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Author Topic: Feedback To Source  (Read 387410 times)

nievesoliveras

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Re: Feedback To Source
« Reply #315 on: February 21, 2009, 11:20:13 PM »
Hi,There is a very clever and gifted user on utube called "theDaftman".He has made a battery swapper circuit which monitors the voltage and when it reaches a level set by a pot ,it swaps batteries.He is using it to swap 12v batteries but you may be able to adjust it for 1.5v batteries.Here is a link to his video.You can download his circuit, details in vid.
http://www.youtube.com/watch?v=BbQQYEsxDpg
Also you may consider using a 4 pole double throw relay.If you can find one which latches(these have 2 coils and have the advantage that they don't need continous power.)If you can't find a 4pdt latching relay,you may be able to modify an ordinary single coil 4pdt relay by adding another coil or use 2 latching 2pdt relays in parallel.Hope this helps. ;D
                                                      regards jonnydavro


Thank you @jonnydavro

By the way I am a member of his site. But last year he said that he could not share that information because it was not his to share.
Now I remember where I read about that swapper.

I will check the video and try to log in on the site if my account is still active.
I even have an information of the tesla switch on my hardisk. I dont know how I forgot.

Thank you!

Jesus

Low-Q

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Re: Feedback To Source
« Reply #316 on: February 21, 2009, 11:35:40 PM »
If the person on the video is you. You seem a very inteligent person.
There is a misunderstanding in all this.  If you have been following this thread from the beginning. You will know by now that the purpose I had is to make a pulse motor to run with a 1.5v and recharge the battery while doing so.

Ok. When I screamed eureka I was screaming not because of the newman motor. If you check the circuit again, you will see that the newman motor does nothing to feedback anything to the source.

The newman motor (I will say pulse motor, because any pulse motor works with this circuit) is just the one I had at hand to make experiments with, that do not take too much space.

There is a problem where I live and is that the wind seldom blows.  I bought a wind turbine kit. The wind does not blow. Then I need to device something to be the wind. In this case a pulse motor. The motor will not do any electric generation whatsoever. Who is going to do all the job is the 1.5v runner circuit.

If you take the circuit I posted and eliminate the pulse motor circuit completely and let only its 2200uf capacitor in place. This circuit will (with an old 1.5v battery) charge a pack of 4 1.5v batteries that somehow the charge given to them does not work on a camera to take a photo, but if you put back the pulse motor and run it with that same pack of batteries, it will work.

Dont be my enemy, Be my friend.
We can share information about motors.
I love electromechanics.  I am retired now, but I use to work on an electromechanic shop for ten years.

Again is not the pulse motor what charge the batteries, is the toroid or Joule thief circuit that does the job.

Lets be friends.

Jesus
Hi,

I'm not the person in the video, so the first conclusion is that I'm not that intelligent -  ;D

However, my intelligence tells me that if you're gonna charge a battery from a 1,5VAA cell, you must take all that capacity from that AA cell. Further, this AA cell is running a circuit that enables a motor to run. This motor is then in turn claimed to charge the battery inside the circuit. Well, I don't tell it's impossible. I see that motor as the same as a step up transformer that enables several volt output. That said, this output also have a current flow, measured in ampéres.

So the questions is:
How much Ah (ampere hour) is the battery capable of being charged, and how many Ah is used from the 1,5V AA cell?
Further the question is also about how much voltage both AA cell and battery represent at the end of charging?

Next stop is now the question on how to use the charged battery to use its excess capacity to replace the 1,5V AA cell. If the total capacity in Ah is more on a fully charged battery than you use in Ah from the 1,5V AA cell, you can simply replace the 1,5V AA cell with a small capacitor, where the plus end is connected to plus on the charged battery via a resistor.

Now, with the right size of the resistor, the charged battery will apply 1,5V in the place of the previous 1,5V AA cell (where approx 4,5V is resting over the resistor), with the same current flow for running that motor. So the motor can charge the battery of four AA cells again - as i have understood the motor is essensial to make a proper charge of those four AA cells (the battery) - to run your camera.

