Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Real OU-Effect to Share with everyone!!!  (Read 197466 times)

Magnethos

  • Hero Member
  • *****
  • Posts: 521
Re: Real OU-Effect to Share with everyone!!!
« Reply #60 on: February 18, 2009, 11:02:26 PM »
Dear Overunity Seekers !

Maybe nobody wants to realize it - but capacitors - like any other electrical components - and everything else on earth - are not perfect.
If you shorten an almost empty battery - you see how the voltage recovers after removing the short-circuit bridge.
Why ?
Because the battery acts as an infinite amount of elementary batteries - which are partly dead (if empty) or not - which can be seen from the outside that the "internal resistance" - thats an "ideal" approach increases.
BTW its really very difficult to discharge a battery to almost "0" - unless u shorten it for a very long periode.
Similar issues apply to most of capacitors - in higher or lower degreee.
HV caps are well known for these effects.

If you short-circuit them - they are not empty. Internal charge arranges in a way that there is no voltage at the connections.
Its like a bottle with some liquid you cannot empty completly.
BTW: Discharged is not the "lowest" internal energy state of these caps. They tend to increase their "outside" voltage to achieve internal lowest energy state again.
Well short circuit again - same thing - can do that ad infinitum.

This is even supported by the very low leakage current of HV caps.

People who design high precision integrators for very sensible equippement know that.
There are some types of caps which shows very less of that effect - mks types for example.

Now you can flame me to death.

rgds.

I have a personal theory similar to your theory. I think a battery is itself a free energy generator. A battery doesn't produces energy. A battery gets energy from the local vacuum and draws it to everywhere (motor, circuit, light bulb...).
I think amperage is not the amount of energy that pass throught a device. I think amperage is like a gate. When the gate is opened the battery can get energy from the vacuum.
In theory, in a perfect superconductor we would only need pure voltage. But the conductors we use (mainly copper wire) are SEMIconductors. That means there is a resistance. When the current saturates the circuit, that resistance decreases the "amperage" of the battery.
I don't know if I you understand my theory...

T. Bearden says that when we draw current, we are closing the bipolar gate. Maybe when the battery is full, there is an assymetry somewhere in the battery, and while that assymetry is present, we can draw energy. When we have drawn too much energy, the amperage is 0 and the bipolar gate is closed and the poles are symmetric and we can't get more power from the battery. When we 'recharge' a battery, we aren't sending electrons to the battery. We are de-symmetricaling the poles. I mean, turning the poles from symetric to assymetric. Then, we have opened the bipolar gate again (recharged) the battery.

In this thread we're trying to explain that when we connect the source to a resistance, the voltage appears instantly in the circuit, but current needs some time to appear. So, if we switch on/off very fast, we have only extracted pure voltage from the battery. We haven't extracted current. So, the battery is full forever (in theory, because in years the battery discharges). Then, the battery can recharge itself the potential (voltage) again. In this case, we don't extract current, because we're only extracting pure voltage. So the semi-conductor acts like a superconductor because there isn't resistance in that 1 msec.
If we don't draw current from the battery, we can extract all the potential we want forever, because the battery can recharge itself the potential, but not the current.
The energy extracted from that battery (pure potential) have different properties in the circuits: a positive resistor is a negative resistor, the battery acts like a diode, etc... There are 'Negative Properties' in the circuit components.

I read somewhere that there are 4 kinds of electric current. We use the 'electron current', and we need to use 'ionic current' if we don't want to discharge a battery. When we draw current we are turning some factor in symmetric. A full charged battery has some kind of broken symmetry or something similar. So, I think in all the cases we're drawing voltage. But in the common systems we can meause the 'amperes', but in reallity we aren't measuring the electron flow. We are measuring the speed we're turning the battery from assymetric to symetric. Of course, current appears when there is resistance, because in a perfect superconductor we can't measure the amperage because there isn't resistance. In a perfect superconductor, we can run any device using only pure voltage. But in the common semi-conductors, there is an opposition to the pass of the electricity and that opposition is the factor that discharges (assymetric to symmetric) the battery.

A battery is also called a Dipole, and each dipole has north and south pole. A magnet is a free energy device, batteries are also a free energy devices. The only reason why we cannot get energy from magnets is because they have equal strengths at the poles. Without a difference in potential, work can not be done.
Leedskalnin shown that we can re-configure the magnetism of a magnet to get energy from a motionless magnet. So, I think the amperage is a magnetic property (remember that ALL is magnetic, but much less than ferromagnetism). When there is a difference in the strengths of the poles, there is assymetry and then we can extract electromagnetic energy. But if we connect for a high amount of time the battery, then the battery discharges. The time current needs to appear in the circuit is some femtoseconds. If we switch on/off very fast, then we have extracted pure voltage and the assymetry of the battery is the same (bipolar gate opened). If we maintain the battery connected for a while, then current appears and we're killing the bipolar gate because we're turning to symmetric the poles.

