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Author Topic: Free energy from gravitation using Newtonian Physic  (Read 99192 times)


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Re: Free energy from gravitation using Newtonian Physic
« Reply #210 on: March 23, 2009, 05:32:36 AM »
The newest model of the cylinder and spheres is pictured with its three attachable pipes. The tall pipe is a 3 inch inside diameter pipe that is stopped by the spheres, just as the tether string enters the slit, when the pipe has a mass of 712g. The widest pipe is a 4 inch inside diameter pipe that has a mass of 541g. The third pipe is a combination of 215g of 3 inch pipe and 428.4g of 3 inch pipe couplers. All three of these add-on attachments have about the same Newtonian momentum when rotated. All three add-on pipe attachments will be stopped by the spheres just as the tether enters the slit in the cylinder, the top cylinder is also stopped of course.

First I determined the necessary quantity of 3 inch pipe mass that is needed to have the cylinder stop just as the tether enters the slit in the cylinder side wall. This is done by trial and error; I just kept taping more and more dimes and pennies to the side wall of the 3 inch pipe until I found the mass that allows the pipe to stop at the appropriate position when the rotation stops. You add more mass if the cylinder is moving backward when the string is in the slit and you subtract mass if the cylinder is moving forward when the tether is in the slit. When you determine the appropriate mass you then cut a new 3 inch pipe to length with the appropriate mass (without the pennies).

This trial and error determination of mass for the 3 inch I.D. pipe took about 20 attempts, but once that that mass is determined I can cut the second two pipes (4 inch and 3 inch with couplers) to the appropriate mass the very first time. Why is that possible that I no longer need trail and error to determine the mass of the second two pipes?

One of the variable factors in the quantity of mass stopped by the spheres in the cylinder and spheres (top coupler), just as the tether enters the slit, is tether length. But once the mass of the 3 inch pipe is determined you need only match its Newtonian momentum when replacing it with other add-on pipes. A 4 inch I.D. pipe has about 4/3 the rotational velocity of a 3 inch pipe and therefore needs only ¾ of the mass to have equal Newtonian momentum.

The three add-on pipes do not have equal angular momentum when rotated and they do not have equal rotational kinetic energy. This not only proves that angular momentum is not conserved in the lab; it also proves that energy has been made in the lab.

This latest cylinder and spheres experiment takes 977g (total mass of cylinder with spheres) of mass moving in a circular path and gives all that motion to 133g (the spheres). Newtonian physics requires that that mass (133g) must then be moving 7.35 times as fast.

With the spheres moving 7.35 times as fast the energy content of the system has increased to 735% of the original energy.    1/2mv² (1/2 * .977 * 1 * 1 = .4885 joules, ½ .133 * 7.35 * 7.35 = 3.524 joules; 3.592/.4885 = 735%

This is the experiment that is worth the Nobel Prize in Physics.