Is someone supplying misleading information on the pulse circuit?
The top image has the amp consuming device in series with the tubes, the bottom image has the amp consuming device in parallel with the tubes.


(http://www.overunity.com/index.php?action=dlattach;topic=3079.0;attach=12479;image)

Runningbare,

If you look in stan meyer tech brief document you'll he used two differnt mathods of electron extraction. The one you showed (in series with the cell) is the old method. It all boils down to extracting the electron from the water during the pulse off time.... it doesn't really matter how you do it. It stops the hydrogen and oxygen atoms from recombining before they leave the water bath.

Robert

Is someone supplying misleading information on the pulse circuit?
The top image has the amp consuming device in series with the tubes, the bottom image has the amp consuming device in parallel with the tubes.


(http://www.overunity.com/index.php?action=dlattach;topic=3079.0;attach=12479;image)

theres no need for a full wave bridge rectifier where they have it. bare an i both know that that is not alternating current going to that rectifier.

someone said that it was what dave lawton used to tune his circuit.

I'll tell you what, I'll be more convinced if someone here can come up with the term amp consuming device in mainstream electronics and electrical engineering and it's use, as an electronics engineer myself I've never heard the term.

In that case you could use the voltage potential from a line output transformer which can be in the 10s of KV range but with currents measured in microamps, around 40 microamps in the case of mine, yes I tried it, the output from the tubes was barely visible.

Stanley reasoned that since his whole method is based on using ONLY VOLTAGE POTENTIAL, it would stand to reason to label one of his elements in his circuit an AMP CONSUMING DEVICE. Since he is seeing amps and voltage are separate things, and they MOST CERTAINLY can be separated, this explains the labeling.

Of course, the AMP CONSUMING DEVICE refers to any loads (preferably resistive loads) which use power in a normal fashion.

The output from a modern line output transformer is DC due to the fact it has a built in diode/capacitor voltage multiplier.

was it DC ?
if not, the plates were constantly changing polarity and  only shaking the molecules

the task is not "breaking the dielectric barrier of water".
it is to apply a force to dissociate its molecules.

imo. at 10KV the distance between plates would need to be revised.

about the schematic, i suggest to replace the lamp by a battery. 

Hi all, okay sorry try this, ill ask my source for you about the figures 

The output from a modern line output transformer is DC due to the fact it has a built in diode/capacitor voltage multiplier.

Quote from: TheNOP on September 18, 2007, 12:18:41 AM

was it DC ?
if not, the plates were constantly changing polarity and  only shaking the molecules

the task is not "breaking the dielectric barrier of water".
it is to apply a force to dissociate its molecules.

imo. at 10KV the distance between plates would need to be revised.

about the schematic, i suggest to replace the lamp by a battery. 

DC isn't what we want to use, we only want to use IMPULSES.

Ponder this profound example:

If you take a 1:1 transformer and put a 12V battery on the primary side of the transformer, and on the secondary side you place a bridge rectifier and a capacitor.

Now, on the primary side in series with the 12V battery and the primary of the transformer you place a simple switching device like a transistor or FETs.

Now, the start conditions are as such: The battery is at 12V, and the capacitor on the secondary is at 12V...

Having 12V on both sides of a transformer means no current flow, so if you were to apply a simple square wave to the primary of the transformer using the 12V from the battery, there is NO current flow in the secondary because the capacitor on the secondary is at 12V, UNTIL that magnetic field that was built up in the transformer collapses...

Now you have a VOLTAGE pulse (pure EMF) of anywhere from 50V-1000V, and since the primary is now an OPEN circuit, this voltage pulse moves onto the secondary, but now, since the voltage is greater than 12V, this voltage DOES ADD to what is stored in the capacitor. Capacitors are the best conversion devices for these TYPES of pure EMF pulses...


That is just one example...

So, we aren't using DC, that is Direct CURRENT, we are using improvised PULSED DC, such that we all but eliminate ALL CURRENT FLOW...

So, you CAN apply 10KV+ to stainless steel plates that are in water, and the distance wouldn't have to be revised, because we aren't ADDING electrons to the plates, only this VOLTAGE FIELD...

This is what Bedini calls his 'radiant energy'........

Guys, i just got given this idea for h20 loads on your WFC.

Ash, i have been research looking for the easiest and simplest and yet most efficient way to demonstrate h2 production doing work.

The way I see it, the practical solution will be to get a Sterling motor and use a flame from the gas production. Trouble is the costs for these motors and I am having trouble finding one that is not a toy but can do a reasonable amount of work.
 
http://www.stirlingengine.com/ecommerce/product.tcl?product_id=29
 
This one unfortunately is electronically heated but if we can find something like this where a direct flame can be used it would be ideal.