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Author Topic: Free energy from gravitation using Newtonian Physic  (Read 80056 times)

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #150 on: August 16, 2008, 02:27:18 AM »
spyblue:   I went to the computer store and told them about not being able to post videos (on the internet) from the DVDs my recorder makes. They said all the DVD recorders (they have) format the same way. They sold me a Dazzle that was supposed to reformat and make a DVD that was computer friendly. I guess my computer is to slow because that did not work either.

Rather than continuing to try to post videos I have decide to go to several less favorable options. I can send free DVDs in the mail; just give me your land address. These DVDs play fine but no one has been able to post from these DVDs.  Also; I think I shall take frame by frame pictures of the monitor as the DVD plays and post those. My player has frame by frame capabilities. A picture of a monitor is poor quality but better than nothing I suppose. You can see the cylinder clearly stopped for about two frames, 2/30 sec.

Free Energy | searching for free energy and discussing free energy


Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #151 on: August 16, 2008, 08:58:03 PM »
This site would not let me post a picture so I posted over in: free_energy; Files; 8-15-08 cylinder and spheres. This is a picture of a monitor and is a little dark. The cylinder is stopped and appears to be as clear as the background. The cylinder has a mass about four times that of the spheres. The spheres are a blur.

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #152 on: August 20, 2008, 12:54:24 PM »
I posted four more pictures on  the free_energy site

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Re: Free energy from gravitation using Newtonian Physic
« Reply #152 on: August 20, 2008, 12:54:24 PM »
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Offline AB Hammer

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Re: Free energy from gravitation using Newtonian Physic
« Reply #153 on: August 20, 2008, 09:27:35 PM »
@pequaide

 Which free energy sight?

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #154 on: August 20, 2008, 11:26:34 PM »
Type (free_energy) in your search engine. Ideally there is about five times more energy after the spheres open, than if the spheres had remained up against the cylinder.

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Re: Free energy from gravitation using Newtonian Physic
« Reply #154 on: August 20, 2008, 11:26:34 PM »
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Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #155 on: August 21, 2008, 12:10:39 AM »
Once you are on line type: free_energy, in your Google search engine. Choose: free energy claims, then files, then posted by pequaide, or 8-19-08 four frames. The Yahoo engine does not bring you to the same site. But it is a Yahoo group site.   

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #156 on: August 22, 2008, 02:17:06 AM »
I posted ten more pictures (in order) from a video (under files) on the free_energy site.

If the spheres had been glued to the cylinder the circumference velocity of all the parts (after they were spun and dropped) would have remained about one meter per second. That would be roughly 690 grams moving 1 m/sec.

In actuality the spheres swing out and absorb all the motion.  That will give us 133.6 g that now must have (.690 kg * 1 m/sec) .690 units of momentum. .1336 kg  * 5.16 m/sec = .690 units of momentum

This is an energy increase of Ke = ? mv?: .5 * .690 kg * 1 m/sec * 1 m/sec = .345 joules to .5 * .1336 * 5.16 * 5.16 = 1.778 joules. 515%

You can make a slideshow of the ten frames, energy has been made in the lab.

Free Energy | searching for free energy and discussing free energy

Re: Free energy from gravitation using Newtonian Physic
« Reply #156 on: August 22, 2008, 02:17:06 AM »
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Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #157 on: August 27, 2008, 12:51:03 PM »
See the picture labeled 8-25-08 drawing, in free_energy, under files, gravity wheel

Only mass A is under gravitational acceleration. Gravity will exert a force of 9.81 newtons upon mass A and then, by design, upon the entire system.

All the parts of the system are moving at approximately the same speed. Therefore it is obvious that the acceleration of all the parts is the same.  The total mass of the system is ten kilograms. Since F = ma;  9.81 N = 10 kg * a, for an acceleration of .981 m/sec?.

d = ? at? or √(d * 2 / a) = t: So mass A will travel a distance of one meter in 1.4278 seconds.

d = ? at?,  or d = ? v?/a because t = v/a,  or √(d * 2 * a) = v: So after mass A travels one meter the whole system (10 kg) will have a velocity of 1.4007 m/sec.  This is 14.007 units of momentum or 9.81 newtons applied for 1.4278 seconds.

To get mass B to stop you must apply 9.81 newtons for 1.4278 seconds or the equivalent. In 1.4278 seconds mass B can travel straight up 10 meters.

Offline hartiberlin

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Re: Free energy from gravitation using Newtonian Physic
« Reply #158 on: September 25, 2008, 03:49:26 AM »
Hi,
if you have a DVD,you can easily use the freeware program:
VOB2MPG
http://software.badgerit.com/VOB2MPG.html

to extract the whole DVD to single MPEG files.

Then you can upload these to youtube or
use
Virtualdubmod
http://virtualdubmod.sourceforge.net/

to recompress them to smaller AVIs
with DIVX.com codec for instance and
MP3 audio.

Hope this helps.

