I did a screen capture of the circuit  in case someone does not wish to run the sim prog.

in the above schematic   the switch at the top of the resistor load array will disconnect the load resistors to the left.
Notice the change in power on the resistors that are still connected, not much change at all.  This would be due to the diodes regulating the voltage to the load while allowing  the oscillations to continue at the highe voltages. So the diodes help us skim off 7v to the load on each half cycle. At 400kv That will take a while to degrade, depending on freq.

If you change the value of the 100nf cap down to say 500pf, note the change in running voltage of the oscillator and the time it takes to run down. But take note of the load consumption also. The load needs to be different now.

Tesla And Tito said, a tiny cap can produce a lot of power, well I think this is what they mean.

Add more resistors, more power will come out with little change to the others, to a point.    Add more diodes in series to get higher voltages to the load, but the oscillations will diminish faster, and the loads will need to be different  in ohm value to put out similar power levels or more.

Remove the diodes or just add in switches to disconnect them and check out the output now. This setup alone can produce tons of heat on the cheep.

Mags

Hello Forest,
Nice to see you again!

Have you seen this very creepy guy around? > <


I know Mags likes the movies ,and what he is describing sounds like a "blockbuster"
Can't wait to see the coming attractions!!

Seems like we should be able to build something here too!

Chet

ok   New code for sim.  here is a simple version that produces 60hz output into the R of the LRC. The input is just the source at 100v with a very low value resistor, so the impulse is good for simple demo. If you just tap the switch you will have a lower working voltage and output. If you hold the switch longer you will be in the mega volts. In the real world, the cap discharge would be a safer way to go as the discharge will be metered. I would avoid producing megavolts.  =]

I think this is an excellent example of amplification and a beautiful way to produce 60hz output.

It all needs to be developed, but this is the idea. This is what Teets is talking about.  The nitty gritty is building it and being able to design it for use where ever.

Fiddle as you wish.  Change the value of the cap slightly and watch the 60hz change.  Or the inductor.
Have fun

Mags

To amend what I stated above, the output is not more during that same time frame as the input, but it is after a couple cycles and the cycles keep coming.

Its funny how the LRC circuit is kind of common place in electronics, and the sim prog starts ya off with it.

I wonder what other things are right in front of our eyes and we never know their potential till we fiddle.


Mags

Hi Dreams

I do get times when it stops due to errors. Like the 2 switches I had to use in the first large circuit above, for some reason, if the is a diode in an open end circuit with another component, she will error. But if you disconnect one end of the diode strings, no error. And it mostly happens when the lrc is oscillating. But in the real world we might not need to use both switches.

In the first circuit, if you understand how the charging circuit turns 20kv into almost 40kv, its sort of the same way the LRC is amplifying the input, just in a unidirectional way.

When we release the discharge cap from the L in the lrc, the L has all this built up potential, still headed in the same direction of current, and it bangs into mr tiny cap. And tiny cap may be small, but with the right voltage breakdown value, it will take the hit and send it right back.
A larger cap would be soft to the inductors potential, thus lower freq.

I use to do a lot of  BEMF  collecting, but I now see FEMF.    Maybe the bemf is a result of the forward emf potential swinging all the way forward, and then bemf. So maybe the FEMF has a bit more potential than its sibling BEMF.  If you watch the precharging circuit in action, the coil builds up during the charge of the discharge cap, and once the cap equals the source voltage, the inductor isnt done yet, and it sucks more from the source than what it should have dumped into the cap normally.  This is negative resistance.  Once the cap is at source voltage level, the source should have no desire to dump any more into the cap. But the inductor had inertia of sorts and it created a load, negative resistance, for the source and pumped it into the cap to the tune of a 2 for 1

But from all that I have read so far, what is happening in these circuits should be somewhere in the ball park.

Higher voltage in the circuit, the longer the oscillations will continue while shaving off some output. 7v    12v    120v   from 400kv

When I first thought of the diode strings to give the oscillator a path to continue oscillations, I thought that then I could put a high value R load without killing the oscillations, and it worked, but I did not consider the voltage drops at the time and my voltage across the load was only 5v, and my high load got nada much. so I lowered the ohms, then more, then added more in parallel and the more I put, the longer the oscillations lasted, due to low R in the LRC, and I got tremendous power out.   I played with this a good bit before I disclosed any of it.  And I believe this is good stuff.  I would love for someone with another sim to try the same to see what we can come up with here.

Mags

Hey DreamThinker
I looked at the circuit you presented.  I cannot say for sure, but it looks like when the switch disconnects from the inductor, that it is singing on its own. I think that the program has a hard time with diodes and having disconnects with the diode still connected to the active passive device, the inductor.  Probably in most circuitry, these situations would not be in place and all components are connected at both ends to some other circuit.

In your sim, the switch on the right opens, and the inductor should continue the current flow through the diode, but then it can not pull from the diode in the opposite direction, say bemf, if any energy is left after dumping what it had through the diode. But I seriously doubt that the inductor would retain any potential across its leads after the switch was opened.  I am supposing here.   BUT

Lets say that the switch opens, yet the inductor, with its inertia mechanism, forces more electrons than it has holes for through the diode to the source, and it may do so easily, being that the source is accepting all incoming.
Now, What might go on in the inductor, with its oscillations, if it had many open holes? Missing electrons.  Would that affect the self capacitance and the inductance, and could it be an ingredient needed to pull from the vacuum?  I never really thought of any of this before now. Im just spittin it as I type here. 

Charge the coil as you show, then disconnect the coil from the circuit on the opposite side of the diode, and the inductor pushes many electrons through the diode and they cannot get back to the inductor. The coil should be 1 big positive charge just waiting for its babies to come home.  Would it just be a static charge? Static.   Is a positive electrode on a battery static when not connected to a load?

I would not put this one down till some experimenting is done, on a safe level.  At first I fully assumed that when the inductor lost its top connection, that how could the inductor retain a potential across itself connected 1 ended to a diode that will only provide and exit and no come back.
Maybe the program does not know what to do with this rectified static, and it shows it some way some how.
I would say give it a shot. Start with low inputs at first and see what a couple pulses will produce.
If it is static, if you provide an earth ground with a spark gap to the static inductor, maybe the babies wil come home, except they will be someone elses babies. lol

I will post this on your thread and here at Energy Amplification