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Author Topic: Possible Overunity  (Read 16249 times)

singerxyz

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Re: Possible Overunity
« Reply #15 on: October 10, 2007, 05:08:05 PM »
Linda,
 Never shut up! You're an angel. And I appreciate every word.

I bought a 1 and 100 ohm 10 watt resistor but all I could find was a 1 watt 1k ohm resistor- other than the heat, will this be sufficient to test with?
If it fries, it fries, no worries. besides, I'm only testing for short durations.

Even more than testing the Volt/Amp output, I'd like to see if it could become self running by sending current back to run timer and circuit. I imagine with a large enough capacitor it could be possible.
I'd need to send 12-18 volts and a few milliamps back.

linda933

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Re: Possible Overunity
« Reply #16 on: October 10, 2007, 05:21:05 PM »
Linda,
 Never shut up! You're an angel. And I appreciate every word.

I bought a 1 and 100 ohm 10 watt resistor but all I could find was a 1 watt 1k ohm resistor- other than the heat, will this be sufficient to test with?
If it fries, it fries, no worries. besides, I'm only testing for short durations.

Even more than testing the Volt/Amp output, I'd like to see if it could become self running by sending current back to run timer and circuit. I imagine with a large enough capacitor it could be possible.
I'd need to send 12-18 volts and a few milliamps back.


I can tell you are anxious to achieve self-running.  That is a very lofty goal, you know.  Certainly there are ways to "close the loop" and they would be the easy part if you truly have more output energy than input energy.  First you have to find out what the ideal load is for maximum efficiency.  as I have written, it's easiest to start by finding the maximum power output load resistance, but you will need more than one or two resistors to play with.  I'd try the 100 ohm first.  See what kind of power level you get with that, since I believe that would be much closer than your 1 ohm.  The 1 ohm will probably drop your output voltage down too far.

Try the 100 ohm and tell us all what output voltage you get with that versus your output voltage with the 1000 ohm and with an open circuit (only the meter as a load).  Then I can give you a good guess as to the next resistors to buy, what value and wattage you'll need to home in on this max power transfer point.

Also...be aware that as you add loading to the output side of your circuit to extract power, unless you are doing something very very special, your input power will no longer be 18Volts "at a few milliamps".  You will undoubtedly observe that the current needed at the input, from the batteries, will go up rapidly as you pull more and more power from the output by adjusting your resistor value toward the maximum power value. 

This is why, sadly, you have to find some operating load resistance where the output power exceeds the input power before you worry about "closing the loop" for self-running!  Despite the many claims to the contrary (a.k.a. lame excuses made by people who have claimed OU but say they can't get self-running to happen because of some mysterious gobbletygook), it will be very easy to close the loop on any system that truly provides more electrical energy output than it requires at the input. 

Linda


singerxyz

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Re: Possible Overunity
« Reply #17 on: October 10, 2007, 05:35:51 PM »

I can tell you are anxious to achieve self-running.  That is a very lofty goal, you know. 
Linda



Hey, if you're gonna be a bear, be a grizzly, right ;-)

I'll work on this stuff tonight,
Thanks again
SingerXYZ

linda933

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Re: Possible Overunity
« Reply #18 on: October 10, 2007, 05:42:32 PM »

I can tell you are anxious to achieve self-running.  That is a very lofty goal, you know. 
Linda



Hey, if you're gonna be a bear, be a grizzly, right ;-)

I'll work on this stuff tonight,
Thanks again
SingerXYZ


"Cold grinding Grizzly bear jaws hot on your heels"  a Jim Morrison Doors lyrics quote

Yes, but be prepared for a lesson in what are known as The Laws of Energy Conservation.  Getting something extra, energy-wise, is a rather elusive task, stating it optimistically!

Have fun and learn at the same time...you can't beat that combination!

Linda

singerxyz

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Re: Possible Overunity
« Reply #19 on: October 11, 2007, 05:43:34 AM »
Doors- love it!

My results- hate it :-(

I tested the unit with the resistor as a load i.e. (positive-->resistor<--negative) and the meter connected meter positive to positive, meter neg to neg. I was using 2 nickel-cadmium 9V's because they seemed to produce more current, lasted a shorter time.
 
