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Author Topic: Testing a SMOT  (Read 34085 times)

Offline Omnibus

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Re: Testing a SMOT
« Reply #60 on: October 01, 2007, 03:30:22 PM »
One other aspect of this setup that may be getting overlooked, is the fact that magnetic fields are conservative.

The SMOT magnets do impart energy to the ball by raising it against gravity, but in an equal and opposite fashion, they will take back that energy (due to attraction) upon the release of the ball at point C.
This is incorrect. Read my analysis and stop posting nonsense which clutters the thread.

Free Energy | searching for free energy and discussing free energy

Re: Testing a SMOT
« Reply #60 on: October 01, 2007, 03:30:22 PM »

Offline gaby de wilde

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Re: Testing a SMOT
« Reply #61 on: October 01, 2007, 06:21:20 PM »
I think it's ok to delete harassment posts Stefan. Just make it so that I can read about the SMOT in the smot topic. That would be cool. They do appear to think it's fun to scream and whine at someone the year round. But if you leave such filth up others will feel encouraged to join in. I specifically mean the post not the poster ok. ;D

I did read up on the SMOT documentation

http://magnetmotor.go-here.nl/smot
SMOT - magnetmotor

I think the best thing to work towards is to make it much more efficient  and more obvious so that everyone can agree it works. This should not be so complicated.

This ground shaking scientific research is most interesting.
Quote
On thinking about it later, I realized that it would stop after the fourth ramp no matter where it was started and that maybe there was just a problem with the fourth ramp. Unfortunately I thought of that too late and (how many times have we heard this :-)) I've since dissassembled it to reuse the magnets.
http://rimstar.org/sdenergy/smot/smotmk1/smotmk1.htm
SMOT Mark 1 Experiments

As the closed loop SMOT's that I know of where the result of at least months worth of tuning it's obvious there is something wrong with his "4th ramp". But he is doing science with clay, one just has to respect that.

A SMOT works much like the testatica device, the charge builds up so the ball enters the field slowly building up flux and it exits with it's flux still inducted into it. This makes it harder to configure it to climb the next ramp. Finstrud used a spring in stead of gravity.

A hollow ball should put the magnet force vectors under better angles. Either filling it with gas or ballast should also make a difference. The arrays of magnets may start slightly above the center of the ball and end slightly below it.

I'm convinced that additional arrays may be constructed to end half way the ramp. The balls will "drop" out of those in favor of the primary array.

I had already re-designed this idea.

http://gabydewilde.googlepages.com/chainreactor

The balls enter and leave the field. It's already a big improvement over just getting stuck onto the magnet. For me the SMOT is a half baked treasure. It may be hard to improve, that should present a challenge IMHO.  :) Everyone else should feel free to give up today.

I'm still looking for the website where you explain your smot analysis Omnibus.

The video is great but it doesn't cover the story.

Offline xpenzif

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Re: Testing a SMOT
« Reply #62 on: October 01, 2007, 07:27:32 PM »
I would like to see a website further explaining Omnibus' finding also. The equation I came up with was actually the same one Sm0ky2 posted(although his post "disappeared"). When new equations are offered, they are answered "You don't understand/ Read it again/ Of course its OU." Rather than "Here's exactly where your equation fails..." I'm trying to learn about smot, help me better understand it. Tell me why exactly sm0ky2 was wrong.
« Last Edit: October 01, 2007, 11:08:37 PM by xpenzif »

Free Energy | searching for free energy and discussing free energy

Re: Testing a SMOT
« Reply #62 on: October 01, 2007, 07:27:32 PM »
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Offline Tesla_2006

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It really works!
« Reply #63 on: October 03, 2007, 09:39:23 AM »
Hi, some 10 years ago I buy plans of a generator like the Steorn Company and it works very good, now days I reduce my electrical energy bill just to zero

 This devices really works and do a too easy life


 Bye

Offline tagor

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Re: It really works!
« Reply #64 on: October 03, 2007, 11:49:21 AM »
Hi, some 10 years ago I buy plans of a generator like the Steorn Company and it works very good, now days I reduce my electrical energy bill just to zero
 This devices really works and do a too easy life

do you have some pic or video of this generator ?

Free Energy | searching for free energy and discussing free energy

Re: It really works!
« Reply #64 on: October 03, 2007, 11:49:21 AM »
Sponsored links:




Offline Ergo

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Re: Testing a SMOT
« Reply #65 on: October 03, 2007, 12:54:57 PM »
C'mon. He's just pulling your leg.

Offline Omnibus

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Re: Testing a SMOT
« Reply #66 on: October 03, 2007, 01:18:44 PM »
I would like to see a website further explaining Omnibus' finding also. The equation I came up with was actually the same one Sm0ky2 posted(although his post "disappeared"). When new equations are offered, they are answered "You don't understand/ Read it again/ Of course its OU." Rather than "Here's exactly where your equation fails..." I'm trying to learn about smot, help me better understand it. Tell me why exactly sm0ky2 was wrong.
Go back to the beginning of this thread or in one of the neighboring threads and you'll find the explanations you're asking for. Stop cluttering the thread with useless postings. Do your homework before posting here.

