Author Topic: Pulse Motors- Your building them wrong. (Read 13576 times)

MagnaProp · « **Reply #120 on:** November 07, 2023, 04:17:22 AM »

Quote from: bistander on November 05, 2023, 05:48:37 PM

...Use Ohm's Law. V = I × R. Or I = V / R. So your 12 volt supply divided by the 6 ohm resistance of the coil takes 2 amperes to satisfy the equation...

Hi bi. Thanks for all the info in that post. It has helped me understand it a bit better.

Quote from: Thaelin on November 06, 2023, 02:14:11 AM

All:
I am off line for a bit...

Mags:
The coil I have is an old wire spool from RS with 2 strands of #20 looped to one and will draw about 3 amps if I let it. Will in fact tho repel the 2 N43 .5 X .5 inch neo's...

No worries Thaelin. Life often gets in the way and it sounds like you are doing what needs to be done which is good. I for one will still be here when you get back up and running since I have a bit to go in learning how to make a pulse motor circuit and such. It'll be good to have you back when you're ready.

Thanks for the info on your spool and setup. I made a tweak to my electro magnet that got it up to 190mT using the same 15.5 volts and 3 amps as before but even that only matches one of my neos now. I was hoping to get up to about 400mT which is about 5 neos stuck together. So I'm still thinking of making a new coil.

rakarskiy · « **Reply #121 on:** November 07, 2023, 08:25:46 AM »

Quote from: MagnaProp on November 05, 2023, 01:34:43 PM

I'm trying to understand this better. I understand that amp turns is the amps times turns.

I don't understand how we got the 2 amp info in (2 amps at 12 volts= 24 watts.) from knowing only (300 turns, and it has a resistance of say 6 ohms).

So we started with 300 turns and 6 ohms resistance. How did we get the 2 amp value from that?

To calculate the voltage drop in a circuit, we use the following formula: I=Ui/R, where I is the current in the circuit (measured in amperes, A), Ui is the voltage drop (measured in volts, V), R is the resistance, the unit of which is the ohm.
In this case, the formula for the effective voltage in the circuit is U=IR=E-Ir.
Power is defined by: W=UI, at the same time the current corresponds to the expression: I=U/R.
For the value of current in the circuit (source + load) the following condition must be fulfilled: Ui/R=I=U/R
it is kind of an axiom.
An example of circuit calculation is at the end of my article.

https://rakatskiy-blogspot-com.translate.goog/2017/08/generator-of-free-energy-vega-ukraine.html?_x_tr_sl=ru&_x_tr_tl=en&_x_tr_hl=ru&_x_tr_pto=wapp

Excel spreadsheet for calculating circuit elements:

https://docs.google.com/spreadsheets/d/1aRyIXNVCGkBHZj6Nzhjejwpj0LJ_kfmA/edit?usp=sharing&ouid=103757942593314724986&rtpof=true&sd=true

MagnaProp · « **Reply #122 on:** November 07, 2023, 01:28:55 PM »

Thank you. Math and I don't get along too good so I appreciate the help on that.

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Author Topic: Pulse Motors- Your building them wrong. (Read 13576 times)

MagnaProp

Re: Pulse Motors- Your building them wrong.

rakarskiy

Re: Pulse Motors- Your building them wrong.

MagnaProp

Re: Pulse Motors- Your building them wrong.