Gravity powered devices > Gravity powered devices

How much weight is needed to create a certain amount of power?

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mapsrg:
Once turned the repulsive forces of the external magnets,2,guide the rotation of the smaller wheels around the larger wheel .

hansvonlieven:
You would be better off to have some kind of arresting or locking mechanism instead of relying on magnets.

While the magnets are holding your weights in place it is costing you a lot of energy in the wheel.

Hans von Lieven

mapsrg:
i agree................but i didn't want to get too complicated.Stepping motors might be used for example since only two wheels are rotated and hundreds of smaller wheels could be used.....up to ferris wheel size.The object though was to generate maybe 1000watts continuously for home use similar to wind or solar installations  .........simpler is better.I appreciate your feedback...

mapsrg:

--- Quote from: mapsrg on September 21, 2007, 12:28:45 PM ---ok  lets see.....You want 5Kw from a 2m Diameter unbalanced wheel so................................................
Assuming clockwise rotation of the unbalanced wheel the weight needed to balance and stop rotation of the wheel positioned at 9oclock would be the mass used to work out the Potential Energy of the system.Potential Energy is mass * gravity * height and is measured in joules.5Kw is 5000 joules per second.So 5000=mass*9.8*1    The height of 1m being the fall from 3oclock to bottom of rotation.Therefore the mass is 5000/9.8=510.2kg.....................................................................................

--- End quote ---
I used this method to find a power output of an unbalanced wheel .The 510.2kg figure seems high to provide 5Kw .

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