Storing Cookies (See : http://ec.europa.eu/ipg/basics/legal/cookies/index_en.htm ) help us to bring you our services at overunity.com . If you use this website and our services you declare yourself okay with using cookies .More Infos here:
https://overunity.com/5553/privacy-policy/
If you do not agree with storing cookies, please LEAVE this website now. From the 25th of May 2018, every existing user has to accept the GDPR agreement at first login. If a user is unwilling to accept the GDPR, he should email us and request to erase his account. Many thanks for your understanding

User Menu

Custom Search

Author Topic: Holcomb Energy Systems:Breakthrough technology to the world  (Read 439213 times)

rakarskiy

  • Hero Member
  • *****
  • Posts: 924
    • Free Energy Systems (UA)
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #810 on: June 22, 2022, 03:15:39 PM »
How can you say "1 J = 1 Watt / second"?

Correct is:

1 J = 1 watt second

J = Joule, a unit of energy or work
W = Watt, a unit of power, defined as the rate at which work is done or rate at which energy is transfered or converted, therefore Power in watts = Joules / second, 1 W = J / s. Math tells us that:
1 J = 1 W • s

Not as you say!
bi

Quote
Power is a scalar physical quantity that characterizes the instantaneous rate of energy transfer from one physical system to another in the process of its use and is generally determined through the ratio of the transferred energy to the transfer time. In the SI system, the unit of power is the watt, which is equal to the energy of 1 joule transmitted over a time of 1 second (1 W ≡ 1 J / s), and any numerical value of power indicated in any information sources, by default, implies just such second time interval

In your opinion, do you need to write down the speed not [m / s] but [m * s]?

Do you want news that the concept of ENERGY on RU and EN on Wikipedia is different

Good luck, gnaw science.

PS
--------------
don't forget that pandora's box is open
https://youtube.com/shorts/0LmQzSx06uE

bistander

  • Hero Member
  • *****
  • Posts: 705
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #811 on: June 22, 2022, 03:33:43 PM »
Do you want news that the concept of ENERGY on RU and EN on Wikipedia is different

Good luck, gnaw science.

In your opinion, do you need to write down the speed not [m / s] but [m * s]?
...

I have no idea what you're talking about. Or what your question means.

Division is s not the same as multiplication.
/ is not •

Watt/second is not same as watt second.

Look it up. Read your own pasted article.
bi

rakarskiy

  • Hero Member
  • *****
  • Posts: 924
    • Free Energy Systems (UA)
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #812 on: June 22, 2022, 03:40:05 PM »




You probably did not study well, since the actual power is confused by the amount of power. But the amount of power is an off-system unit, invented for billing cash cows by corporations. The engineer does not need it, he needs a physical quantity.  https://www.quora.com/What-is-the-S-I-unit-of-speed-1


PS
--------------
don't forget that pandora's box is open
https://youtube.com/shorts/0LmQzSx06uE


alan

  • Hero Member
  • *****
  • Posts: 716
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #813 on: June 22, 2022, 04:07:10 PM »
yeah, watt is an indicator for average energy consumption, not for low-duration high energy peaks: a 1kj pulse with a  2ms duration  = 1kj*2ms=2 joules-second, the power rate of such a pulse per second is 2 watt. cmiiw.

rakarskiy

  • Hero Member
  • *****
  • Posts: 924
    • Free Energy Systems (UA)
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #814 on: June 22, 2022, 05:46:20 PM »
If you bring the indicator to SI, then to a second, if the moment is real. Only the calculation of the chain will be done on the world value. And the output power is conditionally average. Well, it's time to understand the axiom right off the bat.

alan

  • Hero Member
  • *****
  • Posts: 716
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #815 on: June 22, 2022, 05:56:44 PM »
If you bring the indicator to SI, then to a second, if the moment is real. Only the calculation of the chain will be done on the world value. And the output power is conditionally average. Well, it's time to understand the axiom right off the bat.
What should I read to understand what you meant regarding energy, russian vs si, etc? I'm listening.

bistander

  • Hero Member
  • *****
  • Posts: 705
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #816 on: June 22, 2022, 06:29:07 PM »
yeah, watt is an indicator for average energy consumption, not for low-duration high energy peaks: a 1kj pulse with a  2ms duration  = 1kj*2ms=2 joules-second, the power rate of such a pulse per second is 2 watt. cmiiw.

alan,
1 kilojoule delivered, converted, otherwise used in 1 millisecond indicates an average of 1 megawatt of power over the 1 millisecond duration.