I know there are techniques to inhibit the current and I know Tesla did something about that.
Maybe the link I posted some posts before, it's a good Current Inhibitor device. If we don't draw current, then we will have a free energy device. Look at the batteries like a Vacuum to Electromagnetic Energy transducers, not like a piece that contains electrons.

I hope someone understand this theory,  ;D
« Last Edit: February 19, 2009, 12:43:43 AM by Magnethos »

CTG Labs

  • Sr. Member
  • ****
  • Posts: 397
Re: Real OU-Effect to Share with everyone!!!
« Reply #61 on: February 18, 2009, 11:07:36 PM »
Hi NRG,

The math looks good!  Can I ask though, and sorry if this has already been covered, you are quoting the printed capacitance values and of course they will have a manufacturing tolerance which could throw all the calculations off.  Have you measured the actual capacitance of each capacitor with a capacitance meter or perhaps used a known resistance and timed discharge method?


Thanks,

Dave.

fritz

  • Sr. Member
  • ****
  • Posts: 424
Re: Real OU-Effect to Share with everyone!!!
« Reply #62 on: February 18, 2009, 11:28:40 PM »
Attached some schematic on the composition of a "real" cap containing infinite amount of elementary caps with a series resistor Rs, a parallel resistor Rp and a parasitic coupling capacitor Ck.
If you have a serious amount of C elementary with high Rs - they can even be charged spontaneous thru Ck - but are quite difficult to discharge because of high Rs.
Thats no theory. Just look into standard literature.
Unused HV caps should be stored short-circuit because of that effect.
Because they can "recharge" by this effect - and that can be dangerous if you operate / mount them.

rgds.


Magnethos

  • Hero Member
  • *****
  • Posts: 521
Re: Real OU-Effect to Share with everyone!!!
« Reply #63 on: February 18, 2009, 11:34:55 PM »
here are discussing about orthodox science and 'alternative' science. Until know, we haven't built any succesfull free energy generator. Maybe because we're using wrong theories, or we aren't using the theories we must to use. We can think un-thinkable theories if we want to achieve un-thinkable things.

fritz

  • Sr. Member
  • ****
  • Posts: 424
Re: Real OU-Effect to Share with everyone!!!
« Reply #64 on: February 18, 2009, 11:37:38 PM »
I wouldn´t trust any cap - which is "more" than a medium sized plate capacitor.
As long as the operating frequency is low - an elctrical shielded plate capacitor (preferable with vaccum as dielectric) should operate almost like an "ideal" cap.
Everything else has Rs, Rp, Ck.
Thats why "professional" RLC meters measure at least Rs and Rp.
If we need overunity to explain the behaviour of an HV cap - than we are far out anyway.

CTG Labs

  • Sr. Member
  • ****
  • Posts: 397
Re: Real OU-Effect to Share with everyone!!!
« Reply #65 on: February 18, 2009, 11:41:31 PM »
Magnethos,

I am all for new theories, but before we should throw away well researched current theory we should atleast elliminate all factors which could lead to error before we re-write all the text books with Beardens theories!


D.

Magnethos

  • Hero Member
  • *****
  • Posts: 521
Re: Real OU-Effect to Share with everyone!!!
« Reply #66 on: February 18, 2009, 11:45:13 PM »
Magnethos,

I am all for new theories, but before we should throw away well researched current theory we should atleast elliminate all factors which could lead to error before we re-write all the text books with Beardens theories!


D.
:)
I like to post that kind of uncommon theories, maybe someone reading that kind of theories can find the 'big solution' about this field. All is about thinking in different ways.. because we are seeing that if we continue thinking with the common point of view, then we cannot obtain nothing.  ;D

CTG Labs

  • Sr. Member
  • ****
  • Posts: 397
Re: Real OU-Effect to Share with everyone!!!
« Reply #67 on: February 18, 2009, 11:47:28 PM »
Magnethos,

I have read all of Beardens books and papers over the years.  Perhaps you can explain to me how his claims that all waves are really Longitudinal can explain the need for antenna polarisation?



Regards,

Dave.

Magnethos

  • Hero Member
  • *****
  • Posts: 521
Re: Real OU-Effect to Share with everyone!!!
« Reply #68 on: February 19, 2009, 12:45:56 AM »
About your question, I haven't enought info to answer you  ???


Again, Here you have the videos I talked about.
http://www.mediafire.com/?oe2gojocmdz

A guy from the youtube shows how to get pure voltage using a circuit. I call this circuit a Current Inhibitor.