Hey, Jesus. I'm not your enemy, and I will gladly share my knowledge about electro motors. And with ten years experience, you sure know how to make a proper motor or a generator for that matter. So keep on going, but be aware that equation: P = U x I (P = watt, U = voltage, I = ampére). P is all that matters.

Just a hint from the sideline, and some off topic: Phase shift between current and voltage, can also trick ones brain to believe there is overunity. Say you have a capacitor and an inductor in parallell. At the resonance frequency, the applied AC voltage does almost not apply current at all. However, the current flown through the capacitor and the inductor internally might be several tens of ampéres, but almost 180 degree out of phase of each other. For sure you're able to measure 10 amps at the same voltage with instruments - making you believe you have much more power out than you put in.

Br.

Vidar

nievesoliveras

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Re: Feedback To Source
« Reply #317 on: February 21, 2009, 11:48:25 PM »
Hi,

I'm not the person in the video, so the first conclusion is that I'm not that intelligent -  ;D

However, my intelligence tells me that if you're gonna charge a battery from a 1,5VAA cell, you must take all that capacity from that AA cell. Further, this AA cell is running a circuit that enables a motor to run. This motor is then in turn claimed to charge the battery inside the circuit. Well, I don't tell it's impossible. I see that motor as the same as a step up transformer that enables several volt output. That said, this output also have a current flow, measured in ampéres.

So the questions is:
How much Ah (ampere hour) is the battery capable of being charged, and how many Ah is used from the 1,5V AA cell?
Further the question is also about how much voltage both AA cell and battery represent at the end of charging?

Next stop is now the question on how to use the charged battery to use its excess capacity to replace the 1,5V AA cell. If the total capacity in Ah is more on a fully charged battery than you use in Ah from the 1,5V AA cell, you can simply replace the 1,5V AA cell with a small capacitor, where the plus end is connected to plus on the charged battery via a resistor.

Now, with the right size of the resistor, the charged battery will apply 1,5V in the place of the previous 1,5V AA cell (where approx 4,5V is resting over the resistor), with the same current flow for running that motor. So the motor can charge the battery of four AA cells again - as i have understood the motor is essensial to make a proper charge of those four AA cells (the battery) - to run your camera.

Hey, Jesus. I'm not your enemy, and I will gladly share my knowledge about electro motors. And with ten years experience, you sure know how to make a proper motor or a generator for that matter. So keep on going, but be aware that equation: P = U x I (P = watt, U = voltage, I = ampére). P is all that matters.

Just a hint from the sideline, and some off topic: Phase shift between current and voltage, can also trick ones brain to believe there is overunity. Say you have a capacitor and an inductor in parallell. At the resonance frequency, the applied AC voltage does almost not apply current at all. However, the current flown through the capacitor and the inductor internally might be several tens of ampéres, but almost 180 degree out of phase of each other. For sure you're able to measure 10 amps at the same voltage with instruments - making you believe you have much more power out than you put in.

Br.

Vidar

Thank you @lowq

What I did now is I disconnected the pulse motor by pulling the trigger negative wire and am testing the circuit to see what happens.

I have somewhere on my hardisk a schematic of a way to increase the amps when the voltage is ac.
I will fetch it and post it for your consideration. By the way I dont know where I found it. I have been years on my energy quest.

Jesus

nievesoliveras

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Re: Feedback To Source
« Reply #318 on: February 21, 2009, 11:53:38 PM »
@lowq

I was lucky today. It was on the first directory searched.
According with the schematic heading it seems that I found it on a search done at EnergeticForum.
Instead of 120v. The output of a toroid coil could be used in order to get feedback to the source that has more amps.

I could be wrong though.

Jesus

Pirate88179

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Re: Feedback To Source
« Reply #319 on: February 21, 2009, 11:54:49 PM »
@ Jonnydavro:

That is exactly what I envisioned and what I posted about a few pages back.  Fantastic!  I knew there should be a way to do that, I just didn't know how.  This is very good information.

