No. With this, power input stays constant regardless of load.
Thanks, I was just looking for confirmation of that.
also
The device is more efficient / more power goes out the rotating shaft
when it runs "smoother".
cool
Given a mind set of conservation of energy and so on....
COP > 1 is "only possible" because, in analogy / example,
one can arrive at having more energy at some point of use / location,
by simply carrying a gallon of gasoline (potential energy)
from one location to another,
than the energy one might expend in the process of
the transporting of that gasoline to that location.
Something like that / one way of conventionally describing COP > 1...
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One aspect of the mechanical output which is the result of the electric input
and which can be calculated, is the amount of energy expended in causing
the accelerations of the reciprocating objects in the device.
examination / observations /
questions / answers /
not asking you to answer these questions
1. What are the number of strokes per revolution ?
2. What are the revolutions per minute ?
3. What are the strokes per second ?
4. What is the combined mass of all of the reciprocating objects (in grams) ?
5. What is the length of the travel (in meters) of the reciprocating objects in 1 stroke ?
6. What is the total length traveled (in meters) as strokes in 1 minute ?
7. What is the total length traveled (in meters) as strokes in 1 second ?
This is what the speed of the reciprocating travel averages out to (? millimeters /second).
This is velocity or meters/second or v.
8. During each stroke mass is accelerated to a velocity of ? meters/second ?
9. The kinetic energy (Joules) present in the form of a moving mass = 1/2 * mass * velocity ^2
10. The kinetic energy present in a moving mass is equal to the energy put into it
to cause it to accelerate to the velocity of its motion.
This is the energy (joules) expended as force to cause the mass to accelerate
to v, in each stroke.
11. Each stroke uses ? joules to cause acceleration ... each second has ? strokes ...
1 joule per second = 1 watt of power.
12. In general... one might consider that the greater the mechanical load one places upon
the spinning shaft the lesser would be the percentage of input energy wasted in
accelerating the reciprocating elements of the device (because they would
accelerate to a lesser velocity) . However, with this kind of device, the arresting
of the output rotation will not arrest the motion of the reciprocating parts ? There is
no mechanical / gear linkage between the two.
13. The less massive the reciprocating objects are, the less the energy is wasted in
accelerations
14. The stronger the magnets which are used are, in proportion to their mass, the more
power the device can output for a given input.
15. The mechanical load upon the rotating shaft does not significantly affect the input
electrical power ?
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Looking forward to
seeing your explorations /
next builds
floor