Open Circuit
600 VDC 1.6 Amps (2 Amps with fresh battery)

100 Ohm Resistor
7 VDC .8 A

10 Ohm Resistor
3.3 VDC 1.3 A

1 Ohm Resistor
.5 VDC .53 A

My batteries were running down pretty quickly, so the results may actually be slightly better but,
I guess it's back to the drawing board...
« Last Edit: October 11, 2007, 02:47:36 PM by singerxyz »

singerxyz

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Re: Possible Overunity
« Reply #20 on: October 11, 2007, 03:20:27 PM »
A little encouragement  from an unexpected source-

Ian Lungold a researcher on the Mayan Calendar says that between Nov. 19th, 2007 - Nov. 12th, 2008
 will be "The end of manufactured lack" and the arrival of free energy for all.

Interesting!

http://mayanmajix.com/cycles.html
http://www.calleman.com
http://www.mayanmajix.com/

linda933

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Re: Possible Overunity
« Reply #21 on: October 11, 2007, 07:10:10 PM »
Doors- love it!

My results- hate it :-(

I tested the unit with the resistor as a load i.e. (positive-->resistor<--negative) and the meter connected meter positive to positive, meter neg to neg. I was using 2 nickel-cadmium 9V's because they seemed to produce more current, lasted a shorter time.
 
Open Circuit
600 VDC 1.6 Amps (2 Amps with fresh battery)

100 Ohm Resistor
7 VDC .8 A

10 Ohm Resistor
3.3 VDC 1.3 A

1 Ohm Resistor
.5 VDC .53 A

My batteries were running down pretty quickly, so the results may actually be slightly better but,
I guess it's back to the drawing board...


Dear Singer,

I think you are still measuring current wrong.  It makes no sense to say you have 1.6A flowing in an open-circuited load!  Makes me think you are still putting the current meter (with its internal low-value shunt resistor) directly across (in parallel with) your output leads.  I was hoping my earlier explanations were sinking in but it looks like not yet. 

Current measurement has to be done by putting the meter in series with the load, not across it.  An open load (infinite resistance) leaves no way to measure current, but that's okay because it will always be zero in an open circuit!

Forget measuring the current.  Measure your resistors each by itself not hooked up to anything with the meter set for ohms measurement.  Write down the results for each resistor.  Then measure the voltage only on each resistor as you load your circuit with it.  Your numbers you give above tell me that you were doing something weird like maybe you got two meters and were trying to measure volts and current at the same time but putting the current meter right across the load.  That would screw up the resistance you have because the meter has a low value internal shunt resistor when in current mode.

I was expecting you would get more voltage across your 100 ohm resistor.  You also didn't test with the 1000 Ohm resistor, which would be interesting to see how much that drops the voltage as compared to open circuit.  I was really hoping that if you didn't get overunity you would at least learn something about measuring basic circuits.  It looks like maybe you're still not understanding yet? 

Linda
« Last Edit: October 11, 2007, 07:50:43 PM by linda933 »

singerxyz

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Re: Possible Overunity
« Reply #22 on: October 11, 2007, 08:20:26 PM »
OK. I just needed this diagram, now I understand. (like the saying goes, that picture could have saved a thousand words!) Basically, I tested everything like the Voltage test in the diagram. I'll re-test tonight.
Thanks again, L

Singer

singerxyz

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Re: Possible Overunity
« Reply #23 on: October 12, 2007, 05:29:54 AM »
I think I got it right now-

1000 ohm=8.8V .009A
100 ohm=4.2V .04A
10 ohm=2.4V .24A


pese

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    • Freie Energie und mehr ... Free energy and more ...
Re: Possible Overunity
« Reply #24 on: October 17, 2007, 08:56:17 AM »
A good way to home in on this magic number to extract maximum power is to notice the following:

As you increase the ohmic value of the load resistor, you will most certainly notice an increase in the output voltage.  It will be zero if you use zero ohms (dead short) and will be maximum if you use an open load (no load...open circuit). 

For most (linear) circuits, and I believe yours will probably fall into this category, the ideal load for maximum power transfer will be very near to whatever load causes the voltage to fall to half its open circuit voltage.  Try to find that value by experimenting.  You will then be able to tell if you have hit the maximum power point by raising and lowering the value slightly from there and observing a power falloff in both directions.

Linda
Somso ,,,

if i put an power load tothe 110volts line , so strom , even tat the voltage go don to 55 volts ..
than i have the maximum "power point" ...
thisway that the whole town will go to darkness ...?

Pese
(smile)

www.pese.cjb.net