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Author Topic: The Lee-Tseung Lead Out Theory  (Read 1807680 times)

Offline jeffc

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Re: The Lee-Tseung Lead Out Theory
« Reply #375 on: September 30, 2007, 09:02:35 AM »

.....

I have been taking a wait and see attitude until this point, considering that Lawrence has repeatedly stated direct involvement with the university, which implies they believe Lead Out has some sort of scientific basis.  If they really do deny even knowing about this, then we are all wasting time, as it is likely the other credible parties which have been claimed to be involved are fabrications as well.

I hope this is not that case, as the optimist part of me would like to believe that there is actually something incredible going on in China with free energy.  I think if Lawrence has contacts at the university, he should help us clarify this apparent flaw in his claims.

Regards,
jeffc

Dear jeffc,

You should have asked for information earlier.  I was eager to share it - especially my picture at the Lecture Hall of Tsing Hua University.  It was an honor for me.  Almost all my friends and relatives have a hard copy.

Please see the attached file.  Hans can now ask his Chinese Lecturer friends at Tsing Hua University to confirm our visit in September-October 2006. 

Lawrence Tseung
Asking intelligent questions Lead Out valuable answers.  You can put good questions on  multiple pulses in case I overlooked them.

Hi Lawrence,

Thank you for the photo and information.  The post which I made before was in direct response to Hans statement about his attempts to verify your relationship with Tsing Hua.  Prior to his statement, I had taken for granted that your credentials with respect to the university were as you stated, and was instead rather happy to try and follow the scientific elements of this discussion.  But when Hans brought what appeared to be a valid challenge to your information, it seemed to be something which needed your help to verify. 

If you read the last part of my post, it says that "I hope this is not that case", because I am an optimistic person and I have no reason to disbelieve anything you have said.  In any case, if we are able to confirm the truth in this issue, perhaps we can get back to science! 

I will continue to read this topic with interest, and ask questions when I think it will be helpful for reaching conclusions.  Please understand that I do not want to make a personal attack on anyone in this forum.  I'm here to be a small part of progress, and thats all.

Regards,
jeffc

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Re: The Lee-Tseung Lead Out Theory
« Reply #375 on: September 30, 2007, 09:02:35 AM »

Offline Mr.Entropy

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Re: The Lee-Tseung Lead Out Theory
« Reply #376 on: September 30, 2007, 10:43:29 PM »
(1)   A pendulum with no pulse force  can be analyzed with the simple law of conservation of energy.  At any point in time, the sum of potential energy and kinetic energy are equal.

  mgh + 1/2 * m *v *v = constant

(2)   When a pulse force is applied, how should the analysis be done?  Can we apply the Law of parallelogram of forces?  Will this pulse force supply energy to the system?  Will the tension of the string contribute to the resulting forces and the resulting energy?

You asked someone else, but I'll answer, anyway.

If you apply a pulse force F (vector) to the pendulum bob while it moves through a displacement D (vector), you do work equal to F dot D, and you should find then find that the total energy in the pendulum has changed by exactly that amount.  If you find that the new total energy exceeds to old total energy by more than that, then congratulations -- you have an overunity device. Note that this does not have anything to do with the tension on the string.

For a pulse force, F is typically very large, and D is typically very small, and this makes it very difficult to measure F dot D directly.  Instead, what you want to do is charge some small resevoir of potential energy, like a spring or a capacitor (but not a battery) or a lifted weight, and expend that energy into the pendulum with a pulse.  It's easy to measure the energy in the original charge, and if you're careful about your engineering, you can ensure that that energy is transferred to the pendulum efficiently.

Measuring the total energy in the pendulum is also problematic if you're adding magnets and stuff, but one way that works is to pick some point in the pendulum's swing (like the bottom) and measure its velocity there before and after the pulse.  The difference is the amount of energy you have added to the pendulum.  Without magnets and stuff, it's easier -- just measure the difference in the height of the pendulum's swing and use mgh.

I'm going to actually propose an experiment in another post...

Cheers,

Mr. Entropy

Footnote:  In cartesian coordinates, where vectors F and D are (Fx,Fy) and (Dx,Dy), F dot D = Fx*Dx + Fy*Dy.  This is equal to length_of_F * length_of_D * cos(angle_between_F_and_D).