Bill

nievesoliveras

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Re: Feedback To Source
« Reply #320 on: February 21, 2009, 11:59:35 PM »
@pirate

I will log on the @daftman forum and if I find any schematic I will post it here for the benefit of all members.

Jesus

nievesoliveras

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Re: Feedback To Source
« Reply #321 on: February 22, 2009, 12:13:35 AM »
@pirate

I will log on the @daftman forum and if I find any schematic I will post it here for the benefit of all members.

Jesus

The Daftman is a very generous person. He posted the swapper diagram on this link:

http://www.mediafire.com/?trzuykmylkm

I also got the one on the forum's page and is this one:

Jesus

Low-Q

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Re: Feedback To Source
« Reply #322 on: February 22, 2009, 11:46:56 AM »
@lowq

I was lucky today. It was on the first directory searched.
According with the schematic heading it seems that I found it on a search done at EnergeticForum.
Instead of 120v.

I could be wrong though.

Jesus
Increasing capacity will allow more current draw between A and B. However, I think I have got lost somewhere, as I honestly do not see the point in having that capacitor there at all but a solid wire, except for reducing voltage over A-B when loaded.

Quote
The output of a toroid coil could be used in order to get feedback to the source that has more amps.

Can you make a drawing of what you are thinking of? Because I cannot see how you can get more amps without loosing voltage.

Br.

Vidar

nievesoliveras

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Re: Feedback To Source
« Reply #323 on: February 22, 2009, 01:26:26 PM »
@all

In order to vanish any doubt out of my mind. I disassembled the circuit. I put the joule thief only on a small breadboard and put a fresh battery with 1.34v on the circuit and in a few seconds maybe a minute, the output voltage went up and made the meter to show the overflow voltage warning.
I changed the meter selector to the 200v scale and the voltage was 25v. While I prepared the camera it kept rising and this are the photos.

This circuit with the new toroid are the heart of this voltage that charges a battery, the batteries cannot make a camera to work, but again, if you connect them to a pulse motor with the circuit included, the motor will spin with a good steady velocity.

Jesus

nievesoliveras

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Re: Feedback To Source
« Reply #324 on: February 22, 2009, 01:37:40 PM »
Increasing capacity will allow more current draw between A and B. However, I think I have got lost somewhere, as I honestly do not see the point in having that capacitor there at all but a solid wire, except for reducing voltage over A-B when loaded.

Can you make a drawing of what you are thinking of? Because I cannot see how you can get more amps without loosing voltage.

Br.

Vidar

Remember that I found that circuit on a search on the web. I dont know if it is true what it states. I need to clear my mind from all the obstacles that I have found with this quest of mine and start brainstorming again in order to increase the amps at the output.
At the moment I have no idea where to start. But the plan will now be to include the toroid on that circuit with a couple of caps and see if the meter can capture the correct measurements ac, dc and amps.

Jesus

Low-Q

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Re: Feedback To Source
« Reply #325 on: February 22, 2009, 05:22:22 PM »
The two pictures with the "1" in the display, just show that the input volt exceeds the 20V limit. I just wonder why these pictures is shown.

Vidar

plengo

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Re: Feedback To Source
« Reply #326 on: February 22, 2009, 05:42:42 PM »
@plengo

I have to get some courage to disconnect the charging batteries from the circuit and take some photos. I am afraid that the motor stop and never again work. As the fan charger I built last year.

When I got the courage to stop the pulse motor I will take some photos. Or wait till I can buy some new batteries and leave that motor running without disturbing it.

It is that is so fulfilling to see the motor with the charging batteries slowly fluctuating between 4.43 volts and 4.49 volts while keeping the source parallel batteries fluctuating between .35 volts and .36 volts.

On the meantime be pleased with this schematic with the charging batteries on their right place.

By the way, the photo maybe will not be that sophisticated, it is the same motor with some changes on it.

