hello fellows, i have a probably stupid question about water pressure.

considering this:

All directions

The pressure is the same in all directions in a fluid at a given point. This is true because of the characteristic of liquids and gases to take the shape of their container.

(http://www.school-for-champions.com/science/images/fluid_pressure-direction.gif)

it is possible that having a recipient with elastic walls of different areas, one wall pushed another in the oppsite direction?
i found kind of hard to explain my self with words so heres a draw:

(http://img409.imageshack.us/img409/2981/pressurequestiontw8.jpg)

fig 1 = the recipient, where the red lines are the elastic walls and the inner white is air.

fig 2 = under water pressure, and according to my question, the water pressure pushing on the bigger area elastic walls and so displacing the contained air, that push the smaller area elastic wall in the opposite direction.

im sorry if the question is too dumb but doubt is killing me. 

hello, thank you for your answer, but! either i dont understand what you mean or i feel you quite didn't answer my question.

from this:

If you pressurize a volume of water from any side and or all sides, the bottom will still have the most pressure due to gravity ..

i think you maybe refer to this:
(http://www.dkimages.com/discover/previews/759/191562.JPG)

how ever im well aware of that and my question is not about that.

the recipient in my example is summerged lets say at the bottom of a tank filled with water, and under a lot of pressure from that water.

what i want to know if the pressure applied to the bigger area elastic walls would affect the smaller area elastic wall in the opposite direction, as my previously draw (fig 2) examples.

any one??

thank you!!

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by the way, the direction air goes in my example dosnt count, because the recipient well could be pointing the the smaller area elastic wall to the left or down direction.
i know air likes to go up, but in this case air would be contained in a recipient that is being squezed by the water pressure.

i just want to know if the fact the elastic walls have different area makes a difference, as exampled in the draw (fig 2)

fig 2 = under water pressure, and according to my question, the water pressure pushing on the bigger area elastic walls and so displacing the contained air, that push the smaller area elastic wall in the opposite direction.

Correct!  the pressure applied is PSI pounds per square inch, The area effected is measured by square units. The sides of your container have more area than the top. therefore the sides will push inward and the top will expand outward.

PSI X area = total applied force. The master brake cylinder in your car has more area than the four wheel cylinders it activates. Before the advent of power and disk brakes this master cylinder was of a larger size.   

The buoyancy of a mass is effected by its density and depth or PSI of the surrounding water. A submarine takes on mass in the form of water to submerge, the amount of water taken in dictates the level the sub will maintain. The sub displaces less water when submerged than it does when afloat. If it is setting on the bottom then it is displaced by volume and not density of mass.   

loop888, "maybe the pressure in the bigger areas would also push outwards?"

 I still don’t think you understood what I was saying. Let me try again.

 If you add a pressure to a air tight container, the pressure added will be evenly distributed to the pressure all the walls already have. The walls will first expand outward where they have the least resistance. The least resistant is the center between two resistances.

Take two expandable containers one large and one small, run an air tight  hose between them. push them under water, the small container will start expanding as the area of the large container pushing inward creates more pressure due to the larger area of compression.

now that image help me so much to understand it, thanks a lot!!