Let usknow, when you have uploaded some  videos
to youtube.com or anywhere else.
Many thanks.

Free Energy | searching for free energy and discussing free energy

Re: Free energy from gravitation using Newtonian Physic
« Reply #158 on: September 25, 2008, 03:49:26 AM »
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Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #159 on: September 25, 2008, 11:54:14 AM »
Thanks; hartiberlin, I will work on it. I am also repeating Laithwaite's figure 7 experiments so I would like to get that out there also.

  Confirmation of the data from the cylinder and spheres experiment has been obtained from the Laithewaite’s Mass Displacement experiments

Similar experiments to the cylinder and spheres have been performed by Prof. E.R Laithwaithe at the University of Sussex. I found it under Gyroscopes – Everything you need to know, after searching ‘Laithwaithe free axis’.   

Of particular interest is figure 7, elsewhere Laithewaite states that momentum is conserved in his experiments but energy is not conserved. I have performed experiments very similar to his, but the cylinder and spheres yield more energy. Laithewaite’s data confirms the concepts behind the cylinder and spheres, because energy has been made in the laboratory, in the United Kingdom.
 
To find Laithwaite’s energy producing experiment click on the link (www.gyroscopes.org/masstran.asp - 22k) and go down to Mass Displacement by Circular Motion. Figure seven is an overhead view (I assume) of three objects on a frictionless plane.

Lets give the object A1-A2 (the sliding center mass, Laithwaite calls it the centre pivot anchor block) a mass of 2 kg and M1 and M2 a mass of 1 kilogram each.

Lets swing M1 and M2 down from .2039 meters so they both have a velocity of 2 m/sec. d = ½*a*t*t or d = .5 * v * v / a

In figure seven that would give us one kilogram going north at 2 m/sec and one kilogram going south at 2 m/sec. They both transfer some of their motion to the center sled (A1, A2). Let us assume that at some point they are all moving at the same velocity, which would mean that all three objects would be moving one meter per second. This would be the conservation of linear Newtonian momentum; 4 kg * 1 m/sec equals 2 kg *2 m/sec.

 In Laithwaite’s figure 7 he starts at a high energy point and goes to a low energy point and then back to a high energy point. At first M1 and M2 have all the motion after they are accelerated by a spring, this is a high energy point. Then the motion is shared with the center sliding mass that contains A1 and A2, this is the low energy point. The lowest energy point is obtained when the velocity of the center mass is closest to the velocity of M1 and M2. The energy is highest again when all the motion returns to M1 and M2.

Lets start the motion at the low energy point by dropping the sliding center(A1 and A2) mass and M1 and M2 .051 meters. Arrange that the masses go in the correct direction of course. Let the sliding mass be equal to the sum of M1 and M2. The original velocity of all masses will be one meter per second. The original energy will be 2 joules.

After the system proceeds from the low energy point to the high energy point M1 and M2 will have all the motion. They will have to be moving 2 m/sec to conserve momentum and the energy content will be 4 joules. With velocities of 2 m/sec M1 and M2 can rise .2034 meters: 2 kg at .2034 m is twice the energy of 4 kg at .051 meters.

Now you may ask: how do you know that linear Newtonian momentum is conserved; because the objects are moving in a circular path?

First: Well what if you arrange a head on collision between M1 (moving 2 m/sec) and the center sled at rest, the three kilograms would move away at .667 m/sec.  Then if you (in line) collide M2 at 2 m/sec into the combination you would have four kilograms moving one meter per second.   Why would you expect different results from the arrangement in figure seven?  Would anyone claim that Newtonian physics does not apply to objects moving in a circular path?

Second: The arrangement in figure seven returns to having only M1 and M2 in motion and the center sled is stopped. Ideally that motion should again be 2 m/sec. How can you have 4 units of momentum at the end of the experiment unless you have 4 units of momentum all the way in between; from start to finish?

Third: Laithwaite said that he observed that momentum was conserved not kinetic energy. If kinetic energy was conserved when the 3 objects are moving at the same velocity then that velocity would have to be 1.4 m/sec. This would mean that 4 units of momentum would give 5.6 units and 5.6 units would yield only 4: a clear violation of Newtonian physics. From mv and 1/2mv²

Here is the importance of this experiment. Ballistic pendulums conserve linear Newtonian momentum. They conserve it when the incoming projectile is a pendulum bob and the final motion of the block projectile combination is linear, on a frictionless plane. They conserve it when the incoming motion is linear and the final motion is a pendulum. They conserve it when both incoming and outgoing motion is a pendulum. Depending on the mass distribution of the projectile to block they can lose 50%, 80%, or 95% etc. of the energy of motion. Always this energy loss is blamed on friction that makes heat. How can heat be blamed on the energy losses in the sliding center experiment when the objects don’t even touch? 

If heat is to blame for the loss of energy (when the motion is shared) then how does the heat come back when the energy is restored; when the motion is again only in M1 and M2?