I will read the camera instructions to see if it can be used with the computer to take photos without having to buy a new pack of batteries. 

Thank you to all well wishers !!!

Jesus
@ nievesoliveras

Today I am trying to replicate your great work but I am having some difficulty with the coil, which is the heart of your design. On the schematics I see that you have a 16 turns and 13 turns. Is the 16 the one with the aluminum and the 13 with the enameled wire? and Is the aluminum going to the collector and  and the base of the transistor?

Is the enameled connect how? I only see on the schematics one wire but where is the other wire going? I could not figure it out looking at the pictures. Would you be able to take a very close picture of the toroid please?

Many thanks in advance,

Fausto

gadgetmall

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Re: Feedback To Source
« Reply #327 on: February 22, 2009, 10:12:36 PM »
I can do that. However John Newman claims you must use a battery to make this work.
A thought you might look more in to; You cannot look at amps or voltage output versus input separately. To verify the power output versus power input, you must compare the product of amps times voltage at output, and amps times voltage at input. Power is not amps alone, but a product of voltage and amps. Many people has been mislead by the thought that amps alone only matter when it comes to power. Just to "warn" you a bit before you scream "EUREKA!!" :)

Maybe this video you'll find interesting:
http://www.youtube.com/watch?v=l_YikaYUEgY
br.

Vidar
You got a lot to learn . Forget your Calculations  . Bemf  IS voltage Amps and TIME
And all of our designs that self runs uses a Buffer(Battery ) as Newman and Bedini as well  like Jesus and i . Its a fact Please Build your own  a working model yourself Prove it to yourself . We prove to ourselves , give you the plans . Make your own and see . This is why a post like yours offends us and we care not see post such as yours . Never come to someones Forum's thread  with Negative Attitude and  start explaining how to measure this and that  about equations you have no idea  to include the Space Time calculation besides just amps and volts . It don't work that way .to use on an overunity or unity device.COP1 :2  you build it YOU WONT KNOW and therefor Have no Right at all to Criticize the great work done here Especially when others have already duplicate and do have the right to offer help .
. .When you get to Our Level Of success you will also Scream EUREKA !!! Don't Spoil it fo other just because you cant understand it and want proof to be shoved down your throat :) Its here already read !
regards
Gadget   
« Last Edit: February 22, 2009, 11:36:23 PM by gadgetmall »

tropes

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Re: Feedback To Source
« Reply #328 on: February 22, 2009, 11:02:09 PM »
You got a lot to learn . Forget your Calculations of old Laws . Bemf  IS voltage Amps and time
And all of our designs that self runs uses a Buffer(Battery )  like Jesus and i . Its a fact and unless you come up with a working model yourself like we Have we really don't care what you Believe . We prove to ourselves , give you the plans . Make your own and see . This is why a post like yours offends us and we care not see to crap like that . either put up or shut up .Talk is Cheap !
regards
Gadget   

Gadget
This is an excellent public forum and "public" means it is for all. If you wish to hear only affirmation and praise you form a group of like-minded "yes people". In a democracy ideas are open to scrutiny and criticism. Learn to welcome those who doubt and prove them wrong.
Tropes

gadgetmall

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Re: Feedback To Source
« Reply #329 on: February 22, 2009, 11:47:47 PM »
Gadget
This is an excellent public forum and "public" means it is for all. If you wish to hear only affirmation and praise you form a group of like-minded "yes people". In a democracy ideas are open to scrutiny and criticism. Learn to welcome those who doubt and prove them wrong.
Tropes
Your are correct and again have you Built one? . If not please by all means produce something useful besides Mumbo Jumbo .  :) No they are not welcome in my Humble opinion . They are procrastinators .Sorry But again another useless post . Build it and you will see .then we have something in common . and if you cant get it to work then offer Doubt .That is well received Feedback someone who is active and is doing the work . Not some one who sits and say . You'll have to convince . me . No you have to convince yourself.
Regards
Gadget