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Author Topic: Gravity/Buoyancy Device Simple Schematic. (Tell me why it won't work)  (Read 9258 times)

Offline tytus

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If you force the ball to pass through paddle wheel type power generation devices on its way up and down the system, the energy could be stored and used to aid in its reinsertion at the bottom of the water tube.
The magnet at the top gives it a little help coming over the edge even though it is already inclined to go over because of its direction of travel caused by the slant at the top of the water container.

Tell me at which point does this device fail ?

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Offline TheOne

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if your ball float they will not able to pass the paddlewheel, so your idea don't work :)

Offline tytus

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Ok, so what if we changed the reinsertion mechanism to have the ball roll to a spot directly under the water tube and then have a plunger push it up through a one way valve/gate ?), then if we make the device 20 feet tall and thin (thereby increasing the energy produced and reducing the water pressure at the bottom of the watertube), the ball would generate a lot of electricity if it floated up and then fell through the air by that distance through a bunch of paddlewheels attached to generators which would store the energy in a capacitor for use in powering a reinsertion mechanism. Surely this amount of energy would be enough to operate a simple reinsertion mechanism at the bottom of the device.

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Offline Dingus Mungus

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Lots of energy required to prevent water from leaking when inserting the ball.
Explain how you'll insert the ball in detail, and you'll answer your own question.

~Dingus Mungus

http://www.overunity.com/index.php/topic,1651.msg17408.html#msg17408

Offline Gearhead

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Inserting the ball at the bottom of the column of water requires displacing the water upward.  This is all the energy the ball can recover when it is displaced by the water.  If the process were 100% efficient the net energy becomes zero.

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Offline karl

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If you force the ball to pass through paddle wheel type power generation devices on its way up and down the system, the energy could be stored and used to aid in its reinsertion at the bottom of the water tube.
The magnet at the top gives it a little help coming over the edge even though it is already inclined to go over because of its direction of travel caused by the slant at the top of the water container.

Tell me at which point does this device fail ?

Hi Tytus,
there is an Video on youtube showing the insertion of a floater cap into an tube like yours.

http://www.youtube.com/watch?v=gxnHJoyrQpM

I like to work with you on this problem.

Like shown in the Video the device is working and driving an bank of lamps while falling from the upper limit.

The insertion is not the problem as shown,
It's like the experiment with a full glass of wather and a sheet of paper covering it.
If you turn the glass arround the glass is tight due to the higher air pressure at the bottom.
Are you firm with that experiment?

Next step is to close the circle and remove the cap from the floatation tube.
To open the tube at the top it should be shuttet at the lower end (drehschieber) with nearly no power and then opened with also no power (simple flap at top of tube).

The outcuppling could be done like in your approach or by floating the container on top of the fluid and link it direct in the working upwards elevator.

Now to the problem in the following step.

You shut the upper flap and there is now an reservoir of air wich is compressible and every time you remove the container there is more air space left.

Should we pump the water again upward to fill?the reservoir before opening the lower vent to insert the next floater?

There should the calculation start. When to switch, what are the relevant relative pressures in the tube at what time and at what switching state of the device (switching costs nothing). Bacause there is a higher pressure at the bottom than at the top,
but the pressure changes as different switching states happens.

Please start your calculation.

Best wishes
FE Karl

Offline karl

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If you force the ball to pass through paddle wheel type power generation devices on its way up and down the system, the energy could be stored and used to aid in its reinsertion at the bottom of the water tube.
The magnet at the top gives it a little help coming over the edge even though it is already inclined to go over because of its direction of travel caused by the slant at the top of the water container.

Tell me at which point does this device fail ?

Add: A taller tube has the same pressure per unit bottom than a wider one, thats not the problem.
The problem is the difference in density between the floater and the water, because this generates the upwards thrust.
If the floater has a lower density per volume, the lost volume of water after taking out the floater at top has to be replaced with a higher density volume which has to be transported to the top region of the tube.
Thats the real problem. In this case it's better to build a waterfall and apply a heavy pump to drive it.

Forget this idea. The problem is always the same....to close the loop....

Please tell me if there are further questions

KArlFUNKEL
 

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Offline tytus

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Karl,

Thanks for showing me that video... very interesting... let me think a while and I'll get back to you

Tytus

Offline truth

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Re: Gravity/Buoyancy Device Simple Schematic. (Tell me why it won't work)
« Reply #8 on: December 21, 2008, 06:41:16 AM »
One more for the construction hat models.

Cool video. Just skips the parts that don't work.

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Re: Gravity/Buoyancy Device Simple Schematic. (Tell me why it won't work)
« Reply #8 on: December 21, 2008, 06:41:16 AM »
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