Free Energy | searching for free energy and discussing free energy

Re: Testing a SMOT
« Reply #66 on: October 03, 2007, 01:18:44 PM »
Sponsored links:




Offline FreeEnergy

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Re: Testing a SMOT
« Reply #67 on: October 03, 2007, 01:43:12 PM »
think smot will work. you just have to be very precise in mm measurements. ball can't be too light/heavy, magnetic field cant be too weak/strong, etc.

if the smot alone won't work then you can always add electromagnetic at the sticky spot.
when a wheel like smot rotates to the point where the sticky spot is, it turns a flywheel that has magnets all around and passes by copper coils that excites the electromagnetic overcoming the sticky spot :)

just my 2 cents.


peace

Offline billmehess

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Re: Testing a SMOT
« Reply #68 on: October 03, 2007, 03:25:44 PM »
Three problems with this Free Energy
1. The ball turning the fly wheel as it passes will not generate enough energy  from an electromagnet  to propel
    the ball past the sticky spot.
2. The ball would have to be a magnet itself, which is kinda hard to do. There are of course round magnets but useless in this application
    as the ball would be switching polarity as it spun.
3. Last  the now magnetized ball? would have to spin the flywheel before it reaches the sticky spot not at the sticky spot where there
   is no movement. Thus when it reaches the sticky spot the electromagnet has already pulsed.

Again this concept of generating enough energy in one spin to propel pastthe sticky point is the essence of Paul Sprains motor .
Isn't this stuff fun?
Bill

Free Energy | searching for free energy and discussing free energy

Re: Testing a SMOT
« Reply #68 on: October 03, 2007, 03:25:44 PM »
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Offline xpenzif

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Re: Testing a SMOT
« Reply #69 on: October 03, 2007, 09:07:55 PM »
I would like to see a website further explaining Omnibus' finding also. The equation I came up with was actually the same one Sm0ky2 posted(although his post "disappeared"). When new equations are offered, they are answered "You don't understand/ Read it again/ Of course its OU." Rather than "Here's exactly where your equation fails..." I'm trying to learn about smot, help me better understand it. Tell me why exactly sm0ky2 was wrong.
Go back to the beginning of this thread or in one of the neighboring threads and you'll find the explanations you're asking for. Stop cluttering the thread with useless postings. Do your homework before posting here.
I said FURTHER EXPLAINING. Anyways this is exactly what I was talking about; the "you don't understand/ read it again" argument. Quit cluttering the thread with your useless postings.
« Last Edit: October 04, 2007, 04:25:25 AM by xpenzif »

Offline Omnibus

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Re: Testing a SMOT
« Reply #70 on: October 04, 2007, 03:51:39 PM »
I would like to see a website further explaining Omnibus' finding also. The equation I came up with was actually the same one Sm0ky2 posted(although his post "disappeared"). When new equations are offered, they are answered "You don't understand/ Read it again/ Of course its OU." Rather than "Here's exactly where your equation fails..." I'm trying to learn about smot, help me better understand it. Tell me why exactly sm0ky2 was wrong.
Go back to the beginning of this thread or in one of the neighboring threads and you'll find the explanations you're asking for. Stop cluttering the thread with useless postings. Do your homework before posting here.
I said FURTHER EXPLAINING. Anyways this is exactly what I was talking about; the "you don't understand/ read it again" argument. Quit cluttering the thread with your useless postings.
Stop cluttering the thread. Noone here needs to be informed how confused you are.

Free Energy | searching for free energy and discussing free energy

Re: Testing a SMOT
« Reply #70 on: October 04, 2007, 03:51:39 PM »
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Offline acp

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Re: Testing a SMOT
« Reply #71 on: October 04, 2007, 04:10:07 PM »
stop cluttering the thread.

Offline gaby de wilde

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Re: Testing a SMOT
« Reply #72 on: October 11, 2007, 03:45:33 PM »
Stop cluttering the thread. Noone here needs to be informed how confused you are.

This is the full thing?


Here is my analysis from which you should somehow try to understand that I am ignoring nothing.

The analysis of a ball going around a closed loop as in http://data.image.zabim.com/o-wa51V9glc9.jpg reveals the following:

Since the ball doesn?t return along B->A the ball does not lose only the energy portion, imparted to it by the researcher, (+mgh1 ?(Ma ? Mb)) from the energy (+mgh1 +Mb) it has at B, that is, it?s not true that the ball returns at A with the energy

(+mgh1 +Mb) - (+mgh1 ?(Ma ? Mb)) = +Ma (CoE obeyed)

As experiment shows, the ball returns along C->A, therefore, the ball loses in addition to (+mgh1 ?(Ma ? Mb)) also the energy portion (+Mb ? 0) = mgh2 + [kinetic + ...] which the ball had stored at B but was realized at C. Therefore, the ball returns at A with the energy

(+mgh1 +Mb) - (+mgh1 ?(Ma ? Mb) - Mb) = +Ma + Mb = +Ma +mgh2 + [kinetic ...+]

As a result, in SMOT, the initial +Ma is restored and in addition an excess of +mgh2 + [kinetic ...+] is produced which is in clear violation of CoE.

http://video.google.com/videoplay?docid=2383887636280790847

You can post images using [ img] tags. Highlight the url and click button 2 on row 2.

(http://data.image.zabim.com/o-wa51V9glc9.jpg)

In the construction drawing here there is steel backing, you don't use this?

http://jnaudin.free.fr/html/s102jlnp.htm

 

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