Thank you for your input.

I did some calculations but I could not verify them myself.

I converted the 135lbs force to Nm and got 183Nm.

And I converted the mass from 39lb to 17.7kg

Then I divided the 183Nm by 17.7kg and got 10.33.

I have read that this number is the acceleration at meters/sec in square.

Earth gravity = 9.81 m/s?

My mass = 10.33 m/s?

If I'm right here I should have better acceleration than the gravity of Earth?

According to your calculations the mass should have reached 16.6km/h (10.31mph) when traveled one foot.

Queston: How did you calculate 14.9 ft/sec (4.47m/sec) at one foot away?

Hi Honk,

I stayed within the British system of units to keep it simple, but the results are the same if converted to SI and back to British to get speed in ft/sec

With 135 lbs force and a body weighing 39 lbs

Your acceleration is about 3.4 times the acceleration of gravity

About 111.4 ft/(sec^2)

Or

About 33.9 m/(sec^2)

The unit conversions you?ve used are not applicable. (easy mixup for many)

For example from British to SI

1lb (force) equals 4.448 Newton etc

So the 135 lbs (force) equals about 600 Newtons.

As for the weight of 39 lbs, it needs to be converted to mass, either Slugs in British unit mass, or Kgs (kilograms) unit mass in SI

So a body that weighs 39 lbs has a mass of about 1.21 slugs (British units)

Or about 17.7 Kgs (SI units)

As for speed and time:

With constant force and constant mass, linear motion (path), linear force application, and again perpendicular to the force of gravity vector at that point, to be more precise (for the extend of the path traveled)

The formulas are

time to travel any given distance from zero start

t=sqrt(2x/a)

and speed at any given distance from zero start

v=sqrt(2ax)

where t=time, x=distance, a=acceleration

I hope this helps