The idea is to use this circuit to draw pure voltage and use the NRG circuit to amplify the energy and ultra-fast charge the caps.

CTG Labs

  • Sr. Member
  • ****
  • Posts: 397
Re: Real OU-Effect to Share with everyone!!!
« Reply #69 on: February 19, 2009, 12:48:24 AM »
How can you measure pure voltage?  A meter requires a small current to flow inside in order to get a voltage drop across it.  Pure voltage cannot be seen?!


D.

Magnethos

  • Hero Member
  • *****
  • Posts: 521
Re: Real OU-Effect to Share with everyone!!!
« Reply #70 on: February 19, 2009, 12:54:12 AM »
How can you measure pure voltage?  A meter requires a small current to flow inside in order to get a voltage drop across it.  Pure voltage cannot be seen?!


D.
Maybe an electrostatic meter? A Scalar waves meter?  ???
I don't know

TinselKoala

  • Hero Member
  • *****
  • Posts: 13958
Re: Real OU-Effect to Share with everyone!!!
« Reply #71 on: February 19, 2009, 01:11:45 AM »
Electrostatic sounds good. There will be an inrush of current while the plates go to their equilibrium positions, but once the voltage is on the plates and the instrument is indicating, there should be ideally no leakage current. Of course no instrument is perfect. But a good ES voltmeter won't even draw much current while it is coming up. I put up a video of an ES voltmeter hooked up to one of my mini VDG machines--its current is probably picoamperes--and you can see how quickly it comes up. This is probably the highest-impedance voltmeter type you will likely encounter, so it comes as close to a "pure voltage" measurement as you are likely to get, outside a standards laboratory.
http://www.youtube.com/watch?v=eogpGHFgV6E

NRGFromTheVacuum

  • Newbie
  • *
  • Posts: 27
Re: Real OU-Effect to Share with everyone!!!
« Reply #72 on: February 19, 2009, 02:10:55 AM »
Hi NRG,

The math looks good!  Can I ask though, and sorry if this has already been covered, you are quoting the printed capacitance values and of course they will have a manufacturing tolerance which could throw all the calculations off.  Have you measured the actual capacitance of each capacitor with a capacitance meter or perhaps used a known resistance and timed discharge method?


Thanks,

Dave.

Dave you make an excellent point,

I did indeed misinterpret the values written on the side of the supposed "1000uF capacitors".

They are .1 Farad capacitors, below is the address for the manufacturer's data sheet.

http://www.cooperbussmann.com/pdf/670fae07-c39d-4a13-852d-803aea8bc2a8.pdf


fritz

  • Sr. Member
  • ****
  • Posts: 424
Re: Real OU-Effect to Share with everyone!!!
« Reply #73 on: February 19, 2009, 03:57:59 AM »
I can recommend vacuum tube (preamp) voltage meters.
>=100MOhm input resistance.
Maybe a little bit bulky - but - somewhat different than
what is used nowadays.

rgds.

hartiberlin

  • Administrator
  • Hero Member
  • *****
  • Posts: 8154
    • free energy research OverUnity.com
Re: Real OU-Effect to Share with everyone!!!
« Reply #74 on: February 19, 2009, 07:45:41 AM »
Looking closer:

Test #3 is:

-37.38 volts?

So #3 should be disregarded.  It was really just a preparation for test #4 (or #3 if you now relabel)

But still, #4 apparantly shows a 10% gain.... hmmm, wonder why....
Is the coil still hooked up in these tests?
And is the coil still hooked up to the battery?
And the pulse time of #4 was much shorter than #1 and #2 as evidenced by the smaller power input.
(1/2 the pulse as test #1)

P.S. It would be nice to have a wider view so as to see how the pulses are done and what leads are being used.
I see the yellow lead from the capacitor...
And the green lead.. isn't that from the battery?
etc. etc.


Okay, I see, I misinterpreted it as 373 Volts..
Surely my fault, cause I could not really see the dot on the meter.

Well, the 4th test is now with 110 % the only overunity result...

Also the new video of him with 5 x 100.000 uF caps in series are all
underunity.

http://www.youtube.com/watch?v=AYQnxDnHMiA

He  draws in the first experiment about 0.4 Joules from the 5 series caps and
gets only 0.096 Joules out at charging up the cap to 80 Volts..

It seems it depends on the cap´s inner resistance,
how good you can drive a high current pulse through the coil
at contact point.
As the 5 x 100.000 uF caps are all in series the inner resistance
is 5 times as high, so using the blue electrolyte cap in the other
video was much better, as it seemed to have less inner resistance.


So better try to use low resistance caps if you work with these systen,

Regards, Stefan.