Offline ltseung888

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Re: The Lee-Tseung Lead Out Theory
« Reply #377 on: October 01, 2007, 09:22:20 AM »
Itseung888:

What the heck does that have to do with anything?  The sum of potential energy and kinetic energy are always equal in any system...at least the ones we know about.  I fail to see how this applies in any way to your theory. I will re-read all of the previous posts (almost done) and I mean no disrespect to you at all. If I have read this right thus far, the "energy" you are describing could easily be described by a bouncing ball, which will also come to rest eventually.  It does not emit or give off or generate any additional energy even though it is "defying" gravity during half of it's cycles.  Maybe I am just ignorant, which is always possible. I always try to maintain an open mind on such matters.  I will research this phenomenon a little more.  Thanks for your reply.

Bill

Dear Bill and Mr. Entrophy,

Thank you for your replies.  Bill is right in comparing the pendulum with the bouncing ball in the case of NO External Pulsing Force.  There is no obvious external energy entering the system.  If there were no loss of energy, we can apply the CoE and limit the energy of the system to be just the two terms - Potential Energy (mgh) and Kinetic Energy (1/2 * M* v* v).  The sum of these two terms will be the same while the ball bounces up and down or while the pendulum is swinging.

We sometimes use the formular
mgH = mgh + 1/2m*v*v) = 1/2m*V*V
where H is the maximum Height reached and V is the highest velocity at the lowest point. h is the height at any instant. v is the velocity at the same instant.

Scientists already know how to use gravitational energy in the following case.  Water from a dam drives a turbine to generate electricity.  The potenital energy of water is used.  However, to get the water back to its original height, we need to wait for the sun to evaporate the water and the rainfall will complete the cycle. 

If we want to continuously use gravitational energy, we should look for repeatable systems.  These systems, fortuanately, are available to us easily.  The first example is the simple pendulum with no external pulse force.  We know that we can safely apply the CoE and use the forumula
 mgh + 1/2 m*v*v = constant.

Now consider exactly how we supply energy to the stationary pendulum.  The pendulum is hanging in the vertical position.  We apply a horizontal Force F.  The pendulum will have both a vertical and a horizontal displacement. (The D vector mentioned by Mr. Entrophy).  Just before we stop the force F, there will be THREE forces involved in the pendulum system.

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )
 
(3) The Tension  of the String (If there were no string, the pendulum will not swing back)


Bill rightly stated that these three forces are also vectors.  In order to determine the energy supplied by these three forces, we need to apply the vector mathematics of Force * Displacement.  (Note that it is Vector Mathematics and not the scalar multiplication.)

The relationship of the forces MUST obey the Law of Parallelogram of Forces.  That set of Laws is taught at Mechanics 101 in secondary school physics.

I shall pause here to get your response first.

Regards,

Lawrence

« Last Edit: October 01, 2007, 11:23:59 PM by ltseung888 »

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Re: The Lee-Tseung Lead Out Theory
« Reply #377 on: October 01, 2007, 09:22:20 AM »
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Offline shruggedatlas

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Re: The Lee-Tseung Lead Out Theory
« Reply #378 on: October 01, 2007, 03:07:31 PM »

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )
 
(3) The Tension  of the String (If there were no string, the pendulum will not swing back)


The weight of the pendulum plus the horizontal pulse force already sum up the force the object exerts on the string.  I do not know why you add (3) above.  If someone was pulling on the string, then yes, you would need to calculate that force, but seeing as the string is fixed at a point, why even include this?

Offline ltseung888

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Re: The Lee-Tseung Lead Out Theory
« Reply #379 on: October 01, 2007, 05:10:21 PM »

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approximately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer.)
 
(3) The Tension of the String (If there were no string, the pendulum will not swing back)


The weight of the pendulum plus the horizontal pulse force already sum up the force the object exerts on the string.  I do not know why you add (3) above.  If someone was pulling on the string, then yes, you would need to calculate that force, but seeing as the string is fixed at a point, why even include this?

Dear shruggedatlas,

When the pendulum is at rest, there were two forces.  They were the tension of the string and the weight of the pendulum bob.  They were equal and opposite to each other.

When we applied a horizontal force on the pendulum bob, there would be three forces.  They were the tension of the string, the weight of the pendulum bob and the horizontal force.  When the Pendulum Bob moved to its new position  and was momentarily at rest under the influence of these three forces, we called this system of three forces as ?at equilibrium?.  When these 3 forces were at equilibrium, we could apply the Law of Parallelogram of Forces.