Laithwaite pays special interest in the fact that the center of mass does not move.  This would mean that when M1 and M2 are directly above and below the center sled and the total mass of both M1 and M2 equal the mass of the center sled, that their velocities must be equal. Because half the mass is moving to the right and half the mass is moving to the left, they both must be moving at the same velocity in order that the center of mass holds its position.

If you have access to a frictionless plane Laithwaite’s experiment should be easy to perform. Are we scientists enough to repeat it?


I have repeated Laithwaite’s figure seven experiments and it appears that he is correct in that the center of mass seems to stay in the same place. In a since this is also the center of momentum, in that if the center sled has twice the mass (of M1 and M2 combined) it has half the velocity (when they are all three in a straight line). This would mean that M1 and M2 always give the center sled half the momentum no matter what mass the sled has.

When M1 and the center sled (with a mass twice that of the combined mass of M1 and M2) and M2 are in a straight line the sled must have half the velocity. If M1 and M2 move 1 cm left then the center sled must move .5 cm right. It seems like this would mean that the experiment proceeds at about the same rate (given the same original velocities) no matter what the mass of the center sled. Because if the M1 and M2 pucks always give half their motion to the center they will always have half left for themselves. But the shape of the oval changes with changing center mass, and maybe that would change the rate at which the experiment proceeds. At any rate this is a very interesting experiment.

If the center of mass stays in position this allows for different quantities of energy to be produced. Because a center mass of 4 kg moving .5 m/sec is not the same energy as 2 kg moving 1 m/sec. In fact if kinetic energy would be conserved the center of mass could not remain is position, because the velocities that conserve momentum retain the center of mass’s position, any other velocities would not move the appropriate quantities of mass to the appropriate position necessary to maintain the position of the center of mass.   

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #160 on: September 29, 2008, 12:50:12 PM »
See http://groups.yahoo.com/group/free_energy/ then go to files, then to pictures titled 9-27-08 Laithwaite’s figure 7.

3 photographs of Laithwaite’s Figure 7
From position one (photograph one) a small double lever is used to accelerate the pucks on the end of the string; one is accelerated north and one south (relative directions). The center puck is initially at rest and has a mass of 76g; the end pucks have a mass of about 32 grams each. That means the center of mass is closer to the center puck than to the end pucks.

As soon as the end pucks begin moving north and south the center puck begins moving right. When the center puck reaches the center of mass (which is about the center of the table) the end pucks are in the positions of photograph two, directly above and below the center puck. If the center of mass is to remain in position as Laithwaite stated then the velocity of the end pucks will be moving with half their original velocity, and the center puck will be moving with 64/76 *1/2 the original velocity of the end pucks. These velocities conserve linear Newtonian momentum, and the velocities also conserve the position of the center of mass. This is what the experimenter will observe upon doing the experiment.

All this motion is then returned to the end pucks upon moving from photograph 2 to photograph 3. In photograph three the center puck (now on the right side) is again at rest. The energy change from photograph 2 to photograph 3 is 217%. Start the motion in the center (photograph 2) and you can make energy.   

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Re: Free energy from gravitation using Newtonian Physic
« Reply #160 on: September 29, 2008, 12:50:12 PM »
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Offline DrWhat

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Re: Free energy from gravitation using Newtonian Physic
« Reply #161 on: October 11, 2008, 02:36:26 AM »
Hi Pequaide,

I find your writings and pics interesting. Hans got me looking at your posts.

Yahoo Tech groups is a low memory messy site.

You should post on somewhere better like Besslerwheel.com

At least your posts will sit together better. And the images can be posted there.

Just friendly suggestions,

Damian

Offline infringer

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Re: Free energy from gravitation using Newtonian Physic
« Reply #162 on: October 11, 2008, 02:58:45 AM »
If you can put them to a DVD you can place them on a computer...

Simply put.

If you do not have one already then buy a dvd burner off the internet affordable for anyone now!: http://www.newegg.com/Store/SubCategory.aspx?SubCategory=5&name=CD-DVD-Burners

First download DVDFabHDDecrypter FREE:  http://www.dvdfab.com/free.htm

Then download autogk: http://www.autogk.me.uk/

Encode the video using Xvid Quality and encode at the maximal amount that youtube will allow. http://www.youtube.com

Viola you have video for the masses!

The instuctions are simple if you can and have been posting to this forum it should take you no longer then one day to accomplish this and finally get your message out to people in video form.

If you do not have highspeed internet which may be the case as I have not read the whole thread send a copy to someone and have them do it for you or do the encoding and have a friend do it for you this would be the fastest.

-infringer-

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #163 on: October 14, 2008, 02:19:03 AM »
Thanks: DrWhat, infringer and hartiberlin, all good advice. I will work on it.

Offline pequaide

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Re: Free energy from gravitation using Newtonian Physic
« Reply #164 on: December 23, 2008, 03:13:29 PM »
You may wish to view BesslerWheel.com, energy producting experiments, pequaide. There are some interesting developments there.

 

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