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Author Topic: Torque  (Read 2891 times)

Offline raykos

  • Newbie
  • *
  • Posts: 19
Torque
« on: March 27, 2008, 03:19:38 PM »
Hi all,

    Since I'm a newbie, maybe this subject has already been covered.  If so, could someone direct to where?
 
    After I got my Bedini running, I thought to myself how neat it would be to attach a flywheel, gear, pulley, etc. to the shaft to "drive something".  But, of course, as soon as you put any kind of load on the shaft everything slows down, and I remember reading somewhere that high RPM does not equate to high torque.  For some strange reason I have a tough time wrapping my brain around the definition and concept of "Torque".

   Anyhow, has anyone done any experiments with attaching anything to the shaft of the Bedini motor?

Thanks,
Ray
   

Free Energy | searching for free energy and discussing free energy

Torque
« on: March 27, 2008, 03:19:38 PM »

Offline dorro1971

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  • *
  • Posts: 19
Re: Torque
« Reply #1 on: March 28, 2008, 12:10:50 AM »
hi,


it is abit like a sprinter and a tug of war...




sprinter = fast

tug of war = slow



still same POWER just in a different way.


and don't forget with the bedini system you get the magnetic push,...then recover at least 1/2 of that back

not to mention that as long as the secondary battery is a lower voltage than is generated by the magnets passing by the coil,.

lenze's law CANNOT and DOES NOT apply.....at least as far as we are concerned..........

don't forget you are only applying flea sized power..so you can only expect flea sized output!....GO BIGGER..


have fun


dorro


Offline Mr.Entropy

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  • Posts: 195
Re: Torque
« Reply #2 on: March 28, 2008, 02:25:25 AM »
Hi Raykos,

Torque is a rotational force.  It's measured in foot-pounds (ft.lbs) or newton-metres (Nm).

If you attach a 1 foot wrench to a bolt and apply a force of one pound, the wrench will apply 1 foot-pound of torque to the bolt, regardless of whether it moves or not.

If you have a 2 foot wrench, you can apply the same torque by pushing the end with only 1/2 pound of force -- 2 feet * 1/2 pound = 1 foot-pound -- because you have more leverage.

If you attach a pole perpendicularly to the shaft of a motor, and the motor is applying 1 foot-pound of torque to it, then if you hold the pole 1 foot away, it'll push against you with 1 pound.  2 feet away, 1/2 pound, 3 feet, 1/3 pound, etc.

Cheers,

Mr. Entropy

 

Free Energy | searching for free energy and discussing free energy

Re: Torque
« Reply #2 on: March 28, 2008, 02:25:25 AM »
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