This would be the situation when the first Pulse Force  was applied.  In this particular situation, the vigorous application of the Physics Law of Parallelogram of Forces and energy analysis conclusively indicated that the total energy entering the system was not  just the energy from the horizontal pulse force.

The Pendulum Bob moved up.  There was displacement up.  The force up  was from the vertical component of the tension of the string.  This displacement up times the force up  represented work done or energy exchanged in the up direction.  This is the Lead Out  Energy!

For more details, see a result from google search:
http://www.antonine-education.co.uk/Physics_AS/Module_2/Topic_2/Forces%20and%20Equilibrium_files/frame.htm.

I shall pause here for responses.

Regards,

Lawrence Tseung
Three forces at equilibrium Leads Out the use of the Parallelogram of Forces. If one of the forces is Pulsed (repeated) at the right moment, resonance can result.  Useful Energy is not just the energy from the Pulse.  Useful Energy will include the Lead Out  Energy.

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Re: The Lee-Tseung Lead Out Theory
« Reply #379 on: October 01, 2007, 05:10:21 PM »
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Offline Pirate88179

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Re: The Lee-Tseung Lead Out Theory
« Reply #380 on: October 01, 2007, 10:24:58 PM »
Lawrence:

I think I follow you and agree to a point.  In your system of the suspended pendulum, I understand and agree with the equalibrium of the three balanced forces at a given point.  You mentioned the initial "push" as being controlled by the experimenter, and that the pulses could be timed in such a way as to produce resonance, which I also agree with.  The example posted earlier about the child in a swing and a small force (push) timed and repeated correctly can send the child in the swing to great heights and velocity.  But, what I was taught, and possible inncorrectly, was that if you added up all of the energy used in the pushes or pulses, they would equal out to exactly the kinetic and potential energy conveyed by the swinging child.  Of course, this example does not involve magnets or magnetic fields.

So, my question is, given that the correctly timed pulses are an efficient way of propelling the child to great swinging arcs, but, they none the less represent no more than the total energy in the system, where or how does any additional energy come into the picture?  I appreciate your patience in your explanations.

Bill

Offline gaby de wilde

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Re: The Lee-Tseung Lead Out Theory
« Reply #381 on: October 02, 2007, 12:15:00 AM »
But, what I was taught, and possible inncorrectly, was that if you added up all of the energy used in the pushes or pulses, they would equal out to exactly the kinetic and potential energy conveyed by the swinging child.


I don't know physics. I think physics should get to know me. ;D

Personally I try to imagine how far I can throw a person up into the sky with a gentle push. A gentle push seems to be enough to throw a person up by say 0 cm? Correct me if I'm wrong but it appears not enough to even lift the passenger off the ground let alone launch them by means of gentle push.

The fact the swing was already moving isn't so much of an issue.

the part where a small push is enough to lift 80 kg of meat by 30 cm really makes no sense with the established theory. One of the 2 has to be wrong.  :D If I give you 2 blocks 1000 kg, block 1 is attached to 50 meters of wire, you will be able to swing block 1 up against gravity.  Block 2 remains in it's spot, you cant even lift it - what are we talking about here? LOL!

look? http://www.youtube.com/watch?v=r5ok4pPgVYA hahaha??

wait, this is pretty convincing... http://www.youtube.com/watch?v=BDla-x-l4Hc no?

Quote
where or how does any additional energy come into the picture?  I appreciate your patience in your explanations.
I think A standing wave is still a wave?

if 10 Joule is the energy required to lift a kg by 1 meter(is it?). Then we need about 5 Joule worth of pulses. It appears you can get about twice the height out of it.

I think it's interesting how the bob is already decelerating. If 9.8 m/s is the maximum acceleration then that must also be the maximum deceleration? (I'm guessing here)  As the bob is already decelerating while moving upwards could it be that gravity has some modified influence? You may test what I mean by pushing an object towards the ground faster as it would drop. You feel you are not assisting gravity but replacing it.

If you toss an object in the air it kind of floats there for a moment then reverses direction. It doesn't just reverse direction but it waits for a bit, this is the moment the pulse disturbs the system most efficiently. Push the swing the moment right after it reverses direction.

