Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: New accelerating gravity wheel ! Converted video from www.newenergymachine.com !  (Read 656247 times)

AB Hammer

  • elite_member
  • Hero Member
  • ******
  • Posts: 1253
It is good to here that Bob is still with it.  :)

LarryC

  • Hero Member
  • *****
  • Posts: 911
@all

I finally received a response from Bob. Sounds like he is moving forward so that's great news.......

> Hi,
> Your website says that your new machine will be completed in early September. I was wondering when you will be adding the update?
> Thanks so much,
> Charlie
>
I'm am presently having one built in Canada and I am traveling to the US to maybe make a deal as well for construction there at
a plant that is geared for what I need. The new unit will be upgradeable from 1000 to 3000 lb. of torque. Like the Windmill, it has
a slow rpm. The only real drawback is the more energy it can put out, the heavier the machine has to be to support the weight.

Thanks for your interest.......Bob

Outstanding, thanks for the info Charlie,
 
I just hope his machine info is released in time, to reduce the climate change, that is destroying so many lives. Trust me, I know from Katrina, it is a great physical and mental burden when your house and neighborhood is taken apart. Now Gustav has inflicted suffering upon many thousand more.

Regards, Larry   

noonespecial

  • Sr. Member
  • ****
  • Posts: 278
Would he be willing to share detailed drawings of his wheels or give a patent number?

Jason

Hi Jason,
I can ask. The only disappointment in all of this is that he claims to have applied for a patent but a search of both Canadian and US patents doesn't show anything. So I don't know what's up with that......
Regards,
Charlie

bobmary

  • Newbie
  • *
  • Posts: 8
Hi Jason,
I can ask. The only disappointment in all of this is that he claims to have applied for a patent but a search of both Canadian and US patents doesn't show anything. So I don't know what's up with that......
Regards,
Charlie
I have applied for a patent in Canada and US and since found out that the US shelve the application for 18 months then process it.
I have to wait about 12 more months for it to be processed.
.

Hello to all. Just like to say how glad I am to see the interest everyone has in my machine.
The machine I am referring to is the one at  www.newsourceofenergy.com . Lots of you say
it can't be done and others say how did you do it. As a matter of fact it was very simple and
I had help. George, a good friend of mine, who was an engineer since 1945 was very interested
in what I had done so far and suggested to try the cam and leaver mechanism that I used in
the unit in the short clip.
Now picture this in your mind. Get 2 weights that weigh 10 lb each and weld a strong rod
between them at about 25 inches. These weight are placed vertically on a track. One at center
and the other at the bottom The 2 weight joined together take less energy to move toward the closer
 to the center you get. If you are moving the weights 25 inches you only have to move them 12 inches
to get to the 0 weight factor as centrifugal force does the rest. The first 2 or 3 inches are the hardest to
move. To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight.
The cam first moves the weights about 4 inches and then the leaver takes over and moves the weight just passed the center position. ( weights are equally divided in the center of the machine) Then
the centrifugal force takes over and moves the weights the other half of the way.
After this month I should have two companies, one in Canada and one in the US manufacturing them.
You can do a lot with a set of leavers.
 
Regards........Bob


helmut

  • Hero Member
  • *****
  • Posts: 723
    • in construction
I have applied for a patent in Canada and US and since found out that the US shelve the application for 18 months then process it.
I have to wait about 12 more months for it to be processed.
.

Hello to all. Just like to say how glad I am to see the interest everyone has in my machine.
The machine I am referring to is the one at  www.newsourceofenergy.com . Lots of you say
it can't be done and others say how did you do it. As a matter of fact it was very simple and
I had help. George, a good friend of mine, who was an engineer since 1945 was very interested
in what I had done so far and suggested to try the cam and leaver mechanism that I used in
the unit in the short clip.
Now picture this in your mind. Get 2 weights that weigh 10 lb each and weld a strong rod
between them at about 25 inches. These weight are placed vertically on a track. One at center
and the other at the bottom The 2 weight joined together take less energy to move toward the closer
 to the center you get. If you are moving the weights 25 inches you only have to move them 12 inches
to get to the 0 weight factor as centrifugal force does the rest. The first 2 or 3 inches are the hardest to
move. To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight.
The cam first moves the weights about 4 inches and then the leaver takes over and moves the weight just passed the center position. ( weights are equally divided in the center of the machine) Then
the centrifugal force takes over and moves the weights the other half of the way.
After this month I should have two companies, one in Canada and one in the US manufacturing them.
You can do a lot with a set of leavers.
 
