Language: 
To browser these website, it's necessary to store cookies on your computer.
The cookies contain no personal information, they are required for program control.
  the storage of cookies while browsing this website, on Login and Register.

Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Mechanical resonant oscillation as basic overunity method  (Read 5799 times)

Offline perpetual

  • Jr. Member
  • **
  • Posts: 69
Re: Mechanical resonant oscillation as basic overunity method
« Reply #60 on: April 20, 2023, 08:19:31 AM »
You are talking nonsense as usual. Container made of steel can have any degree of buoyancy, positive or negative simply by increasing or decreasing the size of air chamber it has within itself.

So spindle can be made out of 10kg of steel and contain within itself an air chamber of proper size so that its weight in water is -10kg. These are simple, obvious things.

Offline Willy

  • Full Member
  • ***
  • Posts: 218
Re: Mechanical resonant oscillation as basic overunity method
« Reply #61 on: April 20, 2023, 08:30:27 AM »

Show me a container that does not sink some amount below the water line (100% buoyant), when it is full of air, and its hull must be less dense than water.

Offline perpetual

  • Jr. Member
  • **
  • Posts: 69
Re: Mechanical resonant oscillation as basic overunity method
« Reply #62 on: April 20, 2023, 08:37:30 AM »
Of course it sinks some amount below water, it must displace it's own weight. That is totally irrelevant.

Spindle made of 10kg of steel with volume which displaces 20kg of water will have -10kg in water and will rise to the surface with force of 10kg.

Offline Willy

  • Full Member
  • ***
  • Posts: 218
Re: Mechanical resonant oscillation as basic overunity method
« Reply #63 on: April 20, 2023, 02:49:27 PM »

Assuming a 100% buoyancy was not a bad guess on my part, given that your
descriptions are worth crap and that you are really bad at this.

Its not my fault that you have to be tricked into giving the device descriptions.
Its like pulling teeth.

By the way, are you totally unaware of the fact that you have lost on every count
during these arguments ?
 
A quote from perpetual
"Ok, let's say conditions are a 10 meter tall tube half meter wide, obviously fully
filled with water above a water pool wide enough to support such large column of water."
The end of quote

Your description in the quote above is again a poor one. It is lacking in detail and
practically worthless.

At least we now know that, what ?

The spindle is less than 100% buoyant
The spindle is made of steel
The spindle is hollow.

A quote from perpetual
Spindle made of 10kg of steel with volume which displaces 20kg of water will have -10kg in water and will rise to the surface with force of 10kg.
The end of quote

The spindle when sealed and fully submerged displaces 20,000 centimeters ^3
or 0.02 meters ^3 of water (displaces 20kg of water)
The spindle by itself, has a weight out of water of 10 kg
The spindle has a weight when sealed and fully submerged in water of - 10 kg


Offline perpetual

  • Jr. Member
  • **
  • Posts: 69
Re: Mechanical resonant oscillation as basic overunity method
« Reply #64 on: April 20, 2023, 05:39:39 PM »
My descriptions are perfectly detailed and clear, it is due to the fact you are really really bad at this that your guessing is totally wrong, confused and ridiculous.

You claimed a ship made of steel full of water would float lol, you can't deny it it's there. To make it even more absurd you also claim 10kg weighing container cannot have -10kg weight in water lol.

It is not my fault that you can't understand the simple principle of buoyancy, you are only tricking the wrong descriptions out of yourself and pulling your own teeth.

You still ridiculously deny the simple fact that steel container weighing 10kg can be made -10kg buoyant (or any value) by changing the amount of displaced water by changing the size of the air tank in it.

And again you wrote a confused worthless mess and you missed the key part which you could've used against me - and i literally gave you the answer - but since you are really REALLY bad at this, you of course missed it. I literally told you spindle has to displace 20kg of water to have -10kg weight in water. This means once that air is released at the top it displaces more than 10kg of water, almost 20kg. Of course, you missed it.