It's like nature shifts the gears from decelerate to accelerate and you have a small window of free motion while the sprockets are detached. ;D

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Re: The Lee-Tseung Lead Out Theory
« Reply #381 on: October 02, 2007, 12:15:00 AM »
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Offline ltseung888

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Re: The Lee-Tseung Lead Out Theory
« Reply #382 on: October 02, 2007, 12:15:04 AM »

.... can send the child in the swing to great heights and velocity.  But, what I was taught, and possible inncorrectly, was that if you added up all of the energy used in the pushes or pulses, they would equal out to exactly the kinetic and potential energy conveyed by the swinging child. 

......

Bill

Dear Bill,

I was taught incorrectly as well.  However, I had my lesson in a painful way.  When I was still a naughty boy (almost half a century ago), I pushed the punch bag a few times and then stood there for it to knock me down.  The punch bag was a few hundred kilograms.  The force knocked me a few meters away and down.

I was convinced that my couple of pushes could not have provided the force or the energy to give me so much pain.  However, my physics teacher  told me the same thing as your teacher (The sum of energy of the few pushes added together was the culprit.)

It took me 50 years later  to realize that I was taught the wrong thing.  (Thanks to Lee waking me up at 7:30 am from the hotel.)  I actually Lead Out some gravitational energy in each of the pushes.  The culprit was the sum of my energy and the Lead Out gravitational energy!

If I did not believe  in my physics teacher, the Lee-Tseung theory would have been out over half a century ago!

Lawrence Tseung
Believing the teacher blindly Leads Out  wrong results even though the Pulses provided the painful lesson.

Offline shruggedatlas

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Re: The Lee-Tseung Lead Out Theory
« Reply #383 on: October 02, 2007, 01:38:09 AM »
the part where a small push is enough to lift 80 kg of meat by 30 cm really makes no sense with the established theory. One of the 2 has to be wrong.  :D If I give you 2 blocks 1000 kg, block 1 is attached to 50 meters of wire, you will be able to swing block 1 up against gravity.  Block 2 remains in it's spot, you cant even lift it - what are we talking about here? LOL!

The established theory is called mechanical advantage.  You are not lifting the 30kg straight up, but at an incline, and it is therefore easier to do, but the total amount of energy needed is the same, assuming no friction or air resistance.

If what you are saying is true, creating an overunity device is trivial.  Just have the pendulum hit something capable of converting the kinetic energy to electrical, and use that stored charge to "pulse" the pendulum when it is on the downswing.

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Re: The Lee-Tseung Lead Out Theory
« Reply #383 on: October 02, 2007, 01:38:09 AM »
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Offline Pirate88179

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Re: The Lee-Tseung Lead Out Theory
« Reply #384 on: October 02, 2007, 01:40:16 AM »
Lawrence:

So, then might it be possible to contruct a decent size pedulum where the "weight" would be a cylinder shaped magnet and suspend it from two lines into one such that it would keep it from twisting, and have it pass twice during it's period through a coil, or a series of coils, to generate enough power to run a small occilator that would add enough of a pulse at the correct time to maintain the pendulum motion?  This would be fairly easy to construct on a smaller scale for testing.  Do you think this would be possible?  thanks.

Bill

Offline ltseung888

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The Ms. Forever Yuen Magnetic Pendulum Experiment
« Reply #385 on: October 02, 2007, 02:15:24 AM »
The Ms. Forever Yuen Magnetic Pendulum Experiment

Ms. Forever Yuen gave me her powerpoint presentation with photos on her Magnetic Pendulum Experiment last night.

I have edited and attached it here.

It is easier to set up  than the toy from the overunity.com store.  It is much cheaper too.  The important element to look for are the three sets  of readings:

(1) No other magnetic material around (32 Oscillations per 30 sec)

(2) Repulsion (25 Oscillations per 30 sec)

(3) Attraction (41 Oscillations per 30 sec)

I shall continue to discuss the significance of this experiment in the coming posts.

Thanks to Ms. Forever Yuen once again.

Lawrence Tseung

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The Ms. Forever Yuen Magnetic Pendulum Experiment
« Reply #385 on: October 02, 2007, 02:15:24 AM »
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Offline Mr.Entropy

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Re: The Lee-Tseung Lead Out Theory
« Reply #386 on: October 02, 2007, 03:35:12 AM »
Now consider exactly how we supply energy to the stationary pendulum.  The pendulum is hanging in the vertical position.  We apply a horizontal Force F.  The pendulum will have both a vertical and a horizontal displacement. (The D vector mentioned by Mr. Entrophy).  Just before we stop the force F, there will be THREE forces involved in the pendulum system.

