Another setup using 1 micro flashtube and 1 4-terminal (“U”) fluorescent:


[120-500 pW]


Photonic output flux: ~80 Lumens
Estimated power conversion: 1.3W


photovoltaic capture: 0.4V, I (intermittent): 20mw


Photon output is verifiably greater than electrostatic input.


I will continue to experiment along these lines.
I believe that univectoral reflectors are key,
In that 90% of the light emits in directions away from the solar cell.


A more powerful electrostatic generator may be able to make use of cylindrical or spherical solar arrays.

The question was posed as to “why” or “how” it is possible for more light energy to be emitted than electrical energy input.


The best attempt i can give at that is as follows:


At the atomic scale, “power” and “current” lose meaning due to the perspective.
we no longer measure in Volts and Amps.
But in Electron-Volts, and a time scale determined by the atomic structure.


For all intensive purposes, Potential is all that is necessary.


Current is a factor of system losses + the ionization/deionization rate
provided that the system doesnt ‘leak’ greatly, increasing the current will increase the amount of cascading that occurs, but not the rate at which it takes place on a physical level. Meaning that forcing higher currents is exactly like having multiple arc-reactor in parallel. But at a greater loss.


So if we used lets say 30 picowatt arc reactors to dimly light 30 tubes
To produce the light of 1 tube on a wall-jack


The 30 tubes would use about 1000x less energy.
To produce the same light.


our solar cells are very inefficient. At best we can convert less than half of the tube’s light back into electricity. You can’t self-run a lamp + solar cell.
But if the solar cell converts 500x more than what’s making the photons
We CAN!


Short answer: it takes less energy to create the photons than the photons provide.
A laser driven by electrostatic potential is exponentially more efficient than one driven by force.
[example: T.E.A. and those mica-converters]