This is standard physics and conventional math. Study reputable sources. Don't take my word. Look it up. But certainly don't believe anything Mr. rakarskiy writes.
bi

alan

  • Hero Member
  • *****
  • Posts: 716
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #817 on: June 22, 2022, 08:51:32 PM »
bistander
"To understand what Joules × seconds means, one must understand the terms by themselves.  The Joule is a unit of energy, and the second is a unit of time.  So, what 500 J × s means, is that there is a source of energy that I can use in the following manner: 500 Joules for 1 second; or 250 Joules for 2 seconds; or 100 Joules for 5 seconds; or 1 Joule for 500 seconds; or in any combination of numbers who's product is 500!"
Thus: 1 joules x seconds = 1kJ for 1ms. 
i wonder if that's even right lol.  also 1 joule-sec = 1 joule/Hz

watt = joules/sec 
joules = watt-seconds

bistander

  • Hero Member
  • *****
  • Posts: 705
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #818 on: June 22, 2022, 09:51:04 PM »
bistander
"To understand what Joules × seconds means, one must understand the terms by themselves.  The Joule is a unit of energy, and the second is a unit of time.  So, what 500 J × s means, is that there is a source of energy that I can use in the following manner: 500 Joules for 1 second; or 250 Joules for 2 seconds; or 100 Joules for 5 seconds; or 1 Joule for 500 seconds; or in any combination of numbers who's product is 500!"
Thus: 1 joules x seconds = 1kJ for 1ms. 
i wonder if that's even right lol.  also 1 joule-sec = 1 joule/Hz

watt = joules/sec 
joules = watt-seconds

alan,

"watt = joule / second"
is correct.

"joules = watt-seconds"
means joules equals watt minus seconds, which is meaninglessness.

joule = watt second

Also can be used joule = watt • second, where • is symbol for "dot product" in vector algebra, or simply multiplication with scalars or numbers. Often times symbols × or * are used for multiplication.

J = ws = Ws = W • s = W × s = W * s = watt second = Joule

This is the standard nomenclature.
bi

edit:
Look it up.

alan

  • Hero Member
  • *****
  • Posts: 716
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #819 on: June 22, 2022, 10:50:46 PM »
okay. - is a dash, not a minus.

Jimboot

  • Hero Member
  • *****
  • Posts: 1407
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #820 on: June 23, 2022, 04:24:27 AM »
Find the optimal position of the rotor in the stator. This is not a simple process, you need to turn the rotor by one stator tooth, each time and try, you need to find the position at which the induction is maximum.

For your drive in this matter:

https://youtube.com/shorts/0LmQzSx06uE


******
 ;) ;) ;)

For all who doubt, doubt your health! Take care of your nervous system!
For alternating current: input and output - the wattmeter showed everything correctly, according to its technical characteristics. It is enough to evaluate the result
Looks like I'm using the same gen. Looks like he has all the output phases wired. I didn't. Bit hard to tell what is going where. Will check again tonight

rakarskiy

  • Hero Member
  • *****
  • Posts: 924
    • Free Energy Systems (UA)
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #821 on: June 23, 2022, 07:28:28 AM »
Looks like I'm using the same gen. Looks like he has all the output phases wired. I didn't. Bit hard to tell what is going where. Will check again tonight

The result obtained on the excitation winding (the one with 8 ohm resistance) - the scheme of the experiment




PS
--------------
don't forget that pandora's box is open
https://youtube.com/shorts/0LmQzSx06uE

Jimboot

  • Hero Member
  • *****
  • Posts: 1407
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #822 on: June 23, 2022, 08:06:54 AM »
Thank you sir. So the 8ohm was referring to the stator and not the rotor coils in series. I appreciate the schematic. Will report back.

Frederik2k1

  • Newbie
  • *
  • Posts: 8
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #823 on: June 23, 2022, 08:44:52 AM »
The result obtained on the excitation winding (the one with 8 ohm resistance) - the scheme of the experiment




PS
--------------
don't forget that pandora's box is open
https://youtube.com/shorts/0LmQzSx06uE

How is this possible? Can you trust the meters?

I wonder if this is the scheme from Xiaodong Liu et. al.: A novel Transformer with compensation coil, which states:
Quote
The power can be delivered with zero input current in the primary coil when the turn number of secondary
coil is the same as that of compensating coil. When a boost coil is added to the
compensating coil, the input current in primary coil is phase inverted relative to its input
voltage. A magnetic shunt is added to adjust the flux leakage of this transformer.

See attached PDF, posted in https://overunity.com/18878/reactive-current-parallel-rcl/345/ .
 

kolbacict

  • Hero Member
  • *****
  • Posts: 1418
Re: Holcomb Energy Systems:Breakthrough technology to the world
« Reply #824 on: June 23, 2022, 10:21:10 AM »
Can you trust the meters?
The best proof is self-running.