(1) The Weight of the Pendulum (or more exactly m *g where m is the mass and g is the gravitational acceleration at the surface of the Earth which is 9.8 m/s/s approxiately.  Please yell if you don't understand the statement)

(2) The Horizontal Pulse Force F (Note that it is an externally applied Force controlled by the Engineer. )
 
(3) The Tension  of the String (If there were no string, the pendulum will not swing back)


Bill rightly stated that these three forces are also vectors.  In order to determine the energy supplied by these three forces, we need to apply the vector mathematics of Force * Displacement.  (Note that it is Vector Mathematics and not the scalar multiplication.)

The relationship of the forces MUST obey the Law of Parallelogram of Forces.  That set of Laws is taught at Mechanics 101 in secondary school physics.

I shall pause here to get your response first.

Right let the displacement D represent the path of the pendulum bob durring the application of the pulse force. Assuming that the displacement D is small enough, since a pulse lasts only a moment, we can consider D to be a straight line and the forces below to be constant over the time when the pulse is applied.  Otherwise we'll have to integrate:

During the pulse time, we have a force due to gravity (Fg), a force due to the tension on the string (Fs) and the applied pulse force (Fp).  By the law of the parallelogram of forces, as you say, these add vectorially, so that the work done by the combination of those forces is W = (Fg + Fs + Fp) \dot D

The \dot product is distributive over addition, so W = (Fg \dot D) + (Fs \dot D) + (Fp \dot D), and we can consider each of these independently:

(Fg \dot D) is the work done by gravity.  If the bob is moving up, Fg and D are in opposing directions and this is negative.  work is done against gravity and stored as potential energy by the increase in the bob's height.

(Fp \dot D) is the work done by the pulse force.  You will probably apply the force in the direction that the bob moves, speeding it up, so this will be positive.  This work will be stored as an increase in the speed and kinetic energy of the pendulum.

(Fs \dot D) is the work done by the tension on the string.  Since the force is applied at a right angle to the direction of motion, Fs \dot D is zero, and the string does no work.

That's the conventional analysis.  What in here is incorrect?

Cheers,

Mr. Entropy

Offline ltseung888

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Re: The Lee-Tseung Lead Out Theory
« Reply #387 on: October 02, 2007, 03:47:39 AM »
Lawrence:

So, then might it be possible to contruct a decent size pedulum where the "weight" would be a cylinder shaped magnet and suspend it from two lines into one such that it would keep it from twisting, and have it pass twice during it's period through a coil, or a series of coils, to generate enough power to run a small occilator that would add enough of a pulse at the correct time to maintain the pendulum motion?  This would be fairly easy to construct on a smaller scale for testing.  Do you think this would be possible?  thanks.

Bill

Dear Bill,

I believe you should read the Bill Mehess  Motor first.

http://www.overunity.com/index.php/topic,919.msg6407.html#msg6407

I advise a more thorough understanding  of the Lee-Tseung theory first before more experiments.  There are already 300 or so Over Unity Inventions worldwide.  Most of them are from "experimenters" who jumped to try some ideas  without the painstaking research first.

Many almost got it  but then spent years spinning around.  We can discuss how to improve some of them here and then do the improvements. 

I shall wait for a few more comments or responses on the Ms. Forever Yuen experiment before further continued discussion of the Lee-Tseung Theory.

Regards,

Lawrence

Offline ltseung888

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Re: The Lee-Tseung Lead Out Theory
« Reply #388 on: October 02, 2007, 06:09:26 AM »
Right let the displacement D represent the path of the pendulum bob during the application of the pulse force. Assuming that the displacement D is small enough, since a pulse lasts only a moment [1], we can consider D to be a straight line and the forces below to be constant over the time [2] when the pulse is applied.  Otherwise we'll have to integrate:

During the pulse time, we have a force due to gravity (Fg), a force due to the tension on the string (Fs) and the applied pulse force (Fp).  By the law of the parallelogram of forces, as you say, these add vectorially, so that the work done by the combination of those forces is W = (Fg + Fs + Fp) \dot D

The \dot product is distributive over addition, so W = (Fg \dot D) + (Fs \dot D) + (Fp \dot D), and we can consider each of these independently[3]:

(Fg \dot D) is the work done by gravity.  If the bob is moving up, Fg and D are in opposing directions and this is negative.  work is done against gravity and stored as potential energy by the increase in the bob's height.

