTERY DOES NEVER DISCHARGE.

Now only one method is missing

As it goes back and forth then it should be doing some magnification there, and we have to step that up first ok.

"for us to use the pure high voltage, we have to add a small caps to make or take effect in a coil ok "
That's it you have it.
The only secret now is the design.

i have gave you all the tools you need.

Quote

ok here is a simple toy to scrutinize : let say for example we can make a make and brake right?, and since we know that a diode can permit a current and voltage to pass then why not after the diode lets make a lot of coils but not permitting bemf to go back is that clear? oh boy my ape English really makes secrets.

http://www.energeticforum.com/renewable-energy/16496-self-induction.html#post248775

Quote

One more thing, about Tesla's bifilar coil. I made an interesting setup once, basically a solid state Bedini type oscillator, but instead of having a cap receiving the coil collapse I connected a bifilar coil. Meaning the output of the power coil was connected to a bifilar coil with a diode (like in normal Bedini setup). The wires on the other side of the bifilar were left open. Running the circuit for even just a fraction of time would charge the bifilar coil like a cap, and the neat thing was that it could sit there for hours after the circuit had been shut off, when I would short its open wires it would discharge with a bang just like a cap, well, because it is

Think about it

Regards

wings · « **Reply #4279 on:** February 03, 2014, 07:03:54 AM »

Quote from: Cadman on February 03, 2014, 04:18:48 AM

From Tito's posts

http://www.energeticforum.com/renewable-energy/16496-self-induction.html#post248775
Think about it

Regards

oops wrong calculations

a.king21 · « **Reply #4280 on:** February 03, 2014, 12:36:45 PM »

2 x 50 mf capacitors in parallel = 100 mf

2 x 50 mf capacitors in series = 25 mf

Dave45 · « **Reply #4281 on:** February 03, 2014, 01:16:22 PM »

Quote

One more thing, about Tesla's bifilar coil. I made an interesting setup once, basically a solid state Bedini type oscillator, but instead of having a cap receiving the coil collapse I connected a bifilar coil. Meaning the output of the power coil was connected to a bifilar coil with a diode (like in normal Bedini setup). The wires on the other side of the bifilar were left open. Running the circuit for even just a fraction of time would charge the bifilar coil like a cap, and the neat thing was that it could sit there for hours after the circuit had been shut off, when I would short its open wires it would discharge with a bang just like a cap, well, because it is

Following that train of thought we can wind a capacitor directly on a core and create a high electrostatic potential on the coil, what happens if it is discharged back into another winding on the same core.

Will we get an electrostatic collapse like a magnetic collapse, very very interesting.

The bifilar wound cap coil would charge itself, not need to charge it just a discharge path........ right?

a.king21 · « **Reply #4282 on:** February 03, 2014, 01:32:12 PM »

DJ, A friend of mine tried your 3 cap circuit on a relay.
There was no energy gain, but there was a constant voltage.
So, listening to Tito and applying the Tesla method we could try this next.
Insert a 2 turn Tesla primary into the circuit.
Better if the secondary is bifilar?

crazycut06 · « **Reply #4283 on:** February 03, 2014, 01:36:32 PM »

Quote from: stupify12 on February 03, 2014, 03:13:10 AM

Hello everyone.
what you have is the proof of the what actually the true nature of capacitor and a cap discharge. Okay i give you this hint. All the necessary parts and set up to have free energy has already been posted here and well understood by our friend a.king21.

I will explain it in words. We need a pre charge capacitor lets say 1.5v in a 1uf to 10uf 250v to 400v cap ( the purpose of smaller capacity is to fill it with charge faster) , then we discharge this cap to a coil which has very low resistance-we also have a many turns of secondary coil which is induced by the capacitor 400v discharge which make will result into multiplication of electrostatic energy. The output of the secondary is to charge a HV cap lets say .50uf 2000v to 4000v, this 4000v energy is to create a HF transformer( this is the part which create the extra energy=frequency)- the primary is also a very low resistance which also has a Secondary- capture only the charge which is more POSITIVE=Spike/Surge of CEMF/BEMF to charge another BANK of capacitor it depends how many capacity you need- it is still be charged faster because you have here a HF charger.Again capture only the POSITIVE and connect it on the POsitive of the BANK, and for the negative- I already give you all the hint of it to where you will get it. We call it charge funnel of energy from the environment.