BTW are YOU aware you lost on every count during these arguments, ever since you claimed that Travis Effect is not overunity, to your idiotic claim that pressure at the bottom of the tube rises with height of the tube, to your claim that force of the partial vacuum at the top of the tube is equal to the force the tube exerts upon the supports (altho only force tube exerts upon the supports is the weight of the tube itself and that has absolutely nothing to do with force of the partial vacuum, partial vacuum being the function of difference in height between bottom and the top and we cannot even talk of vacuum at all below 10 meter height since up to that height tube is completely filled with water - no empty space, no vacuum, we can only talk difference in pressure), to denying that linked perpetual overbalanced wheel from India is real.....

My descriptions are perfectly detailed and of high worth, only things lacking in detail and practically worthless are your confused constructs. You are incapable to understand even the basics.

Unlike you i admit my errors and i have to point them out to you since you are incapable of, you on the other hand can't even see your own errors and when i point them out to you you refuse to admit them like a 5yo.

It took you days just to admit pressure at the bottom does not rise with height of the tube. Everyone saw how you sleazily tried to confuse the issue and dragged it on and on and on before finally admitting you were WRONG. (just like you are wrong for Travis effect etc).

And to remind of another of your pearls you claimed my spindle will not sink even when full of water, quote...

"The spindle will not sink to the bottom of the tube even when the spindle is full of water. "

Which is literally saying a steel ship full of water floats. LOL. I have never and i really mean NEVER read anything dumber than that.

And to make it more absurd and ironic, AT THE SAME TIME you deny that steel tank weighing 10kg can be made buoyant -10kg (or any degree) in water.

So not only you make absolutely dumb statements, you also totally contradict yourself.

Sorry bud. It is great fun for me to watch you wriggle in your confusions and misconceptions, since i have entered into a battle of wits with an unarmed opponent.

Nix

Offline perpetual

  • Jr. Member
  • **
  • Posts: 69
Re: Mechanical resonant oscillation as basic overunity method
« Reply #65 on: April 22, 2023, 04:54:23 AM »
As an example that my ideas get proven as overunity, 3 years ago i proposed this idea

"I had this idea to pulse high inductance coil with short square pulse, so short virtually no current gets through the coil and then collect the backEMF that develops across the coil."

https://overunity.com/7837/magnetic-resonance-devices-based-on-don-smith-concepts/msg551080/#msg551080

At the time i had no idea that exact principle was already proven as overunity in 2017. by Tanju Argun. He is doing various stuff here but main thing i refer to is, quote from video description

"In 1993 Tom Bearden came up with the idea of “Massless Displacement Current”. I was inspired by that.

As you might know there is a process called “The Skin Effect” where Electrons, before forming a current, must travel from the center of a conductor to the peripheric rim to travel. The time, the electrons traverse from center to the rim is called the” Relaxation Time”. We are talking Microseconds here.

So, what I am simply doing here is, just letting a big Capacitor to sniff the Potential of a 24 volts Battery for only 100 Microseconds. During these 100 microseconds, electrons start to move to outside perimeter of the conductor to start the current. But unfortunate for them time is not enough to form the current.  Instead those trapped electrons just attain a “Potential Gradient “across them. So, the capacitor gets the Potential Difference across it with minimum current, which is called the “Massless Displacement Current”.

In analogy; the young man “the capacitor”, just catches -a glimpse of a passing by super-mini skirted young lady- “the battery”.

Capacitor is loaded with minimum power.


Ideal case is to use iron wire or doped conductors and plates to block the electrons from forming a current by increasing the “Relaxation Time”.

After 100 microseconds, the Mosfet switch (Blue) opens and disconnects the battery from the capacitor.

Another Mosfet switch (Yellow) closes and connects the loaded capacitor to the load for just 1 millisecond (In our case the load is the Bedini wheels and Coils).

After that millisecond when both Blue and Yellow switches open, this time the Red mosfet switch connects the charger to the battery when nothing else is connected. Red switch connection time is adjustable.

All these timing operations and void loop is controlled by an Arduino Uno micro-computer composed of a simple sketch of time delays."

https://www.youtube.com/watch?v=70_xKJh91eE

Nix