(Fp \dot D) is the work done by the pulse force.  You will probably apply the force in the direction that the bob moves, speeding it up, so this will be positive.  This work will be stored as an increase in the speed and kinetic energy [4]  of the pendulum.

(Fs \dot D) is the work done by the tension on the string.  Since the force is applied at a right angle to the direction of motion, Fs \dot D is zero[5],  and the string does no work.

That's the conventional analysis[6].  What in here is incorrect?

Cheers,

Mr. Entropy

Let us discuss your assumptions point by point.
[1]We assume that the Pulse Force is controllable by the Engineer.  It can be as short or as long as desired.  In this case of the first application on the stationary pendulum, we assume that the Pulse Force is long enough to let the pendulum swing fully to its new position.  At the new position, the pendulum stopped momentarily to change direction to swing back.

[2] The forces are constant over time. 

The Gravitational Force (Fg) can be regarded as constant as the mass and the gravitational acceleration (g = 9.8 m/s/s) can be regarded as constant during this first pulse and swing.

The Horizontal Pulse Force (Fp) can be regarded as constant because this is under the control of the Engineer.  We assume the ideal situation of capable of turning the Force on and off.

The Tension in the String (Fs) unfortunately, cannot be regarded as a constant.  Before the application of the Pulse Force (Fp), Fs = Fg.  When Fp is being applied, Fs MUST change.  At the new momentary stationary position, Fs must be equal and opposite to the resultant force of Fp and Fg.  Thus this particular assumption is incorrect.

[3] We cannot consider them independently if Fs is a function of Fp and Fg.  Thus this particular assumption is incorrect.

[4] As we stated, the final position for this analysis is the momentary stationary position.  There is NO velocity  and hence no kinetic energy.  This particular assumption is incorrect.

[5] Fs \dot D is zero  You are making the assumption that the force vector Fs is always at right angles to the displacement vector D.  In constant circular motion such as the Earth going around the Sun, this is correct.  However, in accelerating and decelerating circular motion, this is incorrect.

[6] Thus the so called conventional analysis as outlined by you have many  incorrect assumptions.

As you have rightly pointed out, without the use of Integrals, we have to make certain assumptions and simplifications.  These assumptions and simplifications may be inexact or even incorrect.  Arguing over inexact or incorrect assumptions will waste much energy and time.

I shall try to explain the Integral Assumption  in the next post.  It will be edited from the notes made after the discussions at Tsing Hua University.

Lawrence Tseung
Simplified Analysis Leads Out  incorrect assumptions.  It increases the Pulse rates of all involved.

« Last Edit: October 02, 2007, 01:03:59 PM by ltseung888 »

Offline Pirate88179

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Re: The Lee-Tseung Lead Out Theory
« Reply #389 on: October 02, 2007, 07:57:04 AM »
Lawrence:

It may not matter in your calculations but I believe that the figure of acceleration due to gravity of 9.8 cm2 does not apply in this case. (Pendulum)  That was calculated for a free falling body in a vaccuum.  I am not going to get into wind resistance or anything but it's the "free falling" aspect that interests me.  Since the sting is forcing the pendulum into a circular path, rather than straight, and if the pendulum is launched (started) at the 3:00 position or the 9:00 position, it would only free fall for an instant before the string causes it to begin it's circular path.  The force imposed by the string in doing this would not allow the pendulum to reach the acceleration figure for a free falling body.

The force of gravity at 1g would also not remain constant during the circular path forced by the string.  I believe it would climb and be at maximum at the 6:00 position of the pendulum arc and taper off back toward 1g, and then 0g at the extreme ends of the swing movement.

I think the most interesting thing is that at each ends of the pendulum arc, there is that one moment where, for all intents and purposes, the pendulm is weightless and would be at 0g.  Velocity would also be 0. The tension on the string would be 0.  It is this exact point in time that interests me.

I saw the slide show done by your friend. The results were not what I would have anticipated if asked beforehand.  Interesting.

Bill

 

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