The capacitor Bank should be timely discharge back to the first capacitor when your switch of the cap 400v is OPEN Circuit. So you can charge it fully. At the same time the path of your discharge is true a transformer, so clock your discharge with 50/60hz.

P.S. with capacitor discharge you can also fast charge a battery it depends upon your frequency of choice. The pre charge could be from 9volt battery, electrostatic machine, Aerial capacity.

Wow thanks! it seems that you have already done this part, any pics or videos that you can share?

wings · « **Reply #4284 on:** February 03, 2014, 02:23:52 PM »

Quote from: a.king21 on February 03, 2014, 12:36:45 PM

2 x 50 mf capacitors in parallel = 100 mf

2 x 50 mf capacitors in series = 25 mf

I am in trouble it is not an equivalent capacitor because we are looking at the charge accumulated when in parallel see this video :

http://www.youtube.com/watch?feature=player_detailpage&v=xgQt8dRhDnE#t=337

I am correct?

Cadman · « **Reply #4285 on:** February 03, 2014, 03:38:06 PM »

DilJalaay, thanks for circuits

@ a.king21, wings, guys,

It doesn't really matter if caps in series are less mf than the same caps in parallel. That's not the point.
As much as possible you want the potential in these caps, in certain circumstances.

Also consider:
Coils have magnetic field. Can induce other coils. Will oscillate when pulsed.
Caps store potential.
Bifilar = coil
Bifilar = cap
Bifilar with one end connected can store potential.
Many uses.

To paraphrase Tito: Who says you must only use one cap?

Listen carefully, with an open mind, to stupify12, totoalas and Tito. Try not to filter what they say through what you have been taught to think.

Regards

Cadman · « **Reply #4286 on:** February 03, 2014, 04:34:14 PM »

Hey guys listen to this.

I have a home made capacitor that I use in a circuit. It's a high voltage low mf cap. In my circuit it is used for storing potential from a fast pulse, just like any other cap. Here's a neat thing about this particular cap. While it is being pulsed, it will transmit electrical energy to several separate circuits without any extra loss from the circuit it is wired to.

Isn't that interesting?

Regards

totoalas · « **Reply #4287 on:** February 03, 2014, 05:13:48 PM »

everything said and they say this and that
We can add up all and build a simple echematic like Gyula did which worked for me.....
can be totally based from Tito or anything that has been partly tested and need only some fine tuning as
Crazycut suggest.... LETS DO THE WALK.......
CHEERS
totoalas

DilJalaay · « **Reply #4288 on:** February 03, 2014, 07:20:52 PM »

Quote from: totoalas on February 03, 2014, 05:13:48 PM

everything said and they say this and that
We can add up all and build a simple echematic like Gyula did which worked for me.....
can be totally based from Tito or anything that has been partly tested and need only some fine tuning as
Crazycut suggest.... LETS DO THE WALK.......
CHEERS
totoalas

can you pls repost that schematic, Sir.

thanks

DilJalaay · « **Reply #4289 on:** February 03, 2014, 07:23:56 PM »

Quote from: Cadman on February 03, 2014, 04:34:14 PM

Hey guys listen to this.

I have a home made capacitor that I use in a circuit. It's a high voltage low mf cap. In my circuit it is used for storing potential from a fast pulse, just like any other cap. Here's a neat thing about this particular cap. While it is being pulsed, it will transmit electrical energy to several separate circuits without any extra loss from the circuit it is wired to.

Isn't that interesting?

Regards

Hmmm

[size=78%] great sir,[/size]

how you find that it transmit energy to other circuit? what is the actual setup/scenario.?

am very much curious, some pictures could be much appreciated.

thanks and regards,
D.J

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Author Topic: ENERGY AMPLIFICATION (Read 3546604 times)

Magluvin

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