Regards........Bob



Hi Bob
Nice to see you again and thanks for sharing.

helmut

spider4re

  • Newbie
  • *
  • Posts: 39
I have applied for a patent in Canada and US and since found out that the US shelve the application for 18 months then process it.
I have to wait about 12 more months for it to be processed.
.

Hello to all. Just like to say how glad I am to see the interest everyone has in my machine.
The machine I am referring to is the one at  www.newsourceofenergy.com . Lots of you say
it can't be done and others say how did you do it. As a matter of fact it was very simple and
I had help. George, a good friend of mine, who was an engineer since 1945 was very interested
in what I had done so far and suggested to try the cam and leaver mechanism that I used in
the unit in the short clip.
Now picture this in your mind. Get 2 weights that weigh 10 lb each and weld a strong rod
between them at about 25 inches. These weight are placed vertically on a track. One at center
and the other at the bottom The 2 weight joined together take less energy to move toward the closer
 to the center you get. If you are moving the weights 25 inches you only have to move them 12 inches
to get to the 0 weight factor as centrifugal force does the rest. The first 2 or 3 inches are the hardest to
move. To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight.
The cam first moves the weights about 4 inches and then the leaver takes over and moves the weight just passed the center position. ( weights are equally divided in the center of the machine) Then
the centrifugal force takes over and moves the weights the other half of the way.
After this month I should have two companies, one in Canada and one in the US manufacturing them.
You can do a lot with a set of leavers.
 
Regards........Bob




Bob - is the goal to create a machine that will run a generator to power a single family home thus eliminating the need for outside power supply?

Thanks

noonespecial

  • Sr. Member
  • ****
  • Posts: 278
Hi Bob,
First, I want to thank you for answering my emails and I certainly join everyone else in welcoming you back!
I'm still a little fuzzy on how the actual lever is activated. Is it at 90 degrees to the weights themselves? I can certainly see how the 36" lever can lift the weights. You mention the 10 pound weight at the end of the 36" but that sounds like the lever is in-line with the weights? Can you explain this a little more?
Thanks so much,
Charlie

noonespecial

  • Sr. Member
  • ****
  • Posts: 278

Bob - is the goal to create a machine that will run a generator to power a single family home thus eliminating the need for outside power supply?

Thanks

You should check out Bob's video on his website www.newsourceofenergy.com and you can see the incredible potential of his machine. This can easily run any generator and definitely eliminate the need for any outside power. The beauty is that you could even backfeed the grid (if allowable in your state) and end up getting a check each month from the power company!
Best regards,
Charlie

AB Hammer

  • elite_member
  • Hero Member
  • ******
  • Posts: 1253
Welcome Back Bob

 I have only recently got involved and have been talking with Larry C for he lives in Louisiana as I do. I am a blacksmith/armourer  Here are some of my past projects http://www.creationtime.com/hisbsaw.htm  and on youtube I am ABthehammer where I have posted some of my past non working wheels to help people.

MY question is. Are you fully done with the design or are you still looking for better ways?

noonespecial

  • Sr. Member
  • ****
  • Posts: 278
Here's my latest concept drawing based on what we know so far. Bob has confirmed that the cam is fixed and works as I thought from 3:30 to around 5:00 then the lever takes over. Larry, you might be able to modify your design in this way.
Best regards,
Charlie

noonespecial

  • Sr. Member
  • ****
  • Posts: 278

MY question is. Are you fully done with the design or are you still looking for better ways?

Hi AB,
I think Bob may be having problems accessing this site. He sent me an email yesterday to say that he is working on a new way to be able to lift more weight. He didn't go into detail in the email but maybe once its complete he will let us know.
Best regards,
Charlie

LarryC

  • Hero Member
  • *****
  • Posts: 911
Here's my latest concept drawing based on what we know so far. Bob has confirmed that the cam is fixed and works as I thought from 3:30 to around 5:00 then the lever takes over. Larry, you might be able to modify your design in this way.



May be able to modify. But, where did the arm with the round weights come from, it would have stuck out in the Bob K. pic. I can see how the lever could be hidden in the base.

@Bob, thanks for sharing. We really needed your help with the design. Looking forward to learning when we can order and how much.

Regards, Larry

PS: Unit slowly coming along. Getting ready for Ike.

noonespecial

  • Sr. Member
  • ****
  • Posts: 278

May be able to modify. But, where did the arm with the round weights come from, it would have stuck out in the Bob K. pic. I can see how the lever could be hidden in the base.

@Bob, thanks for sharing. We really needed your help with the design. Looking forward to learning when we can order and how much.

Regards, Larry

PS: Unit slowly coming along. Getting ready for Ike.

Hi Larry,
I was keying off of Bob's previous comment: "To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb (actually 60 but who's counting :) )plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight."

I don't know if my drawing is correct or not. And you are right that there is no arm sticking out in the video. From what he wrote, we know that there is a 10 pound weight pressing down on the long arm of the lever somewhere to lift the weights. This is the only way that I can envision it. You say that it could be hidden in the base but how would it act like a lever from below?
Best regards,
Charlie

LarryC

  • Hero Member
  • *****
  • Posts: 911
I was keying off of Bob's previous comment: "To do this, a strong rod 3 feet out from the center to the end of the circumference of the rotating
unit. This is were the pivot point is for the leaver to lift the weights. The actual length of the rod is 42
inches. A 42 inch rod acts like a pry bar36 inches to develop the force and 6 inches to do the work.
---------------------o---
36 inches            cl   6 inches
The 10 lb weight at the end of the 36 inch rod generates 30 lb (actually 60 but who's counting :) )plus 400 lb of weight from the wheel
rotating (flywheel affect) and with the pivot point 6 inches from the end , it can move a lot of weight."

I don't know if my drawing is correct or not. And you are right that there is no arm sticking out in the video. From what he wrote, we know that there is a 10 pound weight pressing down on the long arm of the lever somewhere to lift the weights. This is the only way that I can envision it. You say that it could be hidden in the base but how would it act like a lever from below?

Actually Charlie, I'm more confused then before ??? Number one is how does the 6 inch section of a lever lift a weight set 8 inches? The second part of that problem is the long end only has one clock position (30 degrees) to move the short end.

About the 36 inch rod discussion, in my last version and Bob K. pic version, the weights moved 24 inches, but with the unusable 1 foot section in the center, the connecting rod was 36 inches. So maybe Bob is talking about a new design with a 25 inch connecting rod.

In your drawing it seems the lever with the pivot and stops are attached to the base. Since Bob K. machine was offset to the left on the base, it seems that the lever could be attached to the base but a little lower.

Your solution is one way, just didn't seem to fit the previous pic. Seems like it would be more of an L shaped lever connected to the backside of the unit, which could remain out of site until pulled. Just can't figure out how to get the distance required.

Not sure if the various 10 lb weight discussions was just a typo or 2 different sets.

@Bob,
Please assist, as we are confused again.

Regards, Larry

noonespecial

  • Sr. Member
  • ****
  • Posts: 278
Actually Charlie, I'm more confused then before ??? Number one is how does the 6 inch section of a lever lift a weight set 8 inches? The second part of that problem is the long end only has one clock position (30 degrees) to move the short end.
Good point! Seems like my previous drawing would work better. So I wonder how he is doing it? In my last email to him I asked specifically how the lever worked but he didn't really say. Just said that he is working on a new way to lift even more weight with a 'super-charger' (his words).

Quote
About the 36 inch rod discussion, in my last version and Bob K. pic version, the weights moved 24 inches, but with the unusable 1 foot section in the center, the connecting rod was 36 inches. So maybe Bob is talking about a new design with a 25 inch connecting rod.
Its possible that there is no 'unusable' section in the middle if the weights are mounted and track outside of the end of the center shaft. And what happened to the 2.5" and 10" lever? Perhaps he has completely revamped his design since he wrote before.

Quote
In your drawing it seems the lever with the pivot and stops are attached to the base. Since Bob K. machine was offset to the left on the base, it seems that the lever could be attached to the base but a little lower.
Your point is well taken and there must be more to this lever that he is not explaining. His crude drawing of the 36"-----------------cl-----6" also seems to indicate that he is leveraging the weights from left as well.

Quote
Your solution is one way, just didn't seem to fit the previous pic. Seems like it would be more of an L shaped lever connected to the backside of the unit, which could remain out of site until pulled. Just can't figure out how to get the distance required.
Agreed. I hope we don't have to wait the additional 12 months before his patent is available before we figure this out :) .

Quote
Not sure if the various 10 lb weight discussions was just a typo or 2 different sets.
This is the part that threw me and why I embarked off on my new incredibly beautiful but hideously wrong drawing...:) .
Quote
@Bob,
Please assist, as we are confused again.
Yes please.
[/quote]

BTW, I was watching the weather and they said that Ike may track more toward Houston so hopefully it will only skirt your area.
